In an access form, I try to make a list field visible when the fokus is on another textfield in which new data should be filled in. The backround is that one should know the last data inputs to create a new one.
As a first step I tried to make the list (liste91) visible when clicking on a button, but I failed using the following code.
Private Sub Befehl97_Click()
Forms!projects!liste91.SetFocus
Me.liste91.visible = True
End Sub
I get error in the line Me.list91
what is wrong?
thank you for your help!
You can't set focus to something not yet visible. Just switch the order:
Private Sub Befehl97_Click()
Me.liste91.visible = True
Me.liste91.SetFocus
End Sub
Related
I'm trying to create a user entry form which both captures the users input and displays a status update message. The slickest way I think of doing it is to have my modal form for the user entry display over a modeless form. After the user enters their info and clicks OK, the info from the modal form is copied to the modeless form, the modal form is closed and status updates get pushed to the modless form as things change during processing:
Hopefully, with a lot of messing about with positions, it will look relatively seamless. My challenge is getting rid of the frame on my modal form. I've done a lot of searching and it seems to involve completely redrawing the form from base libraries - is there seriously no easier way to do it?
I would not use a 2nd form but just place a simple Frame on top of your form. When you want to show the "modal form", just set the visibility of the frame to True, and when you want to hide it, set it to False - all controls (in your case, the input field and the OK and Cancel button) that are placed on the frame are automatically shown or hidden.
If you have controls outside the "modal form" frame that you don't want to be active at that time, set them to enabled = False. You could handle this with a simple routine within your form.
In this example I have a frame FrameModal painted on top of the form. Note that this frame could be places over other controls.
Option Explicit
Private Sub UserForm_Activate()
showHideModalFrame False
End Sub
Private Sub buttonShowModal_Click()
' Show the "modal" dialog
showHideModalFrame True
End Sub
Private Sub buttonOK_Click()
' Do your stuff here...
Me.tbUpdates = Me.tbUpdates & vbCrLf & Me.tbInput
' Hide the "modal" dialog"
showHideModalFrame False
End Sub
Private Sub showHideModalFrame(show As Boolean)
Me.FrameModal.Visible = show
Me.buttonShowModal.Enabled = Not show
End Sub
Start the form
Click the show button:
I want to programmatically select/highlight entire column on button click to let users know what they searched.
This is what currently happens on button click ("GO" button)
but this is what I need to happen.
I have tried these so far to no avail:
DataGridView2.SelectionMode = DataGridViewSelectionMode.FullColumnSelect
DataGridView2.Columns(2).Selected = True
Doing so gave me this error: DataGridView control's SelectionMode cannot be set to FullColumnSelect while it has a column with SortMode set to DataGridViewColumnSortMode.Automatic.
I also tried to simply select the whole column. No error, but it didn't work.
DataGridView2.Columns(2).Selected = True
Just set the Selected property of each cell in the column.
Found this thread. I modified the code like so:
Dim row As DataGridViewRow
For Each row In DataGridView2.Rows
row.Cells(1).Selected = True
Next
and placed it inside Private Sub Button1_Click
I noticed that the first cell is automatically selected. This solved that problem.
I want to enable a few fields when i click on the Add button on my form.I have change the onclick to Event Procedure to be able to add the following code
Category_Desc.Enabled = True
My Category field get enable as expected but the Add button no long work
Private Sub add_Click()
Category_Desc.Enabled = True
Me.Refresh
End Sub
If you wish to go to a new record, include this command:
DoCmd.GoToRecord, , acNewRec
Also, if you wish to have Category enabled only on a new record, remove that code from the Add button and replace it with this line in the OnCurrent event of the form:
Category_Desc.Enabled = Me.NewRecord
I know, that there are many questions related to this, but still I cannot find a workable solution.
Usually, it would work like this: A form creates an instance of another form in it's container like this:
Dim PolInstIn As New SubForm1
Private Sub LoadDetail()
PolInstIn.TopLevel = False
PolInstIn.Name = "Sub From"
PolInstIn.FormBorderStyle = Windows.Forms.FormBorderStyle.None
PolInstIn.Dock = DockStyle.Fill
Me.GroupBox6.Controls.Add(PolInstIn)
PolInstIn.Show()
End Sub
Then it's easy to call a Public Sub from the sub form like this:
Call PolInstIn.MyPublicSubInSubForm1()
However, this doesn't work for me in this case. When I run MyPublicSubInSubForm1() it doesn't throw any error, but does no action. If I write a value to SubForm1 textbox and read it back, it reads, but I don't see it on the screen, so I suspect it is written to some other accidental instance.
I suspect it is because my parent form is also an instance of an form created in very similar way like SubForm1. Basically the ParentForm is a form loaded into tabPage and SubForm1 is a module loaded into ParentForm. It can exist in many copies (tabs).
Could you point to any simple solutions?
Regards,
Libor
I see this question got a lot of views, so here is an answer.
1) No visual response of child form (only results) - this could have happened if I created more then 1 instances of the form. The example is just an example, but if one use it (accidentally) this way, it may result in new definition of a child form every time (and consequent symptoms like the ones described). In practice, I split form loading from loading data into to the form (done by a public sub in that form).
2) If you want also a back reference (to i.e. parent grid form), define a Public ParentFormGrid as GridName (note ParentForm is a reserved name) and on loading a child form, set
PollInstIn.ParentFormGrid = Me
This way you can alway asccess the parent form, i.e. reload the grid when you save changes on a line edited in child form.
make Private Sub LoadDetail() to a public :
Public Sub LoadDetail()
It work on my project. Hopely its what you want
Dim PolInstIn As New SubForm1
Private Sub LoadDetail()
PolInstIn.Name = "Sub From"
PolInstIn.Show()
PolInstIn.TopLevel = False
PolInstIn.FormBorderStyle = Windows.Forms.FormBorderStyle.None
PolInstIn.Dock = DockStyle.Fill
PolInstIn.Update()
PolInstIn.Refresh()
Me.GroupBox6.Controls.Add(PolInstIn)
End Sub
I want create one form from another. But the Form class has no the Show method, which described at http://msdn.microsoft.com/en-us/library/office/gg251540.aspx
It's code in Form_Main:
Private Sub btnTemp_Click()
Dim frmOpt As Form_Option
Set frmOpt = New Form_Option
frmOpt.Show vbModal
End Sub
But I received the "Compile error: Method or data member not found".
Where I made mistake?
Thanks
(VBA version 6.5; Access 2007)
=====
Sorry for my previous comment: right now I see that comment isn't obvious.
I don't have subForm on my mainForm.
I have two simple form: Form_Main and Form_Option. And I want to be the next logic:
Form_Main has button "btnOption"
Click on "btnOption". The Form_Option is opening
I change options on Form_Option
And click the btnSave button on Form_Option, and the next idea is executing:
Form_Main.TimerInterval = CLng(Form_Option.edtTimerInterval.Value)
At the moment I made it simple. And that is enough for me.
I write so:
Private Sub btnOptions_Click()
' After changing options, refresh timer interval of main form
DoCmd.OpenForm "Options", , , , , acDialog
Me.TimerInterval = 1000 * CLng(MOptions.loadOption("fPeriodVerifyNoticeInterval"))
End Sub
Where fPeriodVerifyNoticeInterval is parameter that stored in the options table.
And the Options Form changes the "fPeriodVerifyNoticeInterval" parameters at saving.
My problem is solved, Thanks
The "mistake" is that Show isn't a valid Method for Access Forms. The link you provided is for UserForms which are forms made in VBA.
If you want to create a new form that way what you want is something like this:
frmOpt.Modal = true
frmOpt.Visible = true
Though what I would recommend is doing this instead:
DoCmd.OpenForm "Option", , , , , acDialog which will open the Option form as a dialog.
Caution: If you create your form using New even though you set it as modal it will not halt the progress of VBA code. This means that your variable will go out of scope as soon as the code finishes. If you want your form to remain open, you will need to set it as static within the sub or declare it outside the sub like this:
static frmOpt As Form_Option
or outside the sub private frmOpt = Form_Option or public frmOpt = Form_Option