I have a question. I have a SQL Server 2008 table with a field column. I have for example the Following dates:
1/1/2001
5/5/2004
8/5/2009
10/7/2011
5/5/2012
1/13/2014
Id like to be able to show all dates >= the current date (7/29/2011) as well as largest table date that is < current date. In this example, the result would be all dates >= 8/5/2009.
Can someone help guide me please??
select max(date) [date] from table where date < getdate()
union
select date from table where date >= getdate()
If I understand correctly, you want to include the date prior to the current date. GETDATE() will get the current date (with time). If you're alright with that, then this should work. Otherwise, you may have to parse out just the date from GETDATE()
SELECT TheDate
FROM DateTable
WHERE TheDate >= (SELECT MAX(TheDate) FROM DateTable WHERE TheDate < GETDATE())
This gets all dates greater than or equal to the most recent date before the current date.
I am not entirely sure I understand, but this looks like a BETWEEN the relevant dates. Or is there something more I am missing?
Assuming your table is called DateTable and your field is called TheDate, do it like this:
SELECT TheDate
FROM DateTable
WHERE TheDate >= DATEADD(d, -2, GETDATE())
Good luck!
It depends on the SQL server you're using. In postgres, for example, you need something like
SELECT fields FROM table WHERE date_field >= CURRENT_DATE - 1
But other SQL servers have different ways to specify "yesterday"
SELECT d1.*
FROM dates d1
LEFT JOIN dates d2 ON d1.Date < d2.Date AND d2.Date < GETDATE()
WHERE d2.Date IS NULL
Explanation:
Select every date for which there does not exist a date that is both earlier than today and later than the one being inspected.
Lots of guessing here based on loose narrative and unknown data types.
DECLARE #t TABLE(d DATE);
INSERT #t SELECT '20010101'
UNION ALL SELECT '20040505'
UNION ALL SELECT '20090805'
UNION ALL SELECT '20111007'
UNION ALL SELECT '20120505'
UNION ALL SELECT '20140113';
DECLARE #now DATE = SYSDATETIME();
WITH t AS
(
SELECT d, rn = ROW_NUMBER() OVER (ORDER BY d)
FROM #t
)
SELECT t.d
FROM t LEFT OUTER JOIN t AS x
ON t.rn = x.rn - 1
WHERE COALESCE(x.d, #now) >= #now
ORDER BY t.d;
Related
I have a table from which I want to select only records that have an entry for every month in the last 12 months from a rolling date. The format of the table is: Record#, Date, LocationName.
I know I can do a sub-query to get everything with dates between a start and end date. However, I need to ensure that the record has an entry for each of those months as opposed to just retrieving values if they fall between them.
I started off with
select Record#, Date from Table where datediff(mm,Date,getdate()) < 12 order by Record#
For a rolling date, I switched to:
select Record#, Date from Table where Date between start_date and end_date order by Record#
Anyone have any suggestions?
Using exists() with an aggregation query using the having clause with count(distinct ...) to make sure that 12 months of records exist for a given Record#
select
t.[Record#]
, t.Date
from tbl t
where t.Date >= #start_date
and t.Date <= #end_date
and exists (
select 1
from tbl i
where i.[Record#] = t.[Record#]
and i.Date >= #start_date
and i.Date <= #end_date
group by dateadd(month, datediff(month, 0, i.Date), 0)
having count(distinct dateadd(month, datediff(month, 0, i.Date), 0)) = 12
)
order by [Record#]
Date range query reference:
Bad habits to kick : mis-handling date / range queries - Aaron Bertrand
What do between and the devil have in common? - Aaron Bertrand
I have query:
SELECT name
FROM (
SELECT name FROM
Hist_answer
WHERE id_city='34324' AND datetime >= DATE_SUB(CURRENT_DATE, INTERVAL 1 MONTH)
UNION ALL
SELECT name FROM
Hist_internet
WHERE id_city='34324' AND datetime >= DATE_SUB(CURRENT_DATE, INTERVAL 1 MONTH)
) x
GROUP BY name ORDER BY name
But DATE_SUB is a MySQL function and I need function for MsSQL 2008
Tell me please how to select data from 30 days by using MsSQL 2008?
P.S.: Data type of datetime is smalldatetime
You should be using DATEADD is Sql server so if try this simple select you will see the affect
Select DATEADD(Month, -1, getdate())
Result
2013-04-20 14:08:07.177
in your case try this query
SELECT name
FROM (
SELECT name FROM
Hist_answer
WHERE id_city='34324' AND datetime >= DATEADD(month,-1,GETDATE())
UNION ALL
SELECT name FROM
Hist_internet
WHERE id_city='34324' AND datetime >= DATEADD(month,-1,GETDATE())
) x
GROUP BY name ORDER BY name
Try this : Using this you can select date by last 30 days,
SELECT DATEADD(DAY,-30,GETDATE())
For those who could not get DATEADD to work, try this instead: ( NOW( ) - INTERVAL 1 MONTH )
Short version for easy use:
SELECT *
FROM [TableName] t
WHERE t.[DateColumnName] >= DATEADD(month, -1, GETDATE())
DATEADD and GETDATE are available in SQL Server starting with 2008 version.
MSDN documentation: GETDATE and DATEADD.
I try to count record which is on current date and pass date from date column
DATE
'2013-03-04 00:00:00'
'2013-02-04 00:00:00'
'2013-02-04 00:00:00'
if today is '2013-03-04 00:00:00'
the result should be
CURRENT_DATE = 1
PASS_DATE = 2
I Don't know how to query it form one resource but different where condition
1st - date >= '2013-03-04 00:00:00'
2nd - date < '2013-03-04 00:00:00'
PLEASE HELP
I suggest using two sub-queries within a SELECT clause
select
(select count(*) from MyDates where DateValue < getdate()) as PastDate,
(select count(*) from MyDates where DateValue >= getdate()) as CurrentDate
You can replace getDate() with a date parameter or a hard-coded value such as '2013-03-04' if you wish.
One way to do it is to query for all dates and place 1\0 according to your condition
then just query again from the table an sum the columns.
SELECT sum([CURRENT_DATE]), sum([PASS_DATE])
FROM
(
SELECT
ID,
case when myDate >= getDate() then 1 else 0 end as [CURRENT_DATE],
case when myDate < getDate() then 1 else 0 end as [PASS_DATE]
FROM mytable
) as SourcTbl
Here is a SQL Fiddle http://sqlfiddle.com/#!3/e9c19/8
Is there a way to use the Now() function in SQL to select values with today's date?
I was under the impression Now() would contain the time as well as date, but today's date would have the time set to 00:00:00 and therefore this would never match?
OK, lets do this properly. Select dates matching today, using indexes if available, with all the different date/time types present.
The principle here is the same in each case. We grab rows where the date column is on or after the most recent midnight (today's date with time 00:00:00), and before the next midnight (tomorrow's date with time 00:00:00, but excluding anything with that exact value).
For pure date types, we can do a simple comparison with today's date.
To keep things nice and fast, we're explicitly avoiding doing any manipulation on the dates stored in the DB (the LHS of the where clause in all the examples below). This would potentially trigger a full table scan as the date would have to be computed for every comparison. (This behaviour appears to vary by DBMS, YMMV).
MS SQL Server: (SQL Fiddle | db<>fiddle)
First, using DATE
select * from dates
where dte = CAST(CURRENT_TIMESTAMP AS DATE)
;
Now with DATETIME:
select * from datetimes
where dtm >= CAST(CURRENT_TIMESTAMP AS DATE)
and dtm < DATEADD(DD, 1, CAST(CURRENT_TIMESTAMP AS DATE))
;
Lastly with DATETIME2:
select * from datetimes2
where dtm2 >= CAST(CURRENT_TIMESTAMP AS DATE)
and dtm2 < DATEADD(DD, 1, CAST(CURRENT_TIMESTAMP AS DATE))
;
MySQL: (SQL Fiddle | db<>fiddle)
Using DATE:
select * from dates
where dte = cast(now() as date)
;
Using DATETIME:
select * from datetimes
where dtm >= cast((now()) as date)
and dtm < cast((now() + interval 1 day) as date)
;
PostgreSQL: (SQL Fiddle | db<>fiddle)
Using DATE:
select * from dates
where dte = current_date
;
Using TIMESTAMP WITHOUT TIME ZONE:
select * from timestamps
where ts >= 'today'
and ts < 'tomorrow'
;
Oracle: (SQL Fiddle)
Using DATE:
select to_char(dte, 'YYYY-MM-DD HH24:MI:SS') dte
from dates
where dte >= trunc(current_date)
and dte < trunc(current_date) + 1
;
Using TIMESTAMP:
select to_char(ts, 'YYYY-MM-DD HH24:MI:SS') ts
from timestamps
where ts >= trunc(current_date)
and ts < trunc(current_date) + 1
;
SQLite: (SQL Fiddle)
Using date strings:
select * from dates
where dte = (select date('now'))
;
Using date and time strings:
select dtm from datetimes
where dtm >= datetime(date('now'))
and dtm < datetime(date('now', '+1 day'))
;
Using unix timestamps:
select datetime(dtm, 'unixepoch', 'localtime') from datetimes
where dtm >= strftime('%s', date('now'))
and dtm < strftime('%s', date('now', '+1 day'))
;
Backup of SQL Fiddle code
There is no native Now() function in SQL Server so you should use:
select GETDATE() --2012-05-01 10:14:13.403
you can get day, month and year separately by doing:
select DAY(getdate()) --1
select month(getdate()) --5
select year(getdate()) --2012
if you are on sql server 2008, there is the DATE date time which has only the date part, not the time:
select cast (GETDATE() as DATE) --2012-05-01
Not sure what your asking!
However
SELECT GETDATE()
Will get you the current date and time
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE()))
Will get you just the date with time set to 00:00:00
Just zero off the time element of the date. e.g.
SELECT DATEADD(dd, DATEDIFF(dd, 0, getdate()), 0)
I've used GetDate as that's an MSSQL function, as you've tagged, but Now() is probably MySQL or you're using the ODBC function call, still should work if you just replace one with the other.
Not sure exactly what you're trying to do, but it sounds like GETDATE() is what you're after. GETDATE() returns a datetime, but if you're not interested in the time component then you can cast to a date.
SELECT GETDATE()
SELECT CAST(GETDATE() AS DATE)
Building on the previous answers, please note an important point, you also need to manipulate your table column to ensure it does not contain the time fragment of the datetime datatype.
Below is a small sample script demonstrating the above:
select getdate()
--2012-05-01 12:06:51.413
select cast(getdate() as date)
--2012-05-01
--we're using sysobjects for the example
create table test (id int)
select * from sysobjects where cast(crdate as date) = cast(getdate() as date)
--resultset contains only objects created today
drop table test
I hope this helps.
EDIT:
Following #dwurf comment (thanks) about the effect the above example may have on performance, I would like to suggest the following instead.
We create a date range between today at midnight (start of day) and the last millisecond of the day (SQL server count up to .997, that's why I'm reducing 3 milliseconds). In this manner we avoid manipulating the left side and avoid the performance impact.
select getdate()
--2012-05-01 12:06:51.413
select dateadd(millisecond, -3, cast(cast(getdate()+1 as date) as datetime))
--2012-05-01 23:59:59.997
select cast(getdate() as date)
--2012-05-01
create table test (id int)
select * from sysobjects where crdate between cast(getdate() as date) and dateadd(millisecond, -3, cast(cast(getdate()+1 as date) as datetime))
--resultset contains only objects created today
drop table test
If you have a table with just a stored date (no time) and want to get those by "now", then you can do this:
SELECT * FROM tbl WHERE DATEDIFF(d, yourdate, GETDATE())=0
This results in rows which day difference is 0 (so today).
For me the query that is working, if I want to compare with DrawDate for example is:
CAST(DrawDate AS DATE) = CAST (GETDATE() as DATE)
This is comparing results with today's date.
or the whole query:
SELECT TOP (1000) *
FROM test
where DrawName != 'NULL' and CAST(DrawDate AS DATE) = CAST (GETDATE() as DATE)
order by id desc
You can try this sql code;
SELECT [column_1], [column_1], ...
FROM (your_table)
where date_format(record_date, '%e%c%Y') = date_format(now(), '%e%c%Y')
You can try:
WHERE created_date BETWEEN CURRENT_TIMESTAMP-180 AND CURRENT_TIMESTAMP
This worked for me:
SELECT * FROM table where date(column_date) = curdate()
I am looking for a good SQL Statement to select all rows from the previous day from one table. The table holds one datetime column. I am using SQL Server 2005.
get today no time:
SELECT dateadd(day,datediff(day,0,GETDATE()),0)
get yestersday no time:
SELECT dateadd(day,datediff(day,1,GETDATE()),0)
query for all of rows from only yesterday:
select
*
from yourTable
WHERE YourDate >= dateadd(day,datediff(day,1,GETDATE()),0)
AND YourDate < dateadd(day,datediff(day,0,GETDATE()),0)
To get the "today" value in SQL:
convert(date, GETDATE())
To get "yesterday":
DATEADD(day, -1, convert(date, GETDATE()))
To get "today minus X days": change the -1 into -X.
So for all yesterday's rows, you get:
select * from tablename
where date >= DATEADD(day, -1, convert(date, GETDATE()))
and date < convert(date, GETDATE())
It's seems the obvious answer was missing. To get all data from a table (Ttable) where the column (DatetimeColumn) is a datetime with a timestamp the following query can be used:
SELECT * FROM Ttable
WHERE DATEDIFF(day,Ttable.DatetimeColumn ,GETDATE()) = 1 -- yesterday
This can easily be changed to today, last month, last year, etc.
SELECT * from table_name where date_field = DATE_SUB(CURRENT_DATE(),INTERVAL 1 DAY);
Its a really old thread, but here is my take on it.
Rather than 2 different clauses, one greater than and less than. I use this below syntax for selecting records from A date. If you want a date range then previous answers are the way to go.
SELECT * FROM TABLE_NAME WHERE
DATEDIFF(DAY, DATEADD(DAY, X , CURRENT_TIMESTAMP), <column_name>) = 0
In the above case X will be -1 for yesterday's records
This should do it:
WHERE `date` = CURDATE() - INTERVAL 1 DAY
Can't test it right now, but:
select * from tablename where date >= dateadd(day, datediff(day, 1, getdate()), 0) and date < dateadd(day, datediff(day, 0, getdate()), 0)
In SQL Server do like this:
where cast(columnName as date) = cast(getdate() -1 as date)
You should cast both sides of the expression to date to avoid issues with time formatting.
If you need to control interval in more detail, then you should try something like:
declare #start datetime = cast(getdate() - 1 as date)
declare #end datetime = cast(getdate() - 1 as date)
set #end = dateadd(second, 86399, #end)
Another way to tell it "Yesterday"...
Select * from TABLE
where Day(DateField) = (Day(GetDate())-1)
and Month(DateField) = (Month(GetDate()))
and Year(DateField) = (Year(getdate()))
This conceivably won't work well on January 1, as well as the first day of every month. But on the fly it's effective.
Well, its easier to cast the datetime column to date and than compare.
SELECT * FROM TABLE_NAME WHERE cast(COLUMN_NAME as date) =
dateadd(day,0, convert(date, getdate(), 105))
A simple alternative
Select GETDATE() - 1
Change 1 to go back that many number of days
PS : This gives you timestamp accuracy.
This worked a charm:
SELECT * FROM mytable WHERE date(mydate) = DATE_SUB(CURDATE(), INTERVAL 1 DAY);
subdate(now(),1) will return yesterdays timestamp
The below code will select all rows with yesterday's timestamp
Select * FROM `login` WHERE `dattime` <= subdate(now(),1) AND `dattime` > subdate(now(),2)