Authenticating JasperServer 6.3 with active directory not WORKING - authentication

Question

I'm trying to use ActiveDirectory to authenticate to JasperServer , that still not working for some reason :
here is my configuration :
1. STEP 1 : access params to the AD Server :
<bean id="ldapContextSource" class="com.jaspersoft.jasperserver.api.security.externalAuth.ldap.JSLdapContextSource">
<constructor-arg value="ldap://192.10.0.190:389/dc=sifast,dc=infra"/>
<!-- manager user name and password (may not be needed) -->
<property name="userDn" value="CN=recherche,CN=Users,DC=sifast,DC=infra"/>
<property name="password" value="*******"/>
<property name="referral">
<value>follow</value>
</property>
</bean>
2.STEP 2: configuration of the access within "userDnPatterns" :
here i wanna access with the login already entered
<bean id="ldapAuthenticationProvider" class="com.jaspersoft.jasperserver.api.security.externalAuth.wrappers.spring.ldap.JSLdapAuthenticationProvider">
<constructor-arg>
<bean class="com.jaspersoft.jasperserver.api.security.externalAuth.wrappers.spring.ldap.JSBindAuthenticator">
<constructor-arg><ref local="ldapContextSource"/></constructor-arg>
<property name="userDnPatterns">
<list>
<value>CN={0},CN=Users,DC=sifast,DC=infra</value>
</list>
</property>
</bean>
</constructor-arg>
<constructor-arg>
<bean class="com.jaspersoft.jasperserver.api.security.externalAuth.wrappers.spring.ldap.JSDefaultLdapAuthoritiesPopulator">
<constructor-arg index="0"><ref local="ldapContextSource"/></constructor-arg>
</bean>
so here i'm setting it within that : CN={0},CN=Users,DC=sifast,DC=infra
3. STEP 3 : configuring the userSearch method:
<bean id="userSearch"
class="com.jaspersoft.jasperserver.api.security.externalAuth.wrappers.spring.ldap.JSFilterBasedLdapUserSearch">
<constructor-arg index="0">
<value></value>
</constructor-arg>
<constructor-arg index="1">
<value>(sAMAccountName={0})</value>
</constructor-arg>
<constructor-arg index="2">
<ref local="ldapContextSource" />
</constructor-arg>
<property name="searchSubtree">
<value>true</value>
</property>
</bean>
here i'm using the login "({0})" entered to look for the similar sAMAccountName of the right user.
that still not working.
my AD Schema looks like this:
so i wanna let simple users inside CN=USERS acquire access
Actually my authentication is still failing. Any ideas?

Answer 1

In your step 2 spring configuration file JSBindAuthenticator missing the following property reference:
<property name="userSearch" ref="userSearch"/>