I have a table with 3 columns, id, name and vote. They're populated with many registers. I need that return the register with the best balance of votes. The votes types are 'yes' and 'no'.
Yes -> Plus 1
No -> Minus 1
This column vote is a string column. I am using SQL SERVER.
Example:
It must return Ann for me
Use conditional Aggregation to tally the votes as Kannan suggests in his answer
If you really only want 1 record then you can do it like so:
SELECT TOP 1
name
,SUM(CASE WHEN vote = 'yes' THEN 1 ELSE -1 END) AS VoteTotal
FROM
#Table
GROUP BY
name
ORDER BY
VoteTotal DESC
This will not allow for ties but you can use this method which will rank the responses and give you results use RowNum to get only 1 result or RankNum to get ties.
;WITH cteVoteTotals AS (
SELECT
name
,SUM(CASE WHEN vote = 'yes' THEN 1 ELSE -1 END) AS VoteTotal
,ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY SUM(CASE WHEN vote = 'yes' THEN 1 ELSE -1 END) DESC) as RowNum
,DENSE_RANK() OVER (PARTITION BY 1 ORDER BY SUM(CASE WHEN vote = 'yes' THEN 1 ELSE -1 END) DESC) as RankNum
FROM
#Table
GROUP BY
name
)
SELECT name, VoteTotal
FROM
cteVoteTotals
WHERE
RowNum = 1
--RankNum = 1 --if you want with ties use this line instead
Here is the test data used and in the future do NOT just put an image of your test data spend the 2 minutes to make a temp table or a table variable so that people you are asking for help do not have to!
DECLARE #Table AS TABLE (id INT, name VARCHAR(25), vote VARCHAR(4))
INSERT INTO #Table (id, name, vote)
VALUES (1, 'John','no'),(2, 'John','no'),(3, 'John','yes')
,(4, 'Ann','no'),(5, 'Ann','yes'),(6, 'Ann','yes')
,(9, 'Marie','no'),(8, 'Marie','no'),(7, 'Marie','yes')
,(10, 'Matt','no'),(11, 'Matt','yes'),(12, 'Matt','yes')
Use this code,
;with cte as (
select id, name, case when vote = 'yes' then 1 else -1 end as votenum from register
) select name, sum(votenum) from cte group by name
You can get max or minimum based out of this..
This one gives the 'yes' rate for each person:
SELECT Name, SUM(CASE WHEN Vote = 'Yes' THEN 1 ELSE 0 END)/COUNT(*) AS Rate
FROM My_Table
GROUP BY Name
Related
If I were to have a table such as the one below:
id_
last_updated_by
1
robot
1
human
1
robot
2
robot
3
robot
3
human
Using SQL, how could I group by the ID and create a new column to indicate whether a human has ever updated the record like this:
id_
last_updated_by
updated_by_human
1
robot
1
2
robot
0
3
robot
1
UPDATE
I'm currently doing the following, though I'm not sure how efficient this is. Selecting the latest record and then merging it with my calculated column via a sub-select.
SELECT MAIN.TRANSACTION_ID,
MAIN.CREATED_DATE
MAIN.CREATED_BY_USER_ID,
MAIN.OWNER_USER_ID,
STP.TOUCHED_BY_HUMAN
FROM (
SELECT TRANSACTION_ID,
CREATED_DATE
CREATED_BY_USER_ID_
OWNER_USER_ID_
FROM TABLE_NAME
WHERE CREATED_DATE >= CAST('{start_date} 00:00:00' AS TIMESTAMP)
AND CREATED_DATE <= CAST('{end_date} 23:59:59' AS TIMESTAMP)
QUALIFY row_number() OVER (partition by TRANSACTION_ID order by End_Dt desc) = 1
) MAIN
LEFT JOIN (
SELECT TRANSACTION_ID,
CASE
WHEN CREATED_BY_USER_ID IN ('ROBOT', 'MACHINE') OR
CREATED_BY_USER_ID LIKE 'N%' OR
CREATED_BY_USER_ID IS NULL
THEN 0
ELSE 1 END AS CREATED_BY_HUMAN,
CASE
WHEN OWNER_USER_ID IN ('ROBOT', 'MACHINE') OR
OWNER_USER_ID LIKE 'N%' OR
OWNER_USER_ID IS NULL
THEN 0
ELSE 1 END AS OWNED_BY_HUMAN,
CASE
WHEN CREATED_BY_HUMAN = 0 AND
OWNED_BY_HUMAN = 0
THEN 0
ELSE 1 END AS TOUCHED_BY_HUMAN_
FROM TABLE_NAME
WHERE CREATED_DATE >= CAST('{start_date} 00:00:00' AS TIMESTAMP)
AND CREATED_DATE <= CAST('{end_date} 23:59:59' AS TIMESTAMP)
QUALIFY row_number() OVER (partition by TRANSACTION_ID order by TOUCHED_BY_HUMAN_ desc) = 1
) STP
ON MAIN.TRANSACTION_ID = STP.TRANSACTION_ID
If I'm following your problem, then something like this should work.
SELECT
t.*
,CASE WHEN a.id IS NOT NULL THEN 1 ELSE 0 END AS updated_by_human
FROM table t
LEFT JOIN (SELECT DISTINCT id FROM table WHERE last_updated_by = 'human') a ON t.id = a.id
That takes care of the updated_by_human field, but if you also need to reduce the records in table (only keeping a subset) then you need more information to do that.
Exists clauses are usually not that performant but if your data isn't big this should work.
select id_,
IF (EXISTS (SELECT 1 FROM table_name t2 WHERE t2.last_updated_by = 'human' and t2.id_ = t1.id_), 1, 0) AS updated_by_human
from table_name t1;
here is another way
SELECT *
FROM table_name t1
GROUP BY ti.id_
HAVING COUNT(*) > 0
AND MAX(CASE t1.last_updated_by WHEN 'human' THEN 1 ELSE 0 END) = 1;
Since you didn't specified which column is used to determine this record is the newest record added by a given id, I assume that there will be a column to track the insert/modify timestamp (which is pretty standard table design), let's put it is last_updated_timestamp (if you don't have any, then I still insist you to have one as an auditing trail without timestamp does not make sense)
Given your table name is updating_trail
SELECT updating_trail.*, last_update_trail.modified_by_human
FROM updating_trail
INNER JOIN (
-- determine the id_, the lastest modified_timestamp, and a flag check to determine if there is any record with last_update_by is 'human' -> if yes then give 1
SELECT updating_trail.id_, MAX(last_update_timestamp) AS most_recent_update_ts, MAX(CASE WHEN updating_trail.last_updated_by = 'human' THEN 1 ELSE 0 END) AS modified_by_human
FROM updating_trail
GROUP BY updating_trail.id_
) last_update_trail
ON updating_trail.id_ = last_update_trail.id_ AND updating_trail.last_update_timestamp = last_update_trail.most_recent_update_ts;
Give
id_
last_updated_by
last_update_timestamp
modified_by_human
1
robot
2021-10-19T20:00:00.000Z
1
2
robot
2021-10-19T17:00:00.000Z
0
3
robot
2021-10-19T16:00:00.000Z
1
Check out this sample db fiddle I created for you
This is a 1:1 translation of your query to conditional aggregation:
SELECT TRANSACTION_ID,
CREATED_DATE,
CREATED_BY_USER_ID,
OWNER_USER_ID,
Max(CASE
WHEN CREATED_BY_USER_ID IN ('ROBOT', 'MACHINE') OR
CREATED_BY_USER_ID LIKE 'N%' OR
CREATED_BY_USER_ID IS NULL
THEN 0
ELSE 1
END) Over (PARTITION BY TRANSACTION_ID) AS CREATED_BY_HUMAN
FROM Table_Name
WHERE CREATED_DATE >= Cast('{start_date} 00:00:00' AS TIMESTAMP)
AND CREATED_DATE <= Cast('{end_date} 23:59:59' AS TIMESTAMP)
QUALIFY Row_Number() Over (PARTITION BY TRANSACTION_ID ORDER BY End_Dt DESC) = 1
I have a table called tbl_A with the following schema:
After insert, I have the following data in tbl_A:
Now the question is how to write a query for the following scenario:
Put (1) in front of any employee who was present three days consecutively
Put (0) in front of employee who was not present three days consecutively
The output screen shoot:
I think we should use case statement, but I am not able to check three consecutive days from date. I hope I am helped in this
Thank you
select name, case when max(cons_days) >= 3 then 1 else 0 end as presence
from (
select name, count(*) as cons_days
from tbl_A, (values (0),(1),(2)) as a(dd)
group by name, adate + dd
)x
group by name
With a self-join on name and available = 'Y', we create an inner table with different combinations of dates for a given name and take a count of those entries in which the dates of the two instances of the table are less than 2 units apart i.e. for each value of a date adate, it will check for entries with its own value adate as well as adate + 1 and adate + 2. If all 3 entries are present, the count will be 3 and you will have a flag with value 1 for such names(this is done in the outer query). Try the below query:
SELECT Z.NAME,
CASE WHEN Z.CONSEQ_AVAIL >= 3 THEN 1 ELSE 0 END AS YOUR_FLAG
FROM
(
SELECT A.NAME,
SUM(CASE WHEN B.ADATE >= A.ADATE AND B.ADATE <= A.ADATE + 2 THEN 1 ELSE 0 END) AS CONSEQ_AVAIL
FROM
TABL_A A INNER JOIN TABL_A B
ON A.NAME = B.NAME AND A.AVAILABLE = 'Y' AND B.AVAILABLE = 'Y'
GROUP BY A.NAME
) Z;
Due to the complexity of the problem, I have not been able to test it out. If something is really wrong, please let me know and I will be happy to take down my answer.
--Below is My Approch
select Name,
Case WHen Max_Count>=3 Then 1 else 0 end as Presence
from
(
Select Name,MAx(Coun) as Max_Count
from
(
select Name, (count(*) over (partition by Name,Ref_Date)) as Coun from
(
select Name,adate + row_number() over (partition by Name order by Adate desc) as Ref_Date
from temp
where available='Y'
)
) group by Name
);
select name as employee , case when sum(diff) > =3 then 1 else 0 end as presence
from
(select id, name, Available,Adate, lead(Adate,1) over(order by name) as lead,
case when datediff(day, Adate,lead(Adate,1) over(order by name)) = 1 then 1 else 0 end as diff
from table_A
where Available = 'Y') A
group by name;
I think I need some guidance as to what is wrong in my query. I am trying to do
Watched_Gladiator=CASE WHEN FilmName IN (CASE WHEN FilmName LIKE '%Gladiator%' THEN 1 END) then OVER(PARTITION BY Cust_Nr) THEN 1 ELSE 0 END
Tried this one too:
Watched_Gladiator=CASE WHEN FilmName IN (CASE WHEN FilmName LIKE '%Gladiator%' THEN Filmnamne END) then OVER(PARTITION BY Cust_Nr) THEN 1 ELSE 0 END
The Error I am currently getting is this:
Incorrect syntax near the keyword 'OVER'.
This is basically how my data looks like
Cust_Nr Date FilmName Watched Gladiator
157649306 20150430 Gladiator 1
158470722 20150504 Nick Cave: 20,000 Days On Earth 0
158467945 20150504 Out Of The Furnace 0
158470531 20150504 FilmA 0
157649306 20150510 Gladiator 1
158470722 20150515 Gladiator 1
I want to create a column (1 or zero) that shows if the customer has watched Gladiator then 1 ELSE 0. How can I do that?
I created a test column trying with a simple LIKE '%Gladiator%' THEN 1 ELSE 0. The problem with this solution is that it will show 1(one) more than once if the customer has watched multiple times. I only need 1 or zero.
I feel I am really close to finding a solution. I am very new to using OVER() and CASE WHEN but enjoying the thrill:=)
So you're saying that:
SELECT Cust_Nr, Date, FilmName,
CASE WHEN FilmName LIKE '%Gladiator%' THEN 1 ELSE 0 END as WatchedGladiator
FROM YourTable
WHERE YourColumn = #somevalue
Doesn't work? Because according to the data you've given, it should.
EDIT:
Well based on Tim's comment, I would simply add this bit to the query.
SELECT Cust_Nr, Date, FilmName, WatchedGladiator
FROM
(
SELECT Cust_Nr, Date, FilmName,
CASE WHEN FilmName LIKE '%Gladiator%' THEN 1 ELSE 0 END as WatchedGladiator
FROM YourTable
WHERE YourColumn = #somevalue
) as wg
WHERE WatchedGladiator = 1
The following does what you want for all films:
select r.*,
(case when row_number() over (partition by filmname order by date) = 1
then 1 else 0
end) as IsWatchedFirstAndGladiator
from results r;
For just Gladiator:
select r.*,
(case when filmname = 'Gladiator' and row_number() over (partition by filmname order by date) = 1
then 1 else 0
end) as IsWatchedFirst
from results r;
So you want to group by customer and add a column if this customer watched a specific film?
You could do:
SELECT Cust_Nr, MAX(Watched_Gladiator)
FROM( SELECT Cust_Nr,
Watched_Gladiator = CASE WHEN EXISTS
(
SELECT 1 FROM CustomerFilm c2
WHERE c2.Cust_Nr = c1.Cust_Nr
AND c2.FilmName LIKE '%Gladiator%'
) THEN 1 ELSE 0 END
FROM CustomerFilm c1 ) X
GROUP BY Cust_Nr
Demo
But it would be easier if you used the customer-table instead of this table, then you don't need the group-by.
Try grouping up to the cust/film level:
select
cust_nbr,
case when film_name like '%Gladiator%' then 1 else 0 end
from
(
select
cust_nbr,
film_name
from
<your table>
group by
cust_nbr,
film_name
) t
Or, as an alternative:
select distinct cust_nbr
from
<your table>
where
filmname = 'Gladiator'
I want a count but it repeats 1 with every record. Can you please suggest what to do?
SELECT Count(*),
innerTable.*
FROM (SELECT (SELECT NAME
FROM tours
WHERE tours.id = tourbooking.tourid) AS NAME,
(SELECT url
FROM tours
WHERE tours.id = tourbooking.tourid) AS Url,
(SELECT TOP 1 NAME
FROM tourimages
WHERE tourimages.tourid = tourbooking.tourid
ORDER BY id ASC) AS ImageName,
(SELECT duration + ' ' + CASE WHEN durationtype = 'd' THEN
'Day(s)' WHEN
durationtype =
'h' THEN 'Hour(s)' END
FROM tours
WHERE tours.id = tourbooking.tourid) AS Duration,
(SELECT Replace(Replace('<a> Adult(s) - <c> Children', '<a>', Sum
(CASE
WHEN [type] = 1 THEN 1
ELSE 0
END)),
'<c>',
Sum(CASE
WHEN [type] = 2 THEN 1
ELSE 0
END))
FROM tourperson
WHERE tourperson.bookingid = tourbooking.id) AS TotalPassengers
,
startdate,
createddate AS BookingDate,
id AS BookingID,
[status],
serviceprice
FROM tourbooking
WHERE memberid = 6)AS innerTable
GROUP BY innerTable.NAME,
innerTable.bookingdate,
innerTable.bookingid,
innerTable.duration,
innerTable.imagename,
innerTable.serviceprice,
innerTable.startdate,
innerTable.status,
innerTable.totalpassengers,
innerTable.url
You select records from tourbooking. One of the columns you select is id. This is probably the table's primary key and thus unique. (If not, you should hurry to change that name.)
You call this ID BookingID, and it is one of the columns you group by. So you get one result record per record in tourbooking. The number of records within such a "group" is of course 1; it is the one record you select and show.
If you built real groups, say a result record per day, then you'd get a real count, e.g. the number of bookings per day.
I want to do something like this:
select id,
count(*) as total,
FOR temp IN SELECT DISTINCT somerow FROM mytable ORDER BY somerow LOOP
sum(case when somerow = temp then 1 else 0 end) temp,
END LOOP;
from mytable
group by id
order by id
I created working select:
select id,
count(*) as total,
sum(case when somerow = 'a' then 1 else 0 end) somerow_a,
sum(case when somerow = 'b' then 1 else 0 end) somerow_b,
sum(case when somerow = 'c' then 1 else 0 end) somerow_c,
sum(case when somerow = 'd' then 1 else 0 end) somerow_d,
sum(case when somerow = 'e' then 1 else 0 end) somerow_e,
sum(case when somerow = 'f' then 1 else 0 end) somerow_f,
sum(case when somerow = 'g' then 1 else 0 end) somerow_g,
sum(case when somerow = 'h' then 1 else 0 end) somerow_h,
sum(case when somerow = 'i' then 1 else 0 end) somerow_i,
sum(case when somerow = 'j' then 1 else 0 end) somerow_j,
sum(case when somerow = 'k' then 1 else 0 end) somerow_k
from mytable
group by id
order by id
this works, but it is 'static' - if some new value will be added to 'somerow' I will have to change sql manually to get all the values from somerow column, and that is why I'm wondering if it is possible to do something with for loop.
So what I want to get is this:
id somerow_a somerow_b ....
0 3 2 ....
1 2 10 ....
2 19 3 ....
. ... ...
. ... ...
. ... ...
So what I'd like to do is to count all the rows which has some specific letter in it and group it by id (this id isn't primary key, but it is repeating - for id there are about 80 different values possible).
http://sqlfiddle.com/#!15/18feb/2
Are arrays good for you? (SQL Fiddle)
select
id,
sum(totalcol) as total,
array_agg(somecol) as somecol,
array_agg(totalcol) as totalcol
from (
select id, somecol, count(*) as totalcol
from mytable
group by id, somecol
) s
group by id
;
id | total | somecol | totalcol
----+-------+---------+----------
1 | 6 | {b,a,c} | {2,1,3}
2 | 5 | {d,f} | {2,3}
In 9.2 it is possible to have a set of JSON objects (Fiddle)
select row_to_json(s)
from (
select
id,
sum(totalcol) as total,
array_agg(somecol) as somecol,
array_agg(totalcol) as totalcol
from (
select id, somecol, count(*) as totalcol
from mytable
group by id, somecol
) s
group by id
) s
;
row_to_json
---------------------------------------------------------------
{"id":1,"total":6,"somecol":["b","a","c"],"totalcol":[2,1,3]}
{"id":2,"total":5,"somecol":["d","f"],"totalcol":[2,3]}
In 9.3, with the addition of lateral, a single object (Fiddle)
select to_json(format('{%s}', (string_agg(j, ','))))
from (
select format('%s:%s', to_json(id), to_json(c)) as j
from
(
select
id,
sum(totalcol) as total_sum,
array_agg(somecol) as somecol_array,
array_agg(totalcol) as totalcol_array
from (
select id, somecol, count(*) as totalcol
from mytable
group by id, somecol
) s
group by id
) s
cross join lateral
(
select
total_sum as total,
somecol_array as somecol,
totalcol_array as totalcol
) c
) s
;
to_json
---------------------------------------------------------------------------------------------------------------------------------------
"{1:{\"total\":6,\"somecol\":[\"b\",\"a\",\"c\"],\"totalcol\":[2,1,3]},2:{\"total\":5,\"somecol\":[\"d\",\"f\"],\"totalcol\":[2,3]}}"
In 9.2 it is also possible to have a single object in a more convoluted way using subqueries in instead of lateral
SQL is very rigid about the return type. It demands to know what to return beforehand.
For a completely dynamic number of resulting values, you can only use arrays like #Clodoaldo posted. Effectively a static return type, you do not get individual columns for each value.
If you know the number of columns at call time ("semi-dynamic"), you can create a function taking (and returning) polymorphic parameters. Closely related answer with lots of details:
Dynamic alternative to pivot with CASE and GROUP BY
(You also find a related answer with arrays from #Clodoaldo there.)
Your remaining option is to use two round-trips to the server. The first to determine the the actual query with the actual return type. The second to execute the query based on the first call.
Else, you have to go with a static query. While doing that, I see two nicer options for what you have right now:
1. Simpler expression
select id
, count(*) AS total
, count(somecol = 'a' OR NULL) AS somerow_a
, count(somecol = 'b' OR NULL) AS somerow_b
, ...
from mytable
group by id
order by id;
How does it work?
Compute percents from SUM() in the same SELECT sql query
SQL Fiddle.
2. crosstab()
crosstab() is more complex at first, but written in C, optimized for the task and shorter for long lists. You need the additional module tablefunc installed. Read the basics here if you are not familiar:
PostgreSQL Crosstab Query
SELECT * FROM crosstab(
$$
SELECT id
, count(*) OVER (PARTITION BY id)::int AS total
, somecol
, count(*)::int AS ct -- casting to int, don't think you need bigint?
FROM mytable
GROUP BY 1,3
ORDER BY 1,3
$$
,
$$SELECT unnest('{a,b,c,d}'::text[])$$
) AS f (id int, total int, a int, b int, c int, d int);