I'm using SQL Server Compact 4.0 version, and although it might seem a simple thing to find in google, the examples I've tried none of them work.
My column signup_date is a DateTime with a value 04-09-2016 09:05:00.
What I've tried so far without success:
SELECT FORMAT(signup_date, 'Y-m-d') AS signup_date;
SELECT CONVERT(signup_date, GETDATE()) AS signup_date
SELECT CAST(data_registo, date) AS signup_date
I found that I could use DATEPART function, but that would force me to concat the values, is this the right path to follow? If so, how do I concat as Y-m-d?
SELECT DATEPART(month, signup_date)
SQL Server Compact has no date type.
If you don't want to see the time, convert the datetime value to a string:
SELECT CONVERT(nvarchar(10), GETDATE(), 120)
(This has been tested and actually works against SQL Server Compact)
you were actually on track with the CAST function just a slight error in the syntax. In the CAST function, there needs to be 'as' i.e CAST(data_registo as date)
SELECT CAST(data_registo as date) AS signup_date;
Most of the answers seek to achieve same thing but the explanation to the codes is not enough
CONVERT(date, Date_Updated, 120)
this code does the conversion with mssql. The first item 'date' is the datatype to return. it could be 'datetime', 'varchar', etc.
The second item 'Date_Updated' is the name of the column to be converted.
the last item '120' is the date style to be returned. There are various styles and the code entered will determine the output. '120' represent YYYY-MM-DD.
Hope this helps
The old fashioned way of doing this in SQL Server might work for your purposes:
select dateadd(day, datediff(day, 0, signup_date), 0)
The datediff() gets the number of days (as an integer) since time 0. The dateadd() adds this number back.
If you don't like 0 as a date, you can put any valid date in its place:
select dateadd(day, datediff(day, '2000-01-01', signup_date), '2000-01-01')
EDIT:
If you simply don't want to see the time, convert the date to a string:
select convert(nvarchar(10), signup_date, 120)
(I recommend the YYYY-MM-DD format, but others are available.)
I have tried this and many other solutions. I wanted a generic solution that would work with any LCID. My solution is a bit of convoluted code, but it works perfectly for me. It's a booking system where I needed to find out who was arriving on a particular date. ArriveDate is the column, d is the DATE I want.
SQL = "SELECT * FROM tablename WHERE dateadd(day, datediff(day, 0,
ArriveDate), 0)=' " & Format(d, "yyyy-MM-dd") & " ' "
This will return only date value in original datetime type. So you can do any comparison using the output
SELECT convert(datetime, CONVERT(nvarchar(10), GETDATE(), 120))
Just saw the Question today, a bit late I know :) but maybe this will help..,
select convert(date,(convert(varchar(20),'04-09-2016 09:05:00')))
select convert(nvarchar, getdate(), 1) = 09/25/19
select convert(nvarchar, getdate(), 2) = 19.09.25
select convert(nvarchar, getdate(), 3) = 25/09/19
select convert(nvarchar, getdate(), 4) = 25.09.19
select convert(nvarchar, getdate(), 5) = 25-09-19
select convert(nvarchar, getdate(), 6) = 25 Sep 19
select convert(nvarchar, getdate(), 7) = Sep 25, 19
select convert(nvarchar, getdate(), 10) = 09-25-19
select convert(nvarchar, getdate(), 11) = 19/09/25
select convert(nvarchar, getdate(), 12) = 190925
select convert(nvarchar, getdate(), 23) = 2019-09-25
select convert(nvarchar, getdate(), 101) = 09/25/2019
select convert(nvarchar, getdate(), 102) = 2019.09.25
select convert(nvarchar, getdate(), 103) = 25/09/2019
select convert(nvarchar, getdate(), 104) = 25.09.2019
select convert(nvarchar, getdate(), 105) = 25-09-2019
select convert(nvarchar, getdate(), 106) = 25 Sep 2019
select convert(nvarchar, getdate(), 107) = Sep 25, 2019
select convert(nvarchar, getdate(), 110) = 09-25-2019
select convert(nvarchar, getdate(), 111) = 2019/09/25
select convert(nvarchar, getdate(), 112) = 20190925
select convert(nvarchar, getdate(), 8) = 13:48:36
select convert(nvarchar, getdate(), 14) = 13:49:48:713
select convert(nvarchar, getdate(), 24) = 13:49:57
select convert(nvarchar, getdate(), 108) = 13:50:07
select convert(nvarchar, getdate(), 114) = 13:50:14:490
select convert(nvarchar, getdate(), 0) = Sep 25 2019 1:50PM
select convert(nvarchar, getdate(), 9) = Sep 25 2019 1:50:31:813PM
select convert(nvarchar, getdate(), 13) = 25 Sep 2019 13:50:39:307
select convert(nvarchar, getdate(), 20) = 2019-09-25 13:50:49
select convert(nvarchar, getdate(), 21) = 2019-09-25 13:50:58.923
select convert(nvarchar, getdate(), 22) = 09/25/19 1:51:07 PM
select convert(nvarchar, getdate(), 25) = 2019-09-25 13:51:14.473
select convert(nvarchar, getdate(), 100) = Sep 25 2019 1:51PM
select convert(nvarchar, getdate(), 109) = Sep 25 2019 1:51:32:227PM
select convert(nvarchar, getdate(), 113) = 25 Sep 2019 13:51:38:740
select convert(nvarchar, getdate(), 120) = 2019-09-25 13:51:50
select convert(nvarchar, getdate(), 121) = 2019-09-25 13:51:57.153
select convert(nvarchar, getdate(), 126) = 2019-09-25T13:52:03.627
Use this, i had the same problem
SELECT CAST(data_registo as date) AS "signup_date"
To get a string value, use CONVERT
select convert(varchar(10), signup_date, 11)
Check here for various formats:
https://msdn.microsoft.com/en-us/library/ms187928.aspx
To get a DATE, and just strip out the time, do this
Select Cast (signup_date as DATE)
Related
How can I get the string from GETDATE() in D-MMM-YYYY format, e.g 3 May 2016
If I use CONVERT(VARCHAR, GETDATE(), 106), I would get a leading zero on day which is not what I want.
If you are on SQL Server 2012 or later, use FORMAT:
SELECT FORMAT(GETDATE(), 'd MMM yyyy')
Edit: some of the answers below are just flat-out wrong so I'm adding a solution for older versions of SQL Server. 2005 is the earliest that I can get my hands on:
SELECT CASE
WHEN CONVERT(varchar(20), GETDATE(), 106) LIKE '0%'
THEN SUBSTRING(CONVERT(varchar(20), GETDATE(), 106), 2, 20)
ELSE CONVERT(varchar(20), GETDATE(), 106)
END
SELECT case when left(convert(varchar(20),[DateColumn],106),1) ='0'
then right(convert(varchar(20),[DateColumn],106),len(convert(varchar(20),[DateColumn],106))-1)
else convert(varchar(20),[DateColumn],106)
end
FROM [DB].[dbo].[Table]
Some sample output :
29 Apr 2016
2 Apr 2016
If you cannot use FORMAT (Below SQL Server 2012)
DECLARE #date DATE = '20160503'
SELECT REPLACE(DATEPART(DAY, #date),' 0','') + ' ' +
CONVERT(CHAR(3), #date, 0) + ' ' +
CAST(DATEPART(YEAR, #date) AS CHAR(4))
Is there a function in SQL that formats a date when given the date and format string?
Similar to how .NET's DateTime.ToString(string format) method works?
I'd like to be able to call something like FORMAT(#myDateTime, 'ddMMMyyyy') and have it give me a string formatted as such.
I know the convert function works but it doesn't quite cover all formats. As an example, SQL can do "dd MMM yyyy" but not "ddMMMyyyy"
As far as I know there is no direct function that will convert date in format passed by you if you are on older SQL version. Format function is available starting from SQL 2012.
You can use convert function but it may not always suit your need.
Refer this: https://msdn.microsoft.com/en-IN/library/ms186724.aspx
To answer your question, this will give you date in DD-MMM-YYYY Format:
select REPLACE(REPLACE(CONVERT(VARCHAR,getdate(),106), ' ','-'), ',','')
For DDMMMYYYY format:
select REPLACE(REPLACE(REPLACE(CONVERT(VARCHAR,getdate(),106), ' ','-'), ',',''),'-','')
Also, you can check the date formats supported by convert function using this:
select convert(varchar, getdate(), 101)
select convert(varchar, getdate(), 102)
select convert(varchar, getdate(), 103)
select convert(varchar, getdate(), 104)
select convert(varchar, getdate(), 105)
select convert(varchar, getdate(), 106)
select convert(varchar, getdate(), 107)
select convert(varchar, getdate(), 108)
select convert(varchar, getdate(), 109)
select convert(varchar, getdate(), 110)
select convert(varchar, getdate(), 111)
select convert(varchar, getdate(), 112)
select convert(varchar, getdate(), 113)
hi i wrote this query in SqlServer 2008
but some thing goes wrong
select * from News_Table
where (DATEDIFF( DAY ,convert(datetime, NewsDate) , convert(datetime,#Todaydate )) <= #Count)
that #NewsDate and #Todaydate are two nvarchar parameters that are saved like this 2014/11/16
running this query give me an error:
Conversion failed when converting date and/or time from character string
Try adding the correct style parameter to your convert function (see MSDN: link )
ie CONVERT(DATETIME, NewsDate, 111) (111 is the style for YYYY/MM/DD)
Then you get:
SELECT *
FROM News_Table
WHERE (DATEDIFF( DAY ,
CONVERT(DATETIME, NewsDate, 111) ,
CONVERT(DATETIME,#Todaydate, 111)
) <= #Count)
use Convert(datetime, #yourvalue, 111)
select * from News_Table
where (DATEDIFF( DAY ,convert(datetime, #NewsDate, 111) , convert(datetime,#Todaydate, 111 )) <= #Count)
http://www.sqlusa.com/bestpractices/datetimeconversion/
To know more click here
SELECT convert(datetime, '2014/11/16', 111) as datetime
OP
So your query would be like this
Select * from News_Table
where (DATEDIFF( DAY ,convert(datetime, '2014/11/16', 111) , convert(datetime,#Todaydate,111 )) <= #Count)
Try like this
SELECT *
FROM News_Table
WHERE (DATEDIFF(DAY,CAST(NewsDate AS Datetime),CAST(#Todaydate AS Datetime)) <= #Count)
You will need to do something like this to convert that string into DATETIME datatype
DECLARE #Date NVARCHAR(20) = '2013/11/16'
SELECT CAST((LEFT(#Date, 4) + SUBSTRING(#Date, 6 ,2) + RIGHT(#Date, 2)) AS DATETIME)
for your query
select * from News_Table
where (DATEDIFF( DAY , CAST((LEFT(NewsDate, 4) + SUBSTRING(NewsDate, 6 ,2) + RIGHT(NewsDate, 2)) AS DATETIME)
, CAST((LEFT(#Todaydate, 4) + SUBSTRING(#Todaydate, 6 ,2) + RIGHT(#Todaydate, 2)) AS DATETIME)
) <= #Count)
Note
If variable #Todaydate is actually storing today's date then why not use simply GETDATE() function.
How can I display a DATETIME value (2010-12-02 15:20:17.000) as 02/12-2010 15:20?
For SQL Server:
select stuff(convert(varchar, getdate(), 105), 3, 1, '/') + ' ' + left(convert(varchar, getdate(), 8), 5)
DateTime is a DateTime is a DateTime - it just holds a date and time and doesn't have any string representation, really.
See the CAST and CONVERT topic in the SQL Server Books Online for details - it shows all supported date formats that SQL Server supports.
For your source format (2010-12-02 15:20:17.000) you could probably use style no. 121
DECLARE #source VARCHAR(50)
SET #source = '2010-12-02 15:20:17.000'
DECLARE #Date DATETIME
SELECT #Date = CONVERT(DATETIME, #source, 121)
SELECT #Date
but your target format is a bit odd..... I don't see any "out of the box" style that would match your needs. You'll need to use some string manipulation code to get that exact format.
Use MSSQL's build-in function to convert datetime to string with format,
SELECT CONVERT(VARCHAR(8), GETDATE(), 1) AS [MM/DD/YY] --2/5/12
SELECT CONVERT(VARCHAR(10), GETDATE(), 103) AS [DD/MM/YYYY] --5/2/2012
You need to create custom function to get various format to use like this;
SELECT dbo.ufn_FormatDateTime(GETDATE(),'YYYY-MM-DD HH:mm:SS tt')
--Output : 2012-02-05 01:58:38 AM
SELECT dbo.ufn_FormatDateTime(GETDATE(),'(dddd) mmmm dd, yyyy hh:mm:ss.fff tt')
--Output : (Sunday) February 05, 2012 01:58:38.723 AM
SELECT dbo.ufn_FormatDateTime(GETDATE(),'dd/MM/yyyy')
--Output : 05/02/2012
SELECT dbo.ufn_FormatDateTime(GETDATE(),'yyyy MMM, dd (ddd) hh:mm:ss tt')
-- Output : 2012 Feb, 05 (Sun) 01:58:38 AM
Get the code snippet from this link.
http://www.tainyan.com/codesnippets/entry-62/sql-server-date-time-format-function.html
http://msdn.microsoft.com/en-us/library/ms189491.aspx
Is this what you're looking for?
Assuming Oracle:
select TO_CHAR(SYSDATE, "dd/mm-yyyy HH24:mi")
from DUAL;
Assuming SQL Server:
select STR(DATEPART(DAY, GETDATE()), 2)
+ '/'
+ STR(DATEPART(MONTH, GETDATE()), 2)
+ '-'
+ STR(DATEPART(YEAR, GETDATE()), 4)
+ ' '
+ STR(DATEPART(HOUR, GETDATE()), 2)
+ ':'
+ STR(DATEPART(MINUTE, GETDATE()), 2);
Little example I use for Germany and Switzerland: dd.mm.yyyy hh:mm
SELECT CONVERT(varchar, GETDATE(), 104) + ' ' + LEFT(CONVERT(varchar, GETDATE(), 108), 5)
How can i convert the datetime format below
2010-10-25 11:13:36.700
into
25-Oct-2010 or 2010-10-25 00:00:00.000
To get "25-Oct-2010"
Assuming the value is supplied as a string, not a DATETIME data type:
SELECT REPLACE(CONVERT(VARCHAR, CAST('2010-10-25 11:13:36.700' AS DATETIME), 106), ' ', '-')
See the CAST/CONVERT documentation for other formats, though the one you requested requires post-processing.
To get "2010-10-25 00:00:00.000"
The best performing means is to use DATEADD & DATEDIFF:
SELECT DATEADD(d, DATEDIFF(dd, 0, '2010-10-25 11:13:36.700'), 0)
References:
DATEADD
DATEDIFF
Testing
WITH sample AS (
SELECT CAST('2010-10-25 11:13:36.700' AS DATETIME) dt)
SELECT REPLACE(CONVERT(VARCHAR, s.dt, 106), ' ', '-') AS col1,
DATEADD(d, DATEDIFF(dd, 0, s.dt), 0) AS col2
FROM sample s
Returns:
col1 col2
-------------------------------------
25-Oct-2010 2010-10-25 00:00:00.000
Addendum
Being that you're on SQL Server 2005, you could make date formatting easier for yourself by creating a SQLCLR function that would allow you to use the .NET date formatting.
check this one
SELECT convert(VARCHAR, getdate(),106)
this will give you 25 Oct 2010
AND
SELECT REPLACE(convert(VARCHAR, getdate(),106), ' ' , '-')
this will give you 25-Oct-2010
Check if this can help you:
SELECT REPLACE(CONVERT(VARCHAR(11), GETDATE(), 106), ' ', '-')
You can get more info Here
PD. Stackoverflow can be too addicted sometimes, you might wanna try google before
select CONVERT(NVARCHAR(20),getDATE(),105)
Please try
SELECT CONVERT(varchar, GETDATE(), 1) --12/30/06
SELECT CONVERT(varchar, GETDATE(), 2) --06.12.30
SELECT CONVERT(varchar, GETDATE(), 3) --30/12/06
SELECT CONVERT(varchar, GETDATE(), 4) --30.12.06
SELECT CONVERT(varchar, GETDATE(), 5) --30-12-06
SELECT CONVERT(varchar, GETDATE(), 6) --30 Dec 06
SELECT CONVERT(varchar, GETDATE(), 7) --Dec 30, 06
SELECT CONVERT(varchar, GETDATE(), 10) --12-30-06
SELECT CONVERT(varchar, GETDATE(), 11) --06/12/30
SELECT CONVERT(varchar, GETDATE(), 12) --061230
SELECT CONVERT(varchar, GETDATE(), 23) --2006-12-30
SELECT CONVERT(varchar, GETDATE(), 101) --12/30/2006
SELECT CONVERT(varchar, GETDATE(), 102) --2006.12.30
SELECT CONVERT(varchar, GETDATE(), 103) --30/12/2006
SELECT CONVERT(varchar, GETDATE(), 104) --30.12.2006
SELECT CONVERT(varchar, GETDATE(), 105) --30-12-2006
SELECT CONVERT(varchar, GETDATE(), 106) --30 Dec 2006
SELECT CONVERT(varchar, GETDATE(), 107) --Dec 30, 2006
SELECT CONVERT(varchar, GETDATE(), 110) --12-30-2006
SELECT CONVERT(varchar, GETDATE(), 111) --2006/12/30
SELECT CONVERT(varchar, GETDATE(), 112) --20061230