I have a table like this
FILEID | FILENAME | STATUS
100 |Employee_06102016.txt |PASS
100 |Employee_06092016.txt |FAIL
100 |Employee_06092016.txt |MISS
101 |ABC_06092016.txt |PASS
I am reading a filename from file and passing to SQL. Lets say, i have only the file name 'Emplyee_06102016.txt' which is with PASS staus. With this, i need to join the same table and take the count of PASS and FAIL filenames which have same file id and should exclude the MISS status.
I am trying something like this below but gives count as 3 including all. I should get only 2.
SELECT COUNT (T.FILEID) FROM TABLE_NAME T, TABLE_NAME S
WHERE T.FILEID=S.FILEID
AND T.FILENAME = 'Employee_06102016.txt' AND T.STATUS IN ('PASS', 'FAIL');
Oracle Setup:
CREATE TABLE table_name ( FILEID, FILENAME, STATUS ) AS
SELECT 100, 'Employee_06102016.txt', 'PASS' FROM DUAL UNION ALL
SELECT 100, 'Employee_06092016.txt', 'FAIL' FROM DUAL UNION ALL
SELECT 100, 'Employee_06092016.txt', 'MISS' FROM DUAL UNION ALL
SELECT 101, 'ABC_06092016.txt', 'PASS' FROM DUAL;
Query:
SELECT *
FROM (
SELECT t.*,
COUNT(1) OVER ( PARTITION BY FileID ) AS num_pass_fail
FROM table_name t
WHERE status IN ( 'PASS', 'FAIL' )
)
WHERE filename = 'Employee_06102016.txt';
Output:
FILEID FILENAME STATUS NUM_PASS_FAIL
---------- --------------------- ------ -------------
100 Employee_06102016.txt PASS 2
SELECT
FILENAME,
SUM(CASE status WHEN 'PASS' THEN 1 ELSE 0 END) as "Pass Count",
SUM(CASE status WHEN 'FAIL' THEN 1 ELSE 0 END) as "Fail Count",
SUM(CASE status WHEN 'MISS' THEN 1 ELSE 0 END) as "Miss Count"
FROM
TableName
WHERE
FILENAME = 'Employee_06102016.txt'
It seems that you simply need:
SELECT COUNT (1)
FROM TABLE_NAME
WHERE FILENAME = 'Employee_06102016.txt'
AND STATUS IN ('PASS', 'FAIL');
Try this one
select cnt from (
select count(*) as cnt,
listagg(filename, ',') within group(order by filename) as filename_list from table_name
where status in ('PASS', 'FAIL') group by fileid
) where instr(filename_list, 'Employee_06102016.txt')>0;
Related
I have two tables:
table1
the_date | my_id |
02/03/2021,123
02/03/2021, 1234
02/03/2021, 12345
table2
the_date | my_id |seq | txt
02/03/2021, 1234, 1 , 'OK'
02/03/2021, 12345, 1, 'OK'
02/03/2021, 12345, 2, 'HELLO HI THERE'
02/03/2021, 123456, 1, 'Ok'
Here is my code:
WITH AB AS (
SELECT A1.my_id
FROM DB1.table1 A1 , DB1.MSG_REC A2 WHERE
A1.my_id=A2.my_id
),
BC AS (
SELECT AB.the_date
COUNT ( DISTINCT (CASE WHEN (TXT like '%OK%') THEN AB.my_id ELSE NULL END )) AS
CASE1 ,
COUNT ( DISTINCT (CASE WHEN (TXT like '%HELLO HI THERE%') THEN AB.my_id ELSE NULL END )) AS
CASE2
FROM AB left JOIN DB1.my_id BC ON AB.my_id =BC.my_id
The issue that stems from above is I am looping over the value '12345' twice because it satisfies both of the case statements.
That causes data duplicates when capturing metrics of the counts. Is there a way to execute the first case and then perform the second case but exclude looping any of the "my_id' records from the first case.
So for example, when it is time to run the above script and the first case executes, it will pick up the below records and the count would be 3
02/03/2021, 1234, 1 , 'OK'
02/03/2021, 12345, 1, 'OK'
02/03/2021, 123456, 1, 'Ok
The second case should only be looping through the below records and the count would be only 1
02/03/2021, 12345, 2, 'HELLO HI THERE'
CASE1 would be 4 and CASE2 would by 2 if I don't create a condition to circumvent this issue. Any tips or suggestions?
Assign case to each your ID before DISTINCT aggregation . After that do distinct aggregation, in such way you will eliminate same IDs counted in different cases. See comments in the code:
select --do final distinct aggregation
count(distinct (case when assigned_case='CASE1' then my_id else null end ) ) as CASE1,
count(distinct (case when assigned_case='CASE2' then my_id else null end ) ) as CASE2
from
(
select my_id
--assign single CASE to all rows with the same id based on some logic:
case when case1_flag = 1 then 'CASE1'
when case1_flag = 1 then 'CASE2'
else NULL
end as assigned_case
from
(--calculate all CASE flags for each ID
select AB.my_id,
max(CASE WHEN (TXT like '%OK%') THEN 1 ELSE NULL END) over (partition by AB.my_id) as case1_flag
max(CASE WHEN (TXT like '%HELLO HI THERE%') THEN 1 ELSE NULL END) over (partition by AB.my_id) as case2_flag
from ...
) s
) s
I've got the following table:
id date status
1 2017-04-20 good
1 2017-04-19 bad
1 2017-04-18 bad
2 2017-04-20 ok
2 2017-04-19 ok
2 2017-04-17 ok
2 2017-04-16 bad
What I need is to get the previous distinct value in status column per id.
Assuming that today is 2017-04-20, the result would look like this:
id previous_status
1 bad
2 bad
Afterwards, I wanna use this information in the case statement:
Case when status = 'good' and previous_status = 'bad', ....
You could you this for your first requirement:
SELECT id, status AS previous_status
FROM table_name
WHERE (id, date_col) IN (
SELECT id, MAX(date_col)
FROM table_name
WHERE DATE(date_col) < "2017-04-20"
);
And this is for second requirement using CASE statement
SELECT t.id, t.status, t1.previous_status,
CASE
WHEN t.status = 'good' AND t1.previous_status = 'bad' THEN 'some_value'
ELSE 'other_value'
END AS case_col
FROM table_name t
INNER JOIN (
SELECT id, status AS previous_status
FROM table_name
WHERE (id, date_col) IN (
SELECT id, MAX(date_col)
FROM table_name
WHERE DATE(date_col) < "2017-04-20"
)
) t1
ON t.id = t1.id
WHERE DATE(t.date_col) = "2017-04-20";
This refer how_to_compare_date_google_big_query
I am trying to select different values that depend on different conditions, but I don't exactly know, how one can achieve this in SQL/Oracle..
Here is an example:
SELECT VALUE (I dont exactly know what to write here)
FROM
(SELECT
(CASE
WHEN (Select 1 from DUAL) = 1 THEN 'TEST'
WHEN (Select 1 from DUAL) = 0 THEN 'TEST1'
WHEN (Select 1 from DUAL) = 0 THEN 'TEST2'
ELSE 'N/A'
END)
FROM DUAL);
I want to print different results according to the conditions...For instance, in the example above it should print "TEST"
You need to provide an alias to the CASE statement:
SELECT alias_for_your_case_value
FROM (
SELECT CASE (Select 1 from DUAL)
WHEN 1 THEN 'TEST'
WHEN 0 THEN 'TEST1'
WHEN 0 THEN 'TEST2'
ELSE 'N/A'
END AS alias_for_your_case_value
FROM DUAL
);
I have these columns
Id Status
----------
1 pass
1 fail
2 pass
3 pass
How do I select all that only have a status of pass but if the Id has at least one fail it will not be selected as well.
If same id can have multiple passes
SELECT id
from table
WHERE status = 'pass'
and id NOT IN (SELECT id FROM table WHERE status = 'fail')
You need to use GROUP BY & HAVING clause
SELECT Id
FROM yourtable
GROUP BY Id
HAVING Sum(case when status ='pass' then 1 else 0 end) = count(status)
HAVING clause can be changed to
HAVING Count(case when status ='pass' then 1 end) = count(status)
I just hate chatty case statement, so
SELECT Id
FROM table1
GROUP BY Id
HAVING COUNT(DISTINCT [Status]) = 1 AND MIN([Status]) = 'pass'
or
SELECT Id
FROM table1
GROUP BY Id
HAVING COUNT(NULLIF([Status], 'fail')) = 1 AND COUNT(NULLIF([Status], 'pass')) = 0
The second query only works when status has two values 'pass' and 'fail'.
I have problem with SQL query.
I have names in column Name in Table_Name, for example:
'Mila', 'Adrianna' 'Emma', 'Edward', 'Adam', 'Piter'
I would like to count how many names contain the letter 'A' and how many contain the letter 'E'.
The output should be:
letter_A ( 5 )| letter_E (3)
I tried to do this:
SELECT Name,
letter_A = CHARINDEX('A', Name),
letter_E = CHARINDEX('E', Name)
FROM Table_Name
GROUP BY Name
HAVING ( CHARINDEX('A', Nazwisko) != 0
OR ( CHARINDEX('E', Nazwisko) ) != 0 )
My query only shows if 'A' or 'E' is in Name :/
Can anyone help? :)
You can use conditional aggregation:
select sum(case when Nazwisko like '%A%' then 1 else 0 end) as A_cnt,
sum(case when Nazwisko like '%E%' then 1 else 0 end) as E_cnt
from table_name
where Nazwisko like '%A%' or Nazwisko like '%E%';
You just need to aggregate if you only need the counts.
select
sum(case when charindex('a',name) <> 0 then 1 else 0 end) as a_count
,sum(case when charindex('e',name) <> 0 then 1 else 0 end) as e_count
from table_name
;WITH CTE
AS (SELECT NAME
FROM (VALUES ('MILA'),
('ADRIANNA'),
('EMMA'),
('EDWARD'),
('ADAM'),
('PITER'))V(NAME)),
CTE_NAME
AS (SELECT COUNT(NAME_A) NAME_A,
COUNT(NAME_E) NAME_E
FROM (SELECT CASE
WHEN NAME LIKE '%A%' THEN NAME
END NAME_A,
CASE
WHEN NAME LIKE '%E%' THEN NAME
END NAME_E
FROM CTE
GROUP BY NAME)A)
SELECT *
FROM CTE_NAME