I've created a very simple app on Wit.ai, but the App is not responding as I expect. So I want to remove it and create a new one.
But the problem is that I don't see any menu option to remove it.
How can I delete an App on Wit.ai?
Setting(right most)>>In danger Zone tab>>Delete App
Hope this helps.
open your wit.ai app from the console to the right click on settings then scroll down till you find delete app
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I am new in Xcode and IOS development.
i have designed and finished my app and i connected with Parse for push notification and core data.
the problem is what i didn't understand is: if in future i want to change the background of my app or add new event or to change the palace of button my app, how can i do that? i have to rebuild and submit it again or there is any way to do by online a website like parse?
i couldn't find the answer any where, help please...
Thanks ,
If you had designed your app to load the background data from Parse, then you could just put the new background on Parse and your app would load it. There is no need to submit a new app to do that. If you did it this way, you'd want to have a default background in the case when the network is not available.
You can't add new code to your application with this method (that is not allowed), but you can add data such as images, text, etc. The key point here is that you have to design your app from the start to work this way, then it is simply a matter of putting the new data on Parse where your app can find it.
Expanding on #vacawama's very good answer:
For this version you are out of luck, since it sounds like you did not design it to use a background that is loaded from your Parse server.
What you need to do is to code an update to your app that has these new abilities, and submit that to the app store. Once that version is approved then you should be able to change the background from the server.
I want to add a link from my app to another of my apps on the appstore.
Question How to link to apps on the app store showed that the itunes.apple.com link was,until recently, the normal way to go. I've tried this and everything is fine. The problem begins when I disgard this and use Apple's new recommendation of using appstore.com. I use the following line of code:
[UIApplication sharedApplication] openURL:[NSURL URLWithString:#http://appstore.com/myappname"]];
The first time I call this from my app it works well. You see it jump through Safari and move onto the appstore where it displays my app.
At this point if you look back into Safari you will notice a new blank tab labelled Favourites has been created.
If I go back to my app and perform the same action to link to the appstore again I'm prompted with one of the two popup boxes:
"Open this page in "App Store"? [Cancel] or [Open].
or
"Cannot Open Page. Safari cannot open the page because the address is invalid" [OK]
I've found that manually deleting the blank tab in Safari will allow the link to work properly but this behaviour isn't what I want my users to see- and I wouldn't be expecting them to delete the blank tabs from Safari.
Any advice on stopping this behaviour whilst following Apple's new rules greatly appreciated.
A simple and clean solution is to present an instance of SKStoreProductViewController inside your app (modally) to display information on the products you are interested in. The user can interact with it as a small view on the App Store and you can simply dismiss it when done.
I am working on a nodewebkit app. Looking for a functionality where in I can change task-bar icon of app to notify users, similar to what Skype does when a new message is received by user.
Is there any way it can be done in Nodewebkit?
Initially I tried changing window.icon in package.json file, but then I came to know that it is used only once, i.e. on app load. So that did not work.
Anything else I can try?
Thanks in advance
Window.requestAttention(Boolean attention) is what I was looking for.
It worked for me.
Thanks to Dhiraj, It gave me an additional feature for icon.
I am a newbie for Robotium and till then I managed to learn a lot by directly writing test cases for public websites and sorted out several issues from answers in stackoverflow. now, I seemed to hit the wall at this (probably)trivial problem.
I would like to navigate to 'Settings' icon which is inside 'Apps' menu of the android emulator using some sort of 'robotium-solo' method.
This is my failed attempt:
solo.sendKey(KeyEvent.KEYCODE_HOME);
//solo.clickOnImageButton(2); // no success!
//solo.clickOnActionBarItem(2); // no success!
solo.clickOnText("Settings");
solo.clickOnText("Music");
I checked for any KEYCODE_var for home screen 'app' icon but couldn't find one.
There is no useful log message in DDMS to figure out the starting activity when clicked/tapped on that button.s
Please guide me whether my approach is any good and help me with an answer. Thanks.
you can check with getCurrentViews() and have the list of views displayed before clicking the menu button and after clicking the menu button.By comparing them you can get the view of the new views displayed (i.e. settings button).
After getting the view,you can go with solo.clickOnView(ViewNameObtained);
This will solve your problem for sure.
As far as I know, navigating to settings is not possible with robotium. Even if you would be able to go there you cannot perform any other action as Settings are not port of your application. Android Instrumentation allows performing actions only within one package and robotium is only wrapper for that, so it's not able to click outside your application as well.
You can use UI Automator for that.
I would like to be able to turn VoiceOver on or off within my iOS app. The reason for this is I am trying to help a person with disabilities which render her unable to read messages (hence the need for VoiceOver), and who is also unable to triple click the home-button due to motor coordination problems. The way to the setting through Settings>General>Accessibility>VoiceOver>VoiceOver>Flipswitch is far too long and complicated.
Is it possible, without jailbreaking the device, to change this setting in an app? The app doesn't need to make it to the App Store, if that helps.
Alternatively, is it easy to do this with a jailbroken device?
Another approach may be to simulate the triple-click on the home-button that automatically turns on VoiceOver. Is there any way to do this?
Get the app aHomeIcon.
Open the app and tap URL.
Insert the url: prefs:root=General&path=ACCESSIBILITY
Tap 'Done'.
Insert a name to be shown below the icon.
Tap the export button at the bottom of the page. Safari opens.
Add a bookmark and select 'to home-screen'.
Now you can tap that icon and you are redirected to the accessibility part of the settings app.
See this link for reference.