Retrieve all XML elements with the same prefix in SQL Server - sql

Question

I have an XML file in a format similar to:
<XML>
<Field1>100</Field1>
<Field2>200</Field2>
<Field3>300</Field3>
<Test>400</Test>
</XML>
I need to write a query that will get all of the element values that start with Field. So given the XML above the result should be
FieldVal
--------
100
200
300
I've tried the following but it does not work:
Select
xc.value('text()', 'int')
From
#XMLData.nodes('/XML/[starts-with(name(), ''Field'')]') As xt(xc)
NOTE: I am well aware that this task could be easily done if I reformatted my XML but unfortunately I have no control over the format of the XML.

Answer 1

One way is
declare #XMLData xml ='<XML>
<Field1>100</Field1>
<Field2>200</Field2>
<Field3>300</Field3>
<Test>400</Test>
</XML>'
Select
xc.value('.', 'int')
From #XMLData.nodes('/XML/*') As xt(xc)
WHERE xc.value('local-name(.)', 'varchar(50)') LIKE 'Field%'

Answer 2

Prefix name with special character and check contains instead.
declare #x xml ='<XML>
<Field1>100</Field1>
<Field2>200</Field2>
<Field3>300</Field3>
<Test>400</Test>
</XML>';
select t.n.value('.','varchar(100)')
from #x.nodes ('XML/*[contains(concat("$",local-name()),"$Field")]') t(n);

Answer 3

I think it's this what you are looking for:
DECLARE #xml XML=
'<XML>
<Field1>100</Field1>
<Field2>200</Field2>
<Field3>300</Field3>
<Test>400</Test>
</XML>';
SELECT Fld.value('.','int') AS FieldOnly
FROM #xml.nodes('/XML/*[substring(local-name(.),1,5)="Field"]') AS A(Fld)
Just because of the discussion in comments:
DECLARE #fldName VARCHAR(100)='Field';
SELECT Fld.value('.','int') AS FieldOnly
FROM #xml.nodes('/XML/*[substring(local-name(.),1,string-length(sql:variable("#fldName")))=sql:variable("#fldName")]') AS A(Fld)
Change the first line to "Test" (case sensitive!), and you'd get just the one row with 400...