As per using select query in postgres along 8 or 9 table using join found output as
1. A 2 34
2. A 2 56
3. B 3 34
4. B 3 56
whereas i required output in two form either
1. A 2 34
2. A 2 34
3. B 3 56
4. B 3 56
or
A 2 34
B 3 56
what can i do?
Using distinct?
select distinct * from table
Related
I Have a data table in postgresql which has these columns and some rows like this:
st
epochnum
satnum
l1
l2
c1
p1
p2
1
1
1
10
11
12
13
14
1
1
2
15
16
17
18
19
1
2
1
20
21
22
23
24
1
2
2
25
26
27
28
29
20
1
1
30
41
52
63
74
20
1
2
75
76
87
88
null
20
2
1
...
I want to get some pairs of rows that have the same value for epochnum and satnum but have different value in "st". By the way, I have a list that specifies which "st" pairs should be subtracted. Its just another table that looks like this:
st1
st2
1
20
The rows in the first table have to be subtracted in l1,l2,c1,p1 and p2 with same epochnum and satnum according to this table and then inserted into a new table like this:
epochnum
st1
st2
satnum
dl1
dl2
dc1
dp1
dp2
1
1
20
1
20
30
40
50
60
1
1
20
2
65
65
75
75
null
...
The actual data has more than 400000 rows that has same epochnums and satnums like this. I have tried java programming in net-beans and used loops to simply get queries for each row and make the new table.
But I think maybe it is not efficient and unnecessarily takes long time due to the lots of queries that has to be done in java.
I wonder if there is a way that this can be done using just a few queries, or creating extra tables and .... I haven't come up with the best solution yet.
Are you looking for joins like this?
select t1.st, t1.epochnum, t1.satnum,
(t2.l1 - t1.l1),
(t2.l2 - t1.l2),
(t2.p1 - t1.p1),
(t2.p2 - t1.p2)
from t t1 join
t t2
on t1.epochnum = t2.epochnum and
t1.satnum = t2.satnum join
pairs p
on t1.st = p.st1 and t2.st = p.st2
Using Teradata :I have two tables with 10 records and 3 variables. All columns and values are same expect for three values in one variable.
My task is to make code changes for table2 where both records are matched, by not hard coding any value.
The second table was created by the first table , so there is no way to pick values by join etc .
Code :
Create multiset table table2 as (
Select * from table1 )
With data primary index(var1);
Eg:
Var1
Var2
Var3
1
Abc
20
2
Cde
30
3
kgk
87
4
kjj
98
5
gvy
67
6
jbn
78
7
hvb
56
8
ihg
62
9
jhn
22
10
hbn
34
Var1
Var2
Var3
1
Abc
20
2
Cde
30
3
kgk
87
4
kjj
98
5
gvy
67
6
jbn
78
7
hvb
56
8
ihg
77
9
jhn
56
10
hbn
23
Not sure what you want but you can find all the matching records using exists as follows:
select t.* from table2 t
where exists
(select 1 from table1 tt
where t.var1 = tt.var1 and t.var2 = tt.var2)
following is scenario:
I have data in following format:
entryid , ac_no, db/cr, amt
-----------------------------------------------
1 10 D 5
1 11 C 5
2 01 D 8
2 11 C 8
3 12 D 10
3 13 C 10
4 14 D 5
4 16 C 5
5 14 D 2
5 17 C 2
6 14 D 3
6 18 C 3
I want data in following format:
So far i have acheived the first 3 columns by query
select wm_concat(entryid),ac_no,db_cr,Sum(amt) from t1 group by ac_no,db_cr
wm_Concat(entryid),ac_no, db/cr, Sum(amt), set_id
------------------------------------------------
1 10 D 5 S1
2 01 D 8 S1
1,2 11 C 13 S1
3 12 D 10 S2
3 13 C 10 S2
4,5,6 14 D 10 S3
4 16 C 5 S3
5 17 C 2 S3
6 18 C 3 S3
I want an additional column `set_id` that either shows this S1, S2.. or any number 1,2.. so that the debit & credit entries sets can be identified.
I am making sets of debit and credit entries based on their Ac_no values.
Any little help will be highly appreciated. Thanks
Create a new column say set and give a unique identifier to the particular set. So for example the first three records will have set id S1, next two will have S2 and so on.
To distinguish a transaction from a set you can use column db/cr along with newly added set column. You can identify that the 3rd row is a set since it's transaction type is 'C' whereas the transactions are of type 'D'.
Here I have assumed that your transactions are debit only, if not please provide more details in the question. Hope this helps.
Say I have two tables, geom_levels and taz_geoms where taz_geoms has the columns as follows:
taz_geoms
id(int) state(int) county(int) taz(int) geom(geometry(MultiPolygon,4326))
and geom_levels looks like this:
geom_levels
TAZ COUNTY STATE DISTRICT
1 1 29 1
2 1 29 1
3 1 29 1
4 2 29 2
5 2 29 2
6 2 29 2
7 2 29 3
8 3 29 3
9 3 29 3
10 3 29 4
11 3 29 4
12 3 29 4
13 4 29 5
14 4 29 5
15 4 29 5
16 4 29 6
17 4 29 6
How would I go about combining these taz geometries into county, state, and district geometries? I would like to have a county_geoms, state_geoms, and district_geoms table. I have see that you can use ST_UNION with a geom array, but how would I generate such an array for counties or districts?
I was thinking something like this for counties:
SELECT ST_UNION(SELECT geom from taz_geoms GROUP BY county);
and for districts:
SELECT ST_UNION(SELECT geom from taz_geoms t LEFT JOIN geom_levels gl ON gl.taz = t.taz GROUP BY district);
But those options do not see possible.
Ideas?
try with:
SELECT ST_UNION( ARRAY( 'YOUR SELECT geoms QUERY' ) );
in your case:
SELECT ST_UNION(ARRAY( (SELECT geom from taz_geoms t LEFT JOIN geom_levels gl ON gl.taz = t.taz GROUP BY district) ));
I had the same problem and got it to work with postgre usin the ARRAY() function ;)
I am running this query:
SELECT u.id as id,
COUNT(DISTINCT YEAR(TIMESTAMP), WEEK(TIMESTAMP)) cc,
GROUP_CONCAT(DISTINCT YEAR(TIMESTAMP),'-',WEEK(TIMESTAMP)) a
FROM users u
JOIN checkins c
ON c.userid = u.id
GROUP BY userid
HAVING COUNT(cc) = 3
And this produces the following results:
id cc a
05 3 2010-43,2010-47,2010-45
06 2 2010-44,2010-45
13 3 2010-43,2010-45,2010-48
20 3 2010-45,2010-43,2010-47
21 3 2010-43,2010-47,2010-45
22 2 2010-47,2010-48
25 3 2010-48,2010-43,2010-46
27 2 2010-42,2010-47
30 2 2010-48,2010-45
41 3 2010-44,2010-45,2010-47
44 2 2010-42,2010-44
50 2 2010-44,2010-47
52 2 2010-48,2010-47
57 2 2010-43,2010-44
71 3 2010-43,2010-48,2010-47
72 2 2010-43,2010-44
78 3 2010-47,2010-42,2010-43
79 2 2010-45,2010-46
80 2 2010-46,2010-44
87 1 2010-46
97 1 2010-48
108 3 2010-43,2010-47,2010-45
As you see the cc column has values 2, 3, or even 1.
How that comes, when I've told with HAVING that should be 3?
MySQL does allow aliases in the Having clause. You would need to use:
HAVING cc = 3
not
HAVING COUNT(cc) = 3
in order to filter the results to only include rows which have a cc value of 3 though. I'm actually quite unsure though why HAVING COUNT(cc) = 3 would return any results at all.
As previously said about aliases and having clause, I'd just like to expand on it.
You already have created cc alias which holds counts that you'd like to filter on, so you just need to reference aliased column in HAVING, like:
HAVING cc = 3
What you have tried (COUNT(cc) = 3) would make sense if you were to group by cc column (if that was possible), and then that would filter out all rows with same cc value that didn't appear exactly 3 times.