I'm new to SQL and am struggling with a case.
I would like to make the case where if an account (account_ID) doesn't have a record (ON billing_id) between current_date-302 and current_date-62 THEN MARK WITH A "1"
Query below:
Thanks in advance
SELECT
billing_date_local_time
,account_id
,contract_owner_name
,date_first_feature_partner
,deal_starts_at
,contract_id
,new_partner_type
,sum(voucher_sold) AS Vouchers
,sum(gross_bookings_local) AS GB
,sum(gross_revenue_local) AS GR
,is_G2
,Case when billing_date_local_time between current_date-302 and current_date-62 = 0 THEN 'YES' ELSE 'NO' End
FROM EMEA_ANALYTICS.eu_deal_flat
WHERE
country_id = 206
and billing_date_local_time between current_date-400
and current_date-2
GROUP BY 1,2,3,4,5,6,10,11
You'll need to do a correlated subquery; something like this:
select
a.billing_date_local_time
,a.account_id
,...
, CASE WHEN EXISTS (SELECT * FROM EMEA_ANALYTICS.eu_deal_flat b WHERE a.account_id = b.account_id AND b.billing_date_local_time between current_date-302 and current_date-62 ) THEN 'YES' ELSE 'NO' END
from
FROM EMEA_ANALYTICS.eu_deal_flat a
WHERE ...
You need to apply an aggregate function like this:
min(case when billing_date_local_time
between current_date-302 and current_date-62
then 0
else 1
end)
Related
I have a table named Bank that contains a Bank_Values column. I need a calculated Bank_Value_Unique column to shows whether each Bank_Value exists somewhere else in the table (i.e. whether its count is greater than 1).
I prepared this query, but it does not work. Could anyone help me with this and/or modify this query?
SELECT
CASE
WHEN NULLIF(LTRIM(RTRIM(Bank_Value)), '') =
(SELECT Bank_Value
FROM [Bank]
GROUP BY Bank_Value
HAVING COUNT(*) = 1)
THEN '0' ELSE '1'
END AS Bank_Key_Unique
FROM [Bank]
A windowed count should work:
SELECT
*,
CASE
COUNT(*) OVER (PARTITION BY Bank_Value)
WHEN 1 THEN 1 ELSE 0
END AS Bank_Value_Unique
FROM
Bank
;
It works also, but I found solution also:
select CASE WHEN NULLIF(LTRIM(RTRIM(Bank_Value)),'') =
(select Bank_Value
from Bank
group by Bank_Value
having (count(distinct Bank_Value) > 2 )) THEN '1' ELSE '0' END AS
Bank_Value_Uniquness
from Bank
It was missing "distinct" in having part.
I Have in table some records:
ID Services
2 A
2 C
2 C1
2 D2
I`m trying make query that will be select a link between services.
For example: If for ID 2 exists Services C then check if exist Service C1, result Yes or No.
SELECT a. ID, a.service,
CASE
WHEN (a.service ='C') = (a.service = 'C1') THEN 'Yes'
ELSE 'No'
END
FROM t1 a
Try this query:
SELECT *
FROM yourTable t1
WHERE NOT EXISTS (SELECT 1 FROM yourTable t2
WHERE (t2.Services LIKE t1.Services + '%' OR
t1.Services LIKE t2.Services + '%') AND
t1.ID = t2.ID AND t1.Services <> t2.Services);
This returns A and D2 only.
Demo
Hmm... what about this? But I now have problem with checking relationship for each ID independently...
SELECT a. ID, a.service,
CASE
WHEN a.service IN ('C','C1') THEN 'Yes'
ELSE 'No'
END
FROM t1 a
If I understand correctly, you can use aggregation:
SELECT ID,
(CASE WHEN SUM(CASE WHEN service = 'C' THEN 1 ELSE 0 END) > 0 AND
SUM(CASE WHEN service = 'C1' THEN 1 ELSE 0 END) > 0
THEN 'Yes' ELSE 'No'
END) as c_c1_flag
FROM t1
GROUP BY ID;
The SUM(CASE . . . ) counts the number of rows that match the conditions. The > 0 simply says that at least one row exists.
I have a 2 column table with the columns : "user_name" and "characteristic". Each user_name may appear multiple times with a different characteristic.
The values in characteristic are:
Online
Instore
Account
Email
I want to write a sql statement that goes like this - but obviously this isn't working:
SELECT user_name,
case
when characteristic in ("online","instore") then 1
else 0
END as purchase_yn,
case
when characteristic in ("online","instore") and
characteristic in ("email",'account') then 1
else 0
END as purchaser_with_account
FROM my_table
GROUP BY user_name;
Essentially the first is a flag where I check for the presence of either value for that user_name.
The Second field is that they meet this criteria AND that they meet the criteria for having either 'email' or 'account'
An example the structure of your data would help better understand what you are trying to accomplish. But I think I get what you are trying to do.
You have to use an aggregate function in order to use a group by.
Something like SUM or AVG.
But you need first to build a pivot of your data and then you could use that pivot to check for your criterias:
This would create a table pivot that shows for each record what criterias are met:
SELECT
user_name,
case when characteristic = "online" then 1 else 0 end as online_yn,
case when characteristic = "instore" then 1 else 0 end as instore_yn,
case when characteristic = "account" then 1 else 0 end as account_yn,
case when characteristic = "email" then 1 else 0 end as email_yn,
FROM my_table
Now what you might wanted to do is to create an averaged version of these entries grouped by user_name and use those averages to create the fields you wanted. For that you need to use the same statement created earlier as an inline table :
Select
user_name,
case when avg(online_yn + instore_yn) >= 1 then 1 else 0 end as purchase_yn,
case when avg(online_yn + instore_yn) >= 1 and avg(email_yn + account_yn) >= 1 then 1 else 0 end as purchaser_with_account
From
(SELECT
user_name,
case when characteristic = "online" then 1 else 0 end as online_yn,
case when characteristic = "instore" then 1 else 0 end as instore_yn,
case when characteristic = "account" then 1 else 0 end as account_yn,
case when characteristic = "email" then 1 else 0 end as email_yn,
FROM my_table) avg_table
group by
user_name;
This should help.
It may not be efficient in terms of performance but you'll get what you want.
You just have to enclose the CASE expressions in COUNT aggregates:
SELECT user_name,
COUNT(case when characteristic in ("online","instore") then 1 END) as purchase_yn,
COUNT(case when characteristic in ("email",'account') then 1 END) as user_with_account
FROM my_table
GROUP BY user_name
If purchase_yn > 0 then you first flag is set. If purchase_yn > 0 and user_with_account > 0 then you second flag is set as well.
Note: You have to remove ELSE 0 from the CASE expressions because COUNT takes into account all not null values.
You haven't mentioned a specific RDBMS, but if SUM(DISTINCT ...) is available the following is quite nice:
SELECT
username,
SUM(DISTINCT
CASE
WHEN characteristic in ('online','instore') THEN 1
ELSE 0
END) AS purchase_yn,
CASE WHEN (
SUM(DISTINCT
CASE
WHEN characteristic in ('online','instore') THEN 1
WHEN characteristic in ('email','account') THEN 2
ELSE 0 END
)
) = 3 THEN 1 ELSE 0 END as purchaser_with_account
FROM
my_table
GROUP BY
username
If I correctly understand, if user have 'online' or 'instore', then for this user you want 1 as purchase_yn column, and if user also have 'email' or 'account', then 1 as purchaser_with_account column.
If this is correct, then one way is:
with your_table(user_name, characteristic) as(
select 1, 'online' union all
select 1, 'instore' union all
select 1, 'account' union all
select 1, 'email' union all
select 2, 'account' union all
select 2, 'email' union all
select 3, 'online'
)
-- below is actual query:
select your_table.user_name, coalesce(max(t1.purchase_yn), 0) as purchase_yn, coalesce(max(t2.purchaser_with_account), 0) as purchaser_with_account
from your_table
left join (SELECT user_name, 1 as purchase_yn from your_table where characteristic in('online','instore') ) t1
on your_table.user_name = t1.user_name
left join (SELECT user_name, 1 as purchaser_with_account from your_table where characteristic in('email', 'account') ) t2
on t1.user_name = t2.user_name
group by your_table.user_name
I have a inventory table with a condition i.e. new, used, other, and i am query a small set of this data, and there is a possibility that all the record set contains only 1 or all the conditions. I tried using a case statement, but if one of the conditions isn't found nothing for that condition returned, and I need it to return 0
This is what I've tried so far:
select(
case
when new_used = 'N' then 'new'
when new_used = 'U' then 'used'
when new_used = 'O' then 'other'
end
)as conditions,
count(*) as count
from myDB
where something = something
group by(
case
when New_Used = 'N' then 'new'
when New_Used = 'U' then 'used'
when New_Used = 'O' then 'other'
end
)
This returns the data like:
conditions | count
------------------
new 10
used 45
I am trying to get the data to return like the following:
conditions | count
------------------
new | 10
used | 45
other | 0
Thanks in advance
;WITH constants(letter,word) AS
(
SELECT l,w FROM (VALUES('N','new'),('U','used'),('O','other')) AS x(l,w)
)
SELECT
conditions = c.word,
[count] = COUNT(x.new_used)
FROM constants AS c
LEFT OUTER JOIN dbo.myDB AS x
ON c.letter = x.new_used
AND something = something
GROUP BY c.word;
try this -
DECLARE #t TABLE (new_used CHAR(1))
INSERT INTO #t (new_used)
SELECT t = 'N'
UNION ALL
SELECT 'N'
UNION ALL
SELECT 'U'
SELECT conditions, ISNULL(r.cnt, 0) AS [count]
FROM (
VALUES('U', 'used'), ('N', 'new'), ('O', 'other')
) t(c, conditions)
LEFT JOIN (
SELECT new_used, COUNT(1) AS cnt
FROM #t
--WHERE something = something
GROUP BY new_used
) r ON r.new_used = t.c
in output -
new 2
used 1
other 0
You can do it as a cross-tab:
select
sum(case when new_used = 'N' then 1 else 0 end) as N,
sum(case when new_used = 'U' then 1 else 0 end) as U,
sum(case when new_used = 'O' then 1 else 0 end) as Other
from myDB
where something = something
I want to add some calculation inside my case statement to dynamically create the contents of a new column but I get the error:
Column 'Test1.qrank' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.
This is the code I'm working on
case
when test1.TotalType = 'Average' then Test2.avgscore
when test1.TotalType = 'PercentOfTot' then (cnt/SUM(test1.qrank))
else cnt
end as displayscore
I did try to group but it didn't work.
Any hints?
The error you posted can happen when you're using a clause in the GROUP BY statement without including it in the select.
Example
This one works!
SELECT t.device,
SUM(case when transits.direction = 1 then 1 else 0 end) ,
SUM(case when transits.direction = 0 then 1 else 0 end) from t1 t
where t.device in ('A','B') group by t.device
This one not (omitted t.device from the select)
SELECT
SUM(case when transits.direction = 1 then 1 else 0 end) ,
SUM(case when transits.direction = 0 then 1 else 0 end) from t1 t
where t.device in ('A','B') group by t.device
This will produce your error complaining that I'm grouping for something that is not included in the select
Please, provide all the query to get more support.
You could use a Common Table Expression to create the SUM first, join it to the table, and then use the WHEN to to get the value from the CTE or the original table as necessary.
WITH PercentageOfTotal (Id, Percentage)
AS
(
SELECT Id, (cnt / SUM(AreaId)) FROM dbo.MyTable GROUP BY Id
)
SELECT
CASE
WHEN o.TotalType = 'Average' THEN r.avgscore
WHEN o.TotalType = 'PercentOfTot' THEN pt.Percentage
ELSE o.cnt
END AS [displayscore]
FROM PercentageOfTotal pt
JOIN dbo.MyTable t ON pt.Id = t.Id
If you're using SQL Server 2005 or above, you can use the windowing function SUM() OVER ().
case
when test1.TotalType = 'Average' then Test2.avgscore
when test1.TotalType = 'PercentOfTot' then (cnt/SUM(test1.qrank) over ())
else cnt
end as displayscore
But it'll be better if you show your full query to get context of what you actually need.