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I have a table X which holds data for each day for a brand. The data for each day is cumulative i.e. sales data for 3 will have data for 1, 2 and 3. Thus data for the last day of each month will be the sales for that month for that brand and company. I want to get the sum of all the sales for that brand for the last 3 months excluding the current month on the last day of each month.
i.e for March: I want sales from 31st Jan 2019 + 28th Feb 2019 + 31st Dec 2018 for each brand and company.
How can I achieve this?
if you are using MSSQL you can use EOMONTH function, example is as under
DECLARE #date VARCHAR(255) = '2/24/2019';
SELECT EOMONTH ( #date ) AS Result;
for MySQL you can use LAST_DAY function
SELECT LAST_DAY('2019-02-24');
Let's say name of your column representing the sales date is "sales_date", then the following predicate will give you the days you're interested in:
sales_date in (
dateadd(day, -1, dateadd(month, datediff(month, 0, getdate()) - 2, 0)),
dateadd(day, -1, dateadd(month, datediff(month, 0, getdate()) - 1, 0)),
dateadd(day, -1, dateadd(month, datediff(month, 0, getdate()), 0))
)
I am trying to aggregate data by weeks. My sample query looks like
SET DATEFIRST 1
Select ID,
DATENAME(week, p.SellingDate) as SellingWeek,
DATENAME(year, p.SellingDate) as SellingYear,
SUM(Quantity),
SUM(Revenue)
From dbo.Sales
Where
p.SellingDate >=’2015-12-20’ and P.SellingDate < ’2016-02-27’
Group by ID,
DATENAME(week, p.SellingDate),
DATENAME(year, p.SellingDate)
When I try to do this, I am facing an issue:
The query returns correct data but the issue appears in the last week of 2015. It considers only the days (12/28 to 12/31) that are part of 2015 as the 53rd week and it considers the remaining part (01/01 to 01/03) as a new week of 2016. I only one row that has data for the whole week i.e. 12/28 to 01/03) but SQL Server returns 2 rows. Is there a workaround this?
I would think you want to create a construct for grouping on week start and week end, then using that to group by for your aggregation clauses.
SET DATEFIRST 1
Select DATEADD(dd, -(DATEPART(dw, p.SellingDate)-1), p.SellingDate) AS [WeekStart],
DATEADD(dd, 7-(DATEPART(dw, p.SellingDate)), p.SellingDate) AS [WeekEnd],
SUM(Quantity),
SUM(Revenue)
From dbo.Sales
Where
p.SellingDate >= '2015-12-20' and P.SellingDate < '2016-02-27'
Group by ID,
DATEADD(dd, -(DATEPART(dw, p.SellingDate)-1), p.SellingDate),
DATEADD(dd, 7-(DATEPART(dw, p.SellingDate)), p.SellingDate)
You can fix this by setting the week not based on the date of the sale but rather on the monday of week of the date of the sale.
select
getdate() as today
datename(week, dateadd(dd,-1* (datepart(weekday, getdate())-1),getdate())) as monday,
I wrote this query to find orders placed on last day of any month.
I know this approach is not recommended if orderdate is indexed. What approach should i use to make it sargable?
select o.orderid, o.orderdate, o.custid, o.empid
from sales.Orders o
where day(o.orderdate) in (30, 31)
or (month(o.orderdate) = 02 and day(o.orderdate)= 28)
or (month(o.orderdate) = 02 and day(o.orderdate)= 29);
You can do this with computed columns:
alter table Orders add column nextdayofmonth as day(dateadd(day, 1, orderdate));
create index orders_nextdayofmonth on orders(orders_nextdayofmonth);
The nextdayofmonth is for the next day, so leap years can easily be handled. After all, the day after the "last day" is the "first day" of the next month.
Then phrase your query as:
where next_dayofmonth = 1
This expression is sargable.
DATEADD is sargable:
WHERE DATEADD(day, DATEDIFF(day, 0, o.orderdate), 0) =
DATEADD(day, -1, DATEADD(month, DATEDIFF(month, 0, o.orderdate) + 1, 0))
The first is just the old way to truncate the time from a datetime. The second adds one month, "truncates" the month and subtracts a day.
Here's a fiddle that returns the last day of the current month with the same "trick".
This query would fail for leap years as it would give you 2 dates as the last day of the month in February. To make it SARGable, you would need to take out the functions on the date column.
This should work fine
select o.orderid, o.orderdate, o.custid, o.empid
from sales.Orders o
where
day(o.orderdate)=day(DATEADD(ms, -3, DATEADD(mm, DATEDIFF(m, 0,o.orderdate) + 1, 0)))
The below query gives the last day of current month, replace getdate() with the date variable as shown above:
SELECT day(DATEADD(ms, -3, DATEADD(mm, DATEDIFF(m, 0, GETDATE()) + 1, 0)))
You can also do is:
select TOP 1 orderid, orderdate, custid, empid
from sales.Orders
ORDER BY orderdate DESC
Get all dates that DAY part of its tomorrow is 1:
SELECT *
FROM Sales.Orders
WHERE DAY(DATEADD(dd, 1, orderdate)) = 1
This question already has answers here:
Get the records of last month in SQL server
(23 answers)
Closed 9 years ago.
How can I get last month date like
select * from table where date in ( last month )
I dont want the last 30 days
AND how can I get last month automatically
Assuming you want all items where the date is within the last month i.e. between today and 30/31 days ago:
Select *
From Table
Where Date Between DATEADD(m, -1, GETDATE()) and GETDATE()
You can use this
Select * from table where date between #startdate and #enddate
Or
SELECT * FROM DATE_SAMPLE WHERE
DATEPART(YEAR, SAMPLE_DATE) = '2013' AND
DATEPART(MONTH,SAMPLE_DATE) = '01' AND
DATEPART(DAY, SAMPLE_DATE) = '01'
Is it usefull for you?
select * from table
where month(date)=month(getdate())-1
Edit
if you mean last month from today. or previous month from a specific date then you need to do something like this
SELECT DATEPART(MONTH, DATEADD(MONTH, -1, [Date]))
Or to get records from previous month of the year you can do something like this
SELECT * FROM Table
WHERE MONTH(Date) = DATEPART(MONTH, DATEADD(MONTH, -1, [Date]))
AND YEAR(Date) = DATEPART(YEAR, DATEADD(MONTH, -1, [Date])) --<-- or pass year for which year you are checking
To make your aquery SARGable (Suggested by t-clausen.dk)
select * from table
where date >=dateadd(m, datediff(m, 0, current_timestamp)-1, 0)
and date < dateadd(m, datediff(m, 0, current_timestamp)-1, 0)
Read here more about sargable Queries when working with date/datetime datatypes.
You can try to use the between statement to get the specific dates:
Select * from table where date between '01-01-2014' and '14-01-2014'
Specifically MSSQL 2005.
Here's a solution that gives you the last second of the current month. You can extract the date part or modify it to return just the day. I tested this on SQL Server 2005.
select dateadd( s, -1, dateadd( mm, datediff( m, 0, getdate() ) + 1, 0 ) );
To understand how it works we have to look at the dateadd() and datediff() functions.
DATEADD(datepart, number, date)
DATEDIFF(datepart, startdate, enddate)
If you run just the most inner call to datediff(), you get the current month number since timestamp 0.
select datediff(m, 0, getdate() );
1327
The next part adds that number of months plus 1 to the 0 timestamp, giving you the starting point of the next calendar month.
select dateadd( mm, datediff( m, 0, getdate() ) + 1, 0 );
2010-09-01 00:00:00.000
Finally, the outer dateadd() just subtracts one second from the beginning timestamp of next month, giving you the last second of the current month.
select dateadd( s, -1, dateadd( mm, datediff( m, 0, getdate() ) + 1, 0 ) );
2010-08-31 23:59:59.000
This old answer (below) has a bug where it doesn't work on the last day of a month that has more days than the next month. I'm leaving it here as a warning to others.
Add one month to the current date, and then subtract the value returned by the DAY function applied to the current date using the functions DAY and DATEADD.
dateadd(day, -day(getdate()), dateadd(month, 1, getdate()))
SELECT DATEADD(M, DATEDIFF(M, '1990-01-01T00:00:00.000', CURRENT_TIMESTAMP), '1990-01-31T00:00:00.000')
Explanation:
General approach: use temporal functionality.
SELECT '1990-01-01T00:00:00.000', '1990-01-31T00:00:00.000'
These are DATETIME literals, being the first time granule on the first day and last day respectively of the same 31-day month. Which month is chosen is entirely arbitrary.
SELECT DATEDIFF(M, '1990-01-01T00:00:00.000', CURRENT_TIMESTAMP)
This is the difference in whole months between the first day of the reference month and the current timestamp. Let's call this #calc.
SELECT DATEADD(M, #calc, '1990-01-31T00:00:00.000')
This adds #calc month granules to the last day of the reference month, the result of which is the current timestamp 'rounded' to the last day of its month. Q.E. D.
Try this:
DATEADD (DAY, -1, DATEADD (MONTH, DATEDIFF (MONTH, 0, CURRENT_TIMESTAMP) + 1, 0)
They key points are if you can get first day of current month,Last Day of Last Month and Last Day of Current Month.
Below is the Step by Step way to write query:
In SQL Server Date Starts from 1901/01/01( Date 0) and up to now each month can be identified by a number. Month 12 is first month of 1902 means January. Month 1200 is January of 2001. Similarly each day can be assigned by unique number e.g Date 0 is 1901/01/01. Date 31 is 1901/02/01 as January of 1901 starts from 0.
To find out First day of Current Month(Current Date or a given date)
First we need to check how many months have passed since date 0(1901/01/01).
SELECT DATEDIFF(MM,0,GETDATE())
Add same number of month to date 0(1901/01/01)
SELECT DATEADD(MM, DATEDIFF(MM,0,GETDATE()),0)
Then we will get first day of current month(Current Date or a given date)
To get Last Day of Last Month
We need to subtract a second from first day of current month
SELECT DATEADD(SS,-1,DATEADD(MM, DATEDIFF(MM,0,GETDATE()),0))
To get Last Day of Current Month
To get first day of current month first we checked how many months have been passed since date 0(1901/01/01). If we add another month with the total months since date 0 and then add total months with date 0, we will get first day of next month.
SELECT DATEADD(MM, DATEDIFF(MM,0,GETDATE())+1,0)
If we get first day of next month then to get last day of current month, all we need to subtract a second.
SELECT DATEADD(SS,-1,DATEADD(MM, DATEDIFF(MM,0,GETDATE())+1,0))
Hope that would help.
Using SQL2005, you do not have access to a helpful function EOMONTH(), So you must calculate this yourself.
This simple function will works similar to EOMONTH
CREATE FUNCTION dbo.endofmonth(#date DATETIME= NULL)
RETURNS DATETIME
BEGIN
RETURN DATEADD(DD, -1, DATEADD(MM, +1, DATEADD(DD, 1 - DATEPART(DD, ISNULL(#date,GETDATE())), ISNULL(#date,GETDATE()))))
END
Query to perform:
SELECT dbo.endofmonth(DEFAULT) --Current month-end date
SELECT dbo.endofmonth('02/25/2012') --User-defined month-end date
Some links to possible answers:
http://www.extremeexperts.com/sql/Tips/DateTrick.aspx
http://www.devx.com/tips/Tip/14405
http://blog.sqlauthority.com/2007/08/18/sql-server-find-last-day-of-any-month-current-previous-next/
http://www.sqlservercurry.com/2008/03/find-last-day-of-month-in-sql-server.html
DECLARE
#Now datetime,
#Today datetime,
#ThisMonth datetime,
#NextMonth datetime,
#LastDayThisMonth datetime
SET #Now = getdate()
SET #Today = DateAdd(dd, DateDiff(dd, 0, #Now), 0)
SET #ThisMonth = DateAdd(mm, DateDiff(mm, 0, #Now), 0)
SET #NextMonth = DateAdd(mm, 1, #ThisMonth)
SET #LastDayThisMonth = DateAdd(dd, -1, #NextMonth)
Sometimes you really do need the last day of this month, but frequently what you really want is to describe the time interval of this month. This is the best way to describe the time interval of this month:
WHERE #ThisMonth <= someDate and someDate < #NextMonth
For completeness, in Oracle you'd do something like ...
select add_months(trunc(sysdate,'MM'),1) ...
or
select last_day(sysdate)+1 ...
DATEADD(dd, -1, DATEADD(mm, +1, DATEADD(dd, 1 - DATEPART(dd, #myDate), #myDate)))