SPARQL: extract the dbo class for each result - sparql

Question

I have a DBpedia request that give me a label, a Dpedia URI and the corresponding wikipedia link. I want to add a column to get the dbo class of each line. Can any one help me please?
PREFIX rdf:<http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
select distinct ?Nom ?resource ?url ?p
where {
?resource rdfs:label ?Nom.
?resource foaf:isPrimaryTopicOf ?url.
?resource rdf:type ?p
FILTER(regex(?p,"http://dbpedia.org/ontology/"))
FILTER ( langMatches( lang(?Nom), "EN" )).
?Nom <bif:contains> "Apple".
}

Answer 1

Firstly, if you have the solution, then you should post it as an answer and then mark it as accepted so that it is easier for others looking for the solution.
Secondly, I feel that the solution you came up would work but is not the right way to do it. For getting dbo: types, one should query for types that are owl:Class types.
This is how I would do it
PREFIX rdf:<http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX owl: <http://www.w3.org/2002/07/owl#>
select distinct ?Nom ?resource ?url ?p
where {
?resource rdfs:label ?Nom ;
foaf:isPrimaryTopicOf ?url ;
a ?p .
?p a owl:Class .
FILTER ( langMatches( lang(?Nom), "EN" )).
?Nom <bif:contains> "Apple".
} limit 100

Answer 2

Not sure what do you mean by:
get the dbo class of each line.
But if you mean to get all predicates related to each row, the following query may help. I limited them to English ones to see the results better.
PREFIX rdf:<http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX dbo: <http://dbpedia.org/ontology/>
select distinct ?Nom ?resource ?url ?p
where {
?resource rdfs:label ?Nom.
?resource ?p ?dbo.
?resource foaf:isPrimaryTopicOf ?url.
FILTER ( langMatches( lang(?Nom), "EN" )).
?Nom <bif:contains> "Apple".
FILTER langMatches( lang(?Nom), "en" )
}
limit 100