In my where clause I have to manually change the weeks for both the clauses ("Week" and "Can_Week_End"). And in my example, the weeks end on Sundays (12/4,12/11,12/18, etc...). How can I manipulate the where clause filter so it does the date changing automatically. If someone queries out
select * from myview
Monday morning, it will show the data correspondent to the last week ending on the passed Sunday (day before). Is there a way to accomplish this? Please provide insights.
create view myview
as
select case when sd."Build_Spec" = 'Spec' then 'X' else '' end as "Spec",
case when sd."Build_Spec" = 'Build' then 'X' else '' end as "Build",
Case when sd."Can_Week_End" = '' then '' else 'X' end as "Cancel",
sd."Price",
sd."Sq_Ft" as "SF",
sd."Price"::money / to_number(sd."Sq_Ft",'99999999') as "PPSF",
case when sd."Realtor_Sale" is not null then 'X' else '' end as "Realtor"
from datapcr sd
left join comppcr ad on "Address" = "Address_of_New_Home"
where sd."Week" = '2016-12-18'or sd."Can_Week_End" = '12/18/2016'
order by "Cancel"
It's unclear why you have two different date formats in the same query, and it's also unclear where you want to draw the line exactly. but basically, you can solve this with date_trunc():
...
where sd."Week" = date_trunc('week', now())::date - 1
...
date_trunc('week', now()) returns Mon, 00:00 of the current week. Cast to date and subtract 1 to get the date of last Sunday. Voilá.
Related:
How do I determine the last day of the previous month using PostgreSQL?
Related
So I have a query in BQ that looks as such:
SELECT
SubscriptionId,
start_time,
STRFTIME_UTC_USEC((UTC_USEC_TO_MONTH(TIMESTAMP_TO_USEC(TIMESTAMP(start_time)))),'%B %Y') AS cohort_month,
UTC_USEC_TO_MONTH(start_time) AS usec_month,
STRFTIME_UTC_USEC((UTC_USEC_TO_WEEK(TIMESTAMP_TO_USEC(TIMESTAMP(start_time)), 0)),'%Y-%m-%d') AS cohort_week,
WEEK(start_time) AS usec_week,
DATE(start_time) AS cohort_day,
UTC_USEC_TO_DAY(start_time) AS usec_day,
amount,
current_period_start,
current_period_end,
cancel_date,
end_date,
cancel_at_period_end,
salesRepEmail,
CASE WHEN (salesRepEmail IS NOT NULL) THEN 'Telesales' ELSE 'Online' END AS sales_channel,
status,
type_id,
CASE WHEN (type_id IN ('150032',
'150033',
'150023')) THEN 'Annual' ELSE 'Monthly' END AS duration,
refunded
FROM
[data_snapshots_daily.subs_charges_refunds_]
WHERE
start_time >= '2016-04-01 00:00:00'
AND refunded = FALSE
What I'm looking to do though, is add on to the query so that it returns all the relevant data from the most recent month, week, and day.
So I imagine it involves something to do with MAX(usec_month) but I can't figure it out. Remember, I only want it to return relevant data when it's included in the most recent month (June)
i think of something like below
for current month
WHERE YEAR(CURRENT_DATE()) = YEAR(start_time)
AND MONTH(CURRENT_DATE()) = MONTH(start_time)
for current week
WHERE YEAR(CURRENT_DATE()) = YEAR(start_time)
AND WEEK(CURRENT_DATE()) = WEEK(start_time)
for current day
WHERE CURRENT_DATE() = DATE(start_time)
quick add
for last two weeks play with something like below (should be improved to handle first week of the year)
WHERE (YEAR(CURRENT_DATE()) = YEAR(start_time) AND WEEK(CURRENT_DATE()) = WEEK(start_time))
OR CASE WHEN WEEK(CURRENT_DATE()) = 1
THEN (YEAR(CURRENT_DATE()) - 1 = YEAR(start_time) AND 53 = WEEK(start_time))
ELSE (YEAR(CURRENT_DATE()) = YEAR(start_time) AND WEEK(CURRENT_DATE()) - 1 = WEEK(start_time))
END
Breakdown of above statement (per your request)
It looks for starttime that either belong to current or previous week. Current week is straightforward. In case of previous week it looks if current week is not the first week of the year - in this case condition is - same year but previous week. And in case if current week is first week of the year - it looks for last week of previous year.
cleaner version to handle last two weeks condition
DATE(start_time)>DATE(DATE_ADD(CURRENT_DATE(),-7*1-DAYOFWEEK(CURRENT_DATE()),'DAY'))
changing 1 in 7*1 to let's say 3 - will give you condition for last four weeks for example
I have the following statement in teradata
case when extract(year from current_date) - 1 = extract(year from event_date)
and weeknumber_of_year(event_date) = weeknumber_of_year(current_date) then 'Y' else 'N' end as "WTD_LY"
The issue is my 'week' is supposed to start on a Monday, instead of Sunday. How would I need to tweak this?
There's an optional parameter for week number_of_year:
weeknumber_of_year(current_date, 'ISO')
But you logic will fail, e.g. there's a week 53 in 2015/16, but not in 2014.
I have a bit tricky question. E.g. I have a start_date: 15/01/2015 and an end date: 17/03/2015 for given record and I would like to generalize that to know, if the record with those exact start and end date belongs to January (by my definition even if it is 31/01/2015, then it belongs to January).
I did the following:
sum(case when to_date('2015/01/01','yyyy/mm/dd') between ROUND(dtime_method_start,'MONTH') and ROUND(dtime_method_end,'MONTH') then 1 else 0 end) as flag_jan
But the problem with Round function is, that it takes everything from 16-31 as next month, which is no good for me. How can I fix it or rewrite it to make it comply with my definition?
I want to know if a record with certain dtime_method_start and dtime_method_end belongs to January. I have many records with many different start and end dates and want to know how many of them belong to January.
SELECT expected,
CASE
WHEN to_date('01/01/2015','DD/MM/YYYY') = ALL (trunc(start_date,'MONTH'), trunc(end_date,'MONTH'))
THEN 1
ELSE 0
END flag_jan
FROM
(SELECT 'notmatch 0' expected
, to_date('15/01/2015','DD/MM/YYYY') start_date
, to_date('17/03/2015','DD/MM/YYYY') end_date
FROM dual
UNION ALL
SELECT 'match 1'
, to_date('12/01/2015','DD/MM/YYYY')
, to_date('23/01/2015','DD/MM/YYYY')
FROM dual
) dates;
this query compares the truncated start_date and end_date to match the first day of the month.
To check another month_flag, juste change the date in the first case expression.
Just use trunc instead of round. Trunc with parameter 'MONTH' will truncate the date to the first day of month. If you test with between using first day of month it's ok.
I would compare the stored dates directly to a range based on the input date, rather than applying a function to every date:
count(case when dtime_method_start >= trunc(to_date('2015/01/01','yyyy/mm/dd'),'mm')
and dtime_method_start < add_months(trunc(to_date('2015/01/01','yyyy/mm/dd'),'mm'),1)
then 1
end) as flag_jan
Or you could
count(case when trunc(dtime_method_start,'mm') = trunc(to_date('2015/01/01','yyyy/mm/dd'),'mm')
then 1
end) as flag_jan
I have created a report for management that will total everything up by month with in a date range. Management has now decided that rather than by month they would like to go by period. We have 13 periods in a year each is 28 days except the last one is 29 or 30 depending on if its a leap year. The beginning of the first period is always 1-1-YYYY. So now I will need to figure out what the beginning and end of each period is and total up each period. I am not really sure how to do this since every year the dates will change and they may want to look at periods from the previous year through the current period. The code and results I am currently using are enclosed
SELECT
DATEADD(MONTH, DATEDIFF(MONTH, 0, finspecteddate), 0) AS 'Date'
,COUNT(*) AS Lots
,sum(flotSize) as 'Lot Size'
,sum(LReject) 'Lots Rejected'
,sum(fnumreject) as Rejected
,sum(fsampleSize) as 'Sample Size'
,sum(BDueDate) as 'Before Due Date'
FROM
ReportData
WHERE
finspecteddate >= '01-01-2014'
AND finspecteddate <= '10-15-2014'
GROUP BY
DATEADD(MONTH, DATEDIFF(MONTH, 0, finspecteddate), 0)
ORDER BY
date
Modify the following queries to suit your needs:
;WITH Period AS (
SELECT 1 AS ReportingPeriod,
CAST('2013-01-01' AS datetime) AS PeriodStartDate,
CAST('2013-01-28' AS datetime) AS PeriodEndDate
UNION ALL
SELECT CASE
WHEN p.ReportingPeriod = 13 THEN 1
ELSE p.ReportingPeriod + 1
END,
CASE
WHEN p.ReportingPeriod = 13 THEN DATEADD(YEAR,YEAR(p.PeriodStartDate)-1899,'1900-01-01')
ELSE DATEADD(DAY,28,p.PeriodStartDate)
END,
CASE
WHEN p.ReportingPeriod = 12 THEN DATEADD(YEAR,YEAR(p.PeriodStartDate)-1900,'1900-12-31')
ELSE DATEADD(DAY,28,p.PeriodEndDate)
END
FROM Period p
WHERE p.PeriodStartDate < '2017-12-03'
)
SELECT
P.PeriodStartDate
,P.PeriodEndDate
,COUNT(*) AS Lots
,sum(flotSize) as 'Lot Size'
,sum(LReject) 'Lots Rejected'
,sum(fnumreject) as Rejected
,sum(fsampleSize) as 'Sample Size'
,sum(BDueDate) as 'Before Due Date'
FROM
ReportData R
INNER JOIN Period P ON R.finspecteddate >= P.PeriodStartDate AND R.finspecteddate <= P.PeriodEndDate
WHERE
finspecteddate >= '01-01-2014'
AND finspecteddate <= '10-15-2014'
GROUP BY
P.PeriodStartDate
,P.PeriodEndDate
ORDER BY
P.PeriodStartDate
It uses a recursive CTE to build a period table, which is then joined to ReportData to aggregate asccording to your requirements. I don't have SQL Server 2005 to test it on. It works with 2008. Post a SQL Fiddle if you need help in 2005.
If you haven't got one, create a period calendar table with a year, period number, start date and end date columns. Then when you need to refer to periods, you can refer to the table. When they change the definition of what a period is, you can change the table. When they decide that February 29 doesn't count as one of the 28 days, you can change the table. When they decide to use the first Monday instead of the first Thursday as the start of the year, you just change the table. And best of all, changing how next year works won't change how last year works.
Then you just join to the table to determine which period you're in.
I need some help to understand a certain line in a code. The code takes the turnovers of every Monday in the year 2010 and at the last line in summarizes all the turnovers to one.
Here is the code:
SELECT
CASE
WHEN GROUPING (DATUM) = 1 THEN 'Gesamtumsatz'
ELSE CAST (DATUM AS VARCHAR (40))
END AS MONTAGSDATEN,
AVG (VERKAUFSWERT * VERKAUFSMENGE) as UMSATZ
FROM Data_Star_Awesome.dbo.VERKAUFSFAKTEN vk
INNER JOIN DIMDATUM dimD on vk.DATUMID=dimD.DATUMID
WHERE DATEDIFF(dd,0, DATUM)%7=0
AND JAHR = 2010
GROUP BY ROLLUP (DATUM)
The problematic line I don't understand is the following:
WHERE DATEDIFF(dd,0, DATUM)%7=0
What I know is that it takes the days out of the date variable but I don't get the %7=0 part. The DATEDIFF function should give back all the days. Are these days saved in the % the placeholder? And how does it get all the Mondays by using the 7=0?
It would be great if someone could help me out.
Thanks a lot :)
Modulo or % operator is the same as in a lot of programming languages. It returns the remainder after the division.
The DATEDIFF function takes two dates and returns the difference in a specified datepart, which in your query is the days represented by dd.
Also 0 as date converts to 1/1/1900 which happens to be a Monday. So your query is calculating the days between 1/1/1900 and the DATUM field in days and if its Mod is 0 then DATUM is Monday.
You could simply say:
datename(weekday,<datetime-value>)
Which will return 'Monday', 'Tuesday', 'Wednesday', etc. The problem with this approach is that the returned value is localized. If the SQL server's language is changed, your test for 'Monday' will fail.
This expression will always work:
( ##datefirst + ( datepart(weekday,today) - 1 ) ) % 7
It evaluates to 1-7, where Monday is always 1 and Sunday is always 7, regardless of culture/language settings or the current value of ##datefirst, as set by set datefirst.
We can then convert this into this discriminant function, yielding 1 or 0 to indicate whether or not the date is Monday:
case ( ##datefirst + ( datepart(weekday,today) - 1 ) ) % 7 when 1 then 1 else 0 end