This is the first time I ask for your help,
Actually I have to create a query, and did a similar example for it. I have two tables,
Report (ReportID, Date, headCount)
Production(ProdID, ReportID, Quantity)
My question is using this query, I get a wrong result,
SELECT
Report.date,
SUM(Report.HeadCount) AS SumHeadCount,
SUM(Production.Quantity) AS SumQuantity
FROM
Report
INNER JOIN
Production ON Report.ReportID = Production.ReportID
GROUP BY
Date
ORDER BY
Date
I guess some rows are being counted more than once, could you please give me a hand?
EDIT
if i run a query to get a sum of headcount grouped by day, I get:
date Headcount
7/2/2012 1843
7/3/2012 1802
7/4/2012 1858
7/5/2012 1904
also for Production Qty I get:
2012-07-02 8362
2012-07-03 8042
2012-07-04 8272
2012-07-05 9227
but when i combine the both queries i get i false one, i expect on 2 july 8362 qty against 1843, but i get:
day TotalHeadcount totalQty
7/2/2012 6021 8362
7/3/2012 7193 8042
7/4/2012 6988 8272
7/5/2012 7197 9227
This may be helpful
SELECT Report.ReportDate,
Sum(Report.HeadCount) AS SumHeadCount,
ProductionSummary.SumQuantity
FROM Report
INNER JOIN (SELECT ReportID,
Sum(Production.Quantity) AS SumQuantity
FROM Production
GROUP BY ReportID) AS ProductionSummary
ON Report.ReportID = ProductionSummary.ReportID
GROUP BY ReportDate
ORDER BY ReportDate
One way of avoiding this (subject to RDBMS support) would be
WITH R
AS (SELECT *,
Sum(HeadCount) OVER (PARTITION BY date) AS SumHeadCount
FROM Report)
SELECT R.date,
SumHeadCount,
Sum(P.Quantity) AS SumQuantity
FROM R
JOIN Production P
ON R.ReportID = P.ReportID
GROUP BY R.date, SumHeadCount
ORDER BY R.date
Group records per date using following
SELECT ReportSummary.ReportDate, SUM(ReportSummary.SumHeadCount) AS SumHeadCount, SUM(ProductionSummary.SumQuantity) AS SumQuantity
FROM
(
SELECT Report.ReportDate, SUM(Report.HeadCount) AS SumHeadCount
FROM Report
GROUP BY Report.ReportDate
) AS ReportSummary
INNER JOIN
(
SELECT Report.ReportDate, Sum(Production.Quantity) AS SumQuantity
FROM Production
INNER JOIN Report
ON Report.ReportID = Production.ReportID
GROUP BY Report.ReportDate
) AS ProductionSummary
ON ReportSummary.ReportDate = ProductionSummary.ReportDate
GROUP BY ReportSummary.ReportDate
ORDER BY ReportSummary.ReportDate
We have same problem but I solved it. Try this.
SELECT tbl_report.SumHeadCount, tbl_report.date, tbl_production.SumQuantity
FROM
( select date,
SUM(HeadCount) AS SumHeadCount FROM Report GROUP by date)as tbl_report
JOIN
( select SUM(Quantity) AS SumQuantity, date FROM Production GROUP by date)as tbl_production
WHERE tbl_report.date = tbl_production.date
Related
I am working on a restaurant management system. There I have two tables
order_details(orderId,dishId,createdAt)
dishes(id,name,imageUrl)
My customer wants to see a report top 3 selling items / least selling 3 items by the month
For the moment I did something like this
SELECT
*
FROM
(SELECT
SUM(qty) AS qty,
order_details.dishId,
MONTHNAME(order_details.createdAt) AS mon,
dishes.name,
dishes.imageUrl
FROM
rms.order_details
INNER JOIN dishes ON order_details.dishId = dishes.id
GROUP BY order_details.dishId , MONTHNAME(order_details.createdAt)) t
ORDER BY t.qty
This gives me all the dishes sold count order by qty.
I have to manually filter max 3 records and reject the rest. There should be a SQL way of doing this. How do I do this in SQL?
You would use row_number() for this purpose. You don't specify the database you are using, so I am guessing at the appropriate date functions. I also assume that you mean a month within a year, so you need to take the year into account as well:
SELECT ym.*
FROM (SELECT YEAR(od.CreatedAt) as yyyy,
MONTH(od.createdAt) as mm,
SUM(qty) AS qty,
od.dishId, d.name, d.imageUrl,
ROW_NUMBER() OVER (PARTITION BY YEAR(od.CreatedAt), MONTH(od.createdAt) ORDER BY SUM(qty) DESC) as seqnum_desc,
ROW_NUMBER() OVER (PARTITION BY YEAR(od.CreatedAt), MONTH(od.createdAt) ORDER BY SUM(qty) DESC) as seqnum_asc
FROM rms.order_details od INNER JOIN
dishes d
ON od.dishId = d.id
GROUP BY YEAR(od.CreatedAt), MONTH(od.CreatedAt), od.dishId
) ym
WHERE seqnum_asc <= 3 OR
seqnum_desc <= 3;
Using the above info i used i combination of group by, order by and limit
as shown below. I hope this is what you are looking for
SELECT
t.qty,
t.dishId,
t.month,
d.name,
d.mageUrl
from
(
SELECT
od.dishId,
count(od.dishId) AS 'qty',
date_format(od.createdAt,'%Y-%m') as 'month'
FROM
rms.order_details od
group by date_format(od.createdAt,'%Y-%m'),od.dishId
order by qty desc
limit 3) t
join rms.dishes d on (t.dishId = d.id)
Hey everyone I have two tables with output like this:
Month_Table
Transaction_Table
I need to calculate the monthly revenue by channel and the previous month's revenue: I did this query but it is not completed
Select date_created, channel, sum(revenue) as monthly_revenue
from transaction_table
GROUP BY date_created,channel
The result should be displaying monthly revenue and the month's revenue of previous month.
How can I do that?
try this code .
with resultTable as(
select RT.channel,RT.sumRevenue,LT.[month-start_date],LT.month_end_date,LT.year_month
from (select t.channel,sum(revenue) as sumRevenue,M.month_index from Month_Table M,Transaction_Table T
where t.date_created BETWEEN m.[month-start_date] AND m.month_end_date
group by m.month_index,t.channel) RT Join Month_Table LT on RT.month_index = LT.month_index
)
select * from resultTable
output:
OR use this query
with resultTable as(
select RT.channel,RT.sumRevenue,LT.[month-start_date],LT.month_end_date,LT.year_month
from (select t.channel,sum(revenue) as sumRevenue,M.month_index from Month_Table M,Transaction_Table T
where t.date_created BETWEEN m.[month-start_date] AND m.month_end_date
group by m.month_index,t.channel) RT Join Month_Table LT on RT.month_index = LT.month_index
)
select *,LAG(sumRevenue,1) OVER (PARTITION BY channel ORDER BY channel) previous_month_sales from resultTable
output:
You could try uing a a join between you tables
Select a.month_index, a.year_month, b.channel, sum(b.revenue) as monthly_revenue
from Month_Table a
from transaction_table b ON b.date_created between a.month_start_date and a.month_and_date
amd month(b.date_created) = betwwen month(curdate()) -1 and month(curdate())
GROUP BY a.month_index, a.year_month, b.channel
order by a.year_month desc
Try this:
Select t1.date_created, t1.channel, sum(t1.revenue) as monthly_revenue ,sum(t2.revenue) prev_month_revenue
from transaction_table t1 left join transaction_table t2 on t1.channel = t2.channel and to_char(t1.date_created,'MM') = to_char(add_months(t2.date_created,-1),'MM')
GROUP BY t1.date_created,t1.channel;
Select
CIDetail.Itemname,
sum(CIDetail.TaxAmount+ CIDetail.LineAmount) As [TotalAmount]
From
CIDetail (Nolock)
INNER JOIN CIHeader On CIDetail.InvoiceNo= CIHeader.InvoiceNo
Where
CIHeader.InvoiceDate Between '2010-04-01' AND '2014-04-01'
Group By
CIDetail.Itemname
Have a derived table where you use ANSI SQL's EXTRACT to get the year part out of the date, and also add the amounts together. At main level you do GROUP BY both Itemname and year:
Select Itemname, "year", SUM(Amount) as TotalAmount
from
(
CIDetail.Itemname,
extract(year from CIHeader.InvoiceDate) as "year",
CIDetail.TaxAmount + CIDetail.LineAmount As Amount
From
CIDetail (Nolock)
INNER JOIN CIHeader On CIDetail.InvoiceNo= CIHeader.InvoiceNo
) dt
Group By
Itemname, "year"
No dbms tagged in question, but if your dbms doesn't support EXTRACT, try YEAR(CIHeader.InvoiceDate) for example, or something else.
Add to the query a order by clause. Here as you are saying that you want it by date, I will assume that one itemname has only one InvoiceDate. And thus its max will have the same value. You will have to do it as follows
Select CIDetail.Itemname,
sum(CIDetail.TaxAmount+ CIDetail.LineAmount) As [TotalAmount],
From CIDetail (Nolock) INNER JOIN CIHeader
On CIDetail.InvoiceNo= CIHeader.InvoiceNo
Where CIHeader.InvoiceDate Between '2010-04-01' AND '2014-04-01' Group By
CIDetail.Itemname
Order By max(CIHeader.InvoiceDate) ASC
I am trying to return the most ordered product per month, of the year 2007. I would like to see the name of the product, how many of them where ordered that month, and the month. I am using the AdventureWorks2012 database. I have tried a few different ways but each time multiple product orders are returned for the same month, instead of the one product that had the most order quantity that month. Sorry if this is not clear. I am trying to test myself so I make up my own questions and try to answer them. If anyone knows a site that have questions and answers like this so I can verify that would be super helpful! Thanks for any help. Here is the farthest I have been able to get with the query.
WITH Ord2007Sum
AS (SELECT sum(od.orderqty) AS sorder,
od.productid,
oh.orderdate,
od.SalesOrderID
FROM Sales.SalesOrderDetail AS od
INNER JOIN
sales.SalesOrderHeader AS oh
ON od.SalesOrderID = oh.SalesOrderID
WHERE year(oh.OrderDate) = 2007
GROUP BY ProductID, oh.OrderDate, od.SalesOrderID)
SELECT max(sorder),
s.productid,
month(h.orderdate) AS morder --, s.salesorderid
FROM Ord2007Sum AS s
INNER JOIN
sales.SalesOrderheader AS h
ON s.OrderDate = h.OrderDate
GROUP BY s.ProductID, month(h.orderdate)
ORDER BY morder;
Make a CTE that groups our products by month and creates a sum
;WITH OrderRows AS
(
SELECT
od.ProductId,
MONTH(oh.OrderDate) SalesMonth,
SUM(od.orderqty) OVER (PARTITION BY od.ProductId, MONTH(oh.OrderDate) ORDER BY oh.OrderDate) ProdMonthSum
FROM SalesOrderDetail AS od
INNER JOIN SalesOrderHeader AS oh
ON od.SalesOrderID = oh.SalesOrderID
WHERE year(oh.OrderDate) = 2007
),
Make a simple numbers table to break out each month of the year
Months AS
(
SELECT 1 AS MonthNum UNION SELECT 2 UNION SELECT 3 UNION SELECT 4
UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8
UNION SELECT 9 UNION SELECT 10 UNION SELECT 11 UNION SELECT 12
)
We query our months table against the data and select the top product for each month based on the sum
SELECT
m.MonthNum,
d.ProductID,
d.ProdMonthSum
FROM Months m
OUTER APPLY
(
SELECT TOP 1 r.ProductID, r.ProdMonthSum
FROM OrderRows r
WHERE r.SalesMonth = m.MonthNum
ORDER BY ProdMonthSum DESC
) d
Your group by statement should not include oh.OrderDate, od.SalesOrderID because this will aggregate your data to the incorrect level. You want the ProductID that was most commonly sold per month so the group by conditions become ProductID, datepart(mm,oh.OrderDate). As Andrew suggested the Row_Number function is useful in this case as it lets you create a key that is ordered by month and sorder and which resets each month. Finally in the outer query limits the results to the first instance (which is the highest quantity)for each month.
WITH Ord2007Sum
AS(
SELECT sum(od.orderqty) AS sorder,
od.productid,
datepart(mm,oh.OrderDate) AS 'Month'
row_number() over (partition by datepart(mm,oh.OrderDate)
Order by datepart(mm,oh.OrderDate)desc, sorder desc) row
FROM Sales.SalesOrderDetail AS od
INNER JOIN
sales.SalesOrderHeader AS oh
ON od.SalesOrderID = oh.SalesOrderID
WHERE datepart(yyyy,oh.OrderDate) = 2007
GROUP BY ProductID, datepart(mm,oh.OrderDate)
)
SELECT productid,
sorder,
[month]
FROM Ord2007Sum
WHERE row =1
I'm creating an SQL statement that will return a month by month summary on sales.
The summary will list some simple columns for the date, total number of sales and the total value of sales.
However, in addition to these columns, i'd like to include 3 more that will list the months best customer by amount spent. For these columns, I need some kind of inline subquery that can return their ID, Name and the Amount they spent.
My current effort uses an inline SELECT statement, however, from my knowledge on how to implement these, you can only return one column and row per in-line statement.
To get around this with my scenario, I can of course create 3 separate in-line statements, however, besides this seeming impractical, it increases the query time more that necessary.
SELECT
DATE_FORMAT(OrderDate,'%M %Y') AS OrderMonth,
COUNT(OrderID) AS TotalOrders,
SUM(OrderTotal) AS TotalAmount,
(SELECT SUM(OrderTotal) FROM Orders WHERE DATE_FORMAT(OrderDate,'%M %Y') = OrderMonth GROUP BY OrderCustomerFK ORDER BY SUM(OrderTotal) DESC LIMIT 1) AS TotalCustomerAmount,
(SELECT OrderCustomerFK FROM Orders WHERE DATE_FORMAT(OrderDate,'%M %Y') = OrderMonth GROUP BY OrderCustomerFK ORDER BY SUM(OrderTotal) DESC LIMIT 1) AS CustomerID,
(SELECT CustomerName FROM Orders INNER JOIN Customers ON OrderCustomerFK = CustomerID WHERE DATE_FORMAT(OrderDate,'%M %Y') = OrderMonth GROUP BY OrderCustomerFK ORDER BY SUM(OrderTotal) DESC LIMIT 1) AS CustomerName
FROM Orders
GROUP BY DATE_FORMAT(OrderDate,'%m%y')
ORDER BY DATE_FORMAT(OrderDate,'%y%m') DESC
How can i better structure this query?
FULL ANSWER
After some tweaking of Dave Barkers solution, I have a final version for anyone in the future looking for help.
The solution by Dave Barker worked perfectly with the customer details, however, it made the simpler Total Sales and Total Sale Amount columns get some crazy figures.
SELECT
Y.OrderMonth, Y.TotalOrders, Y.TotalAmount,
Z.OrdCustFK, Z.CustCompany, Z.CustOrdTotal, Z.CustSalesTotal
FROM
(SELECT
OrdDate,
DATE_FORMAT(OrdDate,'%M %Y') AS OrderMonth,
COUNT(OrderID) AS TotalOrders,
SUM(OrdGrandTotal) AS TotalAmount
FROM Orders
WHERE OrdConfirmed = 1
GROUP BY DATE_FORMAT(OrdDate,'%m%y')
ORDER BY DATE_FORMAT(OrdDate,'%Y%m') DESC)
Y INNER JOIN
(SELECT
DATE_FORMAT(OrdDate,'%M %Y') AS CustMonth,
OrdCustFK,
CustCompany,
COUNT(OrderID) AS CustOrdTotal,
SUM(OrdGrandTotal) AS CustSalesTotal
FROM Orders INNER JOIN CustomerDetails ON OrdCustFK = CustomerID
WHERE OrdConfirmed = 1
GROUP BY DATE_FORMAT(OrdDate,'%m%y'), OrdCustFK
ORDER BY SUM(OrdGrandTotal) DESC)
Z ON Z.CustMonth = Y.OrderMonth
GROUP BY DATE_FORMAT(OrdDate,'%Y%m')
ORDER BY DATE_FORMAT(OrdDate,'%Y%m') DESC
Move the inline SQL to be a inner join query. So you'd have something like...
SELECT DATE_FORMAT(OrderDate,'%M %Y') AS OrderMonth, COUNT(OrderID) AS TotalOrders, SUM(OrderTotal) AS TotalAmount, Z.OrderCustomerFK, Z.CustomerName, z.OrderTotal as CustomerTotal
FROM Orders
INNER JOIN (SELECT DATE_FORMAT(OrderDate,'%M %Y') as Mon, OrderCustomerFK, CustomerName, SUM(OrderTotal) as OrderTotal
FROM Orders
GROUP BY DATE_FORMAT(OrderDate,'%M %Y'), OrderCustomerFK, CustomerName ORDER BY SUM(OrderTotal) DESC LIMIT 1) Z
ON Z.Mon = DATE_FORMAT(OrderDate,'%M %Y')
GROUP BY DATE_FORMAT(OrderDate,'%m%y'), Z.OrderCustomerFK, Z.CustomerName
ORDER BY DATE_FORMAT(OrderDate,'%y%m') DESC
You can also do something like:
SELECT
a.`y`,
( SELECT #c:=NULL ) AS `temp`,
( SELECT #d:=NULL ) AS `temp`,
( SELECT
CONCAT(#c:=b.`c`, #d:=b.`d`)
FROM `b`
ORDER BY b.`uid`
LIMIT 1 ) AS `temp`,
#c as c,
#d as d
FROM `a`
Give this a shot:
SELECT CONCAT(o.order_month, ' ', o.order_year),
o.total_orders,
o.total_amount,
x.sum_order_total,
x.ordercustomerfk,
x.customername
FROM (SELECT MONTH(t.orderdate) AS order_month,
YEAR(t.orderdate) AS order_year
COUNT(t.orderid) AS total_orders,
SUM(t.ordertotal) AS total_amount
FROM ORDERS t
GROUP BY MONTH(t.orderdate), YEAR(t.orderdate)) o
JOIN (SELECT MONTH(t.orderdate) AS ordermonth,
YEAR(t.orderdate) AS orderyear
SUM(t.ordertotal) 'sum_order_total',
t.ordercustomerfk,
c.customername
FROM ORDERS t
JOIN CUSTOMERS c ON c.customerid = o.ordercustomerfk
GROUP BY t.ordercustomerfk, MONTH(t.orderdate), YEAR(t.orderdate)) x ON x.order_month = o.order_month
AND x.order_year = o.order_year
ORDER BY o.order_year DESC, o.order_month DESC