xslt nested transformation : unable to transnform - xslt-1.0

Question

I am learning XSLT and trying to transform below xml. But couldn't achieve the task
<sample id="7">
<land1 id="8">
<owner>TOMMY</owner>
<type>INDIVIDUAL</type>
<hint>TOM_INDIVIDUAL</hint>
<date>12.02.2014</date>
<text>land details</text>
<number>1</number>
<cost>WIDERRUFLICH</cost>
</land1>
</sample>
and trying to convert above into
<table name="sample">
<tablename="land1">
<rel name="owner" value="TOMMY"/>
<rel name="type" value="INDIVIDUAL"/>
<rel name="<hint" value="TOM_INDIVIDUAL"/>
<rel name="date" value="12.02.2014"/>
<rel name="details" value="land details"/>
<rel name="number" value="1"/>
<rel name="cost" value="25%"/>
</table>
</table>
I tried below to generate the same, but it's not working.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<xsl:for-each select="*">
<xsl:if test="current().count(*)>0">
<xsl:element name="table">
<xsl:attribute name="name">
<xsl:value-of select="name(.)"/>
</xsl:attribute>
<xsl:apply-templates select="/"
</xsl:element>
</xsl:if>
<xsl:if test="current().count(*)=0">
<xsl:element name="rel">
<xsl:attribute name="name">
<xsl:value-of select="name(.)"/>
</xsl:attribute>
<xsl:attribute name="value">
<xsl:value-of select="current()"/>
</xsl:attribute>
</xsl:element>
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Can someone please let me know where I am doing wrong?

Answer 1

Can someone please let me know where I am doing wrong?
Well, for one thing, current().count(*)>0 is not a valid expression.
And you have <xsl:apply-templates select="/" without closing the tag. Which may be a good thing - because if it worked, it would have created an infinite loop.
I also don't understand the overall logic of your approach. Couldn't you do simply:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="*[*]">
<table name="{name()}">
<xsl:apply-templates/>
</table>
</xsl:template>
<xsl:template match="*">
<rel name="{name()}" value="{.}"/>
</xsl:template>
</xsl:stylesheet>
Added:
every element with an attribute should also be a table. For example,
in the above xml, <land1 id="8"> has children and your logic works
fine. But my inout can also contain <land1 id="8"/>. Now even though
it doesn't have any child elements, still element name has to be
considered as Table
Then use:
<xsl:template match="*[#*]">
instead of:
<xsl:template match="*[*]">