Pivot dataset with column names - sql

Question

if you have a table (example)
declare #MyTable table (
CustomerName nvarchar(50),
BirthDate datetime,
BirtPlace nvarchar(50),
Phone nvarchar(50),
Email nvarchar(50)
)
insert into #MyTable
(
CustomerName,
BirthDate,
BirtPlace,
Phone,
Email
)
values (
'Customer1',
'12.05.1990',
'Place1',
N'+000125456789',
N'customer#customer.com'
)
Is it possible to get following result set:
CustomerName Customer1
BirtDate 1990-12-05
BirtPlace Place1
Phone [phone]
Email customer#customer.com
Something like pivot, but i don't have any idea how to get to this result.

Answer 1

As you want to change columns to rows the function you want is unpivot not pivot.
This should do the trick:
SELECT col, val
FROM
(
SELECT
CustomerName,
CAST(BirthDate AS NVARCHAR(50)) BirthDate,
BirtPlace,
Phone,
Email
FROM #MyTable
) AS t
UNPIVOT
(
val FOR col IN (CustomerName, BirthDate, BirtPlace, Phone, Email)
) AS u

Answer 2

Try this
SELECT myColumn, myDetail
FROM
(
SELECT
CustomerName,
CONVERT(NVARCHAR(50),BirthDate,121) AS BirthDate,
BirtPlace,
Phone,
Email
FROM
#MyTable
) AS A
UNPIVOT
(
myDetail FOR myColumn IN (CustomerName, BirthDate, BirtPlace, Phone, Email)
) AS tbUnpivot

Answer 3

This is a unpivot issue, and if you used old version sql server 2000, this unpivot syntax will not work, then you can use UNION:
SELECT 'CustomerName' AS colName, CustomerName AS colVal FROM #MyTable
UNION
SELECT 'BirthDate' AS colName, CAST(BirthDate AS NVARCHAR(50)) AS colVal FROM #MyTable
UNION
SELECT 'BirthPlace' AS colName, BirthPlace AS colVal FROM #MyTable
UNION
SELECT 'Phone' AS colName, Phone AS colVal FROM #MyTable
UNION
SELECT 'Email' AS colName, Email AS colVal FROM #MyTable;

Answer 4

SELECT CustomerName,BirtDate,BirtPlace,Phone,Email FROM #MyTable\G
You have no ID and no Foreign keys so i think thats a way to solve your problem. The \G give´s you the SQL-query as a list.
values (
'Customer1', '1990-12-05', 'Place1', '+000125456789', 'customer#customer.com'
);
I hope i could help you
Have a nice Day