I have data 20160526094432, and I want to convert into datetime in SQLServer
The result will be 2016-05-26 09:44:32
Is there simple way to do that ?
Thanks
If you use MS SQL Server 2012 or newer then you can enjoy format function.
select cast(format(20160526094432,'####-##-## ##:##:##') as datetime) [date-time]
If your long number is a string then you have to convert it.
declare #d varchar(20)='20160526094432'
select cast(format(cast(#d as bigint),'####-##-## ##:##:##') as datetime) [date-time]
Hmmm. I don't think there is a really clean way, but something like this should work:
select (convert(datetime, left(col, 8) as datetime) +
convert(datetime, convert(time,
stuff(stuff(right(col, 6), 5, 0, ':'), 3, 0, ':')
)
)
)
Maybe you can try in this way, for example Date is the column of your table, 103 is the format of Date you want to convert, google for more details.
CONVERT(datetime, Date, 103)
Related
I need to convert a column that contains dates and times in the format 08-JAN-19 09.35.58.173000000 AM to datetime. I've included the code I've tried below - the code commented out is currently not working.
SELECT [last_updated_at]
, SUBSTRING([last_updated_at], 1, 9)
, convert(datetime, SUBSTRING([last_updated_at], 1, 9), 103) as Date
, SUBSTRING([last_updated_at], 11, 18)
--, convert(datetime, SUBSTRING([last_updated_at], 11, 18), 103) as Time --This fails
--, convert(datetime, SUBSTRING([last_updated_at], 1, 9), 103) + convert(datetime, SUBSTRING([last_updated_at], 11, 18), 103) as DateTime --final output datetime column
FROM #temp_dates
The only problem with your data is that you need the time portion of your date to look like this: 2019-01-08 09:35:58.173 instead of 2019-01-08 09.35.58.173 (the dots after the hour and minute need to be colons instead of dots.
--==== Original formatting
DECLARE #date VARCHAR(20) = '08-JAN-19 09.35.58.173000000'
--==== Solution
SELECT CAST(STUFF(STUFF(#date,13,1,':'),16,1,':') AS DATETIME);
Note that this truncates (not rounds) to the nearest millisecond so, 09:35:58.173 becomes 09:35:58.100. If milliseconds are an issue then a bit more finagling will be required.
Please try the below:
select convert(datetime, substring(replace(replace('08-JAN-19 09.35.58.173000000', '-', ' '), '.', ':'), 1, 18))
Before you can convert a string to datetime, your string must conform to certain patterns as shown in https://learn.microsoft.com/en-us/sql/t-sql/data-types/datetime-transact-sql?view=sql-server-ver15
I have table with column COL1(char 23) with full date e.g. '2007-11-13 12:34:49:012'. Now I want to change my date to '2007-11-12 59:59:59:999' (last moment in day before).
Why the convert paremeters dont work property? My query:
convert(varchar(10),convert(date,DateAdd(day,-1,COL1),121)) + ' 23:59:59:999'
After
DateAdd(day,-1,COL1)
i get: "Nov 12 2007" and this is my problem.
Finally i get: "Nov 12 200 23:59:59:999"
How about this?
select dateadd(millisecond, -1, dateadd(day, 1, cast(left(col1, 10) as datetime)))
Varchar(10) isn't quite ling enough for the data try varchar(11)
try this:
select cast(dateadd(ms, -1, cast(convert(varchar(8), cast(col1 as datetime), 112) as datetime2)) as varchar(23))
Here is what I have tried thus far:
select CAST(
DATEPART(month,getDate())+'-'+
DATEPART(day,getDate())+'-'+
2012
as datetime)
I end up with the date: 1905-08-02 00:00:00.0. I was expecting to get today's date. I have rearranged the order and it doesn't seem to change. Can anyone offer as to why it gives me this? For the record, I plan to use other values than 2012 for the year.
Thanks in advance.
CAST() each piece as a varchar first:
select
cast(
cast(DATEPART(month,getDate()) as varchar(2))+'-'+
cast(DATEPART(day,getDate()) as varchar(2))+'-'+
'2012' as datetime)
select CAST ('2012'+
CAST(DATEPART(month,getDate()) as char(2))+
CAST(DATEPART(day,getDate()) as char(2))
as datetime)
You have to concatenate strings. Your code is casting the number 2039 to date.
If the goal with this little exercise is to be able to change the year of a given date you can do like this instead.
declare #NewYear int = 2003
-- with time part
select dateadd(year, #NewYear - year(getdate()), getdate())
-- time part removed
select dateadd(year, #NewYear - year(getdate()), dateadd(day, 0, datediff(day, 0, getdate())))
This code will work, you need to make sure that you are concatenating same data types and use convert with specific DateTime Format:
SELECT CONVERT(DATETIME,
CAST(DATEPART(month,getDate()) AS NVARCHAR(50))
+'-'+CAST(DATEPART(day,getDate()) AS NVARCHAR(50))
+'-2012'
,121)
When I select date in SQL it is returned as 2011-02-25 21:17:33.933. But I need only the Date part, that is 2011-02-25. How can I do this?
For SQL Server 2008:
Convert(date, getdate())
Please refer to https://learn.microsoft.com/en-us/sql/t-sql/functions/getdate-transact-sql
I guess he wants a string.
select convert(varchar(10), '2011-02-25 21:17:33.933', 120)
120 here tells the convert function that we pass the input date in the following format: yyyy-mm-dd hh:mi:ss.
Using CAST(GETDATE() As Date) worked for me
The fastest is datediff, e.g.
select dateadd(d, datediff(d,0, [datecolumn]), 0), other..
from tbl
But if you only need to use the value, then you can skip the dateadd, e.g.
select ...
WHERE somedate <= datediff(d, 0, getdate())
where the expression datediff(d, 0, getdate()) is sufficient to return today's date without time portion.
CAST(
FLOOR(
CAST( GETDATE() AS FLOAT )
)
AS DATETIME
)
http://www.bennadel.com/blog/122-Getting-Only-the-Date-Part-of-a-Date-Time-Stamp-in-SQL-Server.htm
For 2008 older version :
SELECT DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()), 0)
you can use like this
SELECT Convert(varchar(10), GETDATE(),120)
In case if you need the time to be zeros like 2018-01-17 00:00:00.000:
SELECT CONVERT(DATETIME, CONVERT(DATE, GETDATE()), 121)
I would use DATEFROMPARTS function. It is quite easy and you don't need casting. As an example this query :
Select DATEFROMPARTS(YEAR(GETDATE()), MONTH(GETDATE()), DAY(GETDATE())) as myNewDate
will return
2021-01-21
The good part you can also create you own date, for example you want first day of a month as a date, than you can just use like below:
Select DATEFROMPARTS(YEAR(GETDATE()), MONTH(GETDATE()), 1) as myNewDate
The result will be:
2021-01-01
You can try this one too.
SELECT CONVERT(DATE, GETDATE(), 120)
Its too late but following worked for me well
declare #vCurrentDate date=getutcdate()
select #vCurrentDate
When data type is date, hours would be truncated
It's a bit late, but use the ODBC "curdate" function (angle brackes 'fn' is the ODBC function escape sequence).
SELECT {fn curdate()}
Output: 2013-02-01
Convert it back to datetime after converting to date in order to keep same datatime if needed
select Convert(datetime, Convert(date, getdate()) )
If you want to return a date type as just a date use
CONVERT(date, SYSDATETIME())
or
SELECT CONVERT(date,SYSDATETIME())
or
DECLARE #DateOnly Datetime
SET #DateOnly=CONVERT(date,SYSDATETIME())
Use is simple:
convert(date, Btch_Time)
Example below:
Table:
Efft_d Loan_I Loan_Purp_Type_C Orig_LTV Curr_LTV Schd_LTV Un_drwn_Bal_a Btch_Time Strm_I Btch_Ins_I
2014-05-31 200312500 HL03 NULL 1.0000 1.0000 1.0000 2014-06-17 11:10:57.330 1005 24851e0a-53983699-14b4-69109
Select * from helios.dbo.CBA_SRD_Loan where Loan_I in ('200312500') and convert(date, Btch_Time) = '2014-06-17'
select DATE(field) from table;
field value: 2020-12-15 12:19:00
select value: 2020-12-15
In PLSQL you can use
to_char(SYSDATE,'dd/mm/yyyy')
First Convert the date to float (which displays the numeric), then ROUND the numeric to 0 decimal points, then convert that to datetime.
convert(datetime,round(convert(float,orderdate,101),0) ,101)
Try this.
SELECT DATEADD(DD, 0, DATEDIFF(DD, 0, GETDATE()))
I would create a scalar function and use format () to set the datatype you want to see. It is must easy on the maintenance later.
Personal favorite:
select convert(datetime, convert(int, getdate()))
I have two columns as orderdate(03/02/2011) and ordertime(10.34 am) in which i have to concatenate these two columns and show it in another column as datetime values(03/02/2011 10:34:16.190)....
any suggestion?
In general, the solution is to add days to the time value which has zero for its day portion. You are not clear as the data types of the two values, however one solution would be:
With Inputs As
(
Select '20110302' As DateVal, '10:34 AM' As TimeVal
)
Select DateAdd(d, DateDiff(d, 0, Cast(DateVal As datetime)), Cast(TimeVal as datetime))
From Inputs
A more explicit version assuming the inputs are strings and given your exact inputs:
Set DateFormat MDY
With Inputs As
(
Select '03/02/2011' As DateVal, '10:34 AM' As TimeVal
)
Select DateAdd(d, DateDiff(d, 0, Cast(DateVal As datetime)), Cast(TimeVal as datetime))
From Inputs
Assuming you are working with a DATE and a TIME, you need to convert before you can add.
SELECT [orderdate] + CONVERT(datetime, [ordertime])
you want in programatically or in sql server:
in Sql Server:
select orderdate + ordertime as 'YourColumnName'
hope this help.
In MySQL, it'll work like this
SELECT Concat(orderdate, " ", ordertime) FROM vendors ORDER BY vend_name;