separate number range from a file using awk - awk

Question

I have a file with 5 columns and I want to separate the columns using number range as a criteria: example:
chr1 2120987 2144159 NM_001282670 0.48106
chr1 2123333 2126214 NM_001256946 2.71647
chr1 4715104 4837854 NM_001042478 0
chr1 4715104 4843851 NM_018836 0
chr1 3728644 3773797 NM_014704 4.61425
chr1 3773830 3801993 NM_004402 4.39674
chr1 3773830 3801993 NM_001282669 0
chr1 6245079 6259679 NM_000983 75.1769
chr1 6304251 6305638 NM_001024598 0
chr1 6307405 6321035 NM_207370 0.273874
chr1 6161846 6240194 NM_015557 0.0149477
chr1 6266188 6281359 NM_207396 0
chr1 6281252 6296044 NM_012405 14.0752
I want to remove 0 from the list , then would like to sort out numbers between 0.01 and 0.27 and so on....
I am new to shell programming....can someone help with awk ?
Thanks.

Answer 1

As you are new to shell programming, you may not be aware of grep and sort which would be simpler for this job.
If you are hell-bent on awk as your tool of choice, please just disregard my answer.
I would do it like this:
grep -v '\s0$' file | sort -k 5,5 -g
chr1 6161846 6240194 NM_015557 0.0149477
chr1 6307405 6321035 NM_207370 0.273874
chr1 2120987 2144159 NM_001282670 0.48106
chr1 2123333 2126214 NM_001256946 2.71647
chr1 3773830 3801993 NM_004402 4.39674
chr1 3728644 3773797 NM_014704 4.61425
chr1 6281252 6296044 NM_012405 14.0752
chr1 6245079 6259679 NM_000983 75.1769
The grep with -v inverts the search and looks for lines not containing the sequence space followed by a zero followed by end of line. The sort sorts the data on column 5, and does a general numeric sort because of the -g.

Answer 2

If you are trying to select the rows in which $5 is non-zero and within a certain range, then indeed awk makes sense, and the following may be close to what you're after:
awk -v min=0.01 -v max=0.27 '
$5 == 0 { next }
min <= $5 && $5 <= max { print }'
Here, the call to awk has been parameterized to suggest how these few lines can be adapted for more general usage.