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I have 2 columns called price and PID in database called seatinginfo.
Both columns will have multiple of the same values like
pid 1,1,1,1,2,2,2,2,2,2,2,3,3,3,3,3
price 10,10,30,40,60,80,70,90,90,90,90 etc
I'm looking to make a query that will give me a list of all unique prices and pick just 1 or the max connected pid.
So example I only want one price,pid like 10,1 30,1 40,1 60,2 etc
Thanks
This is probably as simple as basic aggregation. Something like this should work based on the pretty vague details.
select price
, max(pid)
from YourTable
group by price
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In above table customer ids are listed what I want to do is to get those ids from this table,
create another table named PROMOTION CLASSES where PREMIUM, PLUS AND NORMAL are in columns and put first 100 ids under PREMIUM COLUMN and soon.
Please help.
This creates you table with classification
CREATE TABLE promotion_classes as
SELECT customer_id,
case when customer_id < 100 then
'PREMIUM'
else
'NORMAL'
END as CLASSES
FROM CUSTOMER_TBL
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like i having table 1 in that amount column is there but how much amount is there in that column i dont know to display top 10 high amounts using sql
As the question misses some details,
SELECT TOP 10 Amounts FROM India_Base
ORDER BY AMOUNTS DESC
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My table in Oracle 11g has 6 fields. I also have a backup table also with no values. The original table has 2 date values. I need to insert into the backup table from the original table the orders having an order-date 5 months back as of today.
The table has a field names ORDER-DATE and has records entered inside.
insert into backup_table
select * from original_table
where order-data > add_months(sysdate,-5);
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I have a table and I want to display the 3 names (Ted, Ringo, Paul) that have the most records using an SQL query.
It's a primitive question, but please help me.
my table:
SELECT TOP 3 Name
FROM YourTable
GROUP BY Name
ORDER BY COUNT(*) DESC