The following SQL statement sets the date for a particular column:
DATEDUE=convert(varchar,GETDATE(),103 )
However, its sets the current date such as 05/08/2015. What I wish to do is to have it in the same dd/mm/yyyy format but to set the day to the 15th and the month to the previous month, so 05/08/2015 should be 15/07/2015 instead.
select CONVERT(VARCHAR(10),
DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE())-1, 0) + 14
,103)
Result: 15/07/2015
Important Note
Since DATEDUE column is storing dates, you should really use the sql server DATE data type for storing date values in that column.
if you decide you just need the most recent previous 15th of the month you can use this.
SELECT CONVERT(VARCHAR(10),
DATEADD(DAY,14,DATEADD(MONTH,DATEDIFF(MONTH,0,GETDATE()) -
(CASE WHEN DATEPART(DAY,GETDATE()) > 15 THEN 0 ELSE 1 END), 0)),
103)
05/08/2015 becomes 15/07/2015 and 24/08/2015 becomes 15/08/2015 instead of 15/07/2015
Related
Hello I'm looking for simple way, how to get data from previous month. I get this code but it didn't work in January (result is 12 2021 and I need 12 2020)
select month(dateadd(month,-1,getdate())), year(getdate())
Presumably, you have some sort of date column.
In SQL Server, you can express this concept using datediff():
where datediff(month, datecol, getdate()) = 1
However, that is not "sargable", meaning that it prevents the use of indexes. So, I would instead recommend:
where datecol < datefromparts(year(getdate()), month(getdate()), 1) and
datecol >= dateadd(month, 1, datefromparts(year(getdate()), month(getdate()), 1))
If you simply want the first day of the previous month, you can use:
dateadd(month, 1, datefromparts(year(getdate()), month(getdate()), 1))
Try This
select CASE WHEN month(getdate())>1 THEN month(getdate())-1 ELSE 12 END ,
CASE WHEN month(getdate())>1 THEN YEAR (getdate()) ELSE YEAR (getdate()) -1 END
Using the answer given here: How can I select the first day of a month in SQL?
SELECT dateadd(month,-1,DATEADD(month, DATEDIFF(month, 0, getdate()), 0)) as previousmonth;
output:
2020-12-01 00:00:00.000
I can provide next query using FORMAT function:
SELECT
-- get current day in previous month
FORMAT(dateadd(month, -1, getdate()), 'yyyy-MM-dd') as current_previousmonth,
-- get first of previous month
FORMAT(dateadd(month, -1, getdate()), 'yyyy-MM-01') as first_previousmonth,
-- previous month without date
FORMAT(dateadd(month, -1, getdate()), 'yyyy-MM') as previousmonth;
test T-SQL here
Here you go!
select dateadd(mm,-1,eomonth(getdate())) as [Previous Month]
Result:
Previous Month
--------------
2020-12-31
You could also use CONVERT() or FORMAT() functions to format the date as you desire.
Try
SELECT FORMAT(DATEADD(month, -1, GETDATE()),'MM/yyyy');
It will give you previous month and the year. If you are comparing to a date column in a existing table, then you need the date part too as you want to know December of which year was the previous month. But if you don't want the year, then just adjust the 'MM/yyyy' part to suit your purpose.
dateadd(mm, DATEPART(MONTH, DATE) - 1, 0) + DATEPART(DAY, DATE) - 1
OUTPUT date is in the year for example 1990-12-02 00:00:00:000
Full query is below:
SELECT dateadd(yy, (
DATEPART(YEAR, GETDATE()) + (
CASE
WHEN DATEPART(MONTH, GP_DATE) > 10
THEN 0
ELSE 1
END
) - 1900
), 0) + dateadd(mm, DATEPART(MONTH, GP_DATE) - 1, 0) + DATEPART(DAY, GP_DATE) - 1 GP_DATE
from table
I am trying to convert this query into snowflake syntax and snowflake syntax dateadd function does not allow 1, 0.
In SQL Server, there are some rather ugly implicit conversions available between datetimes and integers.
0, when converted to a date, becomes 1900-01-01.
You're also allowed to do maths on dates. Adding or subtracting 1 adds or subtracts 1 day from the date. Putting these facts together, we have:
dateadd(yy, (
DATEPART(YEAR, GETDATE()) + (
CASE
WHEN DATEPART(MONTH, GP_DATE) > 10
THEN 0
ELSE 1
END
) - 1900
), 0)
Which is taking the current year, and subtracting 1900 from it (or 1899 if the month is less than 11, for whatever reason). We then take that number and add it back to the date 0 (which as stated above is 1900-01-01). The result is that we get the first of January of next year or this year, depending on the month of GP_DATE. Call this D1.
Moving on:
dateadd(mm, DATEPART(MONTH, GP_DATE) - 1, 0)
is taking the month of GP_DATE, subtracting 1 from it and adding that number of months to the date 0 (1900-01-01). The result is a the 1st of whichever month GP_DATE is in, but in 1900. Let's call this D2.
When we add D1 and D2 together, we approximately get a date of the 1st of whichever month GP_DATE is in, in either this year or next year. Note, however, that this goes wrong if the D1 year is a leap year, we get it wrong by a day for months after February.
Finally, we take DATEPART(DAY, GP_DATE) - 1, where we take the day of the month from GP_DATE, subtract 1, and add that on to our result so far. This should set the final date to be on the same day of the month as GP_DATE, except for the error mentioned above.
So, it appears that the code is trying to take GP_DATE and get the same date in either this year or next year, depending on how late in the year GP_DATE is. However, it also appears it was never tested with consideration for leap years.
A far more likely correct version of this query would be this instead:
SELECT
DATEADD(year,
DATEDIFF(year,GP_DATE,CURRENT_TIMESTAMP) +
CASE WHEN DATEPART(month,GP_DATE)>10 THEN 0 ELSE 1 END
,GP_DATE)
How to get the current month end date through db2 query.
I should not need to modify the query for every month
Every month the sql is executing so it need to automatically take care
In Db2 11.1 this could be a solution:
select next_month(current date) - 1 day from sysibm.sysdummy1
Next_Month will return the first day of the next month from the data provided.
SELECT LAST_DAY(CURRENT_DATE) AS LASTDAY
FROM SYSIBM.SYSDUMMY1;
The query is working
LASTDAY
2019-04-30
The old way would be
CURRENT DATE - (DAY(CURRENT DATE)) DAYS + 1 MONTH
To get the last day of the current month, use this:
SELECT DATEADD (dd, -1, DATEADD(mm, DATEDIFF(mm, 0, GETDATE()) + 1, 0))
This will format the date for you
SELECT CONVERT(VARCHAR(10), DATE, 12)
See this for more information regarding the '12'. 12 is the right code
Another solution is to use TIMESTAMP_FORMAT as such:
TIMESTAMP_FORMAT('190404', 'YYMMDD')
i need help on my little problem.
SELECT FORMAT(ServiceDate, 'dd-MM-yyy") AS ServiceDate
FROM Services
WHERE Day(ServiceDate) BETWEEN '1' AND Day(getdate() -2)
AND Month(ServiceDate) =
CASE
WHEN Day(getdate()) <=2
THEN Month(getdate() -1
ELSE Month(getdate())
END
AND Year(ServiceDate) = Year(getdate())
Now the problem is the first and the second of the Month.
The query don't use the last month. It shows the actual month.
I hope its clear what i need.
if we have the 01-06-2016 and i need minus 2, so the query must give me back to the day 30-05-2016
big THX
the output for today with this query
output query
Assuming you are using sql-server, you need to use DATEADD(Day, -2, GETDATE()) for subtracting 2 days from current date.
I think I understand the logic now:
If the current day is the 1st of the month, get all the records from the start of previous month, until 2 days before it ends.
If the current day is the 2nd of the month, get all the records from the start of the previous month until one day before it ends.
If the current day is the 3rd of the month or higher, get all the records from the beginning of the current month until 2 days ago.
Since you are using the FORMAT() function that was introduced in 2012 version, you can also use the EOMONTH() function that was introduced in the same version.
This function returns the date of the end of the month of the date it receives as an argument, and also have a useful optional second argument that specifies the numbers of months to add to the date passed to the function.
Using this function will allow you to write your query without using any functions on the ServiceDate column, thus enabling the use of any indexes defined on this column.
DECLARE #Now datetime = GETDATE()
SELECT FORMAT(ServiceDate, 'dd-MM-yyy') AS ServiceDate
FROM Services
WHERE (
DAY(#Now) <= 2
AND ServiceDate >= DATEADD(DAY, 1, EOMONTH(#Now, -2))
AND ServiceDate < DATEADD(DAY, -(DAY(#Now)-1), EOMONTH(#Now, -1))
)
OR
(
DAY(GETDATE()) > 2
AND ServiceDate >= DATEADD(DAY, 1, EOMONTH(#Now, -1))
AND ServiceDate < DATEADD(DAY, -2, #Now)
)
Compute enddate as 2 days before getdate() and select data in interval from enddate's first of month and enddate.
SELECT FORMAT(ServiceDate, 'dd-MM-yyy") AS ServiceDate
FROM Services
CROSS APPLY (SELECT enddate = DATEADD(D,-2,getdate()) x
WHERE ServiceDate BETWEEN DATEADD(MONTH,DATEDIFF(MONTH,0,x.enddate),0) AND x.enddate
Specifically MSSQL 2005.
Here's a solution that gives you the last second of the current month. You can extract the date part or modify it to return just the day. I tested this on SQL Server 2005.
select dateadd( s, -1, dateadd( mm, datediff( m, 0, getdate() ) + 1, 0 ) );
To understand how it works we have to look at the dateadd() and datediff() functions.
DATEADD(datepart, number, date)
DATEDIFF(datepart, startdate, enddate)
If you run just the most inner call to datediff(), you get the current month number since timestamp 0.
select datediff(m, 0, getdate() );
1327
The next part adds that number of months plus 1 to the 0 timestamp, giving you the starting point of the next calendar month.
select dateadd( mm, datediff( m, 0, getdate() ) + 1, 0 );
2010-09-01 00:00:00.000
Finally, the outer dateadd() just subtracts one second from the beginning timestamp of next month, giving you the last second of the current month.
select dateadd( s, -1, dateadd( mm, datediff( m, 0, getdate() ) + 1, 0 ) );
2010-08-31 23:59:59.000
This old answer (below) has a bug where it doesn't work on the last day of a month that has more days than the next month. I'm leaving it here as a warning to others.
Add one month to the current date, and then subtract the value returned by the DAY function applied to the current date using the functions DAY and DATEADD.
dateadd(day, -day(getdate()), dateadd(month, 1, getdate()))
SELECT DATEADD(M, DATEDIFF(M, '1990-01-01T00:00:00.000', CURRENT_TIMESTAMP), '1990-01-31T00:00:00.000')
Explanation:
General approach: use temporal functionality.
SELECT '1990-01-01T00:00:00.000', '1990-01-31T00:00:00.000'
These are DATETIME literals, being the first time granule on the first day and last day respectively of the same 31-day month. Which month is chosen is entirely arbitrary.
SELECT DATEDIFF(M, '1990-01-01T00:00:00.000', CURRENT_TIMESTAMP)
This is the difference in whole months between the first day of the reference month and the current timestamp. Let's call this #calc.
SELECT DATEADD(M, #calc, '1990-01-31T00:00:00.000')
This adds #calc month granules to the last day of the reference month, the result of which is the current timestamp 'rounded' to the last day of its month. Q.E. D.
Try this:
DATEADD (DAY, -1, DATEADD (MONTH, DATEDIFF (MONTH, 0, CURRENT_TIMESTAMP) + 1, 0)
They key points are if you can get first day of current month,Last Day of Last Month and Last Day of Current Month.
Below is the Step by Step way to write query:
In SQL Server Date Starts from 1901/01/01( Date 0) and up to now each month can be identified by a number. Month 12 is first month of 1902 means January. Month 1200 is January of 2001. Similarly each day can be assigned by unique number e.g Date 0 is 1901/01/01. Date 31 is 1901/02/01 as January of 1901 starts from 0.
To find out First day of Current Month(Current Date or a given date)
First we need to check how many months have passed since date 0(1901/01/01).
SELECT DATEDIFF(MM,0,GETDATE())
Add same number of month to date 0(1901/01/01)
SELECT DATEADD(MM, DATEDIFF(MM,0,GETDATE()),0)
Then we will get first day of current month(Current Date or a given date)
To get Last Day of Last Month
We need to subtract a second from first day of current month
SELECT DATEADD(SS,-1,DATEADD(MM, DATEDIFF(MM,0,GETDATE()),0))
To get Last Day of Current Month
To get first day of current month first we checked how many months have been passed since date 0(1901/01/01). If we add another month with the total months since date 0 and then add total months with date 0, we will get first day of next month.
SELECT DATEADD(MM, DATEDIFF(MM,0,GETDATE())+1,0)
If we get first day of next month then to get last day of current month, all we need to subtract a second.
SELECT DATEADD(SS,-1,DATEADD(MM, DATEDIFF(MM,0,GETDATE())+1,0))
Hope that would help.
Using SQL2005, you do not have access to a helpful function EOMONTH(), So you must calculate this yourself.
This simple function will works similar to EOMONTH
CREATE FUNCTION dbo.endofmonth(#date DATETIME= NULL)
RETURNS DATETIME
BEGIN
RETURN DATEADD(DD, -1, DATEADD(MM, +1, DATEADD(DD, 1 - DATEPART(DD, ISNULL(#date,GETDATE())), ISNULL(#date,GETDATE()))))
END
Query to perform:
SELECT dbo.endofmonth(DEFAULT) --Current month-end date
SELECT dbo.endofmonth('02/25/2012') --User-defined month-end date
Some links to possible answers:
http://www.extremeexperts.com/sql/Tips/DateTrick.aspx
http://www.devx.com/tips/Tip/14405
http://blog.sqlauthority.com/2007/08/18/sql-server-find-last-day-of-any-month-current-previous-next/
http://www.sqlservercurry.com/2008/03/find-last-day-of-month-in-sql-server.html
DECLARE
#Now datetime,
#Today datetime,
#ThisMonth datetime,
#NextMonth datetime,
#LastDayThisMonth datetime
SET #Now = getdate()
SET #Today = DateAdd(dd, DateDiff(dd, 0, #Now), 0)
SET #ThisMonth = DateAdd(mm, DateDiff(mm, 0, #Now), 0)
SET #NextMonth = DateAdd(mm, 1, #ThisMonth)
SET #LastDayThisMonth = DateAdd(dd, -1, #NextMonth)
Sometimes you really do need the last day of this month, but frequently what you really want is to describe the time interval of this month. This is the best way to describe the time interval of this month:
WHERE #ThisMonth <= someDate and someDate < #NextMonth
For completeness, in Oracle you'd do something like ...
select add_months(trunc(sysdate,'MM'),1) ...
or
select last_day(sysdate)+1 ...
DATEADD(dd, -1, DATEADD(mm, +1, DATEADD(dd, 1 - DATEPART(dd, #myDate), #myDate)))