SQL Extract Value from XML - sql

Question

I have the following XML and I want to extract the FieldValue using SQL. How can I do this?
<Field Group="Annuitant">
<FieldName>Contract Number</FieldName>
<FieldValue>TR13116544</FieldValue>
</Field>
Thanks

Answer 1

DECLARE #xml XML=
'<Field Group="Annuitant">
<FieldName>Contract Number</FieldName>
<FieldValue>TR13116544</FieldValue>
</Field>';
--the lazy approach
SELECT #xml.value('(//FieldValue)[1]','varchar(50)')
--Better
SELECT #xml.value('(/Field/FieldValue)[1]','varchar(50)')
--This is, what you should do: Be as specific as possible...
SELECT #xml.value('(/Field/FieldValue/text())[1]','varchar(50)')
If there are - what I assume - are several <Field> elements and you need to pick the rigth one, you can do something like this:
DECLARE #name VARCHAR(100)='Contract Number';
SELECT #xml.value('(/Field[(FieldName/text())[1]=sql:variable("#name")]/FieldValue/text())[1]','varchar(50)')
Hint: Your question is not very clear, that needs a lot of guessing on my side. For your next question I ask you to be more specific.

Answer 2

Sample code:
DECLARE #MyXML XML
SET #MyXML ='<SampleXML>
<Fruits>
<Fruits1>Apple</Fruits1>
<Fruits2>Pineapple</Fruits2>
</Fruits>
</SampleXML>'
SELECT
a.b.value('Fruits[1]/Fruits1[1]','varchar(10)') AS Fruits1,
a.b.value('Fruits[1]/Fruits2[1]','varchar(10)') AS Fruits2
FROM #MyXML.nodes('SampleXML') a(b)

Answer 3

In oracle you can do the following:
WITH TABL (FIELD) AS (
select xmltype('<Field Group="Annuitant">
<FieldName>Contract Number</FieldName>
<FieldValue>TR13116544</FieldValue>
</Field>') from dual
)
SELECT
EXTRACTVALUE(FIELD,'/Field/FieldName') AS FIELDNAME,
EXTRACTVALUE(field,'/Field/FieldValue') AS FieldValue
FROM TABL ;