I want to extract date and time which is in unixformat.
Example: I have a date field in HDFS file. I want to extract date field
-2016:08:12 13:22:11:7897669
I want date as
2016:08:12 13:22:11
Anybody has answer?
you can use SUBSTR(datefield,1,19);
1 is the starting position and upto 19 character it will display..
Related
One of the columns is present in date datatype. I need to convert that date column in character datatype so that it can be concatenated with another character column.
Right now my date column is present in the following format : 09-JUN-2020.
Please help me in converting this column to character column.This needs to be done sas enterprise guide.
Thank u so much in advance.
You can use PUT() to convert from numeric to character. You need to find the format you want the output to look like and use that as your second parameter. Assuming you want your date to look like 2020-06-02 character this works:
*puts date as 2020-06-02;
newVar1 = put(dateVar, yymmddd10.);
*creates date variable as 02Jun2020;
newVar2 = put(dateVar, date9.);
FYI - You can find the list of formats available here
I have a column in postgresql of type varchar that stores time in the format "ID:HH24:MI" and I would like to add/subtract time to it. For example, a value of "4:21:35" would translate to Thursday 9:35PM. If I wanted to add thirty minutes to it, I expect the string "4:22:05".
I tried the query below but it does not work because it returns the wrong day. I'm expecting 4:22:05 and it returns 6:22:05.
SELECT to_char(to_timestamp('4:21:35', 'ID:HH24:MI' ) + INTERVAL '30 minute', 'ID:HH24:MI');
6:22:05
How could I modify the query or change my approach to achieve the right output? I want to compare time strings in the format "ID:HH24:MI" and would like to be able to add/subtract time to those time strings. Any help would be greatly appreciated.
I have a column for dates and the values are like this 1181202 and i want to convert it to normal date format "02-12-2018" so i can compare it with another date however when i am trying the following it returning wrong year and date
SELECT CONVERT(Datetime, Text_UPD_DATE,106) -- i have tried all numbers
From Notes
it's returning 5134-01-09 00:00:00.000
Can you please advise on the correct command
At a total guess, based on your one example:
CONVERT(date,'20'+STUFF(Text_UPD_DATE,1,1,''),112)
I am trying to convert a date to a number.
I need to have in my table a field with default value based on a date.
So if today is 23/01/2018, I want to have a number look like this 23012018.
Any ideas?
You can use the format command like this:
=Format$(Date, "ddmmyyyy")
I have a date in format of YYYY-MM-DDThh:mm:ss
Please provide a GREL expression that increments date to 1 month from the present date value for all cells in the column in openrefine. Thanks!
First you need to make sure the data in the cells is of type 'date' - if the text in the cell is in green then the data is already 'date' type. Otherwise you will need to convert it using the GREL:
value.toDate()
Screenshot - before converting to date
Screenshot - after converting to date
Once you have the data as Date type, then you can use the following GREL to increment by one month:
value.inc(1,'month')
For more on using dates in OpenRefine see https://github.com/OpenRefine/OpenRefine/wiki/GREL-Date-Functions