I want to search records between today's date and a specified month of this year. If i wanted to perform the same query next year without altering the query, then the month has to be based from sysdate I think? This is what I am trying to achieve anyway. Here is my query:
SELECT *
FROM details n
WHERE n.id (SELECT p.nhno
FROM patient p
WHERE p.fname = 'James'
AND p.surname = 'Gump'
AND p.nhno = n.nhno
AND n.daterecorded
BETWEEN '01-OCT-15' AND to_char(sysdate, 'dd-mon-yy'))
Thanks
What u are inferring above is not correct. U have given a date of '01-oct-15' and u want to run the same query without altering
the date for next year also. And what you think the result would be? U will be getting the records from '01-oct-15' to every year u run the query not a specific month in the same year!
As u said above, u seemed to need only records for a specified month of the same year but not the same '01-oct-15' for every year.
IF U NEED RECORDS BETWEEN 2 MONTHS(BEFORE) AND TODAY, USE BELOW QUERY,
SELECT *
FROM details n
WHERE EXISTS (SELECT p.nhno
FROM patient p
WHERE p.fname = 'James'
AND p.surname = 'Gump'
AND p.nhno = n.nhno
AND p.daterecorded BETWEEN ADD_MONTHS(SYSDATE, -2) AND TO_CHAR(SYSDATE, 'dd-mon-yy'));
IF U NEED RECORDS BETWEEN 2 MONTHS(AFTER) AND TODAY, REPLACE THE BETWEEN STATEMENT IN THE ABOVE QUERY WITH,
'BETWEEN ADD_MONTHS(SYSDATE, 2) AND TO_CHAR(SYSDATE, 'dd-mon-yy'))'
U can also alter this query in 'add_months' to the specified month u need.
Say, if u want records between 6 months(before) and present date,
'BETWEEN ADD_MONTHS(SYSDATE, -6) AND TO_CHAR(SYSDATE, 'dd-mon-yy'))'
U can run this query every year without any alterations.
This should do it. If not, get back to me.
Try this:
SELECT *
FROM details n
WHERE n.id (SELECT p.nhno
FROM patient p
WHERE p.fname = 'James'
AND p.surname = 'Gump'
AND p.nhno = n.nhno
AND n.daterecorded
BETWEEN TO_DATE('01-OCT-'||(SELECT EXTRACT(YEAR FROM SYSDATE) FROM DUAL),'DD-MON-YY')
AND TO_DATE(SYSDATE,'DD-MON-YY');
Related
I have the following query where I need to count weekdays and weekends for following months
SELECT
fname,
MONTH(eventDate),
SUM(IF(WEEKDAY(eventDate) < 5,1,0)) AS WeekdayCount,
SUM(IF(WEEKDAY(eventDate) >= 5,1,0)) AS WeekendCount
FROM eventcal AS e
LEFT JOIN users AS u ON e.primary = u.username
GROUP BY fname, MONTH(eventDate);
But I'm having a problem with timestamp and I'm getting this
(Postgrex.Error) ERROR 42883 (undefined_function) function weekday(timestamp without time zone) does not exist
since I have an event date which is a timestamp for inserted_at. It's not able to do query on that. What should I do?
does postgres doesn't have this function?
what can be an alternative to this in Postgres?
Use EXTRACT with the date part isodow. This returns a value of 1 to 7 for Monday through Sunday.
SELECT
u.fname,
MONTH(e.eventDate),
COUNT(*) FILTER (WHERE EXTRACT(idodow FROM e.eventDate) < 6) AS WeekdayCount,
COUNT(*) FILTER (WHERE EXTRACT(idodow FROM e.eventDate) IN (6, 7)) AS WeekendCount,
FROM users u
LEFT JOIN eventcal e ON e.primary = u.username
GROUP BY
u.fname,
MONTH(e.eventDate);
Note also that a left join from users to the eventcal table would seem to make the most sense here, not the reverse.
I've gotten myself stuck working in Oracle with SQL for the first time. In my library example, I need to make a query on my tables for a library member who has borrowed more than 5 books in some week during the past year. Here's my attempt:
SELECT
PN.F_NAME,
PN.L_NAME,
M.ENROLL_DATE,
COUNT(*) AS BORROWED_COUNT,
(SELECT
(BD.DATE_BORROWED + INTERVAL '7' DAY)
FROM DUAL, BORROW_DETAILS BD
GROUP BY BD.DATE_BORROWED + INTERVAL '7' DAY
HAVING COUNT(*) > 5
) AS VALID_INTERVALS
FROM PERSON_NAME PN, BORROW_DETAILS BD, HAS H, MEMBER M
WHERE
PN.PID = M.PID AND
M.PID = BD.PID AND
BD.BORROWID = H.BORROWID
GROUP BY PN.F_NAME, PN.L_NAME, M.ENROLL_DATE, DATEDIFF(DAY, BD.DATE_RETURNED, VALID_INTERVALS)
ORDER BY BORROWED_COUNT DESC;
As I'm sure you can tell, Im really struggling with the Dates in oracle. For some reason DATEDIFF wont work at all for me, and I cant find any way to evaluate the VALID_INTERVAL which should be another date...
Also apologies for the all caps.
DATEDIFF is not a valid function in Oracle; if you want the difference then subtract one date from another and you'll get a number representing the number of days (or fraction thereof) between the values.
If you want to count it for a week starting from Midnight Monday then you can TRUNCate the date to the start of the ISO week (which will be Midnight of the Monday of that week) and then group and count:
SELECT MAX( PN.F_NAME ) AS F_NAME,
MAX( PN.L_NAME ) AS L_NAME,
MAX( M.ENROLL_DATE ) AS ENROLL_DATE,
TRUNC( BD.DATE_BORROWED, 'IW' ) AS monday_of_iso_week,
COUNT(*) AS BORROWED_COUNT
FROM PERSON_NAME PN
INNER JOIN MEMBER M
ON ( PN.PID = M.PID )
INNER JOIN BORROW_DETAILS BD
ON ( M.PID = BD.PID )
GROUP BY
PN.PID,
TRUNC( BD.DATE_BORROWED, 'IW' )
HAVING COUNT(*) > 5
ORDER BY BORROWED_COUNT DESC;
db<>fiddle
You haven't given your table structures or any sample data so its difficult to test; but you don't appear to need to include the HAS table and I'm assuming there is a 1:1 relationship between person and member.
You also don't want to GROUP BY names as there could be two people with the same first and last name (who happened to enrol on the same date) and should use something that uniquely identifies the person (which I assume is PID).
Let's say I have an 'employees' table with employee start and end dates, like so:
employees
employee_id start_date end_date
53 '19901117' '99991231'
54 '19910208' '20010512'
55 '19910415' '20120130'
. . .
. . .
. . .
And let's say I want to get the monthly count of employees who were employed at the end of the month. So the resulting data set I'm after would look like:
month count of employees
'20150131' 120
'20150228' 118
'20150331' 122
. .
. .
. .
The best way I currently know how to do this is to create a "helper" table to join onto, such as:
helper_tbl
month
'20150131'
'20150228'
'20150331'
.
.
.
And then do a query like so:
SELECT t0b.month,
count(t0a.employee_id)
FROM employees t0a
JOIN helper_tbl t0b
ON t0b.month BETWEEN t0a.start_date AND t0a.end_date
GROUP BY t0b.month
However, this is somewhat annoying solution to me, because it means I'm having to create these little helper tables all the time and they clutter up my schema. I feel like other people must run into the same need for "helper" tables, but I'm guessing people have figured out a better way to go about this that isn't so manual. Or do you all really just keep creating "helper" tables like I do to get around these situations?
I understand this question is a bit open-ended up for stack overflow, so let me offer a more closed-ended version of the question which is, "Given just the 'employees' table, what would YOU do to get the resulting data set that I showed above?"
You can use a CTE to generate all the month values, either form a fixed starting point or based on the earliest date in your table:
with months (month) as (
select add_months(first_month, level - 1)
from (
select trunc(min(start_date), 'MM') as first_month from employees
)
connect by level <= ceil(months_between(sysdate, first_month))
)
select * from months;
With data that was an earliest start date of 1990-11-17 as in your example, that generates 333 rows:
MONTH
-------------------
1990-11-01 00:00:00
1990-12-01 00:00:00
1991-01-01 00:00:00
1991-02-01 00:00:00
1991-03-01 00:00:00
...
2018-06-01 00:00:00
2018-07-01 00:00:00
You can then use that in a query that joins to your table, something like:
with months (month) as (
select add_months(first_month, level - 1)
from (
select trunc(min(start_date), 'MM') as first_month from employees
)
connect by level <= ceil(months_between(sysdate, first_month))
)
select m.month, count(*) as employees
from months m
left join employees e
on e.start_date <= add_months(m.month, 1)
and (e.end_date is null or e.end_date >= add_months(m.month, 1))
group by m.month
order by m.month;
Presumably you wan to include people who are still employed, so you need to allow for the end date being null (unless you're using a magic end-date value for people who are still employed...)
With dates stored as string it's a bit more complicated but you can generate the month information in a similar way:
with months (month, start_date, end_date) as (
select add_months(first_month, level - 1),
to_char(add_months(first_month, level - 1), 'YYYYMMDD'),
to_char(last_day(add_months(first_month, level - 1)), 'YYYYMMDD')
from (
select trunc(min(to_date(start_date, 'YYYYMMDD')), 'MM') as first_month from employees
)
connect by level <= ceil(months_between(sysdate, first_month))
)
select m.month, m.start_date, m.end_date, count(*) as employees
from months m
left join employees e
on e.start_date <= m.end_date
and (e.end_date is null or e.end_date > m.end_date)
group by m.month, m.start_date, m.end_date
order by m.month;
Very lightly tested with a small amount of made-up data and both seem to work.
If you want to get the employees who were employed at the end of the month, then you can use the LAST_DAY function in the WHERE clause of the your query. Also, you can use that function in the GROUP BY clause of your query. So your query would be like below,
SELECT LAST_DAY(start_date), COUNT(1)
FROM employees
WHERE start_date = LAST_DAY(start_date)
GROUP BY LAST_DAY(start_date)
or if you just want to count employees employed per month then use below query,
SELECT LAST_DAY(start_date), COUNT(1)
FROM employees
GROUP BY LAST_DAY(start_date)
so the question is "Produce a list of those employees who have made bookings at the Sports Club more than 5 times in the last calendar year (this should be calculated and not hard coded). Order these by the number of bookings made."
what i am struggling with is being able to get todays year and then subtract 1 year aswell as showing ONLY one name of people appearing 5 times.
this is what i have so far, but it doesnt work.
SELECT DISTINCT
FIRSTNAME,SURNAME,DATEBOOKED,MEMBERSHIPTYPEID,BOOKINGID,MEMBER.MEMBERID
FROM MEMBERSHIP,MEMBER,BOOKING
WHERE MEMBER.MEMBERID = BOOKING.MEMBERID
AND MEMBERSHIP.MEMBERSHIPTYPEID = 3 AND BOOKING.DATEBOOKED = (SYSDATE,
'DD/MON/YY -1') AND FIRSTNAME IN (
SELECT FIRSTNAME
FROM MEMBER
GROUP BY FIRSTNAME,SURNAME
HAVING COUNT(FIRSTNAME) >= 5
)
ORDER BY MEMBER.MEMBERID;
EDR
tabele structures
What you need is this day last year. There are various different ways of calculating that. For instance,
add_months(sysdate, -12)
or
sysdate - interval '1' year
The subquery looks a bit whacky too. What you're after is the number of BOOKING records in the last year. So the subquery should drive off the BOOKING table, and the date filter should be there.
Finally, there is a missing join condition between MEMBER and MEMBERSHIP. That's probably why you think you need that distinct; fix the join and you'll get the result set you want and not a product. One advantage of the ANSI 92 explicit join syntax is that it stops us from missing joins.
Your query needs to be sorted by the number of bookings, so you need to count those and sort by the total. This means you don't actually need a subquery at all.
So your query should look something like:
SELECT MEMBER.MEMBERID
, MEMBER.FIRSTNAME
, MEMBER.SURNAME
, count(BOOKING.BOOKID) as no_of_bookings
FROM MEMBER
inner join MEMBERSHIP
on MEMBER.MEMBERID = MEMBERSHIP.MEMBERID
inner join BOOKING
on MEMBER.MEMBERID = BOOKING.MEMBERID
WHERE MEMBERSHIP.MEMBERSHIPTYPEID = 3
and BOOKING.DATEBOOKED >= add_months(trunc(sysdate), -12)
GROUP BY MEMBER.MEMBERID
, MEMBER.FIRSTNAME
, MEMBER.SURNAME
HAVING COUNT(*) >= 5
ORDER BY no_of_bookings desc;
Here is a SQL Fiddle demo for my query.
SELECT
FIRSTNAME,SURNAME,DATEBOOKED,MEMBERSHIPTYPEID,BOOKINGID,MEMBER.MEMBERID
FROM MEMBERSHIP,MEMBER,BOOKING
WHERE MEMBER.MEMBERID = BOOKING.MEMBERID
AND MEMBERSHIP.MEMBERSHIPTYPEID = 3 AND BOOKING.DATEBOOKED between (SYSDATE) and
(sysdate - interval '1' year)
AND FIRSTNAME IN (
SELECT distinct FIRSTNAME
FROM MEMBER
GROUP BY FIRSTNAME,SURNAME
HAVING COUNT(FIRSTNAME) >= 5
)
ORDER BY MEMBER.MEMBERID;
I think this answers the question:
SELECT m.FIRSTNAME, m.SURNAME, m.MEMBERID
FROM MEMBER m JOIN
BOOKING b
ON m.MEMBERID = b.MEMBERID JOIN
MEMBERSHIP ms
ON ms.MEMBERID = m.MEMBERID
WHERE ms.MEMBERSHIPTYPEID = 3 AND
B.DATEBOOKED >= SYSDATE - INTERVAL '1 YEAR'
GROUP BY m.FIRSTNAME, m.SURNAME, m.MEMBERID
HAVING COUNT(*) >= 5
ORDER BY COUNT(* DESC;
Table aliases make the query much easier to write and to read.
I have a SQL code that looks like this:
select cast(avg(age) as decimal(16,2)) as 'avg' From
(select distinct acct.Account, cast(Avg(year(getdate())- year(client_birth_date)) as decimal(16,2)) as 'Age'
from WF_PM_ACCT_DB DET
inner join WF_PM_ACCT_DET_DB ACCT
ON det.Account = acct.Account
where (acct_closing_date is null or acct_closing_date > '2017-01-01')
and Acct_Open_Date < '2017-01-01'
group by acct.Account
) x
Then basically what this give me is a simple one cell answer of the average age of accounts in the year Acct_Open_Date < '2017-01-01' . I am an ameture so i change the date everytime and run the query again and again to get the remaining year. Is there an easy way to say lets have all the years as column headings and just one row with the average account age in that year.
Please note that the account closing date being null means accounts never got close and i have to change it to less than the analysis year in order to get a true picture of the average account age that existed at that time
Any help is appreciated. Thanks.
You can run this for multiple dates by including them in a single derived table:
with dates as (
select cast('2017-01-01' as date) as yyyy union all
select cast('2016-01-01' as date)
)
select yyyy, cast(avg(age) as decimal(16,2)) as avg_age
From (select dates.yyyy, acct.Account,
cast(Avg(year(getdate())- year(client_birth_date)) as decimal(16,2)) as Age
from dates cross join
WF_PM_ACCT_DB DET inner join WF_PM_ACCT_DET_DB
ACCT
on det.Account = acct.Account
where (acct_closing_date is null or acct_closing_date > dates.yyyy) and
Acct_Open_Date < dates.yyyy
group by acct.Account, dates.yyyy
) x
group by yyyy
order by yyyy;