I have SQL table what looks like:
+----------+-----------+
| ID | Direction |
+----------+-----------+
| 1 | left |
| 1 | null |
| 2 | left |
| 2 | null |
| 3 | null |
| 4 | left |
| 4 | null |
| 5 | null |
+----------+-----------+
I want to show each value only once:
If there will be ID 1 with Direction null and left, then show only ID 1 with direction left.
If there will be ID 1 only with null value, show it with null value.
Use a common table expression (cte):
with cte as
(
Your huge select...
)
select *
from cte t1
where t1.Direction = 'left'
or not exists (select * from cte t2
where t2.kanbanid = t1.kanbanid
and t2.Direction = 'left')
I.e. if your select has Direction 'left' for a kanbanid, return that row. Also return that row if same kanbanid has no Direction 'left' at all.
Why wont below query work:
select id,max(dir)
from #temp
group by id
below is test data:
create table #temp
(
id int,
dir char(10)
)
insert into #temp
select 1,'left'
union all
select 1,null
union all
select 2,null
union all
select 3,'right'
union all
select 3,null
union all
select 3,null
select id,max(dir)
from #temp
group by id
aggregate functions will ignore null,below is the output:
select distinct *,
row_number() over (partition by id order by ,Direction )as row1 into #any_table
from #your_table_name
select * from #any_table
where row1 =1
Related
I have a table that looks like this:
ID | PARENT_ID
--------------
0 | NULL
1 | 0
2 | NULL
3 | 1
4 | 2
5 | 4
6 | 3
Being an SQL noob, I'm not sure if I can accomplish what I would like in a single command.
What I would like is to start at row 6, and recursively follow the "history", using the PARENT_ID column to reference the ID column.
The result (in my mind) should look something like:
6|3
3|1
1|0
0|NULL
I already tried something like this:
SELECT T1.ID
FROM Table T1, Table T2
WHERE T1.ID = 6
OR T1.PARENT_ID = T2.PARENT_ID;
but that just gave me a strange result.
With a recursive cte.
If you want to start from the maximum id:
with recursive cte (id, parent_id) as (
select t.*
from (
select *
from tablename
order by id desc
limit 1
) t
union all
select t.*
from tablename t inner join cte c
on t.id = c.parent_id
)
select * from cte
See the demo.
If you want to start specifically from id = 6:
with recursive cte (id, parent_id) as (
select *
from tablename
where id = 6
union all
select t.*
from tablename t inner join cte c
on t.id = c.parent_id
)
select * from cte;
See the demo.
Results:
| id | parent_id |
| --- | --------- |
| 6 | 3 |
| 3 | 1 |
| 1 | 0 |
| 0 | |
This is how the main order table looks :-
| Order_num | Collection_Num |
+--------------+----------------+
| 20143045585 | 123456 |
| 20143045585 | 789012 |
| 20143045585 | 456897 |
| 20143758257 | 546465 |
+--------------+----------------+
These are the collections:-
| tops | bottom |
+--------------+----------------+
| 353735 | 745758 |
| 123456 | 789012 |
| 456456 | 456897 |
| 323456 | 546465 |
+--------------+----------------+
Desired Output:-
| Order_num |
+--------------+
| 20143045585 |
Here Order number 20143045585 has both a top and a bottom from the same row in table number 2 (each row in 2nd table forms a particular combination called 'A Collection' i.e. 1 top and corresponding bottom ).
What I want to know -
All the order numbers which have a top and a corresponding bottom in 'Collection_num' column.
Can anyone help me with a SQL code for this ?
Let me know if any of this is unclear.
select Order_num
From table_1 as A
where exists
(select tops from table_2 as B where B.tops = A.Collection_num)
AND
(select bottom from table2 as B where B.bottom = A.Collection_num)
I am assuming you just have the first table of data and each order can only have the two relevant collections or less. Perhaps:
select T1.Order_Num
,T1.Collection_Num AS Tops
,T2.Collection_Num AS Bottom
from Table1 T1
inner join Table1 T2
on T1.Order_Num = T2.Order_Num
and T1.Collection_Num < T2.Collection_Num
order by T1.Order_Num
You can try using subquery
select distinct order_num from #yourorder where collection_num
in (select tops from #yourcollections)
and order_num in
( select order_num from #yourorder where collection_num in
(select bottom from #yourcollections) )
Pretty sure that something like this should work for you. I am just using the ctes here to create the test data so it can be queried.
with Orders (OrderNum, CollectionNum) as
(
select 20143045585, 123456 union all
select 20143045585, 789012 union all
select 20143045585, 456897 union all
select 20143758257, 546465
)
, Collections (CollectionID, tops, bottoms) as
(
select 1, 353735, 745758 union all
select 2, 123456, 789012 union all
select 3, 456456, 456897 union all
select 4, 323456, 546465
)
select o.OrderNum
, t.tops
, b.bottoms
from Orders o
join Collections t on t.tops = o.CollectionNum
join
(
select o.OrderNum
, b.bottoms
, b.CollectionID
from Orders o
join Collections b on b.bottoms = o.CollectionNum
) b on b.CollectionID = t.CollectionID
Here is the query that I used:
Select *
From (select A.Order_num, B.Coll_ID, B.Bottoms from Orders_table as A
Join Collections_Table as B
on A.Collection_num = B.Bottoms
) as C
join
(select K.Order_num, M.Coll_ID, M.Tops from Orders_table as K
Join Collections_Table as M
on A.Collection_num = B.Tops
) as D
on C.Orders_B = D.Orders_Num AND C.Coll_ID = D.Coll_ID
)
Sample Table:
Id |Acc_Code|Description |Balance | Acclevel| Acctype| Exttype|
--- -------- ----------------- |-------- |-------- | -------| -------|
1 |SA |Sales | 0.00 | 1 | SA | |
2 |CS |Cost of Sales | 0.00 | 1 | CS | |
3 |5000/001|Revenue | 94.34 | 2 | SA | |
4 |5000/090|Sales(Local) | 62.83 | 2 | SA | |
5 |7000/000|Manufacturing Acc |-250.80 | 2 | CS | MA |
6 |7000/200|Manufacturing Acc | 178.00 | 2 | CS | |
This is a sample data of a temporary table which would be used to be inserted into another temporary table that would calculate the data for Profit and Loss Statement (For Manufacturing related Accounts only).
In this case, the acc_code for Manufacturing accounts start from 7000/000 and separated/partitioned for each following Exttype.
Eg: We start from the exttype of MA and based on its acclevel (could be 2 or more) until the next exttype.
The idea is we get the manufacturing accounts by SELECT FROM tmp_acc_list WHERE acc_code BETWEEN #start_acc_code (7000/000 in this case) AND #end_acc_code (the data before the next exttype)
I don't know what the exttype is, I'm still learning the tables.
How do we create the #end_acc_code part out from this sample table?
So here is a all in one script.
I created Your table for test:
create table #tmp_acc_list(
Id numeric,
Acc_Code nvarchar(100),
Acclevel numeric,
Acctype nvarchar(100),
Exttype nvarchar(100));
GO
insert into #tmp_acc_list(Id, Acc_Code, Acclevel, Acctype, Exttype)
select 1 , 'SA', 1,'SA', null union all
select 2 , 'CS', 1,'CS', null union all
select 3 , '5000/001', 2,'SA', null union all
select 4 , '5000/090', 2,'SA', null union all
select 5 , '7000/000', 2,'CS', 'MA' union all
select 6 , '7000/200', 2,'CS', null
;
Then comes the query:
with OrderedTable as -- to order the table is Id is not an order
(
select
t.*, ROW_NUMBER() over (
order by id asc --use any ordering You need here
)
as RowNum
from
#tmp_acc_list as t
),
MarkedTable as -- mark with common number
(
select
t.*,
Max(case when t.Exttype is null then null else t.RowNum end)
over (order by t.RowNum) as GroupRownum
from OrderedTable as t
),
GroupedTable as -- add group Exttype
(
select
t.Id, t.Acc_Code, t.Acclevel, t.Acctype, t.Exttype,
max(t.Exttype) over (partition by t.GroupRownum) as GroupExttype
from MarkedTable as t
)
select * from GroupedTable where GroupExttype = 'MA'
Is this what You need?
select *
from
(
select Id, Acc_Code
from tmp_acc_list
where Acc_Code = '7000/000'
) s
cross join tmp_acc_list a
cross apply
(
select top 1 x.Id, x.Acc_Code
from tmp_acc_list x
where x.Id >= a.Id
and x.AccLevel = a.AccLevel
and x.Acctype = a.Acctype
and x.Exttype = ''
order by Id desc
) e
where a.Id between s.Id and e.Id
Raw Data
| ID | STATUS |
| 1 | A |
| 2 | A |
| 3 | B |
| 4 | B |
| 5 | B |
| 6 | A |
| 7 | A |
| 8 | A |
| 9 | C |
Result
| START | END |
| 1 | 2 |
| 6 | 8 |
Range of STATUS A
How to query ?
This should give you the correct ranges:
SELECT
STATUS,
MIN(ID),
max_id
FROM (
SELECT
t1.STATUS,
t1.ID,
COALESCE(MAX(t2.ID), t1.ID) max_id
FROM
yourtable t1 LEFT JOIN yourtable t2
ON t1.STATUS=t2.STATUS AND t1.ID<t2.ID
WHERE
NOT EXISTS (SELECT NULL
FROM yourtable t3
WHERE
t3.STATUS!=t1.STATUS
AND t3.ID>t1.ID AND t3.ID<t2.ID)
GROUP BY
t1.ID,
t1.STATUS
) s
WHERE
status = 'A'
GROUP BY
STATUS,
max_id
Please see fiddle here.
You are probably better off with a cursor-based solution or a client-side function.
However, if you were using Oracle - the following would work.
WITH LOWER_VALS AS
( -- All the Ids with no immediate predecessor
SELECT ROWNUM AS RN, STATUS, ID AS LOWER FROM
(
SELECT STATUS, ID
FROM RAWDATA RD1
WHERE RD1.ID -1 NOT IN
(SELECT ID FROM RAWDATA PRED_TABLE WHERE PRED_TABLE.STATUS = RD1.STATUS)
ORDER BY STATUS, ID
)
) ,
UPPER_VALS AS
( -- All the Ids with no immediate successor
SELECT ROWNUM AS RN, STATUS, ID AS UPPER FROM
(
SELECT STATUS, ID
FROM RAWDATA RD2
WHERE RD2.ID +1 NOT IN
(SELECT ID FROM RAWDATA SUCC_TABLE WHERE SUCC_TABLE.STATUS = RD2.STATUS)
ORDER BY STATUS, ID
)
)
SELECT
L.STATUS, L.LOWER, U.UPPER
FROM
LOWER_VALS L
JOIN UPPER_VALS U ON
U.RN = L.RN;
Results in the set
A 1 2
A 6 8
B 3 5
C 9 9
http://sqlfiddle.com/#!4/10184/2
There is not a lot to go on from what you put, but I think this might work. I am using T-SQL because I don't know what you are using?
SELECT
min(ID)
, max(ID)
FROM RawData
WHERE [Status] = 'A'
Following / copying computhomas's question, but adding some twists...
I have the following table in MSSQL2008
id | business_key | result | date
1 | 1 | 0 | 9
2 | 1 | 1 | 8
3 | 2 | 1 | 7
4 | 3 | n | 6
5 | 4 | 1 | 5
6 | 4 | 0 | 4
And now i want to group based on the business_key returning the complete entry with the newest date.
So my expected result is:
id | business_key | result | date
1 | 1 | 0 | 9
3 | 2 | 1 | 7
4 | 3 | n | 6
5 | 4 | 1 | 5
I also bet that there is a way to achieve that, i just can't find / see / think of it at the moment.
edit: sorry about this, I actually meant something else from original question I did. I felt like editing this might be better than accepting a solution and making another question. my original problem was that I am not filtering by id.
SELECT t.*
FROM
(
SELECT *, ROW_NUMBER() OVER
(
PARTITION BY [business_key]
ORDER BY [date] DESC
) AS [RowNum]
FROM yourTable
) AS t
WHERE t.[RowNum] = 1
SELECT
*
FROM
mytable
WHERE
ID IN (SELECT MAX(ID) FROM mytable GROUP BY business_key)
SELECT
MAX(T1.id) AS [id],
T1.business_key,
T1.result
FROM
dbo.My_Table T1
LEFT OUTER JOIN dbo.My_Table T2 ON
T2.business_key = T1.business_key AND
T2.id > T1.id
WHERE
T2.id IS NULL
GROUP BY T1.business_key,
T1.result
ORDER BY MAX(T1.id)
Edited based on clarifications
SELECT M1.*
FROM My_Table M1
INNER JOIN
(
SELECT [business_key], MAX([date]) as MaxDate
FROM My_Table
GROUP BY [business_key]
) M2 ON M1.business_key = M2.business_key AND M1.[date] = M2.MaxDate
ORDER BY M1.[id]
Assuming the combination of business_key & date is unique then....
Working example (3rd time is a charm):
declare #src as table(id int, business_key int,result int,[date] int)
insert into #src
SELECT 1,1,0,9
UNION SELECT 2,1,1,8
UNION SELECT 3,2,1,7
UNION SELECT 4,3,1,6
UNION SELECT 5,4,1,5
UNION SELECT 6,4,0,4
;with bkdate(business_key,[date])
AS
(
select business_key,MAX([date])
from #src
group by business_key
)
select src.* from #src src
inner join bkdate
ON src.[date] = bkdate.date
and src.business_key = bkdate.business_key
order by id
How about (edited after question change):
with latestdate as (
select business_key, maxdate=max(date)
from the_table
group by business_key
), latest as (
select ID = max(id)
from the_table
inner join latestdate
on the_table.business_key=latestdate.business_key
and the_table.date=latestdate.maxdate
group by the_table.business_key
)
select the_table.*
from the_table
inner join latest
on latest.id=the_table.id