I am running this query:
SELECT u.id as id,
COUNT(DISTINCT YEAR(TIMESTAMP), WEEK(TIMESTAMP)) cc,
GROUP_CONCAT(DISTINCT YEAR(TIMESTAMP),'-',WEEK(TIMESTAMP)) a
FROM users u
JOIN checkins c
ON c.userid = u.id
GROUP BY userid
HAVING COUNT(cc) = 3
And this produces the following results:
id cc a
05 3 2010-43,2010-47,2010-45
06 2 2010-44,2010-45
13 3 2010-43,2010-45,2010-48
20 3 2010-45,2010-43,2010-47
21 3 2010-43,2010-47,2010-45
22 2 2010-47,2010-48
25 3 2010-48,2010-43,2010-46
27 2 2010-42,2010-47
30 2 2010-48,2010-45
41 3 2010-44,2010-45,2010-47
44 2 2010-42,2010-44
50 2 2010-44,2010-47
52 2 2010-48,2010-47
57 2 2010-43,2010-44
71 3 2010-43,2010-48,2010-47
72 2 2010-43,2010-44
78 3 2010-47,2010-42,2010-43
79 2 2010-45,2010-46
80 2 2010-46,2010-44
87 1 2010-46
97 1 2010-48
108 3 2010-43,2010-47,2010-45
As you see the cc column has values 2, 3, or even 1.
How that comes, when I've told with HAVING that should be 3?
MySQL does allow aliases in the Having clause. You would need to use:
HAVING cc = 3
not
HAVING COUNT(cc) = 3
in order to filter the results to only include rows which have a cc value of 3 though. I'm actually quite unsure though why HAVING COUNT(cc) = 3 would return any results at all.
As previously said about aliases and having clause, I'd just like to expand on it.
You already have created cc alias which holds counts that you'd like to filter on, so you just need to reference aliased column in HAVING, like:
HAVING cc = 3
What you have tried (COUNT(cc) = 3) would make sense if you were to group by cc column (if that was possible), and then that would filter out all rows with same cc value that didn't appear exactly 3 times.
Related
Just wanted to preface this by saying while I do have a basic understanding, I am still fairly new to using Bigquery tables and sql statements in general.
I am trying to make a new view out of a query that grabs all of the best test scores for each version by each employee:
select emp_id,version,max(score) as score from `project.dataset.table` where type = 'assessment_test' group by version,emp_id order by emp_id
I'd like to take the results of that query, and make a new table comprised of employee id's with a column for each versions best score for that rows emp_id. I know that I can manually make a table for each version by including a "where version = a", "where version = b", etc.... and then joining all of the tables at the end but that doesn't seem like the most elegant solution plus there is about 20 different versions in total.
Is there a way to programmatically create a column for each unique version or at the very least use my initial query as maybe a subquery and just reference it, something like this:
with a as (
select id,version,max(score) as score
from `project.dataset.table`
where type = 'assessment_test' and version is not null and score is not null and id is not null
group by version,id
order by id),
version_a as (select score from a where version = 'version_a')
version_b as (select score from a where version = 'version_b')
version_c as (select score from a where version = 'version_c')
select
a.id as id,
version_a.score as version_a,
version_b.score as version_b,
version_c.score as version_c
from
a,
version_a,
version_b,
version_c
Example Picture: left table is example data, right table is expected output
Example Data:
id
version
score
1
a
88
1
b
93
1
c
92
2
a
89
2
b
99
2
c
78
3
a
95
3
b
83
3
c
89
4
a
90
4
b
90
4
c
86
5
a
82
5
b
78
5
c
98
1
a
79
1
b
97
1
c
77
2
a
100
2
b
96
2
c
85
3
a
83
3
b
87
3
c
96
4
a
84
4
b
80
4
c
77
5
a
95
5
b
77
Expected Output:
id
a score
b score
c score
1
88
97
92
2
100
99
85
3
95
87
96
4
90
90
86
5
95
78
98
Thanks in advance and feel free to ask any clarifying questions
Use below approach
select * from your_table
pivot (max(score) score for version in ('a', 'b', 'c'))
if applied to sample data in your question - output is
In case if versions is not known in advance - use below
execute immediate (select '''
select * from your_table
pivot (max(score) score for version in (''' || string_agg(distinct "'" || version || "'") || "))"
from your_table
)
I Have a data table in postgresql which has these columns and some rows like this:
st
epochnum
satnum
l1
l2
c1
p1
p2
1
1
1
10
11
12
13
14
1
1
2
15
16
17
18
19
1
2
1
20
21
22
23
24
1
2
2
25
26
27
28
29
20
1
1
30
41
52
63
74
20
1
2
75
76
87
88
null
20
2
1
...
I want to get some pairs of rows that have the same value for epochnum and satnum but have different value in "st". By the way, I have a list that specifies which "st" pairs should be subtracted. Its just another table that looks like this:
st1
st2
1
20
The rows in the first table have to be subtracted in l1,l2,c1,p1 and p2 with same epochnum and satnum according to this table and then inserted into a new table like this:
epochnum
st1
st2
satnum
dl1
dl2
dc1
dp1
dp2
1
1
20
1
20
30
40
50
60
1
1
20
2
65
65
75
75
null
...
The actual data has more than 400000 rows that has same epochnums and satnums like this. I have tried java programming in net-beans and used loops to simply get queries for each row and make the new table.
But I think maybe it is not efficient and unnecessarily takes long time due to the lots of queries that has to be done in java.
I wonder if there is a way that this can be done using just a few queries, or creating extra tables and .... I haven't come up with the best solution yet.
Are you looking for joins like this?
select t1.st, t1.epochnum, t1.satnum,
(t2.l1 - t1.l1),
(t2.l2 - t1.l2),
(t2.p1 - t1.p1),
(t2.p2 - t1.p2)
from t t1 join
t t2
on t1.epochnum = t2.epochnum and
t1.satnum = t2.satnum join
pairs p
on t1.st = p.st1 and t2.st = p.st2
As per using select query in postgres along 8 or 9 table using join found output as
1. A 2 34
2. A 2 56
3. B 3 34
4. B 3 56
whereas i required output in two form either
1. A 2 34
2. A 2 34
3. B 3 56
4. B 3 56
or
A 2 34
B 3 56
what can i do?
Using distinct?
select distinct * from table
I am new to SQL Server and need help with one of my SQL query.
I have 2 tables (Rating and LikeDislike).
I am trying to get data from both of these tables using a LEFT JOIN like this:
SELECT distinct LD.TopicID, R.ID, R.Topic, R.CountLikes, R.CountDisLikes, LD.UserName, LD.Clikes
FROM Rating As R
LEFT JOIN LikeDislike AS LD on LD.TopicID = R.ID
The above SELECT statement displays results fine but also includes duplicates. I want to remove duplicates when the data is displayed, I tried using DISTINCT and GROUP BY, but with no luck, maybe because I am not using it correctly.
To be more clear and less confusing let me tell you what exactly each table does and what I am trying to achieve.
The Rating table has following columns (ID, Topic, CountLikes, CountDisLikes, Extra, CreatedByUser). It stores topic information and number of likes and dislikes for each topics and the UserID of the user who created that topic.
Rating table with sample data
ID Topic CountLikes CountDisLikes Extra CreatedByUser
1 Do You Like This 211 58 YesId 2
2 Or This 17 25 This also 3
79 Testing at home 1 0 Testing at home 2
80 Testing at home again 1 0 Testing 2
82 testing dislikes 0 1 Testing 2
76 Testing part 3 7 5 Testing 3 4
77 Testing part 4 16 6 Testing 4 5
The LikeDisLike table has following columns (ID, TopicID, UserName, Clikes). TopicID is a FK to the ID column in Rating table.
LikeDislike table with sample data
ID TopicID UserName Clikes
213 77 2 TRUE
214 76 2 FALSE
215 77 5 TRUE
194 77 3 TRUE
195 76 3 FALSE
196 2 3 TRUE
197 1 3 FALSE
Now what I am trying to do is get information from both of this table without duplicate rows. I need to get data all the columns from Rating table + UserName and Clikes columns from LikeDislike table without any duplicate rows
Below are the results with duplicates
TopicID ID Topic CountLikes CountDislikes UserName Clikes
NULL 79 Testing at home 1 0 NULL NULL
NULL 80 Testing at home2 1 0 NULL NULL
NULL 82 testing dislikes 0 1 NULL NULL
1 1 Do You Like This 211 58 3 FALSE
2 2 Or This 17 25 3 TRUE
76 76 Testing part 3 7 5 2 FALSE
76 76 Testing part 3 7 5 3 FALSE
77 77 Testing part 4 16 6 2 TRUE
77 77 Testing part 4 16 6 3 TRUE
77 77 Testing part 4 16 6 5 TRUE
Just like in yesterday's post, I don't think you understand what DISTINCT is suppose to return you. Because you have different values in your LikeDislike table, you are returning the DISTINCT rows.
Let's take TopicId 77 for instance. It returns 3 DISTINCT rows because you have 3 matching records in your LikeDislike table. If your desired output is a single row where the UserName and Clikes are comma delimted, that is possible -- look into using for xml and perhaps stuff (here is a recent answer on the subject). Or if you want to return the first row that matches the TopicId, then that is possible as well -- look into using a subquery with row_number.
Please let us know your desired output and we can help provide a solution.
Good luck.
Need your help with a SQL query in Oracle db. I have data that I want to partition into groups when event = "Start". E.g. Row 1-6 is a group, row 7-9 is a group. I want to ignore rows with event = "Ignore". Finally I want to calculate max(Value)-min(Value) for these groups. I dont have any way to group the data.
Can this be achieved? Is it possible to use partition by Event = start. Same data is below:
Row Event Value Required Result is max-min of value
1 Start 10
2 A 11
3 B 12
4 C 13
5 D 14
6 E 15 5
--------------------------------------------
7 Start 16
8 A 18
9 B 20 4
--------------------------------------------
10 Start 27
11 A 30
12 B 33
13 C 34 7
--------------------------------------------
14 Ignore 35
--------------------------------------------
15 Ignore 36
--------------------------------------------
16 Start 33
17 A 34
18 B 35
19 C 36
20 D 37
21 E 38 5
--------------------------------------------
Yes, you can do this in SQL.
The following query first finds the group that a row is in, by finding the largest start before the row id. This version uses a correlated subquery for this calculation.
It then does the grouping on the id and does the calculation.
select groupid, max(value) - min(value)
from (select t.*,
(select max(row) from t t2 where t2.row < t.row and t2.event = start
) as groupid
from t
) t
where event <> 'IGNORE'