How to Add First for 1 to 10 dates for a month and Add Last for 20 to 30 days of month.
DECLARE #Today DATE = '2016-11-05'
Select CONVERT(VARCHAR(5),datepart (DW, #Today)-1 )+' DAYS of '+ LEFT(DATENAME(month,#Today),3) Comments
I'm getting like this
Comments
6 DAYS of Nov
How to get like this :
Comments
First 6 DAYS of Nov
if I give date as '2016-11-24'
need output like this
Comments
Last 4 DAYS of Nov
Suggest me the way to proceed
Use a case statement:
Select (CASE WHEN day(#today) <= 10 THEN 'First '
WHEN day(#today) >= 20 THEN 'Last '
ELSE ''
END) + CONVERT(VARCHAR(5), datepart(DW, #Today)-1 ) + ' DAYS of ' +
LEFT(DATENAME(month, #Today), 3) as Comments
EDIT:
Oh, now I see the original query was not right. So you want something more like this:
Select (CASE WHEN day(#today) <= 10 THEN 'First ' + DATENAME(day, #today) + ' DAYS of ' + LEFT(DATENAME(month, #Today), 3)
WHEN day(#today) >= 20 AND MONTH(#Today) IN (1, 3, 5, 7, 8, 10, 12) THEN 'Last ' + CAST(31 - day(#today) as varchar(255))
WHEN day(#today) >= 20 AND MONTH(#Today) IN (4, 6, 9, 11) THEN 'Last ' + CAST(30 - day(#today) as varchar(255))
WHEN day(#today) >= 20 AND MONTH(#Today) IN (2) AND YEAR(#Today) % 4 = 0 THEN 'Last ' + CAST(29 - day(#today) as varchar(255))
WHEN day(#today) >= 20 AND MONTH(#Today) IN (2) AND YEAR(#Today) % 4 <> 0 THEN 'Last ' + CAST(29 - day(#today) as varchar(255))
ELSE CAST(day(#today) as varchar(255))
END) + ' DAYS of ' + LEFT(DATENAME(month, #Today), 3) as Comments
DECLARE #Today DATE = '2016-11-09'
Select (CASE WHEN day(#today) <= 10 THEN 'First ' + DATENAME(day, #today)
WHEN day(#today) >= 20 THEN 'Last ' + CAST(DAY(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,#Today)+1,0))) - day(#today) as varchar(255))
ELSE CAST(day(#today) as varchar(255) )
END) + ' DAYS of ' + LEFT(DATENAME(month, #Today), 3)
With SQL Server 2012 developers can now use new SQL date function EOMonth() for calculating the last date of the month where a given date is in.
Here is my query
--DECLARE #Today DATE = '2016-11-05'
DECLARE #Today DATE = '2016-11-24'
SELECT
case when DATEPART(dd,#Today) <= 10 then
'First ' + convert(varchar(2), DATEPART(dd,#Today)) + ' of ' + DATENAME(mm,#Today)
else
'Last ' + convert(varchar(2), DATEDIFF(dd, #Today, EOMONTH (#Today))) + ' of ' + DATENAME(mm,#Today)
end
The SQL EOMonth() function makes it easier to calculate the last date of a month, and also indirectly calculating the first date of next month or previous month
SELECT case when DATEPART(dd,#Today) <= 10 then
'First ' + convert(varchar(2), DATEPART(dd,#Today)) + ' DAYS of ' + DATENAME(mm,#Today)
WHEN DATEPART(dd,#Today) >= 20 then 'Last ' + convert(varchar(2),
DATEDIFF(dd, #Today, EOMONTH (#Today))) + ' DAYS of ' + DATENAME(mm,#Today)
ELSE #Today END
Related
I have table with employees work experience. I want to get summary experience in format like yy mm dd.
e_id work_from work_to
2 2003-10-13 2004-02-12
2 2004-02-16 2004-06-30
2 2004-07-01 2006-01-31
2 2006-02-01 2017-07-12
Result should be: 13Y 8M 27D
Query like:
sum(datediff(month,work_from,work_to))/12,
sum(datediff(month,work_from,work_to)%12
works fine, but what about days?
Please note, the following query is a general summation which does not include leap years and the months are averaged between 365/12 in days since the amount of days in each month vary. If you want an exact figure that includes the exact amount of days, the algorithm will be more involved, but hopefully this gets you in a reasonably close ballpark figure.
SELECT CONVERT(VARCHAR(10), sum(datediff(year,work_from,work_to))-1) + 'Y' AS Years,
CONVERT(VARCHAR(10), FLOOR((sum(datediff(day, work_from,work_to)) - ((sum(datediff(year,work_from,work_to)) - 1) * 365)) / 30.4166)) + 'M' AS Months,
CONVERT(VARCHAR(10), CEILING(sum(datediff(day, work_from,work_to)) - ((sum(datediff(year,work_from,work_to)) - 1) * 365) - (FLOOR((sum(datediff(day, work_from,work_to)) - ((sum(datediff(year,work_from,work_to)) - 1) * 365)) / 30.4166) * 30.4166))) + 'D' AS Days,
CONVERT(VARCHAR(10), sum(datediff(day,work_from,work_to))) AS Total_Days
Here is my solution. This is the closest I can get. The problem that I had is that I cant escape the M after month.
DECLARE #SumExp Datetime = (SELECT CONCAT(
DATENAME(day, (SELECT SUM(DATEDIFF(day, WorkFrom, WorkTo))
FROM EmployeeWorkExperience)),
DATENAME(month, (SELECT SUM(DATEDIFF(day, WorkFrom, WorkTo))
FROM EmployeeWorkExperience)),
DATENAME(year, (SELECT SUM(DATEDIFF(day, WorkFrom, WorkTo))
FROM EmployeeWorkExperience))))
SELECT REPLACE(FORMAT(#SumExp, 'yyY MM# ddD'), '#', 'M')
DECLARE #work TABLE(
WorkId INT IDENTITY(1,1) PRIMARY KEY ,
work_from DATETIME NOT NULL,
work_to DATETIME NOT NULL )
INSERT INTO #work
( work_from, work_to )
VALUES ( '10/13/2003',
'2/12/2004'
),
(
'2/16/2004',
'6/30/2004'
),
('7/1/2004',
'1/31/2006'
),
('2/1/2006',
'7/12/2017'
)
DECLARE #seconds int
SELECT #seconds = SUM(DATEDIFF(SECOND, work_from, work_to))
FROM #work
DECLARE #VARDT DATETIME = DATEADD(SECOND, #seconds, 0)
SELECT CAST(DATEPART(YEAR, #VARDT) - 1900 AS VARCHAR(10)) + ' year(s) ' + CAST(DATEPART(MONTH, #VARDT) - 1 AS VARCHAR(2)) + ' month(s) '
+ CAST(DATEPART(DD, #VARDT) - 1 AS VARCHAR(2)) + ' day(s) ' + CAST(DATEPART(HOUR, #VARDT) AS VARCHAR(2)) + ' hour(s) '
+ CAST(DATEPART(MINUTE, #VARDT) AS VARCHAR(2)) + ' minute(s) ' + CAST(DATEPART(SECOND, #VARDT) AS VARCHAR(2)) + ' second(s)'
I have a sql job which queries the database. The job is scheduled to run every 24 hours and it sends out an email with required data which has a query range from 07:30 today to 07:30 the previous day. Here is the code for the heading of my email :
INSERT INTO #ReportContentBuilder VALUES('<h4>Query Range : ' + DATENAME(WEEKDAY,#StartTimestamp)
+ ', ' + CONVERT(varchar, #StartTimestamp, 106) + ' ' + CONVERT(varchar, #StartTimestamp, 108)
+ ' (UTC) to ' + DATENAME(WEEKDAY,#EndTimestamp) + ', ' + CONVERT(varchar, #EndTimestamp, 106)
+ ' ' + CONVERT(varchar, #EndTimestamp, 108) + ' (UTC)</h4>')
Here is the value I have for #StartTimestamp:
SET #StartTimestamp = CAST((CONVERT(varchar(11), DATEADD(DAY, -1, #EndTimestamp), 106) + ' 07:30') as datetime)
Here is the expected output for my email heading :
Query Range : Wednesday, 19 Nov 2014 07:30:00 (UTC) to Thursday, 20 Nov 2014 07:30:00 (UTC)
My question is what value do I use for #EndTimestamp??
If I use GETUTCDATE() and the job runs 2 mins late then the range is incorrect. I also don't want to hardcode it because of the changes needed for daylight savings each time.
The trick is that the "dynamic" part is the difference between current time (GETUTCDATE()) and 7:30 . So with #timeDiff you can handle this dynamic part of the ecuation. Try this (replace last select with your needed insert; I only tested the output):
DECLARE #StartTimestamp datetime
DECLARE #EndTimestamp datetime = GETUTCDATE()
DECLARE #timeDiff time
SET #timeDiff = CONVERT(time, (#EndTimestamp - cast('1900-01-01 07:30:00.000' as datetime)))
SELECT #EndTimestamp = dateadd(second,
datepart(hour,#timeDiff) * -3600 +
datepart(minute,#timeDiff) * -60 +
datepart(second,#timeDiff) * -1,
#EndTimestamp)
SET #StartTimestamp = DATEADD(DAY, -1, #EndTimestamp)
SELECT #StartTimestamp, #EndTimestamp
SELECT '<h4>Query Range : ' + DATENAME(WEEKDAY,#StartTimestamp)
+ ', ' + CONVERT(varchar, #StartTimestamp, 106) + ' ' + CONVERT(varchar, #StartTimestamp, 108)
+ ' (UTC) to ' + DATENAME(WEEKDAY,#EndTimestamp) + ', ' + CONVERT(varchar, #EndTimestamp, 106)
+ ' ' + CONVERT(varchar, #EndTimestamp, 108) + ' (UTC)</h4>'
I'm trying to display a start and end time for a SQL report. I always want to display the previous month period to look like:
Start Time: Aug 1st 2014 00:00:00
End Time: September 1st 2014 00:00:00
If the report was run in Oct it would give Sept1-Oct1. Not sure how to actually display that as a Datetime variable?
In a DATETIME format, that would be
SELECT
DATEADD(month, DATEDIFF(month, 0, GETDATE())-1, 0) AS StartTime,
DATEADD(month, DATEDIFF(month, 0, GETDATE()), 0) AS EndTime
If you want to play around with character formats, you can do a bunch of things, like
SELECT
DATENAME(MONTH,StartTime) + ' ' + CAST(YEAR(StartTime) AS VARCHAR(4)) + ' - ' + DATENAME(MONTH,EndTime) + ' ' + CAST(YEAR(EndTime) AS VARCHAR(4)),
LEFT(DATENAME(MONTH,StartTime),3) + ' ' + CAST(YEAR(StartTime) AS VARCHAR(4)) + ' - ' + LEFT(DATENAME(MONTH,EndTime),3) + ' ' + CAST(YEAR(EndTime) AS VARCHAR(4))
FROM
(
SELECT
DATEADD(month, DATEDIFF(month, 0, GETDATE())-1, 0) AS StartTime,
DATEADD(month, DATEDIFF(month, 0, GETDATE()), 0) AS EndTime
) dt
I apologize if i misunderstood but is this what you are looking for?
SELECT CAST(DATEADD(MONTH,-1,[date]) AS VARCHAR(12)) + '-' + CAST([date] AS VARCHAR(12)) FROM table
If you were to insert into your table a SMALLDATETIME such as
'2014-09-23 10:28:00'
then what would be produced is:
'Aug 23 2014 -Sep 23 2014 '
DATE_SUB(Date,INTERVAL 1 MONTH) AS PastMonth
would display one month prior to Date
I need an algorithm for calculating the number of the day of the week in the month. Like 1st Friday of the month, 3rd Monday of the month, etc.)
Any ideas are appreciated.
Here is the final result:
declare #dt date = GetDate()
declare #DayOfWeek tinyint = datepart(weekday,#dt)
declare #DayOfMonth smallint = day(#dt)
declare #FirstDayOfMonth date = dateadd(month,datediff(month,0,#dt),0)
declare #DayOfWeekInMonth tinyint = #DayOfMonth / 7 + 1 -
(case when day(#FirstDayOfMonth) > day(#dt) then 1 else 0 end)
declare #Suffix varchar(2) =
case
when #DayOfWeekInMonth = 1 then 'st'
when #DayOfWeekInMonth = 2 then 'nd'
when #DayOfWeekInMonth = 3 then 'rd'
when #DayOfWeekInMonth > 3 then 'th'
end
select
cast(#DayOfWeekInMonth as varchar(2))
+ #Suffix
+ ' '
+ datename(weekday,#Dt)
+ ' of '
+ datename(month,#dt)
+ ', '
+ datename(year,#Dt)
PS: And if you can think of a better way to state the problem, please do.
Followint code will give you 1st Wednesday of April 2014 for today:
SELECT cast((DATEPART(d, GETDATE() - 1) / 7) + 1 as varchar(12))
+ 'st ' + DATENAME(WEEKDAY, getdate()) + ' of ' +
DATENAME(month, getdate()) + ' ' + DATENAME(year, getdate());
For any date use the code below. It gives 5th Tuesday of April 2014 for #mydate = '2014-04-29' in the example:
DECLARE #mydate DATETIME;
SET #mydate = '2014-04-29';
SELECT
case
when DATEPART(d, #mydate) = 1 then cast((DATEPART(d, #mydate ) / 7) + 1 as varchar(12))
else cast((DATEPART(d, #mydate - 1) / 7) + 1 as varchar(12))
end
+
case
when (DATEPART(d, #mydate - 1) / 7) + 1 = 1 then 'st '
when (DATEPART(d, #mydate - 1) / 7) + 1 = 2 then 'nd '
when (DATEPART(d, #mydate - 1) / 7) + 1 = 3 then 'rd '
else 'th '
end
+ DATENAME(WEEKDAY, #mydate) + ' of ' +
DATENAME(month, #mydate) + ' ' + DATENAME(year, #mydate) as [Long Date Name]
Okeeeey my tuuuurn ,
Please rate my answer Metaphor hhh, Here's the cooode :
declare #v_month nvarchar(2) = '04'
,#v_annee nvarchar(4) = '2014'
declare #v_date date = convert(date,#v_annee+'-'+#v_month+'-01')
declare #v_date_2 date = dateadd(M,1,#v_date)
if OBJECT_ID('temp') is not null
drop table temp
create table temp(_date date, _DayOfMonth nvarchar(20), _order int)
while (#v_date<#v_date_2)
begin
set #v_date =#v_date;
WITH _DayOfWeek AS (
SELECT 1 id, 'monday' Name UNION ALL
SELECT 2 id, 'tuesday' Name UNION ALL
SELECT 3 id, 'wednesday' Name UNION ALL
SELECT 4 id, 'thursday' Name UNION ALL
SELECT 5 id, 'friday' Name UNION ALL
SELECT 6 id, 'saturday' Name UNION ALL
SELECT 7 id, 'sunday' Name)
insert into temp(_date,_DayOfMonth)
SELECT
#v_date
,(select Name from _DayOfWeek where id = DATEPART(WEEKDAY,#v_date))
SET #v_date = DATEADD(DAY,1,#v_date)
END
UPDATE tmp1
SET _order = _order_2
FROM temp tmp1
INNER JOIN
(SELECT *, ROW_NUMBER() OVER(PARTITION BY _DayOfMonth ORDER BY _date ASC) AS _order_2 FROM temp) tmp2
ON tmp1._date = tmp2._date
SELECT * FROM temp
SELECT *
FROM temp
WHERE _DayOfMonth = 'thursday'
AND _order = 3
I hope this will help you :)
Good Luck
OK, here's what I came up with, I'll +1 everyone who answered anyway:
declare #dt date = GetDate()
declare #DayOfWeek tinyint = datepart(weekday,#dt)
declare #DayOfMonth smallint = day(#dt)
declare #FirstDayOfMonth date = dateadd(month,datediff(month,0,#dt),0)
declare #DayOfWeekInMonth tinyint =
#DayOfMonth / 7 + 1
- (case when day(#FirstDayOfMonth) > day(#dt) then 1 else 0 end)
declare #Suffix varchar(2) =
case
when #DayOfWeekInMonth = 1 then 'st'
when #DayOfWeekInMonth = 2 then 'nd'
when #DayOfWeekInMonth = 3 then 'rd'
when #DayOfWeekInMonth > 3 then 'th'
end
select
cast(#DayOfWeekInMonth as varchar(2))
+ #Suffix
+ ' '
+ datename(weekday,#Dt)
+ ' of '
+ datename(month,#dt)
+ ', '
+ datename(year,#Dt)
declare #dt date = getdate()
declare #DayOfMonth smallint = datepart(d, #dt)
declare #Suffix varchar(2) =
case
when floor((#DayOfMonth - 1) / 7.0) = 0 then 'st' -- implies there were no such days previously in the month
when floor((#DayOfMonth - 1) / 7.0) = 1 then 'nd'
when floor((#DayOfMonth - 1) / 7.0) = 2 then 'rd'
else 'th'
end
select cast(floor((#DayOfMonth - 1) / 7.0) + 1 as varchar(1)) + #Suffix +
' ' + datename(weekday, #dt) + ' of ' + datename(month, #dt) +
', ' + datename(year, #dt)
DECLARE #dt DATETIME
SET #dt = DATEADD(d, 6, GETDATE())
SELECT #dt,
CAST((DAY(#dt) / 7) + CASE WHEN DATEPART(weekday, #dt) >= DATEPART(weekday, CAST(MONTH(#dt) AS NVARCHAR) + '/01/' + CAST(YEAR(#dt) AS NVARCHAR)) THEN 1 ELSE 0 END AS NVARCHAR)
+ '' + CASE (DAY(#dt) / 7) + CASE WHEN DATEPART(weekday, #dt) >= DATEPART(weekday, CAST(MONTH(#dt) AS NVARCHAR) + '/01/' + CAST(YEAR(#dt) AS NVARCHAR)) THEN 1 ELSE 0 END
WHEN 1 THEN N'st'
WHEN 2 THEN N'nd'
WHEN 3 THEN N'rd'
ELSE N'th'
END
+ ' ' + DATENAME(dw, #dt)
+ ' of ' + DATENAME(M, #dt)
+ ', ' + CAST(YEAR(#dt) AS NVARCHAR)
Result is a single SELECT (provided the assignment of #dt happened earlier) but is, essentially, the same logic as yours.
This following code will give you DATE for any day of the week in any month or year that you specify. All the variables that I have are to reduce repeating logic to improve code speed.
This code gives you date for 1st Monday in February in 2013
DECLARE #DayNumber INT = 1
,#DayWeekNumber INT = 2
,#MonthNumber INT = 2
,#YearNumber INT = 2013
,#FoM DATE
,#FoMWD INT;
SET #FoM = DATEFROMPARTS(#YearNumber,#MonthNumber,1)
SET #fomwd = DATEPART(WEEKDAY, #FoM);
SELECT CASE WHEN #fomwd = #DayWeekNumber THEN DATEADD(WEEK, #DayNumber - 1, #FoM)
WHEN #fomwd < #DayWeekNumber THEN DATEADD(DAY, #DayWeekNumber - #fomwd, DATEADD(WEEK, #DayNumber - 1, #FoM))
WHEN #fomwd > #DayWeekNumber THEN DATEADD(DAY, #DayWeekNumber - #fomwd, DATEADD(WEEK, #DayNumber, #FoM))
END AS DateOfDay;
I have an app that allows users schedule an action to occur in the future. For example, that can select a date and schedule it to run on that day every month (ex: the 15th of each month). However, I now need to allow them to select a week day and week of the month. For example, they need to run an action the first friday of the month. Therefore I am allowing the to select the weekday (monday, tuesday, wednesday....) and week of the month (1st, 2nd, 3rd, 4th or 5th).
Here is the query I currently use:
Declare #nowString varchar(19)
Declare #nowDateString varchar(19)
Declare #now datetime
Declare #lastMinute datetime
Declare #nowDate datetime
Set #nowString = '#currentDateTime#:00'
Set #nowDateString = LEFT(#nowString, 10)
set #now = #nowString
set #nowDate = DATEADD(dd, 0, DATEDIFF(dd, 0, #now))
set #lastMinute = DATEADD(mi, -1, #now)
select *
from message_prepared
where schedule = '1'
and active = '1'
and noaa = '0'
and (
(
schedule_type = 'recurring'
and startdate <= #nowDate
and isnull(enddate, DATEADD(yy, 1, #nowDate)) >= #nowDate
and (
#nowDateString + ' ' + isnull(recurring_start_time_hour, '00') + ':' + isnull(recurring_start_time_min, '00') + ':00' = #now
or #nowDateString + ' ' + isnull(recurring_start_time_hour, '00') + ':' + isnull(recurring_start_time_min, '00') + ':00' = #lastMinute
)
-- Test for different type of recurring
and (
( ltrim(rtrim(recurring)) = 'M' and DATEPART(dd, startdate) = DATEPART(dd, #now) )
or ( ltrim(rtrim(recurring)) = 'W' and DATEPART(dw, startdate) = DATEPART(dw, #now) )
or ltrim(rtrim(recurring)) = 'D'
)
)
or (
schedule_type = 'once'
and startdate = #nowDate
and (
#nowDateString + ' ' + onetime_start_time_hour + ':' + onetime_start_time_min + ':00' = #now
or #nowDateString + ' ' + onetime_start_time_hour + ':' + onetime_start_time_min + ':00' = #lastMinute
)
)
)
and repeat_multiple_times = 0
UNION ALL
SELECT *
FROM MESSAGE_PREPARED
WHERE schedule = '1'
AND active = 1
AND noaa = 0
AND recurring = 'D'
AND repeat_multiple_times = 1
AND startDate IS NOT NULL
AND recurring_start_time_hour IS NOT NULL
AND recurring_start_time_hour < 24
AND recurring_start_time_min IS NOT NULL
AND recurring_start_time_min < 60
AND startdate <= #nowDate
AND ISNULL(enddate, DATEADD(yy, 1, #nowDate)) >= #nowDate
AND
(
CASE WHEN repeat_unit = 'M'
THEN
DATEDIFF(n,
CONVERT(DATETIME,
CAST(DATEPART(yyyy, startDate) AS VARCHAR(4)) + '-' +
CAST(DATEPART(mm, startDate) AS VARCHAR(2)) + '-' +
CAST(DATEPART(dd, startDate) AS VARCHAR(2)) + ' ' +
CAST(recurring_start_time_hour AS VARCHAR(2)) + ':' +
CAST(recurring_start_time_min AS VARCHAR(2)) + ':00', 20),
GETDATE()) % repeat_interval
ELSE
DATEDIFF(n,
CONVERT(DATETIME,
CAST(DATEPART(yyyy, startDate) AS VARCHAR(4)) + '-' +
CAST(DATEPART(mm, startDate) AS VARCHAR(2)) + '-' +
CAST(DATEPART(dd, startDate) AS VARCHAR(2)) + ' ' +
CAST(recurring_start_time_hour AS VARCHAR(2)) + ':' +
CAST(recurring_start_time_min AS VARCHAR(2)) + ':00', 20),
GETDATE()) % (repeat_interval * 60)
END = 0
OR
CASE WHEN repeat_unit = 'M'
THEN
(DATEDIFF(n,
CONVERT(DATETIME,
CAST(DATEPART(yyyy, startDate) AS VARCHAR(4)) + '-' +
CAST(DATEPART(mm, startDate) AS VARCHAR(2)) + '-' +
CAST(DATEPART(dd, startDate) AS VARCHAR(2)) + ' ' +
CAST(recurring_start_time_hour AS VARCHAR(2)) + ':' +
CAST(recurring_start_time_min AS VARCHAR(2)) + ':00', 20),
GETDATE()) - 1) % repeat_interval
ELSE
(DATEDIFF(n,
CONVERT(DATETIME,
CAST(DATEPART(yyyy, startDate) AS VARCHAR(4)) + '-' +
CAST(DATEPART(mm, startDate) AS VARCHAR(2)) + '-' +
CAST(DATEPART(dd, startDate) AS VARCHAR(2)) + ' ' +
CAST(recurring_start_time_hour AS VARCHAR(2)) + ':' +
CAST(recurring_start_time_min AS VARCHAR(2)) + ':00', 20),
GETDATE()) - 1) % (repeat_interval * 60)
END = 0
)
This will only occur when reocurring is set to "M" and I would like to determine if today is the specific day of the week, week of the month and hour/min.
This is pretty simple logic. Today is the nth DOW of the month when the following is true:
Today is that day of the week
The day of the month is between 7*(n-1) + 1 and 7 * n
So, the first Monday of the month is always between the 1st and 7th, and so on. Here is an example case statement to test this:
declare #DayOfWeek varchar(255) = 'Thursday';
declare #Which int = 3;
select (case when datename(dw, Today) = #DayOfWeek and
(DAY(Today) - 1) / 7 = #Which - 1
then 1
else 0
end)
from (select CAST(getdate() as date) as Today) t
I've structured the query this way so you can test it with different values. Just replace the expression that defines Today, with something like getdate() - 3 or '2013-01-01'.