I am trying to convert the following VB6 code to VB.NET:
Public Function SingleToHex(ByVal Tmp As Single) As String
Dim TmpBytes(0 To 3) As Byte
Dim TmpSng As Single
Dim tmpStr As String
Dim x As Long
TmpSng = Tmp
Call CopyMemory(ByVal VarPtr(TmpBytes(0)), ByVal VarPtr(TmpSng), 4)
For x = 3 To 0 Step -1
If Len(Hex(TmpBytes(x))) = 1 Then
tmpStr = tmpStr & "0" & Hex(TmpBytes(x))
Else
tmpStr = tmpStr & Hex(TmpBytes(x))
End If
Next x
SingleToHex = tmpStr
End Function
I tried to find a function in the "Conversions" namespace, but I did not find any.
Can anybody tell me how this can easily be done?
Public Function SingleToHex(ByVal Tmp As Single) As String
Dim arr = BitConverter.GetBytes(Tmp)
Array.Reverse(arr)
Return BitConverter.ToString(arr).Replace("-", "")
End Function
Related
I want to remove all string except string startwith EVOPB-
how can I make it happen ?
Private Sub StringResult()
Try
Dim web As New HtmlDocument()
web.Load(WebBrowser1.DocumentStream)
'' Extracting All Links
Dim redeem As HtmlNode = web.DocumentNode.SelectSingleNode("//div[#class='_58b7']")
If (redeem.InnerText.Contains("")) Then
Dim r As String = redeem.InnerText.ToString.Replace(vbNewLine, "")
TextBox1.Text = r
End If
Catch
Return
End Try
End Sub
Assuming what you are trying to match always starts with the same prefix and runs until the next space, something like this would work:
Public Shared Function ExtractStartsWith(ByVal Output As String, Optional StartsWith As String = "EVOPB") As List(Of String)
Dim pos As Integer = 0
Dim nextSpace As Integer
Dim results As New List(Of String)
Dim result As String
Do While pos >= 0 AndAlso pos < Output.Length
pos = Output.IndexOf(StartsWith, pos)
If pos >= 0 Then
nextSpace = Output.IndexOf(" ", pos)
If nextSpace > 0 Then
result = Output.Substring(pos, nextSpace - pos)
pos = nextSpace + 1
Else
result = Output.Substring(pos)
pos = Output.Length
End If
results.Add(result)
End If
Loop
Return results
End Function
How To get StartString And EndString
Dim startNumber As Integer
Dim endNumber As Integer
Dim i As Integer
startNumber = 1
endNumber = 4
For i = startNumber To endNumber
MsgBox(i)
Next i
Output: 1,2,3,4
I want mo make this like sample: startString AAA endString AAD
and the output is AAA, AAB, AAC, AAD
This is a simple function that should be easy to understand and use. Every time you call it, it just increments the string by one value. Just be careful to check the values in the text boxes or you can have an endless loop on your hands.
Function AddOneChar(Str As String) As String
AddOneChar = ""
Str = StrReverse(Str)
Dim CharSet As String = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
Dim Done As Boolean = False
For Each Ltr In Str
If Not Done Then
If InStr(CharSet, Ltr) = CharSet.Length Then
Ltr = CharSet(0)
Else
Ltr = CharSet(InStr(CharSet, Ltr))
Done = True
End If
End If
AddOneChar = Ltr & AddOneChar
Next
If Not Done Then
AddOneChar = CharSet(0) & AddOneChar
End If
End Function
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
Dim S = TextBox1.Text
Do Until S = TextBox2.Text
S = AddOneChar(S)
MsgBox(S)
Loop
End Sub
This works as a way to all the codes given an arbitrary alphabet:
Public Function Generate(starting As String, ending As String, alphabet As String) As IEnumerable(Of String)
Dim increment As Func(Of String, String) = _
Function(x)
Dim f As Func(Of IEnumerable(Of Char), IEnumerable(Of Char)) = Nothing
f = _
Function(cs)
If cs.Any() Then
Dim first = cs.First()
Dim rest = cs.Skip(1)
If first = alphabet.Last() Then
rest = f(rest)
first = alphabet(0)
Else
first = alphabet(alphabet.IndexOf(first) + 1)
End If
Return Enumerable.Repeat(first, 1).Concat(rest)
Else
Return Enumerable.Empty(Of Char)()
End If
End Function
Return New String(f(x.ToCharArray().Reverse()).Reverse().ToArray())
End Function
Dim results = New List(Of String)
Dim text = starting
While True
results.Add(text)
If text = ending Then
Exit While
End If
text = increment(text)
End While
Return results
End Function
I used it like this to produce the required result:
Dim alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
Dim results = Generate("S30AB", "S30B1", alphabet)
This gave me 63 values:
S30AB
S30AC
...
S30BY
S30BZ
S30B0
S30B1
It should now be very easy to modify the alphabet as needed and to use the results.
One option would be to put those String values into an array and then use i as an index into that array to get one element each iteration. If you do that though, keep in mind that array indexes start at 0.
You can also use a For Each loop to access each element of the array without the need for an index.
if the default first two string value of your output is AA.
You can have a case or if-else conditioning statement :
and then set 1 == A 2 == B...
the just add or concatenate your default two string and result string of your case.
I have tried to understand that you are looking for a series using range between 2 textboxes. Here is the code which will take the series and will give the output as required.
Dim startingStr As String = Mid(TextBox1.Text, TextBox1.Text.Length, 1)
Dim endStr As String = Mid(TextBox2.Text, TextBox2.Text.Length, 1)
Dim outputstr As String = String.Empty
Dim startNumber As Integer
Dim endNumber As Integer
startNumber = Asc(startingStr)
endNumber = Asc(endStr)
Dim TempStr As String = Mid(TextBox1.Text, 1, TextBox1.Text.Length - 1)
Dim i As Integer
For i = startNumber To endNumber
outputstr = outputstr + ", " + TempStr + Chr(i)
Next i
MsgBox(outputstr)
The First two lines will take out the Last Character of the String in the text box.
So in your case it will get A and D respectively
Then outputstr to create the series which we will use in the loop
StartNumber and EndNumber will be give the Ascii values for the character we fetched.
TempStr to Store the string which is left off of the series string like in our case AAA - AAD Tempstr will have AA
then the simple loop to get all the items fixed and show
in your case to achive goal you may do something like this
Dim S() As String = {"AAA", "AAB", "AAC", "AAD"}
For Each el In S
MsgBox(el.ToString)
Next
FIX FOR PREVIOUS ISSUE
Dim s1 As String = "AAA"
Dim s2 As String = "AAZ"
Dim Last As String = s1.Last
Dim LastS2 As String = s2.Last
Dim StartBase As String = s1.Substring(0, 2)
Dim result As String = String.Empty
For I As Integer = Asc(s1.Last) To Asc(s2.Last)
Dim zz As String = StartBase & Chr(I)
result += zz & vbCrLf
zz = Nothing
MsgBox(result)
Next
**UPDATE CODE VERSION**
Dim BARCODEBASE As String = "SBA0021"
Dim BarCode1 As String = "SBA0021AA1"
Dim BarCode2 As String = "SBA0021CD9"
'return AA1
Dim FirstBarCodeSuffix As String = Replace(BarCode1, BARCODEBASE, "")
'return CD9
Dim SecondBarCodeSuffix As String = Replace(BarCode2, BARCODEBASE, "")
Dim InternalSecondBarCodeSuffix = SecondBarCodeSuffix.Substring(1, 1)
Dim IsTaskCompleted As Boolean = False
For First As Integer = Asc(FirstBarCodeSuffix.First) To Asc(SecondBarCodeSuffix)
If IsTaskCompleted = True Then Exit For
For Second As Integer = Asc(FirstBarCodeSuffix.First) To Asc(InternalSecondBarCodeSuffix)
For Third As Integer = 1 To 9
Dim tmp = Chr(First) & Chr(Second) & Third
Console.WriteLine(BARCODEBASE & tmp)
If tmp = SecondBarCodeSuffix Then
IsTaskCompleted = True
End If
Next
Next
Next
Console.WriteLine("Completed")
Console.Read()
Take a look into this check it and let me know if it can help
First part of the code is to retrieve data from the web. It takes only a part of the second to complete the request. Second part of the code is to split data so that parts of data can be shown in different labels and it takes around 5-6 second to complete this operation?
Why is that? Can it be done faster?
First part of the code (textbox1 key down event)
If e.KeyCode = Keys.Enter Then
TextBox1.Text = UCase(TextBox1.Text)
If TextBox1.Text = "" Then
GoTo exx
Else
Dim strURL As String
Dim strSymbol As String = TextBox1.Text
strURL = " http://quote.yahoo.com/d/quotes.csv?" & _
"s=" & strSymbol & _
"&d=t" & _
"&f=snl1pmwvj1l1"
MessageBox.Show(RequestWebData(strURL))
Second part of the code and functions :
Label24.Text = (GetName2(RequestWebData(strURL), 3))
Dim myText = Label24.Text
Dim dIndex = myText.IndexOf("Inc.")
If (dIndex > -1) Then
Label24.Text = (Strings.Left(Label24.Text, dIndex + 4))
Else
Label24.Text = (Label24.Text)
End If
Dim myText2 = Label24.Text
Dim dIndex2 = myText2.IndexOf("Common")
If (dIndex2 > -1) Then
Label24.Text = (Label24.Text.Replace("Common", ""))
Else
Label24.Text = (Label24.Text)
End If
Label6.Text = (GetName(RequestWebData(strURL), 4))
Label6.Text = (GetName3(Label6.Text, 1))
Label6.Text = FormatNumber(Label6.Text, 2)
Label17.Text = (GetName(RequestWebData(strURL), 5))
Label21.Text = (GetName(RequestWebData(strURL), 7))
Dim x As String = GetName(RequestWebData(strURL), 8)
Label30.Text = GetName3(x, 1)
Label30.Text = FormatNumber(Label30.Text, 0)
Label32.Text = GetName3(x, 2)
TextBox2.Focus()
Function GetName(ByVal LineIn As String, ByVal i As Integer) As String
'Dim x As Integer
Return LineIn.Split(""",")(i)
End Function
Function GetName2(ByVal LineIn As String, ByVal i As Integer) As String
'Dim x As Integer
Return LineIn.Split("""")(i)
End Function
Function GetName3(ByVal LineIn As String, ByVal i As Integer) As String
'Dim x As Integer
Return LineIn.Split(",")(i)
End Function
Maybe it is so slow because of these three functions that I am using to split data?
I am little bit confused in this program.
I am new to Visual Basic but intermediate to C.
Actually I want to get sub-string of string without using library function of Visual Basic.
Here is the C source code I also given my VB code too.
1.The Program will get two inputs from user i.e A & B
2. Than Find the substring from B.
3. Finally Print the result.
int i,j=0,k=0,substr=0;
for(i=0;i<strlen(a);i++)
{
if(a[i]==b[j])
{
j++;
if(b[j]==0)
{
printf("second string is substring of first one");
substr=1;
break;
}
}
}
for(i=0;i<strlen(b);i++)
{
if(b[i]==a[k])
{
k++;
if(a[k]==0)
{
printf(" first string is substring of second string");
substr=1;
break ;
}
}
}
if(substr==0)
{
printf("no substring present");
}
While my code is
Dim a As String
Dim b As String
a = InputBox("Enter First String", a)
b = InputBox("Enter 2nd String", b)
Dim i As Integer
Dim j As Integer = 0
Dim k As Integer = 0
Dim substr As Integer = 0
For i = 0 To a.Length - 1
If a(i) = b(j) Then
j += 1
If b(j) = 0 Then
MsgBox("second string is substring of first one")
substr = 1
Exit For
End If
End If
Next i
For i = 0 To b.Length - 1
If b(i) = a(k) Then
k += 1
If a(k) = 0 Then
MsgBox(" first string is substring of second string")
substr = 1
Exit For
End If
End If
Next i
If substr = 0 Then
MsgBox("no substring present")
End If
End Sub
While compiling it gives following debugging errors.
Line Col
Error 1 Operator '=' is not defined for types 'Char' and 'Integer'. 17 24
Error 2 Operator '=' is not defined for types 'Char' and 'Integer'. 27 24
Part of your confusion is that .Net strings are much more than just character buffers. I'm going to assume that you can at least use strings. If you can't, use need to declare character arrays instead. That out of the way, this should get you there as a 1:1 translation:
Private Shared Function search(ByVal a As String, ByVal b As String) As Integer
Dim i As Integer = 0
Dim j As Integer = 0
Dim firstOcc As Integer
While i < a.Length
While a.Chars(i)<>b.Chars(0) AndAlso i < a.Length
i += 1
End While
If i >= a.Length Then Return -1 'search can not continue
firstOcc = i
While a.Chars(i)=b.Chars(j) AndAlso i < a.Length AndAlso j < b.Length
i += 1
j += 1
End While
If j = b.Length Then Return firstOcc
If i = a.Length Then Return -1
i = firstOcc + 1
j = 0
End While
Return 0
End Function
Shared Sub Main() As Integer
Dim a As String
Dim b As String
Dim loc As Integer
Console.Write("Enter the main string :")
a = Console.ReadLine()
Console.Write("Enter the search string :")
b = Console.ReadLine()
loc = search(a, b)
If loc = -1 Then
Console.WriteLine("Not found")
Else
Console.WriteLine("Found at location {0:D}",loc+1)
End If
Console.ReadKey(True)
End Sub
But please don't ever actually use that. All you really need is this:
Private Shared Function search(ByVal haystack as String, ByVal needle As String) As Integer
Return haystack.IndexOf(needle)
End Function
VB has a built-in function called InStr, it's part of the language. It returns an integer specifying the start position of the first occurrence of one string within another.
http://msdn.microsoft.com/en-us/library/8460tsh1(v=VS.80).aspx
Pete
Try this one, this will return a List(Of Integer) containing the index to all occurrence's of the find text within the source text, after the specified search starting position.
Option Strict On
Public Class Form1
''' <summary>
''' Returns an array of indexes where the find text occurred in the source text.
''' </summary>
''' <param name="Source">The text you are searching.</param>
''' <param name="Find">The text you are searching for.</param>
''' <param name="StartIndex"></param>
''' <returns>Returns an array of indexes where the find text occurred in the source text.</returns>
''' <remarks></remarks>
Function FindInString(Source As String, Find As String, StartIndex As Integer) As List(Of Integer)
If StartIndex > Source.Length - Find.Length Then Return New List(Of Integer)
If StartIndex < 0 Then Return New List(Of Integer)
If Find.Length > Source.Length Then Return New List(Of Integer)
Dim Results As New List(Of Integer)
For I = StartIndex To (Source.Length) - Find.Length
Dim TestString As String = String.Empty
For II = I To I + Find.Length - 1
TestString = TestString & Source(II)
Next
If TestString = Find Then Results.Add(I)
Next
Return Results
End Function
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
Try
Dim Search As String = "Hello world, this world is an interesting world"
Dim Find As String = "world"
Dim Indexes As List(Of Integer) = New List(Of Integer)
Try
Indexes = FindInString(Search, Find, 0)
Catch ex As Exception
MsgBox(ex.ToString)
End Try
RichTextBox1.Text = "Search:" & vbCrLf
RichTextBox1.Text = RichTextBox1.Text & Search & vbCrLf & vbCrLf
RichTextBox1.Text = RichTextBox1.Text & "Find:" & vbCrLf
RichTextBox1.Text = RichTextBox1.Text & Find & vbCrLf & vbCrLf
RichTextBox1.Text = RichTextBox1.Text & "-----------" & vbCrLf
RichTextBox1.Text = RichTextBox1.Text & "Result Indexes:" & vbCrLf & vbCrLf
For Each i As Integer In Indexes
RichTextBox1.Text = RichTextBox1.Text & i.ToString & vbCr
Next
Catch ex As Exception
MsgBox(ex.ToString)
End Try
End Sub
End Class
Here is another way, where there is no use of .Net functions.
Function FindInString(Source As String, Find As String, StartIndex As Integer) As Integer()
If StartIndex > Len(Source) - Len(Find) Then Return {}
If StartIndex < 0 Then Return {}
If Len(Find) > Len(Source) Then Return {}
Dim Results As Integer() = {}, ResultCount As Integer = -1
For I = StartIndex To Len(Source) - Len(Find)
Dim TestString As String = ""
For II = I To I + Len(Find) - 1
TestString = TestString & Source(II)
Next
If TestString = Find Then
ResultCount += 1
ReDim Preserve Results(ResultCount)
Results(ResultCount) = I
End If
Next
Return Results
End Function
Can you help me in having a proper casing,
I have this code...
Private Function NameCsing(ByVal sValue As String) As String
Dim toConvert As String() = sValue.Split(" ")
Dim lst As New List(Of String)
For i As Integer = 0 To toConvert.Length - 1
Dim converted As String = ""
If toConvert(i).Contains("~") Then
Dim toName As String() = toConvert(i).Split("~")
Dim sName As String = ""
For n As Integer = 0 To toName.Length - 1
Dim sconvert As String = ""
If n = 0 Then
sName = StrConv(toName(n), VbStrConv.ProperCase)
Else
sName += StrConv(toName(n), VbStrConv.ProperCase)
End If
Next
converted = sName
Else
converted = toConvert(i)
End If
lst.Add(converted)
Next
Dim ret As String = ""
For i As Integer = 0 To lst.Count - 1
If i = 0 Then
ret = lst(0)
Else
ret += " " + lst(i)
End If
Next
Return ret
End Function
My codes will just output like this "McDonalds" is you input "mc~donalds"
now my problem is eh I input "evalue", my output must be "eValue"
The only way to know how to treat a special string is to code it yourself from a list of rules:
Private Function NameCsing(ByVal sValue As String) As String
If sValue.Trim.ToLower = "evalue" Then Return "eValue"
'Then process any other special cases
End Function