Current file path in Live Template - intellij-idea

Is it possible to get the full path of the current file within a live template in IntelliJ? I've tried using groovyScript("new File('.').absolutePath") function, but that returns /Applications/IntelliJ IDEA.app/Contents/bin/. and not the file path as I was hoping for.
Thanks!

According to the docs (emphasis mine):
You can use groovyScript macro with multiple arguments. The first argument is a script text that is executed or a path to the file that contains a script. The next arguments are bound to _1, _2, _3, ..._n variables that are available inside your script. Also, _editor variable is available inside the script. This variable is bound to the current editor.
The _editor is an instance of EditorImpl which holds a reference to the VirtualFile that represents the currently opened file.
Therefore, the following script gets the full path of currently opened file.
groovyScript("_editor.getVirtualFile().getPath()")
Or if you want to get the path relative to the project's root:
groovyScript("_editor.getVirtualFile().getPath().replace(_editor.getProject().getBaseDir().getPath(), \"\")")

Since IntelliJ IDEA 2019.3 the Live Template macros filePath() and fileRelativePath() are available. A complicated Groovy script macro is no longer required.

Related

IntelliJ - File watchers: wrong output of macros

I am trying to setup a file watcher for scss files which is working on files with a filename not starting with _.
But if I have a file named _file_name.scss the output of any macros that include the filename will be file.name.scss.
The first _ is removed and following ones are replaced by ..
Even though in the insert macros selection tool I can see that the output when you select a macro is correct.
Like $FilePathRelativeToProjectRoot$ will display mypath/_file_name.scss in the selection tool but then my command from this file watcher will output mypath/file.name.scss.
Am I missing a parameter here ?
Full configuration:
For me, existing file names are not changed when using similar file watcher. But files with names starting the _ are not prettified, the main .scss that includes them is processed instead.
To avoid this, try adding COMPILE_PARTIAL=true variable to your file watcher settings:
Also, make sure that Track only root files is off.
See the comments in https://youtrack.jetbrains.com/issue/WEB-13459

Check if Windows batch variable starts with a specific string

How can I find out (with Windows a batch command), if, for example, a variable starts with ABC?
I know that I can search for variables if I know the whole content (if "%variable%"=="abc"), but I want that it only looks after the beginning.
I also need it to find out where the batch file is located, so if there is a other command that reveals the file's location, please let me know.
Use the variable substring syntax:
IF "%variable:~0,3%"=="ABC" [...]
If you need the path to the batch file without the batch file name, you can use the variable:
%~dp0
Syntax for this is explained in the help for the for command, although this variable syntax extends beyond just the for command syntax.
to find batch file location use %0 (gives full patch to current batch file) or %CD% variable which gives local directory

Execute scripts by relative path in Oracle SQL Developer

First, this question relates to Oracle SQL Developer 3.2, not SQL*Plus or iSQL, etc. I've done a bunch of searching but haven't found a straight answer.
I have several collections of scripts that I'm trying to automate (and btw, my SQL experience is pretty basic and mostly MS-based). The trouble I'm having is executing them by a relative path. for example, assume this setup:
scripts/A/runAll.sql
| /A1.sql
| /A2.sql
|
/B/runAll.sql
/B1.sql
/B2.sql
I would like to have a file scripts/runEverything.sql something like this:
##/A/runAll.sql
##/B/runAll.sql
scripts/A/runAll.sql:
##/A1.sql
##/A2.sql
where "##", I gather, means relative path in SQL*Plus.
I've fooled around with making variables but without much luck. I have been able to do something similar using '&1' and passing in the root directory. I.e.:
scripts/runEverything.sql:
#'&1/A/runAll.sql' '&1/A'
#'&1/B/runAll.sql' '&1/B'
and call it by executing this:
#'c:/.../scripts/runEverything.sql' 'c:/.../scripts'
But the problem here has been that B/runAll.sql gets called with the path: c:/.../scripts/A/B.
So, is it possible with SQL Developer to make nested calls, and how?
This approach has two components:
-Set-up the active SQL Developer worksheet's folder as the default directory.
-Open a driver script, e.g. runAll.sql, (which then changes the default directory to the active working directory), and use relative paths within the runAll.sql script to call sibling scripts.
Set-up your scripts default folder. On the SQL Developer toolbar, Use this navigation:
Tools > Preferences
In the preference dialog box, navigate to Database > Worksheet > Select default path to look for scripts.
Enter the default path to look for scripts as the active working directory:
"${file.dir}"
Create a script file and place all scripts associated in it:
runAll.sql
A1.sql
A2.sql
The content of runAll.sql would include:
#A1.sql;
#A2.sql;
To test this approach, in SQL Developer, click on File and navigate and open the script\runAll.sql file.
Next, select all (on the worksheet), and execute.
Through the act of navigating and opening the runAll.sql worksheet, the default file folder becomes "script".
I don't have access to SQL Developer right now so i can't experiment with the relative paths, but with the substitution variables I believe the problem you're seeing is that the positional variables (i.e. &1) are redefined by each start or #. So after your first #runAll, the parent script sees the same &1 that the last child saw, which now includes the /A.
You can avoid that by defining your own variable in the master script:
define path=&1
#'&path/A/runAll.sql' '&path/A'
#'&path/B/runAll.sql' '&path/B'
As long as runAll.sql, and anything that runs, does not also (re-define) path this should work, and you just need to choose a unique name if there is the risk of a clash.
Again I can't verify this but I'm sure I've done exactly this in the past...
you need to provide the path of the file as String , give the patch in double quote it will work
**
For Example
#"C:\Users\Arpan Saini\Zions R2\Reports Statements and Notices\Patch\08312017_Patch_16.2.3.17\DB Scripts\snsp.sql";
**
Execution of Sql
#yourPath\yourFileName.sql
How to pass parameters in file
#A1.sql; (Parameter)
#A2.sql; (Parameter)
This is not absolute or relative path issue. It's the SQL interpreter issue, where by default it will look for files which are having .sql extention.
Please make sure to modify the file name to file_name.sql
Ex: if workspace is having file name called "A", then move the file from A to "A.sql"

Cmake script problems find_path

I have put these two lines in my Findglm.cmake file to point to the headers for this header library.
find_path(glm_INCLUDE_DIR NAMES glm.hpp matrix_transform.hpp type_ptr.hpp PATHS
${CMAKE_SOURCE_DIR}/libs/glm-0.9.3.2/glm ${CMAKE_SOURCE_DIR}/libs/glm-0.9.3.2/glm/gtc
${CMAKE_SOURCE_DIR}/libs/glm-0.9.3.2/glm/gtx ${CMAKE_SOURCE_DIR}/libs/glm-0.9.3.2glm/core)
set(glm_INCLUDE_DIRS ${glm_INCLUDE_DIR})
However when I generate my Xcode project it says that it cannot locate matrix_transform.hpp and type_ptr.hpp
I have played around with this some more it appears to only find the first argument I am wondering if I am using find path wrong ?
I am using cmake 2.8.8 darwinports.
The find_path() command returns single directory. In your case, it's the first dir, which contains the first file.
If this glm will be always located in your source dir, it would be sufficient to do
include_directories(${CMAKE_SOURCE_DIR}/libs/glm-0.9.3.2/glm
${CMAKE_SOURCE_DIR}/libs/glm-0.9.3.2/glm/gtc
${CMAKE_SOURCE_DIR}/libs/glm-0.9.3.2/glm/gtx
${CMAKE_SOURCE_DIR}/libs/glm-0.9.3.2/glm/core)
The find_path() is used to determine dir somewhere outside of your project.

Automatically locating a file

By default AutoCAD installs a text based file called acad2010.lsp at the set location below
Dim FILE_NAME As String = "C:\Program Files\AutoCAD 2010\Support\acad2010.lsp"
However it my be that the user/ administrator/ or third party has changed the location of this file. Is it possible to then locate it using the following
Dim FILE_NAME As String = "C:\*\acad2010.lsp"
In other words search the entire c:\ drive for file acad2010.lsp?
If this doesn't work can you please let me know what would?
You could search for it with an FSO. It's not going to be fast however you do it but this is the fastest way I can think of.
http://www.microbion.co.uk/developers/fso.htm should give you a rough idea of how it's done.
Your solution will not work. Is not possible to locate it using *. (BTW is possible in ms-builds scripts). The only way of doing it is:
1- Create a FindFile function (check for example
http://xlvba.3.forumer.com/index.php?showtopic=125)
2- Use it to locate the exact path of the file. (It could be really time
consuming)
3- From this point your code is the same...
Unfortunately, you can't use wildcards in a filepath. You have two options:
Prompt the user for the file location using the "Open File" dialog. The code to do this varies based on which Office product you are using. In Excel, you would use the Application.FindFile method (more info here).
Write your own function to search the filesystem for the file. Microsoft provides an example here.
If that file is used by internal functions of the application, the installer will have recorded a registry key for the file's location.
Open regedit.exe and search for the file name and path.
You can read a registry entry using this VBA one-liner:
CreateObject("WScript.Shell").RegRead(strRegPath)
You may need a terminating backslash on the key address, but that's a safe and simple registry access method. More details on the MSDN site:
https://msdn.microsoft.com/en-us/library/x05fawxd%28v=vs.84%29.aspx