I´m struggling with this update...
I would like to update the column result from table #b with the column columna_1 resulting from the last row of the select below. The matching filed is id_car.
So if you run the select below, the last row of columna_1 is 42229.56230859 and the only record of #b would be:
id_car = 1
result = 42229.56230859
can anyone help please? thanks!!!
CREATE TABLE #b(
id_car int,
result money
)
INSERT INTO #b VALUES (1,0)
CREATE TABLE #f(
id_car int,
fecha datetime,
sales money
)
INSERT INTO #f VALUES (1,'2010-10-31',1.10912)
INSERT INTO #f VALUES (1,'2010-11-30',1.77227)
INSERT INTO #f VALUES (1,'2010-12-31',0.66944)
INSERT INTO #f VALUES (1,'2011-01-31',0.34591)
INSERT INTO #f VALUES (1,'2011-02-28',1.73468)
INSERT INTO #f VALUES (1,'2011-03-31',1.50102)
INSERT INTO #f VALUES (1,'2011-04-30',0.87270)
INSERT INTO #f VALUES (1,'2011-05-31',1.51555)
;with ctesource as
(
select
id_car, fecha, sales,
sum( log( 1e0 + sales ) ) over ( partition by id_car order by fecha rows unbounded preceding) as LogAssetValue
from
#f
WHERE id_car= 1 and fecha > '2010-10-30'
)
select convert(varchar, fecha, 104) AS fecha1, fecha,
CAST(SUM(exp(LogAssetValue)-1)*100 AS numeric(20, 8)) as columna_1
from ctesource
GROUP BY fecha
order by fecha;
SqlFiddleDemo
;with
ctesource as (
SELECT
id_car, fecha, sales,
sum( log( 1e0 + sales ) ) over ( partition by id_car order by fecha rows unbounded preceding) as LogAssetValue,
row_number() over (order by fecha) as rn
FROM
f
WHERE id_car= 1
and fecha > '2010-10-30'
)
SELECT convert(varchar, fecha, 104) AS fecha1,
fecha,
rn,
CAST(SUM(exp(LogAssetValue)-1)*100 AS numeric(20, 8)) as columna_1
FROM ctesource
GROUP BY fecha, rn
HAVING rn = (SELECT max(rn) from ctesource)
Related
I want to be able to insert the results of this CTE query into a temp table so I can sum the Total column.
CREATE TABLE #tmp
(
SerialNumber NVARCHAR(50),
StartDateTime NVARCHAR(50),
EndDateTime NVARCHAR(50),
Total NVARCHAR(50)
)
;WITH cte1 AS
(
SELECT
*,
CASE
WHEN Temperature > #maxthreshold AND LAG(Temperature) OVER (PARTITION BY SerialNumber ORDER BY CombineDateTime) IS NULL THEN 1
WHEN Temperature <= #maxthreshold AND LEAD(Temperature) OVER (PARTITION BY SerialNumber ORDER BY CombineDateTime) > #maxthreshold THEN 1
WHEN Temperature <= #maxthreshold AND LAG(Temperature) OVER (PARTITION BY SerialNumber ORDER BY CombineDateTime) > #maxthreshold THEN 1
END AS chg
FROM
[RawData]
WHERE
SerialNumber = #_Serial
AND CombineDateTime BETWEEN #_DateFrom AND #_DateTo
), cte2 AS
(
SELECT
*,
SUM(chg) OVER (PARTITION BY SerialNumber ORDER BY CombineDateTime) AS grp
FROM
cte1
)
INSERT INTO #tmp
SELECT
SerialNumber,
MIN(CombineDateTime) AS StartDateTime,
MAX(CombineDateTime) AS EndDateTime,
DATEDIFF(SECOND, MIN(CombineDateTime), MAX(CombineDateTime)) / 60.0 AS 'Total'
FROM
cte2
GROUP BY
SerialNumber, grp
HAVING
MAX(Temperature) > #maxthreshold)
SELECT *
FROM #tmp
DROP TABLE #tmp
I have tried putting the insert in various places, but it does not insert, I have tried the following answers. I am confused as to why the insert won't work as it is outside of the recursion.
Answer 1
Answer 2
TIA
I have the below table (#temp1) where I need to replace the string in the column'Formula' with the matching input 'VALUE' column based on the group 'Yearmonth'.
The 'Formula' column may be of any mathematical expression for better understanding I have mentioned a simple example below.
IDNUM formula INPUTNAME VALUE YEARMONTH
---------------------------------------------------------------------
1 imports(398)+imports(399) imports(398) 17.000 2003:1
2 imports(398)+imports(399) imports(398) 56.000 2003:2
3 imports(398)+imports(399) imports(399) 15.000 2003:1
4 imports(398)+imports(399) imports(399) 126.000 2003:2
For eg :From the above table i need the output as
Idnum Formula Yearmonth
1. 17.00 +15.00 2003:1
2. 56.00 +126.00 2003:2
I tried with the below different query from various suggestions but coludnt achieve it. Could someone help me this out ?
Type1 :
SELECT
REPLACE(FORMULA, INPUTName, AttributeValue) AS realvalues,
yearmonth
FROM #temp1
GROUP BY yearmonth
TYPE2 :
USING XML PATH... In this case it got worked but I need to replace only the strings with the values and not to stuff the strings based on mathematcal operation.(Because the formula might be of any type).
SELECT
IDNUM = MIN(IDNUM),
FORMULA =
(SELECT STUFF(
(SELECT ' +' + CONVERT(VARCHAR(10), Value)
FROM #temp1
WHERE YEARMONTH = t1.YEARMONTH
FOR XML PATH(''))
,1, 2, '')),
YEARMONTH
FROM #TEMP1 t1
GROUP BY YEARMONTH
TYPE3:Using Recursions...This is returning only the null values...
;with t as (
select t.*,
row_number() over (partition by yearmonth order by idnum) as seqnum,
count(*) over (partition by yearmonth) as cnt
from #temp1 t
)
,cte as (
select t.seqnum, t.yearmonth, t.cnt,
replace(formula, inputname, AttributeValue) as formula1
from t
where seqnum = 1
union all
select cte.seqnum, cte.yearmonth, cte.cnt,
replace(CTE.formula1, T.inputname, T.AttributeValue) as formula2
from cte join
t
on cte.yearmonth = t.yearmonth
AND cte.seqnum = t.seqnum + 1
)
select row_number() over (order by (select null)) as id,formula1
from cte
where seqnum = cnt
This is full working example using recursive CTE:
DECLARE #DataSource TABLE
(
[IDNUM] TINYINT
,[formula] VARCHAR(MAX)
,[INPUTNAME] VARCHAR(128)
,[VALUE] DECIMAL(9,3)
,[YEARMONTH] VARCHAR(8)
);
INSERT INTO #DataSource ([IDNUM], [formula], [INPUTNAME], [VALUE], [YEARMONTH])
VALUES ('1', 'imports(398)+imports(399)', 'imports(398)', '17.000', '2003:1')
,('2', 'imports(398)+imports(399)', 'imports(398)', '56.000', '2003:2')
,('3', 'imports(398)+imports(399)', 'imports(399)', '15.000', '2003:1')
,('4', 'imports(398)+imports(399)', 'imports(399)', '126.000', '2003:2')
,('5', '(imports(391)+imports(392)-imports(393))/imports(394)', 'imports(391)', '5.000', '2003:3')
,('6', '(imports(391)+imports(392)-imports(393))/imports(394)', 'imports(392)', '10.000', '2003:3')
,('7', '(imports(391)+imports(392)-imports(393))/imports(394)', 'imports(393)', '3.000', '2003:3')
,('8', '(imports(391)+imports(392)-imports(393))/imports(394)', 'imports(394)', '-5.000', '2003:3');
WITH DataSource AS
(
SELECT ROW_NUMBER() OVER(PARTITION BY [YEARMONTH] ORDER BY [IDNUM]) AS [ReplacementOrderID]
,[YEARMONTH]
,[formula]
,[INPUTNAME] AS [ReplacementString]
,[VALUE] AS [ReplacementValue]
FROM #DataSource
),
RecursiveDataSource AS
(
SELECT [ReplacementOrderID]
,[YEARMONTH]
,REPLACE([formula], [ReplacementString], [ReplacementValue]) AS [formula]
FROM DataSource
WHERE [ReplacementOrderID] = 1
UNION ALL
SELECT DS.[ReplacementOrderID]
,DS.[YEARMONTH]
,REPLACE(RDS.[formula], DS.[ReplacementString], DS.[ReplacementValue]) AS [formula]
FROM RecursiveDataSource RDS
INNER JOIN DataSource DS
ON RDS.[ReplacementOrderID] + 1 = DS.[ReplacementOrderID]
AND RDS.[YEARMONTH] = DS.[YEARMONTH]
)
SELECT RDS.[YEARMONTH]
,RDS.[formula]
FROM RecursiveDataSource RDS
INNER JOIN
(
SELECT [YEARMONTH]
,MAX([ReplacementOrderID]) AS [ReplacementOrderID]
FROM DataSource
GROUP BY [YEARMONTH]
) DS
ON RDS.[YEARMONTH] = DS.[YEARMONTH]
AND RDS.[ReplacementOrderID] = DS.[ReplacementOrderID]
ORDER BY RDS.[YEARMONTH]
Generally, you simply want to perform multiple replacements over a string in one statement. You can have many replacement values, just play with the MAXRECURSION option.
--Create sample data
DROP TABLE #temp1
CREATE TABLE #temp1 (IDNUM int, formula varchar(max), INPUTNAME varchar(max), VALUE decimal, YEARMONTH varchar(max))
INSERT INTO #temp1 VALUES
(1, 'imports(398)+imports(399)', 'imports(398)', 17.000, '2003:1'),
(2, 'imports(398)+imports(399)', 'imports(398)', 56.000, '2003:2'),
(3, 'imports(398)+imports(399)', 'imports(399)', 15.000, '2003:1'),
(4, 'imports(398)+imports(399)', 'imports(399)', 126.000, '2003:2')
--Query
;WITH t as (
SELECT formula, YEARMONTH, IDNUM
FROM #temp1
UNION ALL
SELECT REPLACE(a.formula, b.INPUTNAME, CAST(b.VALUE AS varchar(100))) AS formula, a.YEARMONTH, a.IDNUM
FROM t a
JOIN #temp1 b ON a.YEARMONTH = b.YEARMONTH AND a.formula LIKE '%' + b.INPUTNAME + '%'
)
SELECT MIN(IDNUM) AS IDNUM, formula, YEARMONTH
FROM t
WHERE formula not LIKE '%imports(%'
GROUP BY formula, YEARMONTH
I have a scenario where I have to select multiple rows from table, I have multiple rows of one record but with different status,
at times I have two identical rows with identical data for status < for that case I canted to select Non zero for the first occurrence and set 0 for the remaining occurrences.
Below is the Image to show and I have marked strike-out and marked 0 for the remaining occurrence.
And body could suggest better SQL Query:
Here is the Query: I am getting zero value for status 1 for ID =1 but I need to show first as regular and then 0 if that status repeats again.
CREATE TABLE #Temp
(ID INT,
ItemName varchar(10),
Price Money,
[Status] INT,
[Date] Datetime)
INSERT INTO #Temp VALUES(1,'ABC',10,1,'2014-08-27')
INSERT INTO #Temp VALUES(1,'ABC',10,2,'2014-08-27')
INSERT INTO #Temp VALUES(1,'ABC',10,1,'2014-08-28')
INSERT INTO #Temp VALUES(2,'DEF',25,1,'2014-08-26')
INSERT INTO #Temp VALUES(2,'DEF',25,3,'2014-08-27')
INSERT INTO #Temp VALUES(2,'DEF',25,1,'2014-08-28')
INSERT INTO #Temp VALUES(3,'GHI',30,1,'2014-08-27')
SELECT CASE WHEN Temp.Status = 1 THEN
0
ELSE
Temp.Price END AS Price,
* FROM (SELECT * FROM #Temp) Temp
DROP TABLE #Temp
Here is the result:
You might modify your inner select using Row_Number() and set price to Zero for RowNumber > 1.
SELECT CASE WHEN Temp.RowNumber > 1 THEN
0
ELSE
Temp.Price END AS Price,
* FROM (
SELECT *,Row_Number() over (PARTITION by ID,Status ORDER BY ID,Date) AS 'RowNumber'
FROM #Temp
) Temp
Order by ID,Date
You can try this:
;WITH DataSource AS
(
SELECT RANK() OVER (PARTITION BY [ID], [ItemName], [Price], [Status] ORDER BY Date) AS [RankID]
,*
FROM #Temp
)
SELECT [ID]
,[ItemName]
,IIF([RankID] = 1, [Price], 0)
,[Status]
,[Date]
FROM DataSource
ORDER BY [ID]
,[Date]
Here is the output:
please try this below code . it is working for me.
CREATE TABLE #Temp
(ID INT,
ItemName varchar(10),
Price Money,
[Status] INT,
[Date] Datetime)
INSERT INTO #Temp VALUES(1,'ABC',10,1,'2014-08-27')
INSERT INTO #Temp VALUES(1,'ABC',10,2,'2014-08-27')
INSERT INTO #Temp VALUES(1,'ABC',10,1,'2014-08-28')
INSERT INTO #Temp VALUES(2,'DEF',25,1,'2014-08-26')
INSERT INTO #Temp VALUES(2,'DEF',25,3,'2014-08-27')
INSERT INTO #Temp VALUES(2,'DEF',25,1,'2014-08-28')
INSERT INTO #Temp VALUES(3,'GHI',30,1,'2014-08-27')
select *,case when a.rn=1 and status!=2 then price else 0 end as price from
(select *,ROW_NUMBER() over(partition by status,date order by date asc) rn from #Temp) a
order by ItemName asc
You can do this with UNION:
SELECT * FROM #Temp t
WHERE NOT EXISTS
(SELECT * FROM #Temp
WHERE t.id = id and t.status = status and t.date < date)
UNION ALL
SELECT ID, ItemName, 0 as Price, status, date
WHERE EXISTS
(SELECT * FROM #Temp
WHERE t.id = id and t.status = status and t.date < date)
Or subquery:
SELECT CASE
WHEN (SELECT COUNT(*)
FROM #Temp
WHERE t.id = id and t.status = status
and t.date > date) > 1 THEN 0 ELSE price END as NewPrice, t.*
FROM #Temp t
Or possibly RANK() function:
SELECT CASE
WHEN RANK() OVER (PARTITION BY id, status ORDER BY date) > 1
THEN 0 ELSE Price END,
t.*
FROM #Temp t
How do I remove duplicates from a table that is set up in the following way?
unique_ID | worker_ID | date | type_ID
A worker can have multiple type_ID's associated with them and I want to remove any duplicate types. If there is a duplicate, I want to remove the type with the most recent entry.
A textbook candidate for the window function row_number():
;WITH x AS (
SELECT unique_ID
,row_number() OVER (PARTITION BY worker_ID,type_ID ORDER BY date) AS rn
FROM tbl
)
DELETE FROM tbl
FROM x
WHERE tbl.unique_ID = x.unique_ID
AND x.rn > 1
This also takes care of the situation where a set of dupes on (worker_ID,type_ID) shares the same date.
See the simplified demo on data.SE.
Update with simpler version
Turns out, this can be simplified: In SQL Server you can delete from the CTE directly:
;WITH x AS (
SELECT unique_ID
,row_number() OVER (PARTITION BY worker_ID,type_ID ORDER BY date) AS rn
FROM tbl
)
DELETE x
WHERE rn > 1
delete from table t
where exists ( select 1 from table t2
where t2.worker_id = t.worker_id
and t2.type_id = t.type_id
and t2.date < t.date )
HTH
DELETE FROM #t WHERE unique_Id IN
(
SELECT unique_Id FROM
(
SELECT unique_Id
,Type_Id
,ROW_NUMBER() OVER (PARTITION BY worker_Id, type_Id ORDER BY date) AS rn
FROM #t
) Q
WHERE rn > 1
)
And to test...
DECLARE #t TABLE
(
unique_ID INT IDENTITY,
worker_ID INT,
date DATETIME,
type_ID INT
)
INSERT INTO #t VALUES (1, DATEADD(DAY, 1, GETDATE()), 1)
INSERT INTO #t VALUES (1, GETDATE(), 1)
INSERT INTO #t VALUES (2, GETDATE(), 1)
INSERT INTO #t VALUES (1, DATEADD(DAY, 2, GETDATE()), 1)
INSERT INTO #t VALUES (1, DATEADD(DAY, 3, GETDATE()), 2)
SELECT * FROM #t
DELETE FROM #t WHERE unique_Id IN
(
SELECT unique_Id FROM
(
SELECT unique_Id
,Type_Id
,ROW_NUMBER() OVER (PARTITION BY worker_Id, type_Id ORDER BY date) AS rn
FROM #t
) Q
WHERE rn > 1
)
SELECT * FROM #t
you may use this query
delete from worker where unique_id in (
select max(unique_id) from worker group by worker_ID , type_ID having count(type_id)>1)
here i am assuming worker as your table name
Assume there were 100 records in tableA and tableA contained a column named 'price'.
How do I select the first-n record if where sum of price > a certain amount (e.g. 1000) without using cursor?
thanks
Top N implies some kind of order, which you did not supply, so I assumed any random order.
You can change this on the OVER clause of the ROW_NUMBER().
Try something like
DECLARE #Table TABLE(
Price FLOAT
)
INSERT INTO #Table SELECT 1
INSERT INTO #Table SELECT 11
INSERT INTO #Table SELECT 12
INSERT INTO #Table SELECT 15
INSERT INTO #Table SELECT 10
INSERT INTO #Table SELECT 65
INSERT INTO #Table SELECT 100
DECLARE #TotalPrice FLOAT
SELECT #TotalPrice = 100
;WITH Vals AS (
SELECT *,
ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) RNR
FROM #Table
)
, Totals AS (
SELECT v.RNR,
SUM(vP.Price) TotalPrice
FROM Vals v LEFT JOIN
Vals vP ON v.RNR >= vP.RNR
GROUP BY v.RNR
)
, LimitValue AS (
SELECT TOP 1
RNR
FROM Totals
WHERE TotalPrice >= #TotalPrice
ORDER BY RNR
)
SELECT *
FROM Vals
WHERE RNR <= (
SELECT RNR
FROM LimitValue
)
select price from tableA
where price > 1000
limit n;
n - no. of records you want in result set
--
Cheers