I have a 10 Character length values in a column in SQL Server. I need to split that column at fixed length and remove the leading zeros and add a - after each of the values.
I am able to split the values by using Substring and converting them to int. It is working well.
However, when I try to concatenate it is failing. Appreciate if you can help.
SELECT TOP 1 R.COL1, CAST(SUBSTRING(R.COL1,1,1) AS int) AS F1,CAST(SUBSTRING(R.COL1,2,5) AS int) AS F2,CAST(SUBSTRING(R.COL1,7,4) AS int) AS F3 CAST(SUBSTRING(R.COL1,1,1) AS int) +'-' +CAST(SUBSTRING(R.COL1,2,5) AS int) +'-' + CAST(SUBSTRING(R.COL1,7,4) AS int) AS finalString FROM MYTABLE R
If the value for COL1 IS 1012950001 the finalString I am expecting is 1-1295-1
however the result I am getting from the above query is 1297 as it is adding all the values.
Appreciate if you can help.
You can't use the + operator with a numerical data type and a varchar that cannot implicitly be converted to that data type. Something like 1 + 'a' isn't going to work, as 'a' isn't an int, and can't be implicitly converted to one.
If you are mixing data types, then use CONCAT, which implicitly converts each part into a (n)varchar:
CONCAT({Numerical Expression},'a',{Other varchar Expression})
You can use concat method to concatenate the substring value
select
concat(CAST(SUBSTRING('1012950001',1,1) AS int), '-',
CAST(SUBSTRING('1012950001',2,5) AS int), '-',
CAST(SUBSTRING('1012950001',7,4) AS int)) AS finalString
This will give you the expected result '1-1295-1'
I have a Varchar column which have data such as 1.025407162E7, 1.268479084E7 basically it contains something called as E7. How can i convert it to decimal ?
I have tried to convert it to decimal, I could have removed the E7 and moved the decimal point 7 steps forward or Add 7 zeros if there are no so many numbers. But I was looking for a right approach to do it.
CONVERT(DECIMAL(27, 7), ETL_AM.BNK_SHR_LGR_BAL_AMT)
So the actual values look different
1.025407162E7 = 10254071.6200000 and 1.268479084E7 = 12684790.8400000
That's a valid float constant for SQL Server. So convert the string to a float, and then to a decimal.
CONVERT(DECIMAL(27, 7), cast(ETL_AM.BNK_SHR_LGR_BAL_AMT as float))
eg
select convert(decimal(27,7), cast( '1.025407162E7' as float) )
returns
10254071.6200000
Okay, So Error_2646 has taken me in right direction. I converted the value to REAL then converted to decimal.
CASE WHEN SF_FAM.FinServ__Balance__c like '%E%' THEN CONVERT(DECIMAL(27, 7), CONVERT(float(27), SF_FAM.FinServ__Balance__c))
ELSE CONVERT(DECIMAL(27, 7), SF_FAM.FinServ__Balance__c) END
If it is an exponential function, a simple select, after converting it to a float can give you the decimal.
SELECT CAST('1.025407162E7' AS FLOAT)
Otherwise, if E is a random character and if you want to do the calculatoin, you can do it using a case statement.
DECLARE #value VARCHAR(100)
SET #value = '1.025407162E7'
SELECT CASE WHEN #value like '%E7%'
THEN (1.025407162 * 10000000)
END
I am trying to accommodate for some rogue values in my database, that contain the string 'unknown', I want to set these to 0 and then sum the rest. But for some reason, this isnt happening. Here is what I have -
Values - VARCHAR(30) -
3
0.1
2
16
2
5
2
Unknown
2.4
7
Unknown
And here is my Cast,Sum,Case
Cast(sum(case when stake = 'Unknown' then 0 else stake end) as float) as totalStake
But I get this error - Conversion failed when converting the varchar value '0.1' to data type int.
Help!
Thanks
You must cast stake as a float:
sum(case when stake = 'Unknown' then 0.0 else cast(stake as float) end) as totalStake
You should explicitly convert to some sort of numeric values. Try this:
sum(try_convert(numeric(18, 4), stake)) as totalStake
Your code has at least two issues. First, your case expression returns an integer (because the first then has an integer). So, it tries to convert stake to an integer, which can generate an error.
Second, you should be doing arithmetic operations on data that is explicitly some sort of number type and not rely on implicit conversion.
You can try the following query using isnumeric() to check numeric data.
create table temp (stake VARCHAR(30))
insert into temp values
('3'), ('0.1'), ('2'), ('16'), ('2'), ('5'), ('2'), ('Unknown'), ('2.4'), ('7'), ('Unknown')
--Select * from temp
Select sum(Cast(stake as Float)) from temp where isnumeric(stake) = 1
To handle some exception like null values or . values only you can try this
Select SUM(TRY_CAST(stake as Float)) from temp
You can find the live demo Here.
Initial step would be to replace the 'Unknown' string with 0 using a replace function and then convert the column datatype to the one which allows to perform Aggregate functions and then perform SUM on top of that. The below query will work only for 'unknown' string, if you have different strings other than 'unknown' you might have to choose a different approach like using IsNumeric in Replace function and update the string value to 0.
select sum(cast((REPLACE(stake,'unknown',0)) as float)) from table
This happens because SQL has some problems while converting decimal values to integer values.
In facts, function sum returns integer values
I solved it using round function on the values1 variable ( sorry for using same name for table and column ):
select Cast(sum(case when values1 = 'Unknown' then 0 else round(values1, 2) end) as
float)as totalstrike
from values1
I'm on Teradata. I have an ID column that looks like this:
23
34
W7
007
021
90
GS8
I want to convert the numbers to numeric so the 007 should be 7 and 021 be 21. When a number is stored as a string, I usually do column * 1 to convert to numeric but in this case it gives me a bad character error since there are letters in there.
How would I do this in a select statement within a query?
Assuming that numeric values always start with a number, then something like this should work:
update t
set col = (case when substr(col, 1, 1) between '0' and '9'
then cast(cast(col as int) as varchar(255))
else col
end);
Or, you can forget the conversion and do:
update t
set col = trim(leading '0' from col);
Note: both of these assume that if the first character is a digit then the whole string comprises digits. The second assumes that the values are not all zeroes (or, more specifically, that returns the empty string).
Simply use TO_NUMBER(col) which returns NULL when the cast fails.
I'm trying to determine the best way to truncate or drop extra decimal places in SQL without rounding. For example:
declare #value decimal(18,2)
set #value = 123.456
This will automatically round #value to be 123.46, which is good in most cases. However, for this project, I don't need that. Is there a simple way to truncate the decimals I don't need? I know I can use the left() function and convert back to a decimal. Are there any other ways?
ROUND ( 123.456 , 2 , 1 )
When the third parameter != 0 it truncates rather than rounds.
Syntax
ROUND ( numeric_expression , length [ ,function ] )
Arguments
numeric_expression
Is an expression of the exact numeric or approximate numeric data
type category, except for the bit data type.
length
Is the precision to which numeric_expression is to be rounded. length must be an expression of type tinyint, smallint, or int. When length is a positive number, numeric_expression is rounded to the number of decimal positions specified by length. When length is a negative number, numeric_expression is rounded on the left side of the decimal point, as specified by length.
function
Is the type of operation to perform. function must be tinyint, smallint, or int. When function is omitted or has a value of 0 (default), numeric_expression is rounded. When a value other than 0 is specified, numeric_expression is truncated.
select round(123.456, 2, 1)
SELECT Cast(Round(123.456,2,1) as decimal(18,2))
Here's the way I was able to truncate and not round:
select 100.0019-(100.0019%.001)
returns 100.0010
And your example:
select 123.456-(123.456%.001)
returns 123.450
Now if you want to get rid of the ending zero, simply cast it:
select cast((123.456-(123.456%.001)) as decimal (18,2))
returns 123.45
Actually whatever the third parameter is, 0 or 1 or 2, it will not round your value.
CAST(ROUND(10.0055,2,0) AS NUMERIC(10,2))
Do you want the decimal or not?
If not, use
select ceiling(#value),floor(#value)
If you do it with 0 then do a round:
select round(#value,2)
Another truncate with no rounding solution and example.
Convert 71.950005666 to a single decimal place number (71.9)
1) 71.950005666 * 10.0 = 719.50005666
2) Floor(719.50005666) = 719.0
3) 719.0 / 10.0 = 71.9
select Floor(71.950005666 * 10.0) / 10.0
Round has an optional parameter
Select round(123.456, 2, 1) will = 123.45
Select round(123.456, 2, 0) will = 123.46
ROUND(number, decimals, operation)
number => Required. The number to be rounded
decimals => Required. The number of decimal places to round number to
operation => Optional. If 0, it rounds the result to the number of decimal. If another value than 0, it truncates the result to the number of decimals. Default value is 0
SELECT ROUND(235.415, 2, 1)
will give you 235.410
SELECT ROUND(235.415, 0, 1)
will give you 235.000
But now trimming0 you can use cast
SELECT CAST(ROUND(235.415, 0, 1) AS INT)
will give you 235
This will remove the decimal part of any number
SELECT ROUND(#val,0,1)
SELECT CAST(Value as Decimal(10,2)) FROM TABLE_NAME;
Would give you 2 values after the decimal point. (MS SQL SERVER)
Another way is ODBC TRUNCATE function:
DECLARE #value DECIMAL(18,3) =123.456;
SELECT #value AS val, {fn TRUNCATE(#value, 2)} AS result
LiveDemo
Output:
╔═════════╦═════════╗
║ val ║ result ║
╠═════════╬═════════╣
║ 123,456 ║ 123,450 ║
╚═════════╩═════════╝
Remark:
I recommend using built-in ROUND function with 3rd parameter set to 1.
I know this is pretty late but I don't see it as an answer and have been using this trick for years.
Simply subtract .005 from your value and use Round(#num,2).
Your example:
declare #num decimal(9,5) = 123.456
select round(#num-.005,2)
returns 123.45
It will automatically adjust the rounding to the correct value you are looking for.
By the way, are you recreating the program from the movie Office Space?
Try like this:
SELECT cast(round(123.456,2,1) as decimal(18,2))
If you desire to take some number like 89.0904987 and turn it into 89.09 by simply omitting the undesired decimal places, simply use the following:
select cast(yourColumnName as decimal(18,2))
The following screenshot is from W3Schools SQL Data Types section, which describes what decimal(18,2) is doing:
Therefore,
select cast(89.0904987 as decimal(18,2))
gives you: 89.09
Please try to use this code for converting 3 decimal values after a point into 2 decimal places:
declare #val decimal (8, 2)
select #val = 123.456
select #val = #val
select #val
The output is 123.46
I think you want only the decimal value,
in this case you can use the following:
declare #val decimal (8, 3)
SET #val = 123.456
SELECT #val - ROUND(#val,0,1)
I know this question is really old but nobody used sub-strings to round. This as advantage the ability to round really long numbers (limit of your string in SQL server which is usually 8000 characters):
SUBSTRING('123.456', 1, CHARINDEX('.', '123.456') + 2)
I think we can go much easier with simpler example solution found in Hackerrank:
Problem statement: Query the greatest value of the Northern Latitudes
(LAT_N) from STATION that is less than 137.2345. Truncate your answer
to 4 decimal places.
SELECT TRUNCATE(MAX(LAT_N),4)
FROM STATION
WHERE LAT_N < 137.23453;
Solution Above gives you idea how to simply make value limited to 4 decimal points. If you want to lower or upper the numbers after decimal, just change 4 to whatever you want.
Mod(x,1) is the easiest way I think.
select convert(int,#value)