In Oracle SQL Developer, how do I compare three tables where A + B = C table? I have to validate if all the data of A and B is converted into C. Also table A is in a different database from B and C, which are in the same database.
Let me assume that the different databases have one column, an id. You could use full outer join for this, assuming it is never NULL. However, this is probably easier using union all and aggregation.
You can get a list of ids that differ using the following query:
select id, sum(inab) as inab, sum(inc) as inc
from ((select id, 1 as inab, 0 as inc
from a
) union all
(select id, 1 as inab, 0 as inc
from b
) union all
(select id, 0 as inab, 1 as inc
from c
)
) c
group by id
having sum(inab) <> 1 or sum(inc) <> 1;
In practice, you would probably have multiple columns. Note: if there are duplicates in A+B or C, this just guarantees that the duplicate appears in both (rather than in both with the same count).
Related
I have two tables that share IDs on a postgresql .
I would like to select certain rows from table A, based on condition Y (in table A) AND based on Condition Z in a different table (B) ).
For example:
Table A Table B
ID | type ID | date
0 E 1 01.01.2022
1 F 2 01.01.2022
2 E 3 01.01.2010
3 F
IDs MUST by unique - the same ID can appear only once in each table, and if the same ID is in both tables it means that both are referring to the same object.
Using an SQL query, I would like to find all cases where:
1 - the same ID exists in both tables
2 - type is F
3 - date is after 31.12.2021
And again, only rows from table A will be returned.
So the only returned row should be:1 F
It is a bit hard t understand what problem you are actually facing, as this is very basic SQL.
Use EXISTS:
select *
from a
where type = 'F'
and exists (select null from b where b.id = a.id and dt >= date '2022-01-01');
Or IN:
select *
from a
where type = 'F'
and id in (select id from b where dt >= date '2022-01-01');
Or, as the IDs are unique in both tables, join:
select a.*
from a
join b on b.id = a.id
where a.type = 'F'
and b.dt >= date '2022-01-01';
My favorite here is the IN clause, because you want to select data from table A where conditions are met. So no join needed, just a where clause, and IN is easier to read than EXISTS.
SELECT *
FROM A
WHERE type='F'
AND id IN (
SELECT id
FROM B
WHERE DATE>='2022-01-01'; -- '2022' imo should be enough, need to check
);
I don't think joining is necessary.
I am using Oracle SQL to extract the data;
I have supply periods for IDs in 2 systems. I have this working with the below code:
select distinct b.ID_Code, b.supply_start_date, b.supply_end_date, b.system_id
from (
select ID_Code, max(supply_start_date) as max_dt
from tmp_mmt_sup
group by ID_Code) a
inner join tmp_mmt_sup b
on a.ID_Code=b.ID_Code and a.max_dt=b.SUPPLY_START_DATE;
However, I have several records that are on the 2 different systems, but have the same start date/end dates. I only want to keep one of them - not bothered which!
So instead of
ID_Code Start End System
123 01-04-2018 30-04-2018 ABC
123 01-04-2018 30-04-2018 DEF
I only have one of these records.
Many thanks
D
If you don't care which one to return, then one of aggregate functions (such as MIN or MAX) does the job. For example:
select b.id_code,
b.supply_start_date,
b.supply_end_date,
max(b.system_id) system_id --> added MAX here ...
from (select id_code,
max(supply_start_date) as max_dt
from tmp_mmt_sup
group by id_code
) a
inner join tmp_mmt_sup b
on a.id_code = b.id_code and a.max_dt = b.supply_start_date
group by b.id_code, --> ... and GROUP BY here
b.supply_start_date,
b.supply_end_date;
Fair warning: I'm new to using SQL. I do so on an Oracle server either via AQT or with SQL Developer.
As I haven't been able to think or search my way to an answer, I put myself in your able hands...
I'd like to combine data from table A (high quality data) with data from table B (fresh data) such that the entries from B are only included when the date stamp are later than those available from table A.
Both tables include entries from multiple entities, and the latest date stamp varies with those entities.
On the 4th of january, the tables may look something like:
A____________________________ B_____________________________
entity date type value entity date type value
X 1.jan 1 1 X 1.jan 1 2
X 1.jan 0 1 X 1.jan 0 2
X 2.jan 1 1 X 2.jan 1 2
Y 1.jan 1 1 (new entry)X 3.jan 1 1
Y 3.jan 1 1 Y 1.jan 1 2
Y 3.jan 1 2
(new entry)Y 4.jan 1 1
I have made an attempt at some code that I hope clarify my need:
WITH
AA AS
(SELECT entity, date, SUM(value)
FROM table_A
GROUP BY
entity,
date),
BB AS
(SELECT entity, date, SUM(value)
FROM table_B
WHERE date > ALL (SELECT date FROM AA)
GROUP BY
entity,
date
)
SELECT * FROM (SELECT * FROM AA UNION ALL SELECT * FROM BB)
Now, if the WHERE date > ALL (SELECT date FROM AA)would work seperately for each entity, I think have what I need.
That is, for each entity I want all entries from A, and only newer entries from B.
As the data in table A often differ from that of B (values are often corrected) I dont think I can use something like: table A UNION ALL (table B MINUS table A)?
Thanks
Essentially you are looking for entries in BB which do not exist in AA. When you are doing date > ALL (SELECT date FROM AA) this will not take into consideration the entity in question and you will not get the correct records.
Alternative is to use the JOIN and filter out all matching entries with AA.
Something like below.
WITH
AA AS
(SELECT entity, date, SUM(value)
FROM table_A
GROUP BY
entity,
date),
BB AS
(SELECT entity, date, SUM(value)
FROM table_B
LEFT OUTER JOIN AA
ON AA.entity = BB.entity
AND AA.DATE = BB.date
WHERE AA.date == null
GROUP BY
entity,
date
)
SELECT * FROM (SELECT * FROM AA UNION ALL SELECT * FROM BB)
I find your question confusing, because I don't know where the aggregation is coming from.
The basic idea on getting newer rows from table_b uses conditions in the where clause, something like this:
select . . .
from table_a a
union all
select . . .
from table_b b
where b.date > (select max(a.date) from a where a.entity = b.entity);
You can, of course, run this on your CTEs, if those are what you really want to combine.
Use UNION instead of UNION ALL , it will remove the duplicate records
SELECT * FROM (
SELECT *
FROM AA
UNION
SELECT *
FROM BB )
I am seeking a way to SELECT rows conditionally without having only compound key A,B (refer to the picture).
Furthermore, I need to select rows where negative value and positive value of column C is present; skipping 0. There may be any combination of row count with A, B group the minimum is 2 where C has a negative or positive row.
The data found below is already queried.
Note: I was able to add another column D, because we can't use actual values for C:
D = CASE WHEN C < 0 THEN 1 ELSE 2 end
So the logic could be SELECT * WHERE SUM(D) >= 3.
I am fully able to complete this task with another language such as C#, but I have to get this done using only SQL.
I would also like to avoid temporary tables. Column D is not required.
Would this work?
Select tblA.*
FROM tblA
INNER JOIN
(select A,B
from tblA
Group By A,B
HAVING
SUM(case when C<0 then 1 else 2 end) >=3
)X
on X.A=tblA.A and X.B=tblA.B
SQLFiddle
http://sqlfiddle.com/#!9/2078f/2
I have a table in my database:
Name | Element
1 2
1 3
4 2
4 3
4 5
I need to make a query that for a number of arguments will select the value of Name that has on the right side these and only these values.
E.g.:
arguments are 2 and 3, the query should return only 1 and not 4 (because 4 also has 5). For arguments 2,3,5 it should return 4.
My query looks like this:
SELECT name FROM aggregations WHERE (element=2 and name in (select name from aggregations where element=3))
What do i have to add to this query to make it not return 4?
A simple way to do it:
SELECT name
FROM aggregations
WHERE element IN (2,3)
GROUP BY name
HAVING COUNT(element) = 2
If you want to add more, you'll need to change both the IN (2,3) part and the HAVING part:
SELECT name
FROM aggregations
WHERE element IN (2,3,5)
GROUP BY name
HAVING COUNT(element) = 3
A more robust way would be to check for everything that isn't not in your set:
SELECT name
FROM aggregations
WHERE NOT EXISTS (
SELECT DISTINCT a.element
FROM aggregations a
WHERE a.element NOT IN (2,3,5)
AND a.name = aggregations.name
)
GROUP BY name
HAVING COUNT(element) = 3
It's not very efficient, though.
Create a temporary table, fill it with your values and query like this:
SELECT name
FROM (
SELECT DISTINCT name
FROM aggregations
) n
WHERE NOT EXISTS
(
SELECT 1
FROM (
SELECT element
FROM aggregations aii
WHERE aii.name = n.name
) ai
FULL OUTER JOIN
temptable tt
ON tt.element = ai.element
WHERE ai.element IS NULL OR tt.element IS NULL
)
This is more efficient than using COUNT(*), since it will stop checking a name as soon as it finds the first row that doesn't have a match (either in aggregations or in temptable)
This isn't tested, but usually I would do this with a query in my where clause for a small amount of data. Note that this is not efficient for large record counts.
SELECT ag1.Name FROM aggregations ag1
WHERE ag1.Element IN (2,3)
AND 0 = (select COUNT(ag2.Name)
FROM aggregatsions ag2
WHERE ag1.Name = ag2.Name
AND ag2.Element NOT IN (2,3)
)
GROUP BY ag1.name;
This says "Give me all of the names that have the elements I want, but have no records with elements I don't want"