MSSQL query range for a day over a month - sql

I am trying to retrieve the range for the value field over each 24hr period over a predefined time period. The issue is that the time period is between 7am and 7am the next day. (not a daily figure)
For example, I would like the range for day 1, then range for day 2, etc. I've tried using the below query but the production field keeps coming back with the same data, could anyone please shed some light on how I can make this work?
Thank you very much.
select tagname, convert(date,datetime),
(
select (max(Value)-min(Value)) as Range
from Runtime.dbo.AnalogHistory
where (TagName = 'LS_CV004_WX1_PROD_DATA.Actual_Input')
and DateTime BETWEEN dateadd(hh,7,convert(datetime,convert(date,datetime))) AND dateadd(hh,31,convert(datetime,convert(date,datetime)))
) as Production
from runtime.dbo.analoghistory
where (TagName = 'LS_CV004_WX1_PROD_DATA.Actual_Input')
and datetime between '20151101' and '20151201'
group by tagname, convert(date,DateTime)
I would like to result to be as per below
tagname | date | production

Below is one method that uses CTEs to generate a row for each date in the specified range, and then joins to the table on the date plus a 7 hour offset. Consider creating a utility calendar table for this type of task.
DECLARE
#StartDate date = '20151101'
, #EndDate date = '20151201';
WITH
t8 AS (SELECT n FROM (VALUES(0),(0),(0),(0),(0),(0),(0),(0)) t(n))
, t512 AS (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 0)) - 1 AS num FROM t8 AS a CROSS JOIN t8 AS b CROSS JOIN t8 AS c)
, dates AS (SELECT DATEADD(day, num, #StartDate) AS Date FROM t512 WHERE num <= DATEDIFF(day, #StartDate, #EndDate))
SELECT TagName, Date, MAX(Value)-MIN(Value) as Production
FROM dates
JOIN dbo.AnalogHistory ON
AnalogHistory.DateTime >= DATEADD(hour, 7, Date)
AND AnalogHistory.DateTime < DATEADD(hour, 31, Date)
GROUP BY TagName, Date
ORDER BY TagName, Date;

Your subquery is not correlated to the outer query, so it is no surprise that it returns the same value. I think you want something like this:
select tagname, convert(date, datetime),
(select (max(ah2.Value) - min(ah2.Value)) as Range
from Runtime.dbo.AnalogHistory ah2
where ah2.TagName = 'LS_CV004_WX1_PROD_DATA.Actual_Input' and
ah2.DateTime BETWEEN dateadd(hour, 7, convert(datetime, convert(date, ah.datetime))) AND
dateadd(hour, 31, convert(datetime, convert(date, ah.datetime)))
) as Production
from runtime.dbo.analoghistory ah
where TagName = 'LS_CV004_WX1_PROD_DATA.Actual_Input' and
datetime between '20151101' and '20151201'
group by tagname, convert(date, DateTime);
Note the use of ah2 and ah in the subquery.

Related

How to subtract an offset to dates generated through a recursive CTE?

The query below uses a recursive CTE to generate days if there is no data for that specific day. I want to group the daily downtime total starting at 7:15 the previous day until 7:15 the next day and do it over a month. This query works fine but I need to subtract DATEADD(minute, -(7 * 60 + 15) from each day.
WITH dates as (
SELECT CONVERT(date, 'Anydate') as dte
UNION ALL
SELECT DATEADD(day, 1, dte)
FROM dates
WHERE dte < 'Anydate + 1 month later'
)
SELECT CONVERT(datetime,d.dte), ISNULL(SUM(long_stop_minutes), 0) AS downtime
FROM dates d LEFT JOIN
long_stops_table b
ON CAST(t_stamp as DATE) = d.dte AND Type = 'downtime'
GROUP BY CONVERT(datetime, d.dte)
ORDER BY CONVERT(datetime, d.dte) ASC;
Just subtract the appropriate time units. Here is one way:
SELECT d.dte,
COALESCE(SUM(lst.long_stop_minutes), 0) AS downtime
FROM dates d LEFT JOIN
long_stops_table lst
ON CONVERT(date, DATEADD(minute, -(7 * 60 + 15), lst.t_stamp) = d.dte AND
lst.Type = 'downtime'
GROUP BY d.dte
ORDER BY d.dte ASC;
I see no reason to convert dates.dte to a datetime, so I just removed the conversion.

SQL Server, filter for max date and max date minus 7 days

I'm trying to design a view and apply several conditions on my timestamp (datetime): last date and last date minus 7 days.
This works fine for the last date:
SELECT *
FROM table
WHERE timestamp = (SELECT MAX(timestamp) FROM table)
I couldn't figure out the way to add minus 7 days so far.
I tried, for instance
SELECT *
FROM table
WHERE (timestamp = (SELECT MAX(timestamp) FROM table)) OR (timestamp = (SELECT DATEADD(DAY, -7, MAX(timestamp)) FROM table)
and some other variations, including GETDATE() instead of MAX, however, I'm getting the execution timeout messages.
Please let me know what logic should I follow in this case.
Data looks like this, but there's more of it :)
So I want to get data only for rows with 29/11/2019 and 22/11/2019. I have an additional requirement for filtering for factors, but it's a simple one.
If you care about dates, then perhaps you want:
select t.*
from t cross join
(select max(timestamp) as max_timestamp from t) tt
where (t.timestamp >= convert(date, max_timestamp) and
t.timestamp < dateadd(day, 1, convert(date, max_timestamp))
) or
(t.timestamp >= dateadd(day, -7, convert(date, max_timestamp)) and
t.timestamp < dateadd(day, -6, convert(date, max_timestamp))
);
So I ended up with the next code:
SELECT *
FROM table
WHERE (timestamp >= CAST(DATEADD(DAY, - 1, GETDATE()) AS datetime)) AND (timestamp < CAST(GETDATE() AS DATETIME)) OR
(timestamp >= CAST(DATEADD(DAY, - 8, GETDATE()) AS datetime)) AND (timestamp < CAST(DATEADD(day, - 7, GETDATE()) AS DATETIME)) AND (Factor1 = 'Criteria1' OR
Factor2 = 'Criteria2')
Not sure if it's the best or the most elegant solution, but it works for me.

How to select data's from this today,week and month sperately?

I have a problem that is I am unable to resolve as of now.
I need to get the data of
this day, this week and this month
I have a table reminder where I want to select reminders according to
following parameters.
1. Today
2. This Week
3. This Month
The column rdate having the date format in dd-mm-yyyy which is stored as nvarchar
For example
If I execute this weeks query I should get data starting from this week i.e.
If it is Friday I should get data from starting from Sunday to Saturday of that week
How can I get the data as mentioned above. I have searched a lot on internet but I didn't get the solution?
This is the query I have been trying
SELECT
*
FROM
reminder
WHERE
date > DATE_SUB(GETDATE(), INTERVAL 1 DAY)
ORDER BY
rdate DESC;
Where I'm converting nvarchar to date format.
If it's not possible to change the [date] column's data type to DATE, then you will incur a massive performance penalty when trying to filter by date.
Add computed column to table
We can add a computed column that will store the date in the correct format, and then index it for quick searchiing:
ALTER TABLE reminder
ADD Date_Value AS (CONVERT(DATE, '12-05-2016', 105)) PERSISTED;
-- This should yield superior performance
CREATE NONCLUSTERED INDEX IX_Date_Value ON reminder (Date_Value);
Table-valued function to calculate date range
Now, let's create an inline table-valued function to generate the date range for specific period types:
CREATE FUNCTION [dbo].[tvfn_Get_Date_Range](
#Period_Type VARCHAR(100)
)
RETURNS
TABLE
AS RETURN
(
WITH date_range AS(
SELECT CAST(GETDATE() AS DATE) d
-- This line works correctly if your week starts on Sunday
,CAST(DATEADD(WEEK, DATEDIFF(WEEK, '19050101', GETDATE()), '19050101') AS DATE) AS week_start
,CAST(DATEADD(DAY, - DAY(GETDATE()) + 1, GETDATE()) AS DATE) AS month_start
,CAST(DATEADD(MONTH, 1, DATEADD(DAY, - DAY(GETDATE()), GETDATE())) AS DATE) AS month_end
)
SELECT d AS From_Date
,d AS To_Date
FROM date_range
WHERE #Period_Type = 'DAY'
UNION ALL
SELECT week_start
,DATEADD(DAY, 7, week_start)
FROM date_range
WHERE #Period_Type = 'WEEK'
UNION ALL
SELECT month_start
,month_end
FROM date_range
WHERE #Period_Type = 'MONTH'
)
In the above function, week starts on Sunday. If you need this to be configurable, then take a look at the answer to SET DATEFIRST in FUNCTION.
Fast, simple querying now possible
You can now use the two together using a simple query:
SET #Range VARCHAR(100) = 'WEEK'
SELECT *
FROM reminder
CROSS APPLY [dbo].[tvfn_Get_Date_Range](#Range) dr
WHERE Date_Value BETWEEN dr.Date_From AND dr.Date_To
If you can't change the columns data type to Date (or DateTime), you must convert it to date in the query.
Here is one way to get the data for today, this week and this month:
Get records from today:
SELECT *
FROM reminder
WHERE CONVERT(Date, [date], 105) = CAST(GETDATE() as date)
ORDER BY rdate DESC;
Get records from this week:
SELECT *
FROM reminder
WHERE DATEPART(WEEK, CONVERT(Date, [date], 105)) = DATEPART(WEEK, GETDATE())
AND DATEPART(YEAR, CONVERT(Date, [date], 105)) = DATEPART(YEAR, GETDATE())
ORDER BY rdate DESC;
Get records from this Month:
SELECT *
FROM reminder
WHERE DATEPART(MONTH, CONVERT(Date, [date], 105)) = DATEPART(MONTH, GETDATE())
AND DATEPART(YEAR, CONVERT(Date, [date], 105)) = DATEPART(YEAR, GETDATE())
ORDER BY rdate DESC;
To my knowledge, SQL server internally deals with date format as MM/dd/yyyy.
Usually I prefer to save date as string in SQL table since it's easier for inserting and retrieving.
For example, suppose that the column rdate is defined as follows in your table reminder:
[rdate] nvarchar NULL
Then you can customize the select statement for a week as follows:
"Select R.* From reminder R Where CAST(R.rdate as datetime) between
'03/04/2011' AND '03/11/2011'"
And for 10 days as follows:
"Select R.* From reminder R Where CAST(R.rdate as datetime) between
'03/04/2011' AND '03/14/2011'"
And so on. If this is not what you want, please provide more details about your requirements.

SQL: Daily report for with user counts

I am trying to get the 30 days report of users, that will return date and total count of users as count created on that date and i did it with this query
Select count(*) As [Count] ,
(SELECT CONVERT(date, AddDate)) As [Date]
from Users
WHERE AddDate >= (SELECT DateAdd(month, -1, Convert(date, GetDate())))
Group By CONVERT(date, AddDate)
it give me only those dates on which any user is created, but i want to show all 30 days either if it has count 0.
Same Case i want to do with monthly report.
i am getting months in which users are created , now i want to change it to get last 12 months from this month and their total users count. For this i am using this query
Select count(*) As [Count] ,
(Select DATEPART( month , DateAdd( month , DATEPART(mm,AddDate) , -1 ) )) as Month
from Users
WHERE AddDate >= (SELECT DateAdd(YEAR, -1, Convert(date, GetDate())))
Group By DATEPART(mm,AddDate)
Using a Calendar CTE:
With NumberSequence ( Number ) as
(
Select 1 as Number
union all
Select Number + 1
from NumberSequence
where Number <= 30
)
, CalendarCTE as
(
select cast(dateadd(dd, -30 + Number,getdate()) as Date) as CalDate
from Numbersequence
)
select CalDate, count(U1.*) as CountUsers
from CalendarCTE
left join Users U1
on CalDate = convert(date, U1.AddDate)
group by CalDate
As I mentioned in comment, You need a Calendar table and Left Join
SELECT Count(u.adddate) AS [Count],
c.dates AS [Date]
FROM calendar_table C
LEFT JOIN users U
ON c.dates = CONVERT(DATE, adddate)
WHERE c.dates >= Dateadd(month, -1, CONVERT(DATE, Getdate()))
GROUP BY c.dates
To generate/create a calendar table or dates check out the below questions
How to generate a range of dates in SQL Server
Generate Dates between date ranges
How to create a Calender table for 100 years in Sql
Try this script :
WITH CTEDates
AS
(
SELECT CAST(GetDate() as date) AS [date]
UNION ALL
SELECT DATEADD(dd, 1, [date])
FROM CTEDates
WHERE DAY([date]) <= 30
)
Select count(*) As [Count] ,CONVERT(date, AddDate) As [Date]
from CTEDates
LEFT JOIN Users ON CTEDates.date=CONVERT(date, AddDate)
WHERE AddDate >= DateAdd(month, -1, GetDate())
Group By CONVERT(date, AddDate)
DECLARE #StartDate Datetime
DECLARE #EndDate Datetime
CREATE TABLE #tMyCalanderDate (dtDate Datetime Primary key)
SELECT #StartDate = '01-Sep-2016'
SELECT #EndDate = '30-Sep-2016'
WHILE #StartDate <= #EndDate
BEGIN
INSERT INTO #tMyCalanderDate (dtDate)
SELECT #StartDate
SELECT #StartDate = DATEADD(day,1,#StartDate)
END
SELECT count(A.UserID) As [Count] , B.dtDate As [Date]
FROM Users AS A
RIGHT JOIN #tMyCalanderDate AS B ON CONVERT(date, A.AddDate) = CONVERT(date, B.dtDate)
WHERE CONVERT(date, A.AddDate) BETWEEN #StartDate AND #EndDate
Group By CONVERT(date, B.dtDate)
You can use a CTE to get a thirty day calendar. Then left join your Users table to it.
DECLARE #CurrentTime DATETIME = GETDATE()
;WITH CTE AS
(
SELECT CONVERT(DATE, #CurrentTime) AS [Date]
UNION ALL
SELECT DATEADD(dd, -1, Date)
FROM CTE
WHERE DATEADD(dd, 29, Date) > #CurrentTime
)
SELECT COUNT(U.AddDate) AS [Count]
, CTE.[Date] AS [Date]
FROM CTE
LEFT JOIN users U
ON CTE.Date = CONVERT(Date, AddDate)
GROUP BY CTE.Date
You can use a similar CTE to get the twelve month calendar and use the same joins to get the count.
HTH.

SQL date question

I have a question. I have a SQL Server 2008 table with a field column. I have for example the Following dates:
1/1/2001
5/5/2004
8/5/2009
10/7/2011
5/5/2012
1/13/2014
Id like to be able to show all dates >= the current date (7/29/2011) as well as largest table date that is < current date. In this example, the result would be all dates >= 8/5/2009.
Can someone help guide me please??
select max(date) [date] from table where date < getdate()
union
select date from table where date >= getdate()
If I understand correctly, you want to include the date prior to the current date. GETDATE() will get the current date (with time). If you're alright with that, then this should work. Otherwise, you may have to parse out just the date from GETDATE()
SELECT TheDate
FROM DateTable
WHERE TheDate >= (SELECT MAX(TheDate) FROM DateTable WHERE TheDate < GETDATE())
This gets all dates greater than or equal to the most recent date before the current date.
I am not entirely sure I understand, but this looks like a BETWEEN the relevant dates. Or is there something more I am missing?
Assuming your table is called DateTable and your field is called TheDate, do it like this:
SELECT TheDate
FROM DateTable
WHERE TheDate >= DATEADD(d, -2, GETDATE())
Good luck!
It depends on the SQL server you're using. In postgres, for example, you need something like
SELECT fields FROM table WHERE date_field >= CURRENT_DATE - 1
But other SQL servers have different ways to specify "yesterday"
SELECT d1.*
FROM dates d1
LEFT JOIN dates d2 ON d1.Date < d2.Date AND d2.Date < GETDATE()
WHERE d2.Date IS NULL
Explanation:
Select every date for which there does not exist a date that is both earlier than today and later than the one being inspected.
Lots of guessing here based on loose narrative and unknown data types.
DECLARE #t TABLE(d DATE);
INSERT #t SELECT '20010101'
UNION ALL SELECT '20040505'
UNION ALL SELECT '20090805'
UNION ALL SELECT '20111007'
UNION ALL SELECT '20120505'
UNION ALL SELECT '20140113';
DECLARE #now DATE = SYSDATETIME();
WITH t AS
(
SELECT d, rn = ROW_NUMBER() OVER (ORDER BY d)
FROM #t
)
SELECT t.d
FROM t LEFT OUTER JOIN t AS x
ON t.rn = x.rn - 1
WHERE COALESCE(x.d, #now) >= #now
ORDER BY t.d;