im a bit new to sql server, so hopefully this isnt something too convoluted. if i have a table with a bunch of data that shows different records that have been complete or not...
TABLE 1
ID CATEGORY COMPLETE
1 reports yes
2 reports no
3 processes no
4 processes yes
5 reports no
6 events yes
...what would be the best way of creating a new field that would show the percentage complete for every category?
TABLE 2
ID CATEGORY PERCENTAGE
1 events 100%
2 processes 50%
3 reports 33%
any help would be greatly appreciated, thank you.
group by category column and use conditional sum to get only complete = 'yes' cases in the numerator.
select category,
100 * 1.0 * sum(case when complete = 'yes' then 1 else 0 end)/count(*) as pct
from tablename
group by category
You can use windowed functions and PARTITION BY Category:
SELECT DISTINCT Category,
[percentage] = ROUND(100 * SUM(CASE complete WHEN 'yes' THEN 1.0 ELSE 0.0 END)
OVER (PARTITION BY Category)/
COUNT(*) OVER (PARTITION BY Category),0)
FROM #tab;
LiveDemo
With insert to second table:
SELECT DISTINCT
[id] = IDENTITY(INT, 1,1)
,category
,[percentage] = ROUND(100 * SUM(CASE complete WHEN 'yes' THEN 1.0 ELSE 0.0 END)
OVER (PARTITION BY CATEGORY)/
COUNT(*) OVER (PARTITION BY Category),0)
INTO #table2
FROM #tab
ORDER BY [percentage] DESC;
SELECT *
FROM #table2;
LiveDemo2
I think the simplest approach is to use avg():
select category,
avg(case when complete = 'yes' then 100.0 else 0 end) as pct
from tablename
group by category;
If you want this as a number with a percentage, you need a bit more string manipulation:
select category,
str(avg(case when complete = 'yes' then 100.0 else 0 end)) + '%' as pct
from tablename
group by category;
However, I would recommend keeping the value as a number.
Related
Below is the solution but I want to know other ways to accomplish the same results (preferably in PostgreSQL).
This is the DB
Question - How many customers have churned straight after their initial free trial? what percentage is this rounded to the
nearest whole number?
WITH ranking AS (
SELECT
s.customer_id,
s.plan_id,
p.plan_name,
ROW_NUMBER() OVER (
PARTITION BY s.customer_id
ORDER BY s.plan_id) AS plan_rank
FROM dbo.subscriptions s
JOIN dbo.plans p
ON s.plan_id = p.plan_id)
SELECT
COUNT(*) AS churn_count,
ROUND(100 * COUNT(*) / (
SELECT COUNT(DISTINCT customer_id)
FROM dbo.subscriptions),0) AS churn_percentage
FROM ranking
WHERE plan_id = 4 -- Filter to churn plan
AND plan_rank = 2
You can achieve the same results with a single aggregation on customer_id with a few CASE WHEN statements:
SELECT count(*) as total_customers
,count(case when total_subscriptions = 2
and includes_free = 1
and includes_churn = 1 then 1 end) as churn_count
,100 * count(case when total_subscriptions = 2
and includes_free = 1
and includes_churn = 1 then 1 end) / count(*) as target_percent
FROM (
SELECT customer_id
,count(*) as total_subscriptions
,max(case when plan_id = 0 then 1 else 0 end) as includes_free
,max(case when plan_id = 4 then 1 else 0 end) as includes_churn
FROM dbo.subscriptions
GROUP BY customer_id
) AS tbl
-- Remove any records for people who didnt use the free trial
-- or people who are still on the free trial
WHERE includes_free = 1 AND total_subscriptions > 1
The difference between our solutions are:
Yours doesn't specify that the customer actually had a free trial
Mine doesn't include customers who went from Free -> Churn -> (something else)
Depending on your requirements you might want to make further alterations/use a different approach.
Here is my sample data table:
ID
Status
1
New
1
Processed
2
New
2
Processed
3
New
3
Processed
4
Processed
5
New
What I am trying to solve here is calculate the conversion rate from Status 'New' to Status 'Processed'. From the dataset, only ID no.1,2 and 3 fulfilled the requirements of my problem, and ID no.4 and 5 do not have both stages. So by theory, the conversion rate should be 3/5 * 100% = 60%. How can I select the data in order to calculate the IDs that have both 'New' and 'Processed' status.
This is the code that I have tried but I know its wrong since it extracts all the IDs with no link between it.
SELECT 'Conversion rate from Assigned enquiry to In progess leads' as 'Name', round((a.processed / b.new),3) * 100 as 'Answer'
FROM
(
SELECT cast(count(ID)as float) as processed
from table1
WHERE STATUS_ID = 'Processed'
) as a
cross join
(
SELECT cast(count(ID)as float) as new
from table_1
WHERE STATUS_ID = 'NEW'
) as b
We can use conditional aggregation here:
WITH cte AS (
SELECT CASE WHEN COUNT(CASE WHEN Status = 'New' THEN 1 END) > 0 AND
COUNT(CASE WHEN Status = 'Processed' THEN 1 END) > 0
THEN 1 ELSE 0 END AS cnt
FROM yourTable
GROUP BY ID
)
SELECT 100.0 * SUM(cnt) / COUNT(*)
FROM cte;
I have a table with 3 columns, id, name and vote. They're populated with many registers. I need that return the register with the best balance of votes. The votes types are 'yes' and 'no'.
Yes -> Plus 1
No -> Minus 1
This column vote is a string column. I am using SQL SERVER.
Example:
It must return Ann for me
Use conditional Aggregation to tally the votes as Kannan suggests in his answer
If you really only want 1 record then you can do it like so:
SELECT TOP 1
name
,SUM(CASE WHEN vote = 'yes' THEN 1 ELSE -1 END) AS VoteTotal
FROM
#Table
GROUP BY
name
ORDER BY
VoteTotal DESC
This will not allow for ties but you can use this method which will rank the responses and give you results use RowNum to get only 1 result or RankNum to get ties.
;WITH cteVoteTotals AS (
SELECT
name
,SUM(CASE WHEN vote = 'yes' THEN 1 ELSE -1 END) AS VoteTotal
,ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY SUM(CASE WHEN vote = 'yes' THEN 1 ELSE -1 END) DESC) as RowNum
,DENSE_RANK() OVER (PARTITION BY 1 ORDER BY SUM(CASE WHEN vote = 'yes' THEN 1 ELSE -1 END) DESC) as RankNum
FROM
#Table
GROUP BY
name
)
SELECT name, VoteTotal
FROM
cteVoteTotals
WHERE
RowNum = 1
--RankNum = 1 --if you want with ties use this line instead
Here is the test data used and in the future do NOT just put an image of your test data spend the 2 minutes to make a temp table or a table variable so that people you are asking for help do not have to!
DECLARE #Table AS TABLE (id INT, name VARCHAR(25), vote VARCHAR(4))
INSERT INTO #Table (id, name, vote)
VALUES (1, 'John','no'),(2, 'John','no'),(3, 'John','yes')
,(4, 'Ann','no'),(5, 'Ann','yes'),(6, 'Ann','yes')
,(9, 'Marie','no'),(8, 'Marie','no'),(7, 'Marie','yes')
,(10, 'Matt','no'),(11, 'Matt','yes'),(12, 'Matt','yes')
Use this code,
;with cte as (
select id, name, case when vote = 'yes' then 1 else -1 end as votenum from register
) select name, sum(votenum) from cte group by name
You can get max or minimum based out of this..
This one gives the 'yes' rate for each person:
SELECT Name, SUM(CASE WHEN Vote = 'Yes' THEN 1 ELSE 0 END)/COUNT(*) AS Rate
FROM My_Table
GROUP BY Name
I think I need some guidance as to what is wrong in my query. I am trying to do
Watched_Gladiator=CASE WHEN FilmName IN (CASE WHEN FilmName LIKE '%Gladiator%' THEN 1 END) then OVER(PARTITION BY Cust_Nr) THEN 1 ELSE 0 END
Tried this one too:
Watched_Gladiator=CASE WHEN FilmName IN (CASE WHEN FilmName LIKE '%Gladiator%' THEN Filmnamne END) then OVER(PARTITION BY Cust_Nr) THEN 1 ELSE 0 END
The Error I am currently getting is this:
Incorrect syntax near the keyword 'OVER'.
This is basically how my data looks like
Cust_Nr Date FilmName Watched Gladiator
157649306 20150430 Gladiator 1
158470722 20150504 Nick Cave: 20,000 Days On Earth 0
158467945 20150504 Out Of The Furnace 0
158470531 20150504 FilmA 0
157649306 20150510 Gladiator 1
158470722 20150515 Gladiator 1
I want to create a column (1 or zero) that shows if the customer has watched Gladiator then 1 ELSE 0. How can I do that?
I created a test column trying with a simple LIKE '%Gladiator%' THEN 1 ELSE 0. The problem with this solution is that it will show 1(one) more than once if the customer has watched multiple times. I only need 1 or zero.
I feel I am really close to finding a solution. I am very new to using OVER() and CASE WHEN but enjoying the thrill:=)
So you're saying that:
SELECT Cust_Nr, Date, FilmName,
CASE WHEN FilmName LIKE '%Gladiator%' THEN 1 ELSE 0 END as WatchedGladiator
FROM YourTable
WHERE YourColumn = #somevalue
Doesn't work? Because according to the data you've given, it should.
EDIT:
Well based on Tim's comment, I would simply add this bit to the query.
SELECT Cust_Nr, Date, FilmName, WatchedGladiator
FROM
(
SELECT Cust_Nr, Date, FilmName,
CASE WHEN FilmName LIKE '%Gladiator%' THEN 1 ELSE 0 END as WatchedGladiator
FROM YourTable
WHERE YourColumn = #somevalue
) as wg
WHERE WatchedGladiator = 1
The following does what you want for all films:
select r.*,
(case when row_number() over (partition by filmname order by date) = 1
then 1 else 0
end) as IsWatchedFirstAndGladiator
from results r;
For just Gladiator:
select r.*,
(case when filmname = 'Gladiator' and row_number() over (partition by filmname order by date) = 1
then 1 else 0
end) as IsWatchedFirst
from results r;
So you want to group by customer and add a column if this customer watched a specific film?
You could do:
SELECT Cust_Nr, MAX(Watched_Gladiator)
FROM( SELECT Cust_Nr,
Watched_Gladiator = CASE WHEN EXISTS
(
SELECT 1 FROM CustomerFilm c2
WHERE c2.Cust_Nr = c1.Cust_Nr
AND c2.FilmName LIKE '%Gladiator%'
) THEN 1 ELSE 0 END
FROM CustomerFilm c1 ) X
GROUP BY Cust_Nr
Demo
But it would be easier if you used the customer-table instead of this table, then you don't need the group-by.
Try grouping up to the cust/film level:
select
cust_nbr,
case when film_name like '%Gladiator%' then 1 else 0 end
from
(
select
cust_nbr,
film_name
from
<your table>
group by
cust_nbr,
film_name
) t
Or, as an alternative:
select distinct cust_nbr
from
<your table>
where
filmname = 'Gladiator'
I'm not an expert in SQL by any means, and am having a hard time getting the data I need from a query. I'm working with a single table, Journal_Entry, that has a number of columns. One column is Status_ID, which is a foreign key to a Status table with three values "Green", "Yellow", and "Red". Also, a journal entry is logged against a particular User (User_ID).
I'm trying to get the number of journal entries logged for each Status, as a percentage of the total number of journal entries logged by a particular user. So far I've got the following for a Status of 1, which is green (and I know this doesn't work):
SELECT CAST((SELECT COUNT(Journal_Entry_ID)
FROM Journal_Entry
WHERE Status_ID = 1 AND User_ID = 3 /
SELECT COUNT(Journal_Entry_ID)
FROM Journal_Entry AND User_ID = 3)) AS FLOAT * 100
I need to continue the query for the other two status ID's, 2 and 3, and ideally would like to end with the selection of three columns as percentages, one for each Status: "Green_Percent", "Yellow_Percent", and "Red_Percent".
This is probably the most disjointed question I've ever asked, so I apologize for any lack of clarity. I'll be happy to clarify as necessary. Also, I'm using SQL Server 2005.
Thanks very much.
Use:
SELECT je.statusid,
COUNT(*) AS num,
(COUNT(*) / (SELECT COUNT(*)+.0
FROM JOURNAL_ENTRY) ) * 100
FROM JOURNAL_ENTRY je
GROUP BY je.statusid
Then it's a matter of formatting the precision you want:
CAST(((COUNT(*) / (SELECT COUNT(*)+.0 FROM BCCAMPUS.dbo.COURSES_RFIP)) * 100)
AS DECIMAL(4,2))
...will give two decimal places. Cast the result to INT if you don't want any decimal places.
You could use a CTE to minimize the duplication:
WITH cte AS (
SELECT je.*
FROM JOURNAL_ENTRY je
WHERE je.user_id = 3)
SELECT c.statusid,
COUNT(*) AS num,
(COUNT(*) / (SELECT COUNT(*)+.0
FROM cte) ) * 100
FROM cte c
GROUP BY c.statusid
This should work:
SELECT
user_id,
(CAST(SUM(CASE WHEN status_id = 1 THEN 1 ELSE 0 END) AS DECIMAL(6, 4))/COUNT(*)) * 100 AS pct_green,
(CAST(SUM(CASE WHEN status_id = 2 THEN 1 ELSE 0 END) AS DECIMAL(6, 4))/COUNT(*)) * 100 AS pct_yellow,
(CAST(SUM(CASE WHEN status_id = 3 THEN 1 ELSE 0 END) AS DECIMAL(6, 4))/COUNT(*)) * 100 AS pct_red
FROM
Journal_Entry
WHERE
user_id = 1
GROUP BY
user_id
If you don't need the user_id returned then you could get rid of that and the GROUP BY clause as long as you're only ever returning data for one user (or you want the aggregates for all users in the WHERE clause). If you want it for each user then you can keep the GROUP BY and simply get rid of the WHERE clause.
DECLARE #JournalEntry TABLE
( StatusID INT
);
INSERT INTO #JournalEntry (StatusID) VALUES
(1), (1),(1),(1),(1),(1),(1)
,(2), (2),(2),(2),(2),(2),(2)
,(3), (3),(3),(3),(3),(3),(3);
SELECT
CAST(SUM(CASE WHEN StatusID = 1 THEN 1 ELSE 0 END) AS DECIMAL) / CAST(COUNT(*) AS DECIMAL) Green
,CAST(SUM(CASE WHEN StatusID = 2 THEN 1 ELSE 0 END) AS DECIMAL) / CAST(COUNT(*) AS DECIMAL) Yellow
,CAST(SUM(CASE WHEN StatusID = 3 THEN 1 ELSE 0 END) AS DECIMAL) / CAST(COUNT(*) AS DECIMAL) Blue
FROM #JournalEntry;