I´m looking for a solution, where I can select the entries between 2 dates. My table is like this
ID | YEAR | MONTH | ....
Now i want to SELECT all entries between
MONTH 9 | YEAR 2015
MONTH 1 | YEAR 2016
I don´t get any entries, because the 2nd month is lower than the 1st month. Here is my query:
SELECT *
FROM table
WHERE YEAR >= '$year'
AND MONTH >= '$month'
AND YEAR <= '$year2'
AND MONTH <= '$month2'
I can´t change the columns of the table, because a csv import is like this. Can anyone help me on this?
The years aren't disconnected from the months, so you can't test them separately.
Try something like
$date1 = $year*100+$month; // will be 201509
$date2 = $year2*100+$month2; // will be 201602
...
SELECT * FROM table WHERE (YEAR*100)+MONTH >= '$date1' AND (YEAR*100)+MONTH <= '$date2'
Make sure you protect against SQL injection though.
SELECT
*
FROM
`my_table`
WHERE
((`YEAR` * 12) + `MONTH`) >= (($year * 12) + $month)
AND ((`YEAR` * 12) + `MONTH`) <= (($year2 * 12) + $month2)
Since they aren't date fields, you need to convert to numbers that can be compared against. Multiplying the year by 12 and adding the month will give you a unique number specific to that month of the year. Then you can compare on that.
There are a couple of good answers, but assuming taht you don't/can't change the date's format something you can do is
WHERE ((YEAR>'$year') OR
(YEAR=='$year' AND MONTH>='$month')
AND ((YEAR<'$year2') OR
(YEAR=='$year2' AND MONTH<='$month2')
I would suggest the workarounds though (like alphabetically comparing in YYYYMM[DD] format).
You need to pad the month to make sure it starts with a zero. Otherwise 20162 will be lower than 201512, for example.
$date1 = $year . str_pad($month, 2, "0", STR_PAD_LEFT);
$date2 = $year2 . str_pad($month2, 2, "0", STR_PAD_LEFT);
"SELECT * FROM dates WHERE concat(`year`, LPAD(`month`, 2, '0')) >= '$date1' AND concat(`year`, LPAD(`month`, 2, '0')) <= '$date2'"
Though there are a lot of ways to solve this problem, but the best way is to convert these values into a proper date type in mysql query using str_to_date it is PHP's equivalent of strtotime, your new query should look like this
SELECT
d.*
from
dates as d
where
STR_TO_DATE( concat('1,',d.month,',',d.year) ,'%d,%m,%Y') > STR_TO_DATE('1,5,2015','%d,%m,%Y')
and
STR_TO_DATE( concat('1,',d.month,',',d.year) ,'%d,%m,%Y') < STR_TO_DATE('1,4,2016','%d,%m,%Y')
Using this technique you can easily compare dates and do much more and not worry about other complexities of calendars.
Source: MySQL date and time functions
Related
I have a column due date in the format 20210701 (YYYYMMDD), using SQL I want to extract all the dates apart from 5th of particular month ( As highlighted in the pic below )
I used the below code:
SELECT Due_Date_Key
FROM Table
WHERE Due_Date_Key <>20210705
However the error in the above code is it will exclude only the month of jul but not for other months.
How can extract the dates apart from 5th from the entire column.
Help would be much appreciated.
Note that column DUE_DATE_KEY is numeric.
A more SQLish way would be to convert string to date and then check if day is not 5
SELECT * FROM Table
WHERE DATE_PART('day', to_date(cast(DUE_DATE_KEY as varchar), 'YYYYMMDD')) != 5
Using modulo operator to determine whether the last two digits of DUE_DATE_KEY are 05.
select * from T where DUE_DATE_KEY % 100 <> 5
Using your sample data, the above query returns the following:
due_date_key
20210701
20210708
20210903
Refer to this db fiddle
I have a datatable with year and month columns. I store these values as number, like 2014 and 1 for jan 2014, etc.
Now, I would like to select all values between 2014-01 and f. e. 2015-5.
I have tried it different ways (between the two values, concating them), but it exists always values, which the result set don't contains.
How should be look the query?
How about the following:
SELECT * FROM MyTable m
WHERE CDate(m.month & "/1/" & m.year) Between #1/1/2014# AND #5/1/2015#
It appears you want:
All data from 2014
2015 data from Jan through May
If that's correct, you can ask Access to give you those data directly ... without the need to first transform your year and month fields to a date value.
SELECT *
FROM datatable
WHERE
year_field = 2014
OR
(
year_field = 2015 AND month_field <= 5
);
With year_field and month_field indexed, this query should be much faster than an alternative where you apply CDate or Format to every row of the table and thereby forego any opportunity to benefit from indexed retrieval.
On the other hand, if your table is small enough, you probably wouldn't notice the horrible inefficiency. :-)
You are not defining your RBDMS, so I'm supposing you use ORACLE, you can change the syntax of course.
SELECT *
FROM [table]
WHERE (SELECT to_date(to_char(year) || '/' || to_char(month) || '/01', 'yyyy/mm/dd')
FROM dual)
BETWEEN (SELECT to_date('year/mm/01', 'yyyy/mm/dd' FROM dual)
AND (SELECT to_date('year2/mm2/01', 'yyyy/mm/dd' FROM dual)
Untested.
Notice you need to replace year and mm for the beginning date and year2 and mm2 for the ending date.
I got yelled at one time because between is not safe apparently, so you may prefer
SELECT *
FROM MYTABLE AS m
WHERE Format(m.month & "/1/" & m.year,"mm/dd/yyyy") >=
Format(#1/1/2014#,"mm/dd/yyyy") AND
Format(m.month & "/1/" & m.year,"mm/dd/yyyy") <=
Format(#5/1/2015#,"mm/dd/yyyy")
Also base code stolen from Linger
You should convert the two parts of all of the involved parameters into actual dates and use BETWEEN on them instead.
SELECT [field_list]
FROM [table_name] t
WHERE CDate(t.year + '/' + t.month + '/02')
BETWEEN #2014/01/01#
AND #2014/05/03#;
If you have an actual day field you can use that, but for simplicity, and assuming you aren't using the day, the above setup should work fine for you.
I am trying to do a query that chart date is the system time the data was charted is more than 8 hrs after the perform date time.
I am using the following query:
select * from pat_results where app_type like 'L' and (chart_dt_utc > perform_dt_utc +8)
The date and time format for both columns are 2012-12-29 11:44:00
Is the +8 correct?
No. In databases that allow you to add a number to a date, the number is measured in days.
The value you want to add is 8/24.0 -- include the decimal place, because some databases calculate 8/24 as integers and give you 0.
No, + 8 adds 8 days. You want:
select * from pat_results where app_type like 'L' and datediff(hour, chart_dt_utc, perform_dt_utc) > 8
Edit: Oh. For some reason I thought you were using SQL server. Well, suffice it to say, use whatever equivalent exists in your RDBMS.
Edit 2: In Oracle you can do this:
select * from pat_results where app_type like 'L'
and (chart_dt_utc > perform_dt_utc + (8 / 24))
How would I go about doing a query that returns results of all rows that contain dates for current year and month at the time of query.
Timestamps for each row are formated as such: yyyy-mm-dd
I know it probably has something to do with the date function and that I must somehow set a special parameter to make it spit out like such: yyyy-mm-%%.
Setting days to be wild card character would do the trick but I can't seem to figure it out how to do it.
Here is a link to for quick reference to date-time functions in mysql:
http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html
Thanks
I think EXTRACT is the function you are looking for:
SELECT * FROM table
WHERE EXTRACT(YEAR_MONTH FROM timestamp_field) = EXTRACT(YEAR_MONTH FROM NOW())
you could extract the year and month using a function, but that will not be able to use an index.
if you want scalable performance, you need to do this:
SELECT *
FROM myTable
WHERE some_date_column BETWEEN '2009-01-01' AND '2009-01-31'
select * from someTable where year(myDt) = 2009 and month(myDt) = 9 and day(myDt) = 12
I'm trying to get the products that havn't been made in the last 2 years. I'm not that great with SQL but here's what i've started with and it doesn't work.
Lets say for this example that my schema looks like this
prod_id, date_created, num_units_created.
I'll take any advice i can get.
select id, (select date from table
where date <= sysdate - 740) older,
(select date from table
where date >= sysdate - 740) newer
from table
where newer - older
I'm not being clear enough.
Basically i want all products that havn't been produced in the last 2 years. Whenever a product is produced, a line gets added. So if i just did sysdate <= 740, it would only give me all the products that were produced from the beginning up til 2 years ago.
I want all products that have been produced in the at least once, but not in the last 2 years.
I hope that clears it up.
GROUP BY with HAVING
select id, max(date)
from table
group by id
having max(date) < add_months(sysdate,-24)
I'd use SQL's dateadd function.
where date < dateadd(year,-2,getdate())
would be a where clause that would select records with date less than 2 years from the current date.
Hope that helps.
EDIT: If you want to go by days, use dateadd(d,-740,getdate())
Maybe something like this?
select id, date
from table
where date <= (sysdate - 730);
SELECT id FROM table WHERE date + (365*2) <= sysdate;
Use SELECT id, date, other, columns ... if you need to get them at the same time.