SQL sum of different status within 24 hrs group by hours - sql

Question

I am trying to sum status within 24 hour groups by hours. I have an order, order status and status table.
Order Table:
+---------+-------------------------+
| orderid | orderdate |
+---------+-------------------------+
| 1 | 2015-09-16 00:04:19.100 |
| 2 | 2015-09-16 00:01:19.490 |
| 3 | 2015-09-16 00:02:33.733 |
| 4 | 2015-09-16 00:03:58.800 |
| 5 | 2015-09-16 00:01:16.020 |
| 6 | 2015-09-16 00:01:16.677 |
| 7 | 2015-09-16 00:02:06.920 |
+---------+-------------------------+
Order Status Table:
+---------+----------+
| orderid | statusid |
+---------+----------+
| 1 | 11 |
| 2 | 22 |
| 3 | 22 |
| 4 | 11 |
| 5 | 22 |
| 6 | 33 |
| 7 | 11 |
+---------+----------+
Status Table:
+----------+----------+
| statusid | status |
+----------+----------+
| 11 | PVC |
| 22 | CCC |
| 33 | WWW |
| | |
+----------+----------+
I am try to write SQL that display the count of the status within 24 hours for distinct orderids grouped by hour like below:
+------+-----+-----+-----+
| Hour | PVC | CCC | WWW |
+------+-----+-----+-----+
| 1 | 0 | 2 | 1 |
| 2 | 1 | 1 | 0 |
| 3 | 1 | 0 | 0 |
| 4 | 1 | 0 | 0 |
+------+-----+-----+-----+
This is my SQL so far. I am stuck trying to get the sum of each order status:
SELECT
DATEPART(hour, o.orderdate) AS Hour,
SUM(
CASE (
SELECT stat.status
FROM Status stat, orderstatus os
WHERE stat.status IN ('PVC') AND os.orderid = o.id AND os.statusid = stat.id
)
WHEN 'PVC' THEN 1
ELSE 0
END
) AS PVC,
SUM(
CASE (
SELECT stat.status
FROM Status stat, orderstatus os
WHERE stat.status IN ('WWW') AND os.orderid = o.id AND os.statusid = stat.id
)
WHEN 'CCC' THEN 1
ELSE 0
END
) AS CCC,
SUM(
CASE (
SELECT stat.status
FROM Status stat, orderstatus os
WHERE stat.status IN ('CCC') AND os.orderid = o.id AND os.statusid = stat.id)
WHEN 'WWW' THEN 1
ELSE 0
END
) AS WWW
FROM orders o
WHERE o.orderdate BETWEEN DATEADD(d,-1,CURRENT_TIMESTAMP) AND CURRENT_TIMESTAMP
GROUP BY DATEPART(hour, o.orderdate)
ORDER BY DATEPART(hour, o.orderdate);

Answer 1

Here you go -- I'm ignoring the errors in your data since this will fail if the status table really had duplicate ids like in your example data.
SELECT hour, sum(PVC) as PVC, sum(CCC) as CCC, sum(WWW) as WWW
from (
select datepart(hour,orderdate) as hour,
case when s.status = 'PVC' then 1 else 0 end as PVC,
case when s.status = 'CCC' then 1 else 0 end as CCC,
case when s.status = 'WWW' then 1 else 0 end as WWW
from order o
join orderstatus os on o.orderid = os.orderid
join status s on s.statusid = os.statusid
) sub
group by hour

Answer 2

this should get you closer, then you have to pivot:
SELECT
DATEPART(HOUR,o.orderdate) AS orderDate_hour,
s.status,
COUNT(DISTINCT o.orderid) AS count_orderID
FROM
orders o INNER JOIN
orderstatus os ON
o.orderid = os.orderid INNER JOIN
status s ON
os.statusid = s.statusid
WHERE
o.orderdate >= DATEADD(d,-1,CURRENT_TIMESTAMP)
GROUP BY
DATEPART(HOUR,o.orderdate) , s.status
ORDER BY
DATEPART(HOUR,o.orderdate)
try this for the pivot:
SELECT
*
FROM
(SELECT
DATEPART(HOUR,o.orderdate) AS orderDate_hour,
s.status,
COUNT(DISTINCT o.orderid) AS count_orderID
FROM
orders o INNER JOIN
orderstatus os ON
o.orderid = os.orderid INNER JOIN
status s ON
os.statusid = s.statusid
WHERE
o.orderdate >= DATEADD(d,-1,CURRENT_TIMESTAMP)
GROUP BY
DATEPART(HOUR,o.orderdate) , s.status) s
PIVOT ( MAX(count_orderID) FOR status IN ('pvc','ccc','www')) AS p
ORDER BY
orderDate_hour