How to Match a string against patterns in Oracle SQL - sql

Question

I have a bit of different scenario. there is one column (Oracle table) in the table which stores patterns.another column with unique id.
Now, i have to match those patterns against a string and have to find out which patterns are matching that string.then i have to pick out those matched patterns along with the ids
Can anybody guide me on how to efficiently do it?
Sample Data
Table 1
-------
Column1 Column2
1 AB%
2 A%
3 %c%
Now, there is a string comes like ABC (take it as an item number. It gets inserted in DB and then a trigger fires that has to do the rest of the job as provided in sample below)
Table 2
---------
Column1 Column2
ABC AB%,A%
or more efficient(desired) Table 2 would be like -
Table 2(desired)
---------
Column1 Column2
ABC 1,2
This is the desired result.

Answer 1

In Oracle 11g you could use function listagg
and simple before insert or update trigger:
Sample data:
create table table1 (column1 number(3), column2 varchar2(10));
insert into table1 values (1, 'AB%');
insert into table1 values (2, 'A%');
insert into table1 values (3, '%c%');
create table table2 (column1 varchar2(10), column2 varchar2(500));
Trigger:
create or replace trigger tg_table2_ins
before insert or update of column1 on table2 for each row
declare
v_list table2.column2%type;
begin
select listagg(t1.column1, ', ') within group (order by t1.column1)
into v_list from table1 t1
where :new.column1 like t1.column2;
:new.column2 := v_list;
end tg_table2_ins;
Test:
insert into table2 (column1) values ('ABC');
insert into table2 (column1) values ('Oracle');
insert into table2 (column1) values ('XYZ');
insert into table2 (column1) values ('Ascii');
select * from table2;
COLUMN1 COLUMN2
---------- ----------
ABC 1, 2
Oracle 3
XYZ
Ascii 2, 3