I have data in table in following format.
CustomerID | CustomerName | DisplayOrder | isActive
1 | Test | 1 | 1
1 | Test | 2 | 1
2 | Test2 | 1 | 1
1 | Test | 3 | 1
2 | Test2 | 2 | 1
Above table need to be sorted based on displayorder column per customer. Each customer will have thier own display order. Here I cannot use OrderBy Clause direcly because Display order will repear per customer.
Expected Output is:
CustomerID | CustomerName | DisplayOrder | isActive
1 | Test | 1 | 1
1 | Test | 2 | 1
1 | Test | 3 | 1
2 | Test2 | 1 | 1
2 | Test2 | 2 | 1
Please help on order by clause to sort based on customer.
You just need to sort by customerId and then display order (if customer id is same) like:
SELECT *
FROM mytable
ORDER BY customerId, displayOrder;
Fiddle for the same.
SELECT *
FROM t
ORDER BY CustomerID,
DisplayOrder;
Related
I have a table where each row consists of an ID, date, variable values (eg. var1).
When there is a null value for var1 in a row, I want like to replace the null value with the most recent non-null value before that date for that ID. How can I do this quickly for a very large table?
So presume I start with this table:
+----+------------|-------+
| id |date | var1 |
+----+------------+-------+
| 1 |'01-01-2022'|55 |
| 2 |'01-01-2022'|12 |
| 3 |'01-01-2022'|45 |
| 1 |'01-02-2022'|Null |
| 2 |'01-02-2022'|Null |
| 3 |'01-02-2022'|20 |
| 1 |'01-03-2022'|15 |
| 2 |'01-03-2022'|Null |
| 3 |'01-03-2022'|Null |
| 1 |'01-04-2022'|Null |
| 2 |'01-04-2022'|77 |
+----+------------+-------+
Then I want this
+----+------------|-------+
| id |date | var1 |
+----+------------+-------+
| 1 |'01-01-2022'|55 |
| 2 |'01-01-2022'|12 |
| 3 |'01-01-2022'|45 |
| 1 |'01-02-2022'|55 |
| 2 |'01-02-2022'|12 |
| 3 |'01-02-2022'|20 |
| 1 |'01-03-2022'|15 |
| 2 |'01-03-2022'|12 |
| 3 |'01-03-2022'|20 |
| 1 |'01-04-2022'|15 |
| 2 |'01-04-2022'|77 |
+----+------------+-------+
cte suits perfect here
this snippets returns the rows with values, just an update query and thats all (will update my response).
WITH selectcte AS
(
SELECT * FROM testnulls where var1 is NOT NULL
)
SELECT t1A.id, t1A.date, ISNULL(t1A.var1,t1B.var1) varvalue
FROM selectcte t1A
OUTER APPLY (SELECT TOP 1 *
FROM selectcte
WHERE id = t1A.id AND date < t1A.date
AND var1 IS NOT NULL
ORDER BY id, date DESC) t1B
Here you can dig further about CTEs :
https://learn.microsoft.com/en-us/sql/t-sql/queries/with-common-table-expression-transact-sql?view=sql-server-ver16
i need a SQL-Query to delete duplicates from a table. Lets start with my tables
rc_document: (there are more entries, this is just an example)
+----------------+-------------+----------------------+
| rc_document_id | document_id | rc_document_group_id |
+----------------+-------------+----------------------+
| 1 | 1 | 1 |
| 2 | 2 | 1 |
| 3 | 3 | 1 |
| 4 | 4 | 1 |
| 5 | 1 | 2 |
| 6 | 3 | 2 |
+----------------+-------------+----------------------+
(document_id can be exists in mulitple rc_document-group´s)
rc_document_group:
+----------------------+----------+
| rc_document_group_id | priority |
+----------------------+----------+
| 1 | 1 |
| 2 | 2 |
+----------------------+----------+
Each rc_document can be joined with the rc_document_group. In the rc_document_group is the priority for each rc_document.
I want to delete the rc_document rows with document_id which have not the highest priority in the rc_document_group. Because the document_id can be exists in multiple rc_document-group´s .. i just want to keep that one, with the highest priority.
here is my expected rc_document table after deleting duplicate document_id´s:
+----------------+-------------+----------------------+
| rc_document_id | document_id | rc_document_group_id |
+----------------+-------------+----------------------+
| 2 | 2 | 1 |
| 4 | 4 | 1 |
| 5 | 1 | 2 |
| 6 | 3 | 2 |
+----------------+-------------+----------------------+
the rc_document´s with rc_document_id 1 and 3 must be deleted, because there document_id 1 and 3 are in another rc_document_group with higher priority.
Im new in sql and i have no idea how to write these sql query ... thank for your help!!
First, you could join the two tables in order to get the corresponding priority on each row. After that, you could use the analytic function MAX() to get, for each row, the max priority within each group of document_id. At this point, you filter out the rows where the priority is not equal to the max priority in the group.
Try this query:
SELECT t.rc_document_id,
t.document_id,
t.rc_document_group_id
FROM (SELECT d.*,
g.priority,
MAX(g.priority) OVER(PARTITION BY document_id) max_priority
FROM rc_document d
INNER JOIN rc_document_group g
ON d.rc_document_group_id = g.rc_document_group_id) t
WHERE t.priority = t.max_priority
Let's imagine a table with two columns ex:
| Value | ID |
+-------+----+
| 2 | 1 |
| 3 | 1 |
| 4 | 1 |
| 1 | 2 |
| 2 | 2 |
| 2 | 2 |
What I am trying to do is to calculate the sum of those with similar id and display them in different table like:
| Sum | ID |
+-----+----+
| 9 | 1 |
| 5 | 2 |
and so on.
I could find a sum of a known id by
SELECT SUM(VALUE) FROM MYTABLE WHERE ID = 1;
However not sure on how to find sum of different id's separately, could you give an idea on how to proceed?
Select SUM(VALUE),ID FROM MYTABLE GROUP BY ID
Use GROUP BY clause:
SELECT SUM(VALUE) Sum, ID FROM MYTABLE GROUP BY ID;
SELECT SUM(VALUE),ID FROM MYTABLE Group By ID
This is my table...
+----+--------+
| id | amount |
+----+--------+
| 1 | 100 |
| 1 | 50 |
| 1 | 0 |
| 2 | 500 |
| 2 | 100 |
| 3 | 300 |
| 3 | -2 |
| 4 | 400 |
| 4 | 200 |
+----+--------+
I would like to choose from it each value of id that does not have a nonpositive (i.e. negative or 0) value associated with it, and the smallest amount associated with that id.
If I use this code...
SELECT DISTINCT id, amount
FROM table t
WHERE amount = (SELECT MIN(amount) FROM table WHERE id= t.id)
... then these results show...
+----+--------+
| id | amount |
+----+--------+
| 1 | 0 |
| 2 | 100 |
| 3 | -2 |
| 4 | 200 |
+----+--------+
But what I want the statement to return is...
+----+--------+
| id | amount |
+----+--------+
| 2 | 100 |
| 4 | 200 |
+----+--------+
Just add amount>0 in your query. You missed out that condition in your query. That should do it.
SELECT DISTINCT id, amount FROM table t
WHERE amount = (SELECT MIN(amount) FROM table WHERE id= t.id)
and amount>0;
If you want to display id, where min(amount) > 0, the use this.
SELECT id, min(amount) as amount
FROM table t
group by id
having min(amount) > 0;
Please try the following...
SELECT id,
MIN( amount )
FROM table
WHERE amount > 0
GROUP BY id
ORDER BY id;
This statement starts by selecting all records WHERE amount is larger than 0.
The records from the resulting dataset are then grouped by each surviving value of id and the smallest value of amount is chosen for that GROUP / id.
The resulting pairs of values are then sorted by ORDER id and returned to the user.
If you have any questions or comments, then please feel free to post a Comment accordingly.
I have a table, and I'd like to select rows with the highest value. For example:
----------------
| user | index |
----------------
| 1 | 1 |
| 2 | 1 |
| 2 | 2 |
| 3 | 4 |
| 3 | 7 |
| 4 | 1 |
| 5 | 1 |
----------------
Expected result:
----------------
| user | index |
----------------
| 1 | 1 |
| 2 | 2 |
| 3 | 7 |
| 4 | 1 |
| 5 | 1 |
----------------
How may I do so? I assume it can be done by some oracle function I am not aware of?
Thanks in advance :-)
You can use MAX() function for that with grouping user column like this:
SELECT "user"
,MAX("index") AS "index"
FROM Table1
GROUP BY "user"
ORDER BY "user";
Result:
| USER | INDEX |
----------------
| 1 | 1 |
| 2 | 2 |
| 3 | 7 |
| 4 | 1 |
| 5 | 1 |
See this SQLFiddle
if you have more than one column
select user , index
from (
select u.* , row_number() over (partition by user order by index desc) as rnk
from some_table u)
where rnk = 1
user is a reserved word - you should use a different name for the column.
select user,max(index) index from tbl
group by user;
Alternatively, you can use analytic functions:
select user,index, max(index) over (partition by user order by 1 ) highest from YOURTABLE
Note: Try NOT to use words like user, index, date etc.. as your column names, as they are reserved words for Oracle. If you will use, then use them with quotation marks, eg. "index", "date"...