I am using the code below to convert decimal to hex.
intPatternColorsRed(1)=255 I get "FF" which is good
intPatternColorsRed(1)=0 I get "0" but I need "00"
Can I format the output to use a placeholder so I alway get a 2 digit return
'//Convert Dec to Hex
strData(0) = intPatternColorsRed(1).ToString("x")
strData(0) = intPatternColorsRed(1).ToString("X2")
ref: https://msdn.microsoft.com/en-us/library/dwhawy9k(v=vs.110).aspx
Related
Please explain why
select convert(int,'1') = 1
but
select convert(int,
convert(varbinary(MAX),'1')) = 49
Convert to varbinary without a style parameter defined translates each ASCII character in input string to a binary byte. That is why the input string '1' first gets mapped to the ASCII code 49, after which the outer convert returns the integer value 49.
Because convert(varbinary(MAX),'1') is binary 0x31 which is integer 49.
By using varbinary you are essentially converting the ascii representation of "1" to the actual binary digits which represent it.
You will get the same result using select ascii('1').
In the same way select convert(varbinary(1),'A') = 0x41 which in base 10 is 65, which is the ascii value for A
If negative number is from -31 to -1 then I would like represent it into the format 111XXXXX.
I try to do it using "and" bitwise operator:
println("0b00011111 & 0xe0 is ${0b00011111 and 0xe0}")
println("31 & 0xe0 is ${31 and 0xe0}")
println("0b00011111 & 0b11100000 is ${0b00011111 and 0b11100000}")
But the result is always 0. Where did I make the mistake?
It prints 0 because 00011111 and 11100000 always returns 0. The return type of and is Int, so if you want to print it in base 2 with leading zeroes, you have to format it.
To convert it to a String in base 2, you can call the toString method on Int with a radix parameter:
val numberString = (0b00011111 and 0b11100000).toString(2);
This will give you the number in binary format, but without leading zeroes. You need to left-pad with zeroes to get the format you want. I leave that task up to you (hint: padStart) ;)
I would like to format an integer 9 to "09" and 25 to "25".
How can this be done?
You can use either of these options:
The "0" Custom Specifier
value.ToString("00")
String.Format("{0:00}", value)
The Decimal ("D") Standard Format Specifier
value.ToString("D2")
String.Format("{0:D2}", value)
For more information:
Custom Numeric Format Strings
Standard Numeric Format Strings
If its just leading zero's that you want, you can use this:
value.tostring.padleft("0",2)
value.ToString().PadLeft(2, '0'); // C#
If you have 2 digits, say 25 for example, you will get "25" back....if you have just one digit, say 9 for example, you will get "09"....It is worth noting that this gives you a string back, and not an integer, so you may need to cast this later on in your code.
String formate is the best way to do that. It's will only add leading zero for a single length. 9 to "09" and 25 to "25".
String.format("%02d", value)
Bonus:
If you want to add multiple leading zero 9 to "0009" and 1000 to "1000". That's means you want a string for 4 indexes so the condition will be %04d.
String.format("%04d", value)
I don't know the exact syntax. But in any language, it would look like this.
a = 9
aString =""
if a < 10 then
aString="0" + a
else
aString = "" + a
end if
The title pretty much explains my issue. I need to convert a single string RGB value into a Hex value. I can do this if the value is given in three separate strings, but as the RGB is given from a color picker I'm unable to do this - unless I split the string which I don't want to do as I feel it's unnecessary.
I want to be able to convert a string such as: 0, 112, 192 into it's hexadecimal equivalent. Can I convert the entire string or do I have to split the string into its RGB parts first?
Since you can have varying numbers of decimal digits for the RGB value, you'll need to separate it before you convert it.
s1 = "0, 112, 192"
s2 = ""
For Each s As String In s1.Split(",")
s2 &= CInt(s).ToString("x2")
Next s
I am writing some code in Visual Basic.net and have a question.
If I have a long number, that is larger than 1000, how can I format this value to be 1,000 (with a comma) and for this to be stored in a string?
For e.g.
1234 will be stored as 1,234
12345 will be stored as 12,345
123456 will be stored as 123,456
Is this done with a TryParse statement?
May I have some help to so this?
Take a look at The Numeric ("N") Format Specifier
General use:
Dim dblValue As Double = -12445.6789
Console.WriteLine(dblValue.ToString("N", CultureInfo.InvariantCulture))
' Displays -12,445.68
If you are only using integers then the following:
Dim numberString As String = 1234.ToString("N0")
Will show numberString = "1,234" as the "N0" format will not add any figures after a decimal point.
For those wanting to do a currency with commas and decimals use the following: .ToString("$0,00.00")
Using $ notation:
int myvar = 12345;
Console.WriteLine($"Here is my number: {myvar:N0}");