I have a data set that I need to transform from rows to columns.
I looked at pivot and does not really answer the problem since I need specific static column headers (not matching the data names).
Here is how the current data is stored:
Id | SpCode
-------------------------
1 AA
1 BB
1 CC
2 FF
2 LL
3 TT
3 YY
3 ZZ
3 XX
4 AA
4 BB
5 AA
6 WW
6 MM
6 PP
I need to display it like this.
I will never have more than 5 columns and would like to keep the column name static so I can join and refer to it easily.
ID SpCode1 |SpCode2 | SpCode3 | SpCode4 | SpCode5
1 AA |BB | CC
2 FF |LL
3 TT |YY |ZZ |XX
4 AA |BB
5 AA
6 WW |MM |PP
Much appreciated for any help.
PS: using SQL Server 2014
Thanks
Oren
One method is pivot. Another is conditional aggregation. I find the latter easier to use:
select id,
max(case when seqnum = 1 then spcode end) as spcode_1,
max(case when seqnum = 2 then spcode end) as spcode_2,
max(case when seqnum = 3 then spcode end) as spcode_3,
max(case when seqnum = 4 then spcode end) as spcode_4,
max(case when seqnum = 5 then spcode end) as spcode_5
from (select t.*,
row_number() over (partition by id order by spcode) as seqnum
from t
) t
group by id;
Related
I have a few tables like this where a person has multiple data rows. The IDs are sequential but do not always start at 1. Is there a way to have the results come out in a single data row for each person. I have a few tables like this and I ultimately would like to join them via CLIENT_ID, but I'm a bit stumped. Is this possible?
Using oracle sql.
CLIENT_ID
NAME
ID
ID_DESCRIPTION
5
joe
1
apple
5
joe
5
orange
68
brian
2
orange
68
brian
6
mango
68
brian
10
lemon
12
katie
3
watermelon
where the results look like this
CLIENT_ID
NAME
ID1
ID1_DESCRIPTION
ID2
ID2_DESCRIPTION
ID3
ID3_DESCRIPTION
5
joe
1
apple
5
orange
68
brian
2
orange
6
mango
10
lemon
12
katie
3
watermelon
If Pivot ist not available, this should do it:
Select
Client_id,
sum(case when id_description='apple' then 1 else 0 end) as Apples,
sum(case when id_description='orange' then 1 else 0 end) as Oranges...
[]etc.
from
t
group by Client_ID
Might need some minor tweaking as I wrote this just off the top of my head, but something like this should work. Will say this doesn't account for more than 3 rows per CLIENT_ID. For that, would need to do a dynamic pivot (plenty of online articles on this topic).
Pivoting Based on Order of Items
WITH cte_RowNum AS (
SELECT ROW_NUMBER() OVER (PARTITION BY CLIENT_ID ORDER BY ID) AS RowNum
,*
FROM YourTable
)
SELECT CLIENT_ID
,MAX(CASE WHEN RowNum = 1 THEN ID END) AS ID1
,MAX(CASE WHEN RowNum = 1 THEN [Description] END) AS ID1_DESCRIPTION
,MAX(CASE WHEN RowNum = 2 THEN ID END) AS ID2
,MAX(CASE WHEN RowNum = 2 THEN [Description] END) AS ID2_DESCRIPTION
,MAX(CASE WHEN RowNum = 3 THEN ID END) AS ID3
,MAX(CASE WHEN RowNum = 3 THEN [Description] END) AS ID3_DESCRIPTION
FROM cte_RowNum
GROUP BY CLIENT_ID;
Given a table sale where id is not unique:
id name item quantity
1 Darsh shoes 5
2 Liyah oil 1
2 Eiliyah watch 1
3 Zakaria notebook 2
3 Elliot shirt 3
4 Reese bag 1
I need to select all unique ids for a row and not loose any data(like for id in (2,3) where both name,item and quantity should be displayed in same row).Also there are maximum of 2 same id in sale table.
I tried using row_number() to get some unique pattern(s).
From this query :
Select a.id,a.name,a.item,a.quantity,b.name as name2,b.item as item2,b.quantity as quantity2
,row_number() over(partition by a.id order by a.id) as f1
,row_number() over(partition by a.name order by a.id) as f2
from sale a inner join sale b on a.id = b.id
I got this
id name item quantity name2 item2 quantity2 f1 f2
1 Darsh shoes 5 Darsh shoes 5 1 1
2 Eiliyah watch 1 Liyah oil 1 2 1
2 Eiliyah watch 1 Eiliyah watch 1 4 2
3 Elliot shirt 3 Zakaria notebook 2 2 1
3 Elliot shirt 3 Elliot shirt 3 4 2
2 Liyah oil 1 Eiliyah watch 1 3 1
2 Liyah oil 1 Liyah oil 1 1 2
4 Reese bag 1 Reese bag 1 1 1
3 Zakaria notebook 2 Elliot shirt 3 3 1
3 Zakaria notebook 2 Zakaria notebook 2 1 2
Now here the problem,If I filter f1,f2 and use IIF for remove repetitive data using this query :
Select id,name,item,quantity
,iif(name = name2,NULL,name2) as name2
,iif(item = item2,NULL,item2) as item2
,iif(quantity = quantity2,NULL,quantity2) as quantity2
from (
Select a.id,a.name,a.item,a.quantity,b.name as name2,b.item as item2,b.quantity as quantity2
,row_number() over(partition by a.id order by a.id) as f1
,row_number() over(partition by a.name order by a.id) as f2
from sale a inner join sale b on a.id = b.id
)t
where (f1=1 and f2=1) or(f1=3 and f2=1)
order by id
then quantity2 is (null) in 2nd row as shown below.
id name item quantity name2 item2 quantity2
1 Darsh shoes 5 NULL NULL NULL
2 Liyah oil 1 Eiliyah watch NULL
3 Zakaria notebook 2 Elliot shirt 3
4 Reese bag 1 NULL NULL NULL
So, there can be same quantity for different item and name.
Expected result:
id name item quantity name2 item2 quantity2
1 Darsh shoes 5 NULL NULL NULL
2 Liyah oil 1 Eiliyah watch 1
3 Zakaria notebook 2 Elliot shirt 3
4 Reese bag 1 NULL NULL NULL
Please help me.
Thanks!
One method is conditional aggregation . . . if you know that there are at most two duplicates per id:
select id,
max(case when seqnum = 1 then name end) as name_1,
max(case when seqnum = 1 then item end) as item_1,
max(case when seqnum = 1 then quantity end) as quantity_1,
max(case when seqnum = 2 then name end) as name_2,
max(case when seqnum = 2 then item end) as item_2,
max(case when seqnum = 2 then quantity end) as quantity_2
from (select s.*,
row_number() over (partition by id order by id) as seqnum
from sale s
) s
group by id;
As per your expected result .You can create temp(or Intermediate table) and as there are maximum of same two id ,then this can be your answer:
select *,row_number() over (partition by id order by id) as u_id into #test from sale
select * from (select * from #test where u_id=1) a
left join (select * from #test where u_id=2)b
on a.id = b.id
I have a table as below in sqlite database. I want to create a line chart showing usage by product groups.
Table: ProductUsageData
UserID ProductName ProductGroup Qty RecordID
1 A1 A 12 1
2 A1 A 12 1
1 A2 A 15 1
3 A1 A 12 2
2 B1 B 12 2
5 B2 B 5 2
1 A1 A 12 3
1 A2 A 15 3
4 A1 A 12 3
3 C1 C 12 3
2 C2 C 15 3
Since I want separate line for each ProductGroup I am using below Query
SELECT
SUM(Qty) as UsedQty,
ProductGroup,
RecordID
FROM ProductUsageData
GROUP BY ProductGroup, RecordID
ORDER BY RecordID ASC;
While I get three records for A (for each RecordID) I get only 1 record each for B & C as they are not used during each RecordID.
Problem is when I am putting one line for each ProductGroup in the chart, the points for B & C are shown as per Qty in the first
My output is like this
A 39 1
A 12 2
B 17 2
A 39 3
C 27 3
So the graph looks like this
instead of
To fix this I changed the query using COALESCE to get 0 Qty if the ProductGroup is not used during each recording.
SELECT
COALESCE(SUM(Qty), 0) as UsedQty,
ProductGroup,
RecordID
FROM ProductUsageData
GROUP BY ProductGroup, RecordID
ORDER BY RecordID ASC;
I was expecting output as below
A 39 1
B 0 1
C 0 1
A 12 2
B 17 2
C 0 2
A 39 3
B 0 3
C 27 3
But I am getting same output as first
Please let me know how can I correct the query to get desired output
A typical solution is to first cross join two queries that select the distinct product groups and record ids from the table; this gives you all possible combinations of productGroup and recordID.
Then, you can bring in the original table with a left join, and aggregate:
select
g.productGroup,
coalesce(sum(p.qty), 0) qty,
r.recordID
from (select distinct productGroup from productUsageData) g
cross join (select distinct recordID from productUsageData) r
left join productUsageData p
on p.productGroup = g.productGroup
and p.recordID = r.recordID
group by r.recordID, g.productGroup
order by r.recordID, g.productGroup
In the real world, you might have separate referential tables for product groups and records ids, which would make the query simpler and more efficient (since it would avoid the need to select distinct in subqueries).
Demo on DB Fiddle:
productGroup | qty | recordID
:----------- | :-- | :-------
A | 39 | 1
B | 0 | 1
C | 0 | 1
A | 12 | 2
B | 17 | 2
C | 0 | 2
A | 39 | 3
B | 0 | 3
C | 27 | 3
I have the following table:
WorkID WorkDesc
--------------------
1 ABCD
2 DEFG
3 HIJK
then I've the following table as the detail of table one:
WorkDetailID WorkID WorkDetailDesc
-----------------------------------------
1 1 001
2 1 002
3 2 006
4 2 007
5 3 015
Each WorkID is always have maximum 2 records and minimum is 1.
I want to have the following result:
WorkID WorkDesc WorkDetailID1 WorkDetailID2
-------------------------------------------------------
1 ABCD 1 2
2 DEFG 3 4
3 HIJK 5 null
Does anyone have an idea how to do that?
Thank you.
You can use pivot. I prefer conditional aggregation. In either case, you need a column for the pivoting. row_number() to the rescue:
select t1.workid, t1.workdesc,
max(case when t2.seqnum = 1 then t2.workdetailid end) as workdetailid1,
max(case when t2.seqnum = 2 then t2.workdetailid end) as workdetailid2
from t1 join
(select t2.*,
row_number() over (partition by t2.workid order by t2.workdetailid) as seqnum
from t2
) t2
on t1.workid = t2.workid
group by t1.workid, t1.workdesc
I am trying to combine multiple rows with the same IDs to one.
My raw table looks like this:
ID | person_id | eur_amount
1 3 200
1 2 100
2 3 80
2 2 100
The output should look like this:
ID | person_1 | eur_amount_1 | person_2 | eur_amount_2 |
1 3 200 2 100
2 3 80 2 100
The max number of persons is the same. I already tried solving it with a multiple JOIN statements and the crosstab() function as mentioned here PostgreSQL Crosstab Query.
But I couldn't find a solution for this - does anyone know a good way to achive the desired output?
Thanks in advance!
You can do this using cross tab or conditional aggregation. But you need to identify the rows, using row_number(). For instance:
select id,
max(case when seqnum = 1 then person_id end) as person_id_1,
max(case when seqnum = 1 then eur_amount end) as eur_amount_1,
max(case when seqnum = 2 then person_id end) as person_id_2,
max(case when seqnum = 2 then eur_amount end) as eur_amount_2
from (select t.*,
row_number() over (partition by id order by id) as seqnum
from t
) t
group by id;