I have this select statement, where I want to show found and not-found in the result set ...
My query gives me only whatever (values) exists in the DB.
How to also add not-found.
Example:
5647994 1234 Data exist in table
5651061 8976 Data exist in table
5823683 null Data not exist in table
6115602 null Data not exist in table
SELECT *
FROM Carrier c
WHERE (SUBSTRING(c.SrcFileName, 14, 7) in (
'5647994',
'5651061',
'5823683',
'6115602',
'6125795',
'6140114',
'6144781',
'6155133')
Try this:
SELECT t1.val,
IF (t2.id IS NULL, 'NOT FOUND', 'FOUND'),
t2.*
FROM (
SELECT '5647994' AS val UNION ALL SELECT '5651061' UNION ALL
SELECT '5823683' UNION ALL SELECT '6115602' UNION ALL
SELECT '6125795' UNION ALL SELECT '6140114' UNION ALL
SELECT '6144781' UNION ALL SELECT '6155133') AS t1
LEFT JOIN Carrier AS t2 ON t1.val = SUBSTRING(t2.SrcFileName, 14, 7)
The idea is to create an in-line table that contains all to-be-searched values. If we LEFT JOIN the original table to this in-line table, then all values are returned.
The above query assumes that id is a field of Carrier table. Checking this field for NULL/NOT NULL values identifies not found / found values respectively.
Updated based upon additional information.
If(OBJECT_ID('tempdb..#TempSrcFileName') Is Not Null) Drop Table #TempSrcFileName
CREATE TABLE #TempSrcFileName
(
src_file_name nchar(7)
)
INSERT INTO #TempSrcFileName (src_file_name)
VALUES
('5647994')
, ('5651061')
, ('5823683')
, ('6115602')
, ('6125795')
, ('6140114')
, ('6144781')
, ('6155133')
;
SELECT
t.src_file_name
, 'Found' AS [Status]
FROM #TempSrcFileName t
LEFT JOIN Carrier c ON SUBSTRING(c.SrcFileName, 14, 7) = t.src_file_name
WHERE (SUBSTRING(c.SrcFileName, 14, 7) IS NOT NULL)
UNION SELECT
t.src_file_name
, 'Not Found' AS [Status]
FROM #TempSrcFileName t
LEFT JOIN Carrier c ON SUBSTRING(c.SrcFileName, 14, 7) = t.src_file_name
WHERE (SUBSTRING(c.SrcFileName, 14, 7) IS NULL)
Related
I have this query
select *
from dbo.EventLogs
where EntityID = 60181615
and EventTypeID in (1, 2, 3, 4, 5)
and NewValue = 'Received'
If 2 and 4 does not exist with NewValue 'Received' it shows this
current results
What I want
Ideally you should maintain somewhere a table containing all possible EventTypeID values. Sans that, we can use a CTE in place along with a left join:
WITH EventTypes AS (
SELECT 1 AS ID UNION ALL
SELECT 2 UNION ALL
SELECT 3 UNION ALL
SELECT 4 UNION ALL
SELECT 5
)
SELECT et.ID AS EventTypeId, el.*
FROM EventTypes et
LEFT JOIN dbo.EventLogs el
ON el.EntityID = 60181615 AND
el.NewValue = 'Received'
WHERE
et.ID IN (1,2,3,4,5);
I'm trying to group by a primary column and a secondary column. I want to ignore NULL in the secondary column unless it's the only value.
CREATE TABLE #tempx1 ( Id INT, [Foo] VARCHAR(10), OtherKeyId INT );
INSERT INTO #tempx1 ([Id],[Foo],[OtherKeyId]) VALUES
(1, 'A', NULL),
(2, 'B', NULL),
(3, 'B', 1),
(4, 'C', NULL),
(5, 'C', 1),
(6, 'C', 2);
I'm trying to get output like
Foo OtherKeyId
A NULL
B 1
C 1
C 2
This question is similar, but takes the MAX of the column I want, so it ignores other non-NULL values and won't work.
I tried to work out something based on this question, but I don't quite understand what that query does and can't get my output to work
-- Doesn't include Foo='A', creates duplicates for 'B' and 'C'
WITH cte AS (
SELECT *,
ROW_NUMBER() OVER (PARTITION BY [Foo] ORDER BY [OtherKeyId]) rn1
FROM #tempx1
)
SELECT c1.[Foo], c1.[OtherKeyId], c1.rn1
FROM cte c1
INNER JOIN cte c2 ON c2.[OtherKeyId] = c1.[OtherKeyId] AND c2.rn1 = c1.rn1
This is for a modern SQL Server: Microsoft SQL Server 2019
You can use a GROUP BY expression with HAVING clause like below one
SELECT [Foo],[OtherKeyId]
FROM #tempx1 t
GROUP BY [Foo],[OtherKeyId]
HAVING SUM(CASE WHEN [OtherKeyId] IS NULL THEN 0 END) IS NULL
OR ( SELECT COUNT(*) FROM #tempx1 WHERE [Foo] = t.[Foo] ) = 1
Demo
Hmmm . . . I think you want filtering:
select t.*
from #tempx1 t
where t.otherkeyid is not null or
not exists (select 1
from #tempx1 t2
where t2.foo = t.foo and t2.otherkeyid is not null
);
My actual problem is a bit more complicated than presented here, I ended up using the idea from Barbaros Özhan solution to count the number of items. This ends up with two inner queries on the data set with two different GROUP BY. I'm able to get the results I need on my real dataset using a query like the following:
SELECT
a.[Foo],
b.[OtherKeyId]
FROM (
SELECT
[Foo],
COUNT([OtherKeyId]) [C]
FROM #tempx1 t
GROUP BY [Foo]
) a
JOIN (
SELECT
[Foo],
[OtherKeyId]
FROM #tempx1 t
GROUP BY [Foo], [OtherKeyId]
) b ON b.[Foo] = a.[Foo]
WHERE
(b.[OtherKeyId] IS NULL AND a.[C] = 0)
OR (b.[OtherKeyId] IS NOT NULL AND a.[C] > 0)
My expected result should be like
----invoiceNo----
T17080003,INV14080011
But right now, I've come up with following query.
SELECT AccountDoc.jobCode,AccountDoc.shipmentSyskey,AccountDoc.docType,
CASE AccountDoc.docType
WHEN 'M' THEN
JobInvoice.invoiceNo
WHEN 'I' THEN
(STUFF((SELECT ', ' + RTRIM(CAST(AccountDoc.docNo AS VARCHAR(20)))
FROM AccountDoc LEFT OUTER JOIN JobInvoice
ON AccountDoc.principalCode = JobInvoice.principalCode AND
AccountDoc.jobCode = JobInvoice.jobCode
WHERE (AccountDoc.isCancelledByCN = 0)
AND (AccountDoc.docType = 'I')
AND (AccountDoc.jobCode = #jobCode)
AND (AccountDoc.shipmentSyskey = #shipmentSyskey)
AND (AccountDoc.principalCode = #principalCode) FOR XML
PATH(''), TYPE).value('.','NVARCHAR(MAX)'),1,2,' '))
END AS invoiceNo
FROM AccountDoc LEFT OUTER JOIN JobInvoice
ON JobInvoice.principalCode = AccountDoc.principalCode AND
JobInvoice.jobCode = AccountDoc.jobCode
WHERE (AccountDoc.jobCode = #jobCode)
AND (AccountDoc.isCancelledByCN = 0)
AND (AccountDoc.shipmentSyskey = #shipmentSyskey)
AND (AccountDoc.principalCode = #principalCode)
OUTPUT:
----invoiceNo----
T17080003
INV14080011
Explanation:
I want to select docNo from table AccountDoc if AccountDoc.docType = I.
Or select invoiceNo from table JobInvoice if AccountDoc.docType = M.
The problem is what if under same jobCode there have 2 docType which are M and I, how I gonna display these 2 invoices?
You can achieve this by using CTE and FOR XML. below is the sample code i created using similar tables you have -
Create table #AccountDoc (
id int ,
docType char(1),
docNo varchar(10)
)
Create table #JobInvoice (
id int ,
invoiceNo varchar(10)
)
insert into #AccountDoc
select 1 , 'M' ,'M1234'
union all select 2 , 'M' ,'M2345'
union all select 3 , 'M' ,'M3456'
union all select 4 , 'I' ,'I1234'
union all select 5 , 'I' ,'I2345'
union all select 6 , 'I' ,'I3456'
insert into #JobInvoice
select 1 , 'INV1234'
union all select 2 , 'INV2345'
union all select 3 , 'INV3456'
select *
from #AccountDoc t1 left join #JobInvoice t2
on t1.id = t2.id
with cte as
(
select isnull( case t1.docType WHEN 'M' THEN t2.invoiceNo WHEN 'I' then
t1.docNo end ,'') invoiceNo
from #AccountDoc t1 left join #JobInvoice t2
on t1.id = t2.id )
select invoiceNo + ',' from cte For XML PATH ('')
You need to pivot your data if you have situations where there are two rows, and you want two columns. Your sql is a bit messy, particularly the bit where you put an entire select statement inside a case when in the select part of another query. These two queries are virtually the same, you should look for a more optimal way of writing them. However, you can wrap your entire sql in the following:
select
Jobcode, shipmentsyskey, [M],[I]
from(
--YOUR ENTIRE SQL GOES HERE BETWEEN THESE BRACKETS. Do not alter anything else, just paste your entire sql here
) yoursql
pivot(
max(invoiceno)
for docType in([M],[I])
)pvt
I have a table for example Persons with person type(Private, Public, Government, Businessman, Jobless). Type can be null or Empty. I am saving type value in Person table with no Master Table. I want to select all grouped types with count by wheather the type exists or not.
I know it is a bit strange but the requirements are like this. Below are the scripts:
CREATE TABLE [Persons](
[ID] [int] IDENTITY(1,1) NOT NULL,
[FULLNAME] [varchar](50) NULL,
[TYPE] [varchar](10) NULL
) ON [PRIMARY]
INSERT INTO Persons(FULLNAME,[TYPE]) VALUES('ABD', 'Private');
INSERT INTO Persons(FULLNAME,[TYPE]) VALUES('DEF', 'Government');
INSERT INTO Persons(FULLNAME,[TYPE]) VALUES('DEF', 'Jobless');
The result should look like as follows:
TYPE COUNT
Private 1
Public 0
Government 1
Businessman 0
Jobless 1
You can create a Common Table Expression (CTE) of all the possible types using with clause and left join it with the persons table.
with types (type)
as (
select 'Private' from dual
union all
select 'Public' from dual
union all
select 'Government' from dual
union all
select 'Businessman' from dual
union all
select 'Jobless' from dual
)
select t.type,
count(p.type) "COUNT"
from types t
left outer join Persons p on t.type = p.type
group by t.type;
In case you use MS Sql Server not Oracle (as syntax of your DDLs suggest):
select all_types.type, count(distinct persons.id) from (
select 'Private' as type union all
select 'Public' union all
select 'Government' union all
select 'Businessman' union all
select 'Jobless'
) all_types left outer join Persons on (all_types.type=persons.type)
group by all_types.type;
Suppose I have a list of values, such as 1, 2, 3, 4, 5 and a table where some of those values exist in some column. Here is an example:
id name
1 Alice
3 Cindy
5 Elmore
6 Felix
I want to create a SELECT statement that will include all of the values from my list as well as the information from those rows that match the values, i.e., perform a LEFT OUTER JOIN between my list and the table, so the result would be like follows:
id name
1 Alice
2 (null)
3 Cindy
4 (null)
5 Elmore
How do I do that without creating a temp table or using multiple UNION operators?
If in Microsoft SQL Server 2008 or later, then you can use Table Value Constructor
Select v.valueId, m.name
From (values (1), (2), (3), (4), (5)) v(valueId)
left Join otherTable m
on m.id = v.valueId
Postgres also has this construction VALUES Lists:
SELECT * FROM (VALUES (1, 'one'), (2, 'two'), (3, 'three')) AS t (num,letter)
Also note the possible Common Table Expression syntax which can be handy to make joins:
WITH my_values(num, str) AS (
VALUES (1, 'one'), (2, 'two'), (3, 'three')
)
SELECT num, txt FROM my_values
With Oracle it's possible, though heavier From ASK TOM:
with id_list as (
select 10 id from dual union all
select 20 id from dual union all
select 25 id from dual union all
select 70 id from dual union all
select 90 id from dual
)
select * from id_list;
the following solution for oracle is adopted from this source. the basic idea is to exploit oracle's hierarchical queries. you have to specify a maximum length of the list (100 in the sample query below).
select d.lstid
, t.name
from (
select substr(
csv
, instr(csv,',',1,lev) + 1
, instr(csv,',',1,lev+1 )-instr(csv,',',1,lev)-1
) lstid
from (select ','||'1,2,3,4,5'||',' csv from dual)
, (select level lev from dual connect by level <= 100)
where lev <= length(csv)-length(replace(csv,','))-1
) d
left join test t on ( d.lstid = t.id )
;
check out this sql fiddle to see it work.
Bit late on this, but for Oracle you could do something like this to get a table of values:
SELECT rownum + 5 /*start*/ - 1 as myval
FROM dual
CONNECT BY LEVEL <= 100 /*end*/ - 5 /*start*/ + 1
... And then join that to your table:
SELECT *
FROM
(SELECT rownum + 1 /*start*/ - 1 myval
FROM dual
CONNECT BY LEVEL <= 5 /*end*/ - 1 /*start*/ + 1) mypseudotable
left outer join myothertable
on mypseudotable.myval = myothertable.correspondingval
Assuming myTable is the name of your table, following code should work.
;with x as
(
select top (select max(id) from [myTable]) number from [master]..spt_values
),
y as
(select row_number() over (order by x.number) as id
from x)
select y.id, t.name
from y left join myTable as t
on y.id = t.id;
Caution: This is SQL Server implementation.
fiddle
For getting sequential numbers as required for part of output (This method eliminates values to type for n numbers):
declare #site as int
set #site = 1
while #site<=200
begin
insert into ##table
values (#site)
set #site=#site+1
end
Final output[post above step]:
select * from ##table
select v.id,m.name from ##table as v
left outer join [source_table] m
on m.id=v.id
Suppose your table that has values 1,2,3,4,5 is named list_of_values, and suppose the table that contain some values but has the name column as some_values, you can do:
SELECT B.id,A.name
FROM [list_of_values] AS B
LEFT JOIN [some_values] AS A
ON B.ID = A.ID