Image: http://i.stack.imgur.com/CyyHo.jpg
I have a dataset as shown in the image. I want to use the values of created_date column as datetime format. How can i do that?
The time you would like to convert is called Unix timestamp, which means how many seconds have passed since 1970/01/01. In this occasion you will have to use DATA function, which will take the total number of seconds and add them to 1970/01/01.
In SQL it is done in the following way:
select DATEADD(s, dateTimeInSeconds, '19700101')
Where s is Seconds and dateTimeInSeconds is your value of date; '19700101' is a starting point.
Column values does not seems to be a TimeStamp.
Use the below script to make the values as datetime .
SELECT credits,amount,city,
CONVERT(DATETIME,LEFT(created_date,8)
+' '+SUBSTRING(created_date,9,2)
+':'+SUBSTRING(created_date,11,2)
+':'+RIGHT(created_date,2)) Created_Date
FROM YourTable
Is created_date of type 'epoch'? And are you trying to use the datetime format within the SQL database or within your business logic? If it is in the business logic, it then depends on the language you use. I'd love to help but I don't fully understand the use case. If you could provide more information that would help us help you!
Cheers!
It doesn't look like unix timestamp but datetime without some chars (just digits are left).
To get "real" timestamp use in MySql: unix_timestamp()
To convert "real" timestamp to datetime use in MySql: FROM_UNIXTIME()
To convert your column to datetime use:
CONCAT(SUBSTR(created_date, 1, 4),
'-',
SUBSTR(created_date, 5, 2),
'-',
SUBSTR(created_date, 6, 2),
' ',
SUBSTR(created_date, 7, 2),
':',
SUBSTR(created_date, 11, 2),
':',
SUBSTR(created_date, 13, 2))
Related
I have values in a column named Date as a nvarachar data type in the form of mmddyy and want to convert the values to a date datatype in the form of yyyy-mm-dd, what sql colde can I use to convert the value.
example
02121955 -> 1955-02-12
You can use datefromparts():
select datefromparts(right(str, 4), left(str, 2), substring(str, 3, 2))
Or reconstruct it as yyyymmdd format and just convert:
select convert(date, left(right(str, 4) + str, 8))
Here is a db<>fiddle.
I have found a similar Question to yours that has been solved: https://stackoverflow.com/a/39139155/14940878
Here is the Code changed for your requests:
declare #date varchar(max)='02121955'
select convert(varchar(8),cast(CONCAT(SUBSTRING(#date,5,4),'/',SUBSTRING(#date,1,2),'/',SUBSTRING(#date,3,2)) as date),112)as [YYYYMMDD]
You need to take each field and concat it into one and then convert it to datetime.
SUBSTRING(#date,5,4) - Takes the last four characters.
SUBSTRING(#date,1,2) - Takes the first two.
SUBSTRING(#date,3,2) - Takes the two in the middle.
Assuming it's SQL Server, I think you just need
select cast(format(02121955,'##-##-####') as date)
DEMO
I have a varchar column with the following format ddmmyyyy and I'm trying to convert it to date in the format dd-mm-yyyy. I'm using the query below but I get the error:
Conversion failed when converting date and/or time from character string.
select *, coalesce(try_convert(date, newdate, 105), convert(date, newdate))
from mydate
You don't have a date, you have a string. So, you can use string operations:
select stuff(stuff(newdate, 5, 0, '-'), 3, 0, '-')
If you want to convert to a date, you can do:
select convert(date, concat(right(newdate, 4), substring(newdate, 3, 2), left(newdate, 2)))
You could then format this as you want.
However, you should not be converting the value to a date. You should be storing it as a date in the first place.
To turn your string to a date, you can just [try_]cast() it; SQL Server is usually flexible enough to figure out the format by itself:
try_cast(newdate as date)
If you want to turn it back to a string in the target format, then you can use format():
format(try_cast(newdate as date), 'dd-MM-yyyy')
Compared to pure string operations, the upside of the try_cast()/format() approach is that it validates that the string is a valid date in the process.
Have to agree with the others. Why are you storing a date as a string in the first place? In a non-standard format, no less? Here's one way, but you should really fix the data model. Store dates as dates.
DECLARE #badIdea table (dt char(8));
INSERT #badIdea(dt) VALUES('21052020');
SELECT newdate = TRY_CONVERT(date, RIGHT(dt,4) + SUBSTRING(dt,3,2) + LEFT(dt,2))
FROM #badIdea;
BTW 105 won't work because it requires dashes. This works:
SELECT CONVERT(date, '21-05-2020', 105);
That's a bad format too, IMHO, because who knows if 07-08-2020 is July 8th or August 7th. But at least that one is supported by SQL Server. Your current choice is not.
SQL doesn't store date data types in different formats, and it's probably not a good idea to try and adjust this.
If, however, you are wanting a result set to simply display the date in a different format, you are on the right track. You just need to convert your date data type to a string.
SELECT *
, COALESCE ( TRY_CONVERT ( CHAR(10), newdate, 105 ), CONVERT ( CHAR(10), newdate ) )
FROM mydate
I'am using SQLite DB and I have "Date" column that is VARCHAR
I need to extract data between 2 dates...
this is what I tried....
SELECT * FROM Table1 WHERE Date BETWEEN '14/03/2017 17:00:10' AND '16/03/2018 17:00:12'
SELECT * FROM Table1 WHERE strftime('%d/%m/%y %H:%M:%S', Date) BETWEEN strftime('%d/%m/%y %H:%M:%S','15/07/2016 20:00:09') AND strftime('%d/%m/%y %H:%M:%S','16/07/2017 21:00:09')
SELECT * FROM Table1 WHERE strftime('%d/%m/%y %H:%M:%S', Date) BETWEEN '2017/07/15 20:00:09' AND '2017/07/17 21:00:09'
Any idea what I am doing wrong ?
If you have a date/time column, then just do:
SELECT t1.*
FROM Table1 t1
WHERE t1.Date >= '2017-03-14 17:00:10' AND
t1.Date < '2018-03-16 17:00:12';
Use ISO/ANSI standard date formats for constants!
I strongly discourage you from using between with date/time values. Here is a blog post on the subject, which although for SQL Server applies to all databases.
You can't use SQLite's strftime because it's formatting function, it can not parse input string.
Basically you have two options:
try to parse string using builtin functions
create user defined function
If you can rely on the fixed positions, you can easily parse your string and format it back to comply with one of supported SQLite DateTime formats. In your case it might look like this:
SELECT [Date] FROM Table1 WHERE
DATETIME(printf('%04d-%02d-%02d %02d:%02d:%02d',
substr([Date], 7, 4), substr([Date], 4, 2), substr([Date], 1, 2),
substr([Date], 12, 2), substr([Date], 15, 2), substr([Date], 18, 2)))
BETWEEN '2017-07-15 20:00:05' AND '2017-07-17 21:00:09'
Please note you have to change also syntax of BETWEEN to match one of supported DATETIME formats.
I'm pretty new to Sybase and am writing a query to return results after a specified date, and also before a specified date. MM/DD/YYYY format
At the moment im doing..
SELECT *
From aTable
WHERE afterDate >= 08/07/2013
AND beforeDate <= 08/08/2013
I'm getting records back, but as I'm a Sybase newbie, I want to be sure Sybase is interpreting these dates correctly..
Their online doc is pretty bad for basic explanations on things like this!
Anyone able to confirm if what I have works, or does it need some formatting round the dates?
You'll need to convert the dates into DATETIME and tell sybase what the format is to be sure.
According to this documentation the code for MM/DD/YYYY is 101, so something like this:
SELECT *
FROM aTable
WHERE afterDate >= CONVERT(DATETIME,'08/07/2013',101)
AND beforeDate <= CONVERT(DATETIME,'08/08/2013',101)
You can see the difference by running the following select statements:
SELECT CONVERT(DATETIME,'08/07/2013',101) --MM/DD/YYYY (2013-08-07 00:00:00.000)
SELECT CONVERT(DATETIME,'08/07/2013',103) --DD/MM/YYYY (2013-07-08 00:00:00.000)
For any date-time field in sybase, instead of going through the convert function, there is a more direct approach.
SELECT *
From aTable
WHERE afterDate >= '2013-08-07'
AND beforeDate <= '2013-08-08'
The date has to be in the form 'YYYY-MM-DD'
If you want to add a time, it can be included along with the date. The date and the time have to be separated by a T.
Any date time field can be directly used using the format 'YYYY-MM-DDTHH:MM:SS'
Using the functions is too lengthy. Noone needs a bazooka to shoot a squirrel! :)
CAST( '2000-10-31' AS DATE )
will convert from text to date format....
I am assuming that your two fields (afterDate and beforeDate) are in Date format.
Your example would be:
SELECT *
From aTable
WHERE afterDate >= CAST( '08/07/2013' AS DATE )
AND beforeDate <= CAST( '08/08/2013' AS DATE )
Also, usually (but not always) a date range is on the SAME field. As I said, that is not true all the time and you may have a good reason for that.
The best approach is to use the ANSI standard which does not require any conversion: yyyymmdd (you can also include hh:mm:ss) for instance:
DateField1 >= "20150101" and DateFile1 <= "20150102"
You should decide which Input-Strings the user is going to use as parameter and then convert them and concatenate them like you want, unless it is Datetime it is not important which initial format it had, you can use it in a between-condition.
E. g. the user is from Europe and uses "DD.MM.YY" and "hh:mm" as an input parameter, I would convert and concatenate like this:
WHERE dateCol between convert(DATETIME,
convert(char(11),
convert(DATETIME, '01.06.14', 4), 16) || ' ' || '00:00', 8)
AND convert(DATETIME,
convert(char(11),
convert(DATETIME, '01.07.14', 4), 16) || ' ' || '16:00', 8)
I need to convert date format in SQL
The current format is yyyy/mm/dd-hh:mm:ss:sss and I need to convert it to yyyy-mm-dd hh:mm:ss CST
I don't really know SQL but did some research and found that I can use instr to find the string and replace it, however, no matter what I try,there is always something off :(
Could anyone here help me with it? thanks in advance.
By the way, it's in oracle sql developer so syntax are different from previous answer. Thanks again
If your current column is stored as a varchar (which it looks like it is based on your example) you can convert it the following way to a datetime.
declare #date varchar(25)
set #date = '2012/02/16-09:40:30:000'
select Convert(datetime, Left(#date, 4) + '-' +
substring(#date, 6, 2) + '-' +
substring(#date, 9, 2) + ' ' +
substring(#date, 12, 8)) As NewDate
And the result would be 2012-02-16 09:40:30.000
There are lots of sites that have details on converting datetime:
http://www.sql-server-helper.com/tips/date-formats.aspx
http://anubhavg.wordpress.com/2009/06/11/how-to-format-datetime-date-in-sql-server-2005/
If the date is stored as a datetime, then you can get your format by doing:
SELECT convert(varchar, getdate(), 120)
thank you so much for your guys help! I got this sorted out by other user's help, the command is,
update b
set first= to_char(substr(FIRST,1,4)||'-'||substr(FIRST, 6, 2)||'-'||substr(FIRST, 9, 2)||' '||substr(FIRST, 12, 8))
Thanks :)
Mylie
The CONVERT() function is normally used for this. The third parameter lets you specify the required date formatting.
If the date is already in a string, then convert it first into a date type and then convert it back to a string in the required format.
http://msdn.microsoft.com/en-us/library/ms187928.aspx
If you're using SQL Server and it's a date field you can do:
convert(varchar,getdate(),120)
Replacing getdate() with the column name
If the date is stored as a DATETIME, then you can convert it to a string in the format you want by doing the following:
SELECT CONVERT(VARCHAR(19),YourColumn,120)
FROM YourTable
CAST AND CONVERT
declare #ds varchar(23)='2012/02/16 12:57:03:002'; --your current format
select convert(varchar(30),cast(#ds as datetime),120)+' CST' --new format you specified