I need to use an SSRS expression to find two dates -
The date that's the end of this week.
The dates that's the start of the week, 2 weeks ago.
For example, if today is 27/05/2016
1 = 29/05/2016
2 = 09/05/2016
This needs to be dynamic e.g. getdate()
I'm using these functions to filter a matrix.
Thanks.
It may be something like below,
1. The date that's the end of this week.
=DateAdd("d", 7 - DatePart("w", CDate(Today)), CDate(Today).AddDays(1)).ToString("dd/MM/yyyy")
2. The dates that's the start of the week, 2 weeks ago.
=DateAdd("d", 2 - WeekDay(Today), DateAdd("d", -14, Today).ToString("dd/MM/yyyy")
SSRS Expression Cheat Sheet
May be something like this,
End of this week
=DateAdd("d", 8 - Weekday(Today), Today).ToString("dd/MM/yyyy")
Start of the week (2 weeks ago)
=DateAdd("d", -(Weekday(Today)+12) , Today).ToString("dd/MM/yyyy")
Related
I have inherited a query from an old MS Access DB and cannot for the life of me figure out what was trying to be done in this date parameter function. I normally only use SQL and this seems a bit different. Can any one assist in describing what this logic is doing?
use pdx_sap_user
go
select po_number,
po_issue_date
from vw_po_header
where po_issue_date > getDate() And PO_issue_date < DateAdd("d",-1,DateAdd("m",8,DateAdd("d",-(Day(getDate())-1),getDate())))
You can de-obfuscate it a lot by using DateSerial:
where
po_issue_date > getDate() And
po_issue_date < DateSerial(Year(getDate()), Month(getDate()) + 8, 0)
First: there is no getDate() function in Access. Probably it should be Date() which returns the current date.
Now starting from the inner expression:
Day(Date()) returns the current day as an integer 1-31.
So in DateAdd("d", -(Day(Date())-1), Date()) from the current date are subtracted as many days as needed to return the 1st of the current month.
Then:
DateAdd("m", 8, DateAdd("d", -(Day(Date())-1), Date()))
adds 8 months to the the 1st of the current month returning the 1st of the month of the date after 8 months.
Finally:
DateAdd("d", -1,...)
subtracts 1 day from the date returned by the previous expression, returning the last day of the previous month of that date.
So if you run today 13-Sep-2019 this code, the result will be:
30-Apr-2020
because this is the last day of the previous month after 8 months.
I think the following:
Take the current date
Substract the current day of month -1 to get the first day of current month
Add 8 month to this
Substract 1 day to get the last day of the previous month
So it calculates some deadline in approx 8 months.
But I wonder how a PO issue date can be in the future...
I have a SQL query that prompts for a startdate and enddate, Between #startdate And #enddate. But what I am trying to do is have the same query automatically look 3 months forward from today's month using a dateadd / getdate code, but can not figure out how to integrate the two?
In sql-server, which I assume because you are referencing GETDATE() and DATEADD()
DATEADD(MONTH,3,GETDATE())
IN Oracle based on Why is the GETDATE() an invalid identifier, and Equivalent function for DATEADD() in Oracle
ADD_MONTHS(SYSDATE,3)
Based on your comment and if Siebel is on sql-server you would need
Where vwS_CoPrimPolicy.S_PrimPolicyExpDT Between #startdate And #enddate And vwS_Co.S_CoStatus = 'Customer' And vwS_Co.S_CoType = 'Automotive
to become
where vwS_CoPrimPolicy.S_PrimPolicyExpDT Between
DATEFROMPARTS(YEAR(DATEADD(MONTH,3,GETDATE())),MONTH(DATEADD(MONTH,3,GETDATE())),1)
AND DATEADD(DAY,-1,DATEFROMPARTS(YEAR(DATEADD(MONTH,4,GETDATE())),MONTH(DATEADD(MONTH,4,GETDATE())),1))
And vwS_Co.S_CoStatus = 'Customer' And vwS_Co.S_CoType = 'Automotive
To Break that down a little because you are actually looking for the start of the month 3 months from today to the end of the month 3 months from today and those months could be 28,29,30,or 31 days long you actually need to find the date 3 months ahead then get the beginning of the month DATEFROMPARTS() is useful for that. Then for the end of the month, find the date 4 months out and go back a day.
I have a date in sql which will always fall on a Monday and I'm subtracting 13 weeks to get a weekly report. I am trying to get the same 13 week report but for last year's figures as well.
At the moment, I'm using the following:
calendar_date >= TRUNC(sysdate) - 91
which is working fine.
I need the same for last year.
However, when I split this into calendar weeks, there will also be a partially complete week as it will include 1 or 2 days from the previous week. I need only whole weeks.
e.g. the dates that will be returned for last year will be 14-Feb-2015 to 16-May-2015. I need it to start on the Monday and be 16-Feb-2015. This will change each week as I am only interested in complete weeks...
I would do this:
Get the date by substracting 91 days as you're already doing.
Get the number of the day of the week with TO_CHAR(DATE,'d')
Add the number of days until the next monday to the date.
Something like this:
SELECT TO_DATE(TO_DATE('16/05/2015','DD/MM/YYYY'),'DD/MM/YYYY')-91 + MOD(7 - TO_NUMBER(TO_CHAR(TO_DATE(TO_DATE('16/05/2015','DD/MM/YYYY'),'DD/MM/RRRR')-91,'d'))+1,7) d
FROM dual
next_day - returns date of first weekday named by char.
with dates as (select to_date('16/05/2015','DD/MM/YYYY') d from dual)
select
trunc(next_day( trunc(d-91) - interval '1' second,'MONDAY'))
from dates;
I want to get next monday from calculated date. In situation when calculated date is monday i have to move back to previous week ( -1 second).
I need some help in writing an SQL in SQL Server where I need to count number of rows group by weeks. There is a tricky description of week which is following
- For any date before 08/13/2015 the week is of 7 days (i.e. from Thu through Wed)
- For date 08/13/2015 the week is consider a 9 day week (i.e. from Thursday through Friday so its between 08/13/2015 through 08/21/2015)
- For date 08/22/2015 the week is back to 7 days (i.e. Sat through Friday)
Now having said all the above the result I want to see in my report is the following way . NOTE: WE column in the below attached image is the last day of the week for the range.
Sample Result Image
Just write a case statement for the 3 different options. You can find the start day with something like this:
DATEADD(week, DATEDIFF(day, 3,getdate()) / 7, 3) -- Thursdays
DATEADD(week, DATEDIFF(day, 5,getdate()) / 7, 5) -- Saturdays
The numbers 3 and 5 come from the fact that day 0 (=1.1.1900) is Monday.
If you use this a lot, it might be a good idea to write a inline table valued function to return the dates you need.
I want to perform an operation in crystal report.
I have a db table contains a date column.
I want to filter and get the rows having data created in last week(last sunday to last saturday = 7 days).For example if today is 24th August Wednesday, then I need data from 14th August(Sunday) to 20th August(Saturday).
Basically I want to find 2 dates and filter the date column.
Date1 = Date(CurrentDate)-Day(7 + WeekDayinNum(CurrentDate)) ; (Ex:for my example it will be 10)
Date2 = Date(CurrentDate)-Day(WeekDayinNum(CurrentDate))
I do not know the Date APIs properly,can anybody help me in this.
This is a common enough date range that CR provides it for you. In your record selection formula, you can just add {table.date} in LastFullWeek
From CR, "LastFullWeek specifies a range of Date values that includes all dates from Sunday to Saturday of the previous week."
Add this to the record selection formula:
{table.date_field} IN Last7Days
If today is Sunday(1) you want rows that are between 7 and 1 days old,
If today is Monday(2) you want rows that are between 8 and 2 days old,
If today is Tuesday(3) you want rows that are between 9 and 3 days old,
etc.
SELECT *
FROM `tablename`
WHERE `somedatefield` >= DATE_SUB(NOW(),INTERVAL (DAYOFWEEK(NOW()) + 6) DAY)
AND `somedatefield` <= DATE_SUB(NOW(),INTERVAL (DAYOFWEEK(NOW())) DAY)