I have VBA code for changing size of shapes, but I want to convert the number to be in cm. Any suggestion for how to convert these numbers?
Another question is that I want to change the same size for multiple selected shapes; can you help me with this as well?
Thank you very much!
Sub test()
Dim objHeigh As Integer
Dim objWidth As Integer
Dim oSh As Shape
On Error GoTo CheckErrors
With ActiveWindow.Selection.ShapeRange
If .Count = 0 Then
MsgBox "You need to select a shape first"
Exit Sub
End If
End With
For Each oSh In ActiveWindow.Selection.ShapeRange
objHeigh = oSh.Height
objWidth = oSh.Width
objHeigh = CInt(InputBox$("Assign a new size of Height", "Heigh", objHeigh))
' give the user a way out
If objHeigh = 0 Then
Exit Sub
End If
If objName <> "" Then
oSh.Name = objName
End If
objWidth = CInt(InputBox$("Assign a new size of Width", "Width", objWidth))
' give the user a way out
If objWidth = 0 Then
Exit Sub
End If
oSh.Height = CInt(objHeigh)
oSh.Width = CInt(objWidth)
Next
Exit Sub
CheckErrors: MsgBox Err.Description
End Sub
According to MSDN, the height / width of the corresponding shape properties are specified in points:
Returns or sets the height of the specified object, in points.
Read/write.
and on that page they specifically show an example and referring to the fact, that 1 inch has 72 points
This example sets the height for row two in the specified table to 100
points (72 points per inch).
Therefore I guess it is safe to rely on that fact and just write a function to convert it yourself:
Function ConvertPointToCm(ByVal pnt As Double) As Double
ConvertPointToCm = pnt * 0.03527778
End Function
Function ConvertCmToPoint(ByVal cm As Double) As Double
ConvertCmToPoint = cm * 28.34646
End Function
As far as your question with sizing multiple objects is concerned, I am not sure if I understand your problem fully. I interpreted it in a way so that moving your prompts to the user out of the For loop should give you the desired result (if that is in fact your desired result :)):
objHeigh = CInt(InputBox$("Assign a new size of Height", "Heigh"))
' give the user a way out
If objHeigh = 0 Then
Exit Sub
End If
objHeigh = ConvertCmToPoint(objHeigh)
objWidth = CInt(InputBox$("Assign a new size of Width", "Width"))
' give the user a way out
If objWidth = 0 Then
Exit Sub
End If
objWidth = ConvertCmToPoint(objWidth)
For Each oSh In ActiveWindow.Selection.ShapeRange
If objName <> "" Then
oSh.Name = objName
End If
oSh.Height = CInt(objHeigh)
oSh.Width = CInt(objWidth)
Next
Related
Is there any way to select the multiples shape from slide with the same shape name.
For e.g., I have 5 shapes with the name "Textbox 60". And I want run a macro which select all the shapes from a slide named "Textbox 60". Have used the below code.
ActiveWindow.View.Slide.Shapes.Range("Textbox 60").Select
Here's one approach:
Sub Tester()
SelectByName ActivePresentation.Slides(1), "Textbox1"
End Sub
Sub SelectByName(sld As Slide, nm As String)
Dim s As Shape, first As Boolean
first = True
For Each s In sld.Shapes
If s.Name = nm Then
s.Select first 'Argument determines whether to add to
first = False ' existing selection, or replace it
End If
Next s
End Sub
You should try following #TinMan's suggestion though - that is the "better" way to go.
Activating and Selecting Objects should be avoided whenever possible. You are better of working with the Shapes using a ShapeRange.
Sub Main()
Dim ShapeRange As ShapeRange
Set ShapeRange = FindShapes(ActiveWindow.View.Slide, "Textbox 60")
If Not ShapeRange Is Nothing Then
End If
End Sub
Function FindShapes(Slide As Slide, Pattern As String) As ShapeRange
Dim Results() As Long
ReDim Results(1 To Slide.Shapes.Count)
Dim n As Long
Dim Index As Long
For Index = 1 To Slide.Shapes.Count
With Slide.Shapes(Index)
.Name = "Textbox 60"
If .Name Like Pattern Then
n = n + 1
Results(n) = Index
End If
End With
Next
If n > 0 Then
ReDim Preserve Results(1 To n)
Set FindShapes = Slide.Shapes.Range(Results)
End If
End Function
Note: I rewrote the code to handle multiple shapes with the same name.
I have used VBA in the past mostly with excel, but I am not very experienced.
I want to cycle through multiple boxes and make each of them have coincident edges. Like they are sitting on top of each other. I am having trouble identifying the position of the first shape in my selection. I've tried a number of different objects including selection.shaperange.
Dim shp As Visio.Shape
Dim shp1 As Visio.Shape
Dim Pos As Double
Set shp1 = ActiveWindow.Selection.ShapeRange.Item
Pos = shp1.Cells("PinY")
For Each shp In Application.ActiveWindow.Selection
'Change the cell name to the one you want
If shp <> ActiveWindow.Selection.Item(1) Then
Pos = Pos + 6
End If
shp.CellsSRC(visSectionControls, visRowXFormOut, visXFormPinY).FormulaU = Pos & "mm"
Pos = shp.Cells("PinY")
Next shp
End Sub
Can you help me get the position of the first selected item and then I may be able to figure out the rest.
This code will abut the left sides of all but the first-selected shape with the right side of the first-selected shape:
Option Explicit
Public Sub AbutLeftsToPrimaryRight()
Dim sel As Visio.Selection
Set sel = Visio.ActiveWindow.Selection
If (sel.Count < 2) Then
Debug.Print "Select two or more shapes (Use Shift + Click)!"
GoTo Cleanup
End If
Dim shp0 As Visio.Shape
Dim shp As Visio.Shape
'// Get the selection and the primary selected shape,
'// which is item(1). See also: Selection.PrimaryItem
Set shp0 = sel(1)
'// Quick calculate the right side of shp0:
'// PinX - LocPinX + Width.
Dim dRight0 As Double
dRight0 = shp0.CellsU("PinX").ResultIU - shp0.CellsU("LocPinX").ResultIU + shp0.CellsU("Width").ResultIU
'// If shapes are rotated, flipped, or not rectangular,
'// then you'll need to use shp.BoundingBox, which
'// is more complicated
Dim dLeft As Double
Dim dx As Double, px As Double
Dim i As Integer
For i = 2 To sel.Count
'// Get the ith shape:
Set shp = sel(i)
'// Get its Pin:
px = shp.CellsU("PinX").ResultIU
'// Calculate the left side of the shape:
'// PinX - LocPinX:
dLeft = px - shp.CellsU("LocPinX").ResultIU
'// The offset:
dx = dLeft - dRight0
'// Set the new pin:
shp.CellsU("PinX").ResultIUForce = px - dx
Next i
Cleanup:
Set shp0 = Nothing
Set shp = Nothing
Set sel = Nothing
End Sub
Hope this helps!
I'm trying to explore how do I apply some formatting to only few selected words in a textbox but so far unable to accomplish this myself.
Somehow with the code I created below, I can only use it to select all the words in the textbox instead of just a few words I want.
It would be great if anyone can provide me a simpler/ existing codes that can help me solve this please ?
Thanks in advance
Sub ActiveTextRange()
Dim sld As slide
Dim sh As Shape
Dim wordcount As Long, j As Long, x As Long, y As Long, z As Long
wordcount = ActiveWindow.Selection.ShapeRange(1).textFrame.TextRange.Words.Count
With ActiveWindow.Selection.ShapeRange(1)
.textFrame.TextRange.Words(Start:=1, Length:=wordcount).Font.Color.RGB = RGB(230, 0, 0)
End With
End Sub
The following might help. Key to this is being able to track the location of the specific text you want to change in amongst larger chunks of text; my suggestion is to format each bit of text as you add it to the shape. Cheers.
Option Explicit
Sub ActiveTextRange()
Dim vPresentation As presentation
Dim vSlide As Slide
Dim vShape As Shape
Dim vAddThisText As String
' Create a new presentation, add a slide and a rectangle shape
Set vPresentation = Application.Presentations.Add
Set vSlide = vPresentation.Slides.Add(vPresentation.Slides.Count + 1, ppLayoutBlank)
Set vShape = vSlide.Shapes.AddShape(msoShapeRectangle, 10, 10, 600, 300)
' Make the shape white with a 3pt dark red border
vShape.Fill.ForeColor.RGB = rgbWhite
With vShape.Line
.ForeColor.RGB = rgbDarkRed
.Weight = 3
End With
' Setup the shape to be left aligned, font color, top anchored, etc
With vShape.TextFrame
.TextRange.Paragraphs.ParagraphFormat.Alignment = ppAlignCenter
.TextRange.Font.Color.RGB = rgbBlack
.VerticalAnchor = msoAnchorMiddle
.TextRange.ParagraphFormat.SpaceAfter = 6
.TextRange.ParagraphFormat.WordWrap = msoCTrue
End With
' And now format the word red, which is the 7th character and is 3 long
vAddThisText = "Hello Red World"
vShape.TextFrame.TextRange.InsertAfter vAddThisText
With vShape.TextFrame.TextRange.Characters(7, 3)
.Font.Color.RGB = rgbRed
' and change other attributes if needed etc
End With
End Sub
And the output is ...
This colors the second and third words red in a Title placeholder. After Words, the first number is the starting position and the second number is the length:
Sub ColorWords()
Dim objSlide As Slide
Dim objShape As Shape
For Each objSlide In ActivePresentation.Slides
For Each objShape In objSlide.Shapes
If objShape.Type = msoPlaceholder Then
If objShape.PlaceholderFormat.Type = ppPlaceholderTitle Or objShape.PlaceholderFormat.Type = ppPlaceholderCenterTitle Then
With objShape.TextFrame2.TextRange.Words(2, 2).Font.Fill
.Solid
.ForeColor.RGB = RGB(255, 0, 0)
End With
End If
End If
Next objShape
Next objSlide
End Sub
To color a word selection, use:
ActiveWindow.Selection.TextRange.Font.Color.RGB = RGB(Red:=255, Green:=0, Blue:=0)
OK. I think I better understand the ask ... but I'm assuming in this response you're selecting text ... rather than just a shape itself. So you're editing the powerpoint, select some text in a shape, and want to run a macro to format(?) It should be as simple as creating the following in a code module (and then I created a custom access toolbar link to run the macro at the top of PowerPoint to make it quick):
Option Explicit
Sub ActiveTextRange()
ActiveWindow.Selection.TextRange.Font.Color.RGB = rgbRed
End Sub
Before:
Select the text "Red" and run macro:
Btw ... if you want to select just the shape and have some logic choose the text, the concept is a mix of this and my first answer.
I would like to align ( in this case center)a shape( round cornered rectangle) within sharp cornered rectangle in a slide i.e the center point of both shapes should be equal using VBA without using 'Selection'.I am thinking to reference them via names(Like, wherever these two shapes come as a bunch, macro should align them) but not sure how to start.
Excuse me for the layman's explanation. Any thoughts would really be helpful and push me to start.
You'll have to set up a loop to check each shape in the slide, finding if its Type is an AutoShape, then if its AutoShapeType is msoShapeRoundedRectangle or msoShapeRectangle. As each are found, you would store the name of each in a variable. If both are found then you would get the left, top, width and height measurements for each and set those values so the centers align.
Sub CenterShapes()
Dim oSlide As Slide
Dim oShape As Shape
Dim bFoundRRect As Boolean, bFoundRect As Boolean
Dim RRectName$, RectName$
For Each oSlide In ActivePresentation.Slides
For Each oShape In oSlide.Shapes
If oShape.Type = msoAutoShape Then
If oShape.AutoShapeType = msoShapeRoundedRectangle Then
bFoundRRect = True
RRectName$ = oShape.Name
End If
If oShape.AutoShapeType = msoShapeRectangle Then
bFoundRect = True
RectName$ = oShape.Name
End If
End If
Next oShape
If bFoundRRect = True And bFoundRect = True Then
RRectVCenter = oSlide.Shapes(RRectName$).Top + (oSlide.Shapes(RRectName$).Height / 2)
RRectHCenter = oSlide.Shapes(RRectName$).Left + (oSlide.Shapes(RRectName$).Width / 2)
RectVCenter = oSlide.Shapes(RectName$).Top + (oSlide.Shapes(RectName$).Height / 2)
RectHCenter = oSlide.Shapes(RectName$).Left + (oSlide.Shapes(RectName$).Width / 2)
VDif = RRectVCenter - RectVCenter
HDif = RRectHCenter - RectHCenter
oSlide.Shapes(RectName$).Top = oSlide.Shapes(RectName$).Top + VDif
oSlide.Shapes(RectName$).Left = oSlide.Shapes(RectName$).Left + HDif
End If
Next oSlide
End Sub
This example assumes you know, or determine with your code, the names of the shapes you want to align. Then it's a quick manner of setting up a ShapeRange and using the built-in alignment functions in PowerPoint.
Option Explicit
Sub AlignMe()
Dim theseShapeNames As Variant
theseShapeNames = Array("Rectangle 3", "Rectangle 4", "Rectangle 5")
Dim thisSlide As Slide
Dim theseShapes As ShapeRange
Set thisSlide = ActivePresentation.Slides(1)
Set theseShapes = thisSlide.Shapes.Range(theseShapeNames)
theseShapes.Align msoAlignCenters, msoFalse
End Sub
I am working on one project. In which i want to find out " Is my textbox going out of slide or not?" . If yes then show error msg.
so my logic is if i found the dimension of the slide then i will use it in IF...Else condition like :
If textbox_position < slide_dimension then
#Error
end if
If you have any other idea then please tell me.
Thanks
The presentation's .PageSetup.SlideWidth and .SlideHeight properties will give you the dimensions of the slide in points.
Your function would need to do something like (off top of head and out of the air ..):
Function IsOffSlide (oSh as Shape) as Boolean
Dim sngHeight as single
Dim sngWidth as Single
Dim bTemp as Boolean
bTemp = False ' by default
With ActivePresentation.PageSetup
sngHeight = .SlideHeight
sngWidth = .SlideWidth
End With
' this could be done more elegantly and in fewer lines
' of code, but in the interest of making it clearer
' I'm doing it as a series of tests.
' If any of them are true, the function will return true
With oSh
If .Left < 0 Then
bTemp = True
End If
If .Top < 0 Then
bTEmp = True
End If
If .Left + .Width > sngWidth Then
bTemp = True
End If
If .Top + .Height > sngHeight Then
bTemp = True
End If
End With
IsOffSlide = bTemp
End Function
Why you not use a placeholders of PowerPoint to make this? for example:
Sub SetText(IndexOfSlide As Integer, txt As String)
'http://officevb.com
ActivePresentation.Slides(IndexOfSlide).Shapes.Placeholders(1).TextFrame.TextRange.Text = txt
End Sub
You can call this sub and pass parameters
IndexOfSlide with a number of slide and txt with a text to create.