SQL Server 2008 Running Total - sql

Question

I'm aware this has been asked but I'm completely baffled.
Trying to run a running total by day using SQL Server 2008. Have looked at solutions elsewhere but would am still completely perplexed.
The below code shows Daily sales but I cannot make a running total fit. Have looked at the similar solutions here but no luck. Have looked at partition by, order by, CTE etc but I'm just not there yet with SQL.
Would appreciate help, my code is below. I know this only returns the total grouped by day...
SELECT
dim_invoice_date.invoice_date AS 'Invoice Date',
round(SUM(invoice_amount_corp),2) AS 'Sales'
FROM
fact_om_bud_invoice
JOIN
dim_invoice_date ON fact_om_bud_invoice.dim_invoice_date_key = dim_invoice_date.dim_invoice_date_key
WHERE
dim_invoice_date.current_cal_month IN ('Current')
AND fact_om_bud_invoice.budget_code IN ('BUDGET')
GROUP BY
dim_invoice_date.invoice_date
HAVING
ROUND(SUM(invoice_amount_corp), 2) <> 0
ORDER BY
'Invoice Date'
This returns the output:
Invoice Date Sales
-----------------------
4/10/2016 24,132
5/10/2016 15,849
6/10/2016 24,481
7/10/2016 10,243
10/10/2016 42,398
11/10/2016 24,187
Required format is something like:
Invoice Date Sales Running Sales
-------------------------------------------
04/10/2016 24,132 24,132
05/10/2016 15,849 39,981
06/10/2016 24,481 64,462
07/10/2016 10,243 74,705
10/10/2016 42,398 117,103
11/10/2016 24,187 141,290
dim_invoice_date is a numeric field, it's looking up a separate date table to display as date time.

Answer 1

For example, can use WITH common_table_expression
WITH cte AS
(
SELECT
ROW_NUMBER() OVER(ORDER BY h.[Date]) RowN,
h.[Date],
SUM(s.Quantity) q
FROM
Sales s
JOIN Headers h
ON s.ID_Headers = h.ID
WHERE
h.[Date] > '2016.10.31'
GROUP BY
h.[Date]
)
SELECT
c.[Date],
c.q,
SUM(c1.q)
FROM
cte c
JOIN cte c1
ON c1.RowN <= c.RowN
GROUP BY
C.[Date],
c.q
ORDER BY
c.[Date]