How can I get the string from GETDATE() in D-MMM-YYYY format, e.g 3 May 2016
If I use CONVERT(VARCHAR, GETDATE(), 106), I would get a leading zero on day which is not what I want.
If you are on SQL Server 2012 or later, use FORMAT:
SELECT FORMAT(GETDATE(), 'd MMM yyyy')
Edit: some of the answers below are just flat-out wrong so I'm adding a solution for older versions of SQL Server. 2005 is the earliest that I can get my hands on:
SELECT CASE
WHEN CONVERT(varchar(20), GETDATE(), 106) LIKE '0%'
THEN SUBSTRING(CONVERT(varchar(20), GETDATE(), 106), 2, 20)
ELSE CONVERT(varchar(20), GETDATE(), 106)
END
SELECT case when left(convert(varchar(20),[DateColumn],106),1) ='0'
then right(convert(varchar(20),[DateColumn],106),len(convert(varchar(20),[DateColumn],106))-1)
else convert(varchar(20),[DateColumn],106)
end
FROM [DB].[dbo].[Table]
Some sample output :
29 Apr 2016
2 Apr 2016
If you cannot use FORMAT (Below SQL Server 2012)
DECLARE #date DATE = '20160503'
SELECT REPLACE(DATEPART(DAY, #date),' 0','') + ' ' +
CONVERT(CHAR(3), #date, 0) + ' ' +
CAST(DATEPART(YEAR, #date) AS CHAR(4))
Related
I'm using SQL Server Compact 4.0 version, and although it might seem a simple thing to find in google, the examples I've tried none of them work.
My column signup_date is a DateTime with a value 04-09-2016 09:05:00.
What I've tried so far without success:
SELECT FORMAT(signup_date, 'Y-m-d') AS signup_date;
SELECT CONVERT(signup_date, GETDATE()) AS signup_date
SELECT CAST(data_registo, date) AS signup_date
I found that I could use DATEPART function, but that would force me to concat the values, is this the right path to follow? If so, how do I concat as Y-m-d?
SELECT DATEPART(month, signup_date)
SQL Server Compact has no date type.
If you don't want to see the time, convert the datetime value to a string:
SELECT CONVERT(nvarchar(10), GETDATE(), 120)
(This has been tested and actually works against SQL Server Compact)
you were actually on track with the CAST function just a slight error in the syntax. In the CAST function, there needs to be 'as' i.e CAST(data_registo as date)
SELECT CAST(data_registo as date) AS signup_date;
Most of the answers seek to achieve same thing but the explanation to the codes is not enough
CONVERT(date, Date_Updated, 120)
this code does the conversion with mssql. The first item 'date' is the datatype to return. it could be 'datetime', 'varchar', etc.
The second item 'Date_Updated' is the name of the column to be converted.
the last item '120' is the date style to be returned. There are various styles and the code entered will determine the output. '120' represent YYYY-MM-DD.
Hope this helps
The old fashioned way of doing this in SQL Server might work for your purposes:
select dateadd(day, datediff(day, 0, signup_date), 0)
The datediff() gets the number of days (as an integer) since time 0. The dateadd() adds this number back.
If you don't like 0 as a date, you can put any valid date in its place:
select dateadd(day, datediff(day, '2000-01-01', signup_date), '2000-01-01')
EDIT:
If you simply don't want to see the time, convert the date to a string:
select convert(nvarchar(10), signup_date, 120)
(I recommend the YYYY-MM-DD format, but others are available.)
I have tried this and many other solutions. I wanted a generic solution that would work with any LCID. My solution is a bit of convoluted code, but it works perfectly for me. It's a booking system where I needed to find out who was arriving on a particular date. ArriveDate is the column, d is the DATE I want.
SQL = "SELECT * FROM tablename WHERE dateadd(day, datediff(day, 0,
ArriveDate), 0)=' " & Format(d, "yyyy-MM-dd") & " ' "
This will return only date value in original datetime type. So you can do any comparison using the output
SELECT convert(datetime, CONVERT(nvarchar(10), GETDATE(), 120))
Just saw the Question today, a bit late I know :) but maybe this will help..,
select convert(date,(convert(varchar(20),'04-09-2016 09:05:00')))
select convert(nvarchar, getdate(), 1) = 09/25/19
select convert(nvarchar, getdate(), 2) = 19.09.25
select convert(nvarchar, getdate(), 3) = 25/09/19
select convert(nvarchar, getdate(), 4) = 25.09.19
select convert(nvarchar, getdate(), 5) = 25-09-19
select convert(nvarchar, getdate(), 6) = 25 Sep 19
select convert(nvarchar, getdate(), 7) = Sep 25, 19
select convert(nvarchar, getdate(), 10) = 09-25-19
select convert(nvarchar, getdate(), 11) = 19/09/25
select convert(nvarchar, getdate(), 12) = 190925
select convert(nvarchar, getdate(), 23) = 2019-09-25
select convert(nvarchar, getdate(), 101) = 09/25/2019
select convert(nvarchar, getdate(), 102) = 2019.09.25
select convert(nvarchar, getdate(), 103) = 25/09/2019
select convert(nvarchar, getdate(), 104) = 25.09.2019
select convert(nvarchar, getdate(), 105) = 25-09-2019
select convert(nvarchar, getdate(), 106) = 25 Sep 2019
select convert(nvarchar, getdate(), 107) = Sep 25, 2019
select convert(nvarchar, getdate(), 110) = 09-25-2019
select convert(nvarchar, getdate(), 111) = 2019/09/25
select convert(nvarchar, getdate(), 112) = 20190925
select convert(nvarchar, getdate(), 8) = 13:48:36
select convert(nvarchar, getdate(), 14) = 13:49:48:713
select convert(nvarchar, getdate(), 24) = 13:49:57
select convert(nvarchar, getdate(), 108) = 13:50:07
select convert(nvarchar, getdate(), 114) = 13:50:14:490
select convert(nvarchar, getdate(), 0) = Sep 25 2019 1:50PM
select convert(nvarchar, getdate(), 9) = Sep 25 2019 1:50:31:813PM
select convert(nvarchar, getdate(), 13) = 25 Sep 2019 13:50:39:307
select convert(nvarchar, getdate(), 20) = 2019-09-25 13:50:49
select convert(nvarchar, getdate(), 21) = 2019-09-25 13:50:58.923
select convert(nvarchar, getdate(), 22) = 09/25/19 1:51:07 PM
select convert(nvarchar, getdate(), 25) = 2019-09-25 13:51:14.473
select convert(nvarchar, getdate(), 100) = Sep 25 2019 1:51PM
select convert(nvarchar, getdate(), 109) = Sep 25 2019 1:51:32:227PM
select convert(nvarchar, getdate(), 113) = 25 Sep 2019 13:51:38:740
select convert(nvarchar, getdate(), 120) = 2019-09-25 13:51:50
select convert(nvarchar, getdate(), 121) = 2019-09-25 13:51:57.153
select convert(nvarchar, getdate(), 126) = 2019-09-25T13:52:03.627
Use this, i had the same problem
SELECT CAST(data_registo as date) AS "signup_date"
To get a string value, use CONVERT
select convert(varchar(10), signup_date, 11)
Check here for various formats:
https://msdn.microsoft.com/en-us/library/ms187928.aspx
To get a DATE, and just strip out the time, do this
Select Cast (signup_date as DATE)
I am working with a query where I fetch date with a sql query. And wondering how to use the CONVERT function to not show todays date, but convert the date saved in the database which is named as: routines.date. The goal is to sort it as D-M-Y and now its saved as Y-M-D
This didn't work:
CONVERT(date,routines.date,105) as Date
Try this
SELECT CONVERT(VARCHAR(10), CAST(routines.date AS DATETIME), 105)
OR
SELECT CONVERT(varchar, DATEPART(yyyy, #routines.date)) + '-' + CONVERT(varchar, DATEPART(mm, #routines.date)) + '-' + CONVERT(varchar, DATEPART(dd, #routines.date))
How do I use sql to get the whole month name in sql server?
I did't find a way using DATEPART(mm, mydate) or CONVERT(VARCHAR(12), CreatedFor, 107).
Basically I need in the format: April 1 2009.
SELECT DATENAME(MONTH, GETDATE())
+ RIGHT(CONVERT(VARCHAR(12), GETDATE(), 107), 9) AS [Month DD, YYYY]
OR Date without Comma Between date and year, you can use the following
SELECT DATENAME(MONTH, GETDATE()) + ' ' + CAST(DAY(GETDATE()) AS VARCHAR(2))
+ ' ' + CAST(YEAR(GETDATE()) AS VARCHAR(4)) AS [Month DD YYYY]
If you are using SQL Server 2012 or later, you can use:
SELECT FORMAT(MyDate, 'MMMM dd yyyy')
You can view the documentation for more information on the format.
Most answers are a bit more complicated than necessary, or don't provide the exact format requested.
select Format(getdate(), 'MMMM dd yyyy') --returns 'October 01 2020', note the leading zero
select Format(getdate(), 'MMMM d yyyy') --returns the desired format with out the leading zero: 'October 1 2020'
If you want a comma, as you normally would, use:
select Format(getdate(), 'MMMM d, yyyy') --returns 'October 1, 2020'
Note: even though there is only one 'd' for the day, it will become a 2 digit day when needed.
109 - mon dd yyyy (In SQL conversion)
The required format is April 1 2009
so
SELECT DATENAME(MONTH, GETDATE()) + RIGHT(CONVERT(VARCHAR(12), GETDATE(), 109), 9)
Result is:
select datename(DAY,GETDATE()) +'-'+ datename(MONTH,GETDATE()) +'- '+
datename(YEAR,GETDATE()) as 'yourcolumnname'
I have searched and i cannot seem to find the answer. I have tried using different styles, but none of them give me exactly what i want.
I am trying to convert a datetime, that I have calculated. However I need it to display the full month.
SELECT CONVERT(VARCHAR(25),DATEADD(dd, #codelife, getdate()),107)
the above line works fine, EXCEPT it displays the date like
Feb 27, 2014
I need it to display date like
February 27, 2014 etc.....
any suggestions?
Nathan's answer seems solid, however if you're using SQL Server 2012 you can make use of the FORMAT() function:
SELECT FORMAT(GETDATE(),'MMMM dd, yyyy')
Or in your case:
SELECT FORMAT(DATEADD(dd, #codelife, getdate()),'MMMM dd, yyyy')
I always use http://www.sql-server-helper.com/tips/date-formats.aspx as my reference
SELECT DATENAME(MM, GETDATE()) + RIGHT(CONVERT(VARCHAR(12), GETDATE(), 107), 9) AS [Month DD, YYYY]
I would declare your date as a variable and do something like:
DECLARE #myDate DATETIME
SET #myDate = DateAdd(dd, #codelife, getdate());
SELECT DATENAME(MM, #myDate) + RIGHT(CONVERT(VARCHAR(12), #myDate, 107), 9) AS [Month DD, YYYY]
You may have to do it in 2 steps.
DECLARE #codelife INT = 120
DECLARE #codedate DATETIME = (SELECT (DATEADD(D, #codelife, GETDATE())))
SELECT DATENAME(MM, #codedate) + SUBSTRING(CONVERT(VARCHAR(25), #codedate, 107), 4, 25)
SELECT DATENAME(MONTH, GETDATE())
+ RIGHT(CONVERT(VARCHAR(12), GETDATE(), 107), 9) AS [Month DD, YYYY]
OR Date without Comma Between date and year, you can use the following
SELECT DATENAME(MONTH, GETDATE()) + ' ' + CAST(DAY(GETDATE()) AS VARCHAR(2))
+ ' ' + CAST(YEAR(GETDATE()) AS VARCHAR(4)) AS [Month DD YYYY]
I answered the same question a couple of days ago have a look here sql server Get the FULL month name from a date
How can I display a DATETIME value (2010-12-02 15:20:17.000) as 02/12-2010 15:20?
For SQL Server:
select stuff(convert(varchar, getdate(), 105), 3, 1, '/') + ' ' + left(convert(varchar, getdate(), 8), 5)
DateTime is a DateTime is a DateTime - it just holds a date and time and doesn't have any string representation, really.
See the CAST and CONVERT topic in the SQL Server Books Online for details - it shows all supported date formats that SQL Server supports.
For your source format (2010-12-02 15:20:17.000) you could probably use style no. 121
DECLARE #source VARCHAR(50)
SET #source = '2010-12-02 15:20:17.000'
DECLARE #Date DATETIME
SELECT #Date = CONVERT(DATETIME, #source, 121)
SELECT #Date
but your target format is a bit odd..... I don't see any "out of the box" style that would match your needs. You'll need to use some string manipulation code to get that exact format.
Use MSSQL's build-in function to convert datetime to string with format,
SELECT CONVERT(VARCHAR(8), GETDATE(), 1) AS [MM/DD/YY] --2/5/12
SELECT CONVERT(VARCHAR(10), GETDATE(), 103) AS [DD/MM/YYYY] --5/2/2012
You need to create custom function to get various format to use like this;
SELECT dbo.ufn_FormatDateTime(GETDATE(),'YYYY-MM-DD HH:mm:SS tt')
--Output : 2012-02-05 01:58:38 AM
SELECT dbo.ufn_FormatDateTime(GETDATE(),'(dddd) mmmm dd, yyyy hh:mm:ss.fff tt')
--Output : (Sunday) February 05, 2012 01:58:38.723 AM
SELECT dbo.ufn_FormatDateTime(GETDATE(),'dd/MM/yyyy')
--Output : 05/02/2012
SELECT dbo.ufn_FormatDateTime(GETDATE(),'yyyy MMM, dd (ddd) hh:mm:ss tt')
-- Output : 2012 Feb, 05 (Sun) 01:58:38 AM
Get the code snippet from this link.
http://www.tainyan.com/codesnippets/entry-62/sql-server-date-time-format-function.html
http://msdn.microsoft.com/en-us/library/ms189491.aspx
Is this what you're looking for?
Assuming Oracle:
select TO_CHAR(SYSDATE, "dd/mm-yyyy HH24:mi")
from DUAL;
Assuming SQL Server:
select STR(DATEPART(DAY, GETDATE()), 2)
+ '/'
+ STR(DATEPART(MONTH, GETDATE()), 2)
+ '-'
+ STR(DATEPART(YEAR, GETDATE()), 4)
+ ' '
+ STR(DATEPART(HOUR, GETDATE()), 2)
+ ':'
+ STR(DATEPART(MINUTE, GETDATE()), 2);
Little example I use for Germany and Switzerland: dd.mm.yyyy hh:mm
SELECT CONVERT(varchar, GETDATE(), 104) + ' ' + LEFT(CONVERT(varchar, GETDATE(), 108), 5)