I need to identify the first character in my data as numeric or character in SQL Server. I am relatively new to this and I don't know where to begin on this one. But here is what I have done to this point. I had data that looked like this:
TypeDep
Transfer From 4Z2
Transfer From BZZ
Transfer From 123
Transfer From abc
I used the right function to remove the 'transfer from' and isolate the data I need to check.
UPDATE #decode
SET firstPartType = Right(z.TypeDep,17)
FROM #decode z
where z.TypeDep like 'TRANSFER FROM%'
firstPartType
4Z2
BZZ
123
abc
Now I need to add a column identifying the first character in the string. Producing the results below.
firstPartType SecondPartType
4Z2 Numeric
BZZ Alpha
123 Numeric
abc Alpha
Using LEFT and ISNUMERIC(), however be aware that ISNUMERIC thinks some additional characters such as . are numeric
UPDATE #decode
SET SecondPartType =
CASE WHEN ISNUMERIC(LEFT(firstPartType, 1)) = 1 THEN'Numeric'
ELSE 'Alpha'
END
FROM #decode;
A more robust approach is to use the limited regex functionality of sql server. ISNUMERIC will return false positives for single characters like .,$ to name a few.
SELECT
CASE WHEN left(firstPartType, 1) like '[0-9]' THEN 'Numeric'
ELSE 'Alpha'
END AS SecondPartType
I think this should work:
SELECT
CASE WHEN ISNUMERIC(SUBSTRING(firstPartType, 1, 1)) = 1
THEN 'Numeric'
ELSE 'Alpha'
END AS 'SecondPartType'
FROM TABLE
you can use this command
ISNUMERIC(LEFT(firstPartType, 1))
this return 1 if the first character is a Numbert
0 if isn't.
i think is all you need
You could try:
UPDATE #decode
SET SecondPartType =
CASE
WHEN LEFT(firstPartType, 1) IN ('0','1','2','3','4','5','6','7','8','9')
THEN'Numeric'
ELSE 'Alpha'
END
FROM #decode;
select ISNUMERIC(left('4ello world',1)) will be a "1" if the first character is a number.
Related
I have a very but tricky question for you guys. So, listen I have a field with spaces and numbers in one of my table columns. The key part is transform the content in a decimal field. The drawback is basically that for some rows I could get something like:
' 1584.00 '
' 156546'
'545.00 '
' '
So, to clean up my column, I have done a LTRIM and RTRIM so spaces gone. So now for a couple of records where the record were just spaces the new content is ''. Finally I need to convert this result to a decimal.
Issue: The thing is that for field that contend just the spaces the new result is '' and I'm not able to apply a REPLACE on this because it's a blank and the code below doesn't work:
SELECT REPLACE('','','0')
-- Final current verison
SELECT CAST(COALESCE(REPLACE(REPLACE([Gross_Weight],' ','0'),',',''),'0') AS DECIMAL(13,3))
How could I figure it out?
thanks so much
SELECT COALESCE(NULLIF(MyColumn, ''), 0)
This has the side-effect that you will also turn NULL values into 0, which you might not want. If that's a problem then a simple CASE statement should do the trick:
SELECT CASE WHEN MyColumn = '' THEN 0 ELSE CAST(MyColumn AS DECIMAL(10, 4)) END
Obviously you'll also have to incorporate any other manipulations that you're already doing.
No need for replace, just concatenate a zero to your column, like
SELECT RTRIM('0' + LTRIM(column))
I presume your data is in a table.
Lets call this table 'DATA' and the column 'VALUE'
Then you might use the below query
UPDATE DATA SET VALUE = 0 where VALUE = ''
To select the value do the below
select case ltrim(rtrim([Gross_Weight])) when ''
THEN 0
ELSE ltrim(rtrim([Gross_Weight])) END
Let me know if i get the requirement wrong.
I had a SQL procedure that increments through each row and and pads some trailing zeros on values depending on the length of the value after a decimal point. Trying to carry this over to a PSQL environment I realized there was a lot of syntax differences between SQL and PSQL. I managed to make the conversion over time but I am still getting a syntax error and cant figure out why. Can someone help me figure out why this wont run? I am currently running it in PGadmin if that makes any difference.
DO $$
DECLARE
counter integer;
before decimal;
after decimal;
BEGIN
counter := 1;
WHILE counter <> 2 LOOP
before = (select code from table where ID = counter);
after = (SELECT SUBSTRING(code, CHARINDEX('.', code) + 1, LEN(code)) as Afterward from table where ID = counter);
IF before = after
THEN
update table set code = before + '.0000' where ID = counter;
ELSE
IF length(after) = 1 THEN
update table set code = before + '000' where ID = counter;
ELSE IF length(after) = 2 THEN
update table set code = before + '00' where ID = counter;
ELSE IF length(after) = 3 THEN
update table set code = before + '0' where ID = counter;
ELSE
select before;
END IF;
END IF;
counter := counter + 1;
END LOOP
END $$;
Some examples of the input/output of the intended result:
Input 55.5 > Output 55.5000
Input 55 > Output 55.0000
Thanks for your help,
Justin
There is no need for a function or even an update on the table to format values when displaying them.
Assuming the values are in fact numbers stored in a decimal or float column, all you need to do is to apply the to_char() function when retrieving them:
select to_char(code, 'FM999999990.0000')
from data;
This will output 55.5000 or 55.0000
The drawback of the to_char() function is that you need to anticipate the maximum number of digits of that can occur. If you have not enough 9 in the format mask, the output will be something like #.###. But as too many digits in the format mask don't hurt, I usually throw a lot into the format mask.
For more information on formatting functions, please see the manual: https://www.postgresql.org/docs/current/static/functions-formatting.html#FUNCTIONS-FORMATTING-NUMERIC-TABLE
If you insist on storing formatted data, you can use to_char() to update the table:
update the_table
set code = to_char(code::numeric, 'FM999999990.0000');
Casting the value to a number will of course fail if there a non-numeric values in the column.
But again: I strong recommend to store numbers as numbers, not as strings.
If you want to compare this to a user input, it's better to convert the user input to a proper number and compare that to the (number) values stored in the database.
The string matching that you are after doesn't actually require a function either. Using substring() with a regex will do that:
update the_table
set code = code || case length(coalesce(substring(code from '\.[0-9]*$'), ''))
when 4 then '0'
when 3 then '00'
when 2 then '000'
when 1 then '0000'
when 0 then '.0000'
else ''
end
where length(coalesce(substring(code from '\.[0-9]*$'), '')) < 5;
substring(code from '\.[0-9]*$') extracts everything the . followed by numbers that is at the end of the string. So for 55.0 it returns .0 for 55.50 it returns .50 if there is no . in the value, then it returns null that's why the coalesce is needed.
The length of that substring tells us how many digits are present. Depending on that we can then append the necessary number of zeros. The case can be shortened so that not all possible length have to be listed (but it's not simpler):
update the_table
set code = code || case length(coalesce(substring(code from '\.[0-9]*$'), ''))
when 0 then '.0000'
else lpad('0', 5- length(coalesce(substring(code from '\.[0-9]*$'), '')), '0')
end
where length(coalesce(substring(code from '\.[0-9]*$'), '')) < 5;
Another option is to use the position of the . inside the string to calculate the number of 0 that need to be added:
update the_table
set code =
code || case
when strpos(code, '.') = 0 then '0000'
else rpad('0', 4 - (length(code) - strpos(code, '.')), '0')
end
where length(code) - strpos(code, '.') < 4;
Regular expressions are quite expensive not using them will make this faster. The above will however only work if there is always at most one . in the value.
But if you can be sure that every value can be cast to a number, the to_char() method with a cast is definitely the most robust one.
To only process rows where the code columns contains correct numbers, you can use a where clause in the SQL statement:
where code ~ '^[0-9]+(\.[0-9][0-9]?)?$'
To change the column type to numeric:
alter table t alter column code type numeric
I have the following query
select case
when Right('BPUREN_3',1) Like '[A-Z]'
then concat('BPUREN','_1')
else
concat('BPUREN_3',right('BPUREN_3',1)+1)
End
I want output as BPUREN_4 But I am getting the result as BPUREN_34
select case
when Right('BPUREN_3',1) Like '[A-Z]' then 'BPUREN_1'
else concat(Left('BPUREN_3', 7),right('BPUREN_3',1)+1)
End
No need to concat('BPUREN','_1') it will always be 'BPUREN_1'
You could change Left('BPUREN_3', 7) to Left('BPUREN_3', LEN('BPUREN_3') - 1) if 'BPUREN_3' could change in length (for example if its a parameter in your real code)
concat('BPUREN_3', right('BPUREN_3', 1)+1) -- concat combines two strings together and returns a string. So you are combining BPUREN_3 with 4 (outputting the BPUREN_34). Instead change BUREN_3 toBPUREN_
I am trying to update a string but I also need to wipe out the rest of the values following the found string. I can't use the replace since the value at the end will change but the middle part will stay the same for many records. I haven't seen a post for removing the trailing portion of a string if you don't know it's exact value or location within the string.
I am using Oracle for my database thru SQL Developer to update the data.
"keep this data" "search on keyword" "wipe out trailing data" "result data"
xyz # psu.edu xyz
Column data value = xyz#psu.edu
I would search for a record with columnname like '#%'
Remove "#%"
End result value = xyz
Column data value = ABCabc123
I would search for a record with columnname like 'abc%'
Remove "abc%"
End result value = ABC
I have not seen any answers with this type of update. Please help!
select substr('xyz#psu.edu',1, instr('xyz#psu.edu','#') - 1) from dual
select substr('ABCabc123',1, instr('ABCabc123','abc') - 1) from dual
You might need to check in case the string you want is not found:
SELECT CASE
WHEN INSTR('xyz#psu.edu','#', 1, 1) > 0
THEN SUBSTR('xyz#psu.edu',1,INSTR('xyz#psu.edu','#', 1, 1)-1)
ELSE 'xyz#psu.edu'
END as "Result Data"
FROM DUAL
oI have a teradata table with about 10 million records in it, that stores a numeric id field as a varchar. i need to transfer the values in this field to a bigint column in another table, but i can't simply say cast(id_field as bigint) because i get an invalid character error. looking through the values, i find that there could be a character at any position in the string, so let's say the string is varchar(18) i could filter out invalid rows like so :
where substr(id_field,1,1) not in (/*big,ugly array of non-numeric chars*/)
and substr(id_field,2,1) not in (/*big,ugly array of non-numeric chars*/)
etc, etc...
then the cast would work, but this is not feasible in the long run. it's slow and if the string has 18 possible characters, it makes the query unreadable. how can i filter out rows that have a value in this field that will not cast as a bigint without checking each character individually for an array of non-numeric characters?
example values would be
123abc464
a2.3v65
a_356087
........
000000000
BOB KNIGHT
1235468099
the values follow no specific patterns, I simply need to filter out the ones that contain ANY non-numeric data.
123456789 is okay but 123.abc_c3865 is not...
Starting with TD14 Teradata added some functions, now there are multiple ways, e.g.:
WHERE RTRIM(col, '0123456789') = ''
But the easiest way is TO_NUMBER, which returns NULL for bad data:
TO_NUMBER(col)
The best that I've ever managed is this:
where char2hexint(upper(id_field)) = char2hexint(lower(id_field))
Since upper case characters give a different hex value to lower case ones, this will ensure that you have no alphabetical characters, but will still leave you with underscores, colons and so forth. If this doesn't meet your requirements, you may need to write an UDF.
could we also try to divide the values in the field by some integer "if divided then must be a number and if not and throws some error,then must have some character...." guess this would be lot fast as has just mathematics involved...
I've faced the same issue to try to exclude alpha characters from street address house numbers. The following will work if you don't mind concatanating all the numeric numbers together......
It checks if the upper of a string equals the lower of the string, if so it's a number, if not it becomes null.
select cast(case when upper(substring('12E'from 1 for 1)) = lower(substring('12E'from 1 for 1)) then substring('12E'from 1 for 1) else null end ||
case when upper(substring('12E'from 2 for 1)) = lower(substring('12E'from 2 for 1)) then substring('12E'from 2 for 1) else null end ||
case when upper(substring('12E'from 3 for 1)) = lower(substring('12E'from 3 for 1)) then substring('12E'from 3 for 1) else null end ||
case when upper(substring('12E'from 4 for 1)) = lower(substring('12E'from 4 for 1)) then substring('12E'from 4 for 1) else null end ||
case when upper(substring('12E'from 5 for 1)) = lower(substring('12E'from 5 for 1)) then substring('12E'from 5 for 1) else null end ||
case when upper(substring('12E'from 2 for 1)) = lower(substring('12E'from 2 for 1)) then substring('12E'from 2 for 1) else null end
as integer)
Try using this code segment
WHERE id_Field NOT LIKE '%[^0-9]%'
I found lins314159 answer to be very helpful with a similar issue. It may be an old thread but for what it's worth, I used:
char2hexint(upper(id_field)) = char2hexint(lower(id_field)) AND substr(id_field,1,1) IN ('1' to '9')
to successfully cast the remaining VARCHAR results to INT
SELECT customer_id
FROM t
WHERE UPPER(customer_id)(CASESPECIFIC) <>
LOWER(customer_id)(CASESPECIFIC);
This works perfectly fine to check whether the values in a numeric field is non-numeric.
SELECT id_field
WHERE oTranslate(id_field, '0123456789','')<>'';
This works well for me! It reveals any id_field containing a non-numeric value