I am using SQL Server 2008R2.
I am trying to get part of a date in an output, and my column is in datetime datatype.
Eg,
If Current date and time is 2016-06-28 17:34:12.060, then I need output as 17:00 only the Hour with :00 mins.
I have tried this until now,
Select DateName(HH,SUBSTRING('2016-06-28 17:34:12.060',12,5)) +':00'
which gives me right output.But when I pass Column Name which is of datetime datatype, then it gives error,
Select DateName(HH,SUBSTRING(TimeInHour,12,5)) +':00'
gives error,
Argument data type time is invalid for argument 1 of substring function.
I know I am using SUBSTRING() at wrong place, But I really don't know how to achieve that output.
A help will be much appreciable.I need output as HH:00, Hour will be anything but 00 mins.
Why would you use substring() at all? The second argument to datename() should be a date/time data type. So, just do:
Select DateName(hour, '2016-06-28 17:34:12.060') + ':00'
Try this:
Select CAST(DATEPART(hour,'2016-06-28 17:34:12.060') AS VARCHAR(2)) +':00'
Below is the code that might be helpful
SELECT CONVERT(VARCHAR(50),DATEPART(YY,'2016-06-28 17:34:12.060')) -- Year
SELECT CONVERT(VARCHAR(50),DATEPART(mm,'2016-06-28 17:34:12.060')) -- Month
SELECT CONVERT(VARCHAR(50),DATEPART(d,'2016-06-28 17:34:12.060')) -- Day
SELECT CONVERT(VARCHAR(50),DATEPART(HH,'2016-06-28 17:34:12.060'))+':00' -- Hour
SELECT CONVERT(VARCHAR(50),DATEPART(mi,'2016-06-28 17:34:12.060'))+':00' -- Minutes
SELECT CONVERT(VARCHAR(50),DATEPART(ss,'2016-06-28 17:34:12.060')) -- Seconds
SELECT CONVERT(VARCHAR(50),DATEPART(ms,'2016-06-28 17:34:12.060')) -- Millisecond
You need to cast your DATETIME type column first, Use CAST function
Select DateName(HH,SUBSTRING(CAST(ColumnName AS VARCHAR(30)),12,5)) +':00'
Or alternative to do is Use LEFT and CONVERT
SELECT LEFT(CONVERT(VARCHAR, ColumnName ,108),2)+':00'
select convert(varchar, datepart(hour, getdate())) + ':' + convert(varchar, datepart(second, getdate()))
Related
Hello I am using SQL Server and I have this column :
data
6/19/2019 3:10:12 PM
12/23/2016 5:02:15 AM
I wanted to extract only the time so I used the following query :
select try_parse([data] as time using 'en-US') from Table_1
But the problem is I get as a result this :
15:10:12.0000000
05:02:15.0000000
All is okay except the 0 I mean I would like to get :
15:10:12
05:02:15
Thank you very much for your help !
You can use TIME() with the correct scale to get your desired results.
select Convert(time(0) , Data ) as time from Table_1
time(0) means a scale of 0, which has a precision of 8. This results as HH:MM:SS. Using another scale, like 1, would give you a single digit for the fractional second. You can read up on all of the scales in the MS Docs
Declare #data varchar(28)='12/23/2016 5:02:15 AM'
select Convert(varchar(20),Cast(#data as time),24)
Try this
select CONVERT(varchar(8), data, 108) from Table_1
that only show time (17:00:59) but you can add + between them if you want full format date as dd/MM/yyyy hh:mm:ss
select CONVERT(varchar(10), data, 101) + ' ' + CONVERT(varchar(8), data, 108) from Table_1
They will work if data using DATETIME type
You can extract time using below query
SELECT CONVERT(VARCHAR(8), cast('12/23/2016 5:02:15 AM' as time),108)
The output is- 05:02:15. I can hope this query/answer is self explanatory.
Actually I have different date in SQL table when I pull those via SQL query, day of datetime field should have fixed day.
Example: (DD-MM-YYYY) day should be "7" > (7-MM-YYYY)
10-08-2007 > 07-08-2007
27-12-2013 > 07-12-2013
01-03-2017 > 07-03-2017
Can someone help me on this. Thanks in Advance.
Find the difference between 7 and the day of the original date and add that to the original date:
SELECT DATEADD(DAY, 7 - DAY(OriginalDate), OriginalDate)
Use DATEPART to take out the month and year parts. Cast those into varchar and concatenate with 07.
Query
select '07-' +
cast(DATEPART(mm, [date_column]) as varchar(2)) + '-' +
cast(DATEPART(yyyy, [date_column]) as varchar(4))
from your_table_name;
Assuming You might have to change the day number example
DECLARE #dayNum char(2)
SELECT #dayNum = '07'
select #dayNum + Right(convert(char(10),getdate(),105),8)
If that is not the case You could do this
select '07'+ Right(convert(char(10),'10-08-2007',105),8)
I'd go this way:
SELECT CONVERT(DATE,CONVERT(VARCHAR(6),GETDATE(),112)+'25',112);
CONVERT with format 112 will return the date as unseparated ISO (today we would get 20170407). Convert this to VARCHAR(6) will implicitly cut away the day's part (201704).
Now we add a day and use again CONVERT with 112, but now with DATE as target type.
One thing to keep in mind: The day you add must be two-digit. You can achieve this with
DECLARE #int INT=7;
SELECT REPLACE(STR(#int,2),' ','0');
Use DATEFROMPARTS: Updated ONLY works from 2012 - OP has tagged SQL-Server 2008
select DATEFROMPARTS ( year('10-08-2007'), month('10-08-2007'), 7 )
Assuming that your field is of datetime datatype and your fixed day is of integer type.
select datetimecolumn+(yourparamfixedday-datepart(dd,datetimecolumn))
I am trying to convert a single integer which represents the hour value into a time. I've tried using cast but this converts the value to a date
cast(datepart(hh,tstart) as datetime) as test
I've also tried casting it as a time and the conversion is not allowed.
The numbers I am working with are 7,8,9,10,11,12,13,...,23, 0
The format I would like is convert 7 to 7:00, 23 to 23:00, etc
Thank you
There are many ways to do that:
WITH table_name AS
(
SELECT * FROM (VALUES
(1),(2),(3),(10),(23)
) T(H)
)
SELECT DATEADD(HOUR, H, 0) DateValue,
CONVERT(time, DATEADD(HOUR, H, 0)) TimeValue,
CONVERT(varchar(2), H)+':00' TextValue
FROM table_name T1
I would recomend storing value as TIME datatype.
You can try this:
select cast(dateadd(hour,3,'00:00:00') as time)
which gives result:
03:00:00.0000000
Use your int values in place of 3 in above statement
Use convert datetime to varchar datatype and use case statement
DECLARE #date datetime ='2016-05-01 10:00:000'
SELECT CASE cast(DATEPART(hh,#date)as varchar(10))
WHEN '10'then '10:00'
WHEN '11'then '11:00'
WHEN '12'then '12:00'
.
.
.
WHEN '23' then '23:00'
END 'Hourpart'
You can concatenate a minute to the time and cast it to time
select cast(concat(20,':00') as time(7)) as 'time'
If you wanted to display like 'HH:MM',use the below query.
SELECT CAST(23 AS VARCHAR(50))+':00'
If you wanted to get the result as time format,use the below query.
SELECT CAST(CAST(23 AS VARCHAR(50))+':00:00' AS TIME)
OR
SELECT CAST(DATEADD(HOUR,23,'00:00:00') as time)
here is the sample output :
Assuming all of your potential values are integers between 1 and 24, I think FORMAT is the simplest way.
FORMAT(tstart*100,'00:00')
I have a date in following format in my DB.
10/16 - mm/yy
I need to convert it to:
October/16
Is this possible?
If it's not possible then please tell me why.
This is not a date, it's missing the day, it's a bad way to store year/month. There should be a 4 digit year to avoid confusion and the year should be listed first to enable correct sorting, e.g. '2016/10' or a numeric value 201610.
You can cast it to a DATE first and then use a FORMAT to disply only month/year:
set dateformat myd;
select format(cast(mystupidcolumn + '/1' as date), 'MMMM/yy')
Or SUBSTR the month part and use a CASE.
try this format,
SELECT DATENAME(month, DATEADD(month, #mydate-1, CAST('2008-01-01' AS datetime)))
You can display date by using this code
select datename(month, YourColumnName) + '/' + right(YEAR(YourColumnName),2)
FROM yourTableName
Simply change yourColumnName with name of your table column and yourTableName with name of table.
Yes you can, and it depend in what database you use to call date functions
If you column Datetime format
SQL server DATENAME(Month, GETDATE())
MySQL database MONTHNAME(now())
otherwise
convert it will in your choice at database or you code logic
split the value and lookup at month enum or fake the date to be accepted and complete date format like 01/10/16
so do something like SELECT DATENAME(Month, datecolumn) + '/' + YEAR (datecolumn)
also you can use instead of Year function DATEPART(yy,datecolumn)
the way you do it with format will look like
CONVERT(VARCHAR(11),GETDATE(),106)
but excepted to get first 3 char of month JUN
I have a script that I am using to populate a time dimension table and I would like to have a column for the time in 12 hour format.
I know this can be done by doing something along the lines of
SELECT CONVERT(varchar(15),[FullTime],100)
Where [FullTime] is a column containing a TIME field in HH:MM:SS format.
But this gives the following result 2:30pm and I would like 2:30:47PM, note the inclusion of seconds.
I know I could build this up using substrings etc. but I wondered if there was a prettier way of doing it.
Thanks
SELECT GETDATE() 'Today',
CONVERT(VARCHAR(8), [FullTime], 108) 'hh:mi:ss'
Taken from here
This will give you a column 'today' followed by the time value you seek 'hh:mi:ss'
If having also milliseconds is not a problem for you, you can use
SELECT CONVERT(VARCHAR, [FullTime], 109)
Declare #tstTime datetime
set #tstTime = GetDate()
Select
#tstTime
,CONCAT(SUBSTRING(CONVERT(varchar(26), #tstTime, 109),1,20),RIGHT(CONVERT(varchar(26), #tstTime, 109),2))