how to get daily profit from sql table - sql

Question

I'm stucking for a solution at the problem of finding daily profits from db (ms access) table. The difference wrt other tips I found online is that I don't have in the table a field "Price" and one "Cost", but a field "Type" which distinguish if it is a revenue "S" or a cost "C"
this is the table "Record"
| Date | Price | Quantity | Type |
-----------------------------------
|01/02 | 20 | 2 | C |
|01/02 | 10 | 1 | S |
|01/02 | 3 | 10 | S |
|01/02 | 5 | 2 | C |
|03/04 | 12 | 3 | C |
|03/03 | 200 | 1 | S |
|03/03 | 120 | 2 | C |
So far I tried different solutions like:
SELECT
(SELECT SUM (RS.Price* RS.Quantity)
FROM Record RS WHERE RS.Type='S' GROUP BY RS.Data
) as totalSales,
(SELECT SUM (RC.Price*RC.Quantity)
FROM Record RC WHERE RC.Type='C' GROUP BY RC.Date
) as totalLosses,
ROUND(totalSales-totaleLosses,2) as NetTotal,
R.Date
FROM RECORD R";
in my mind it could work but obviously it doesn't
and
SELECT RC.Data, ROUND(SUM (RC.Price*RC.QuantitY),2) as DailyLoss
INTO #DailyLosses
FROM Record RC
WHERE RC.Type='C' GROUP BY RC.Date
SELECT RS.Date, ROUND(SUM (RS.Price*RS.Quantity),2) as DailyRevenue
INTO #DailyRevenues
FROM Record RS
WHERE RS.Type='S'GROUP BY RS.Date
SELECT Date, DailyRevenue - DailyLoss as DailyProfit
FROM #DailyLosses dlos, #DailyRevenues drev
WHERE dlos.Date = drev.Date";
My problem beyond the correct syntax is the approach to this kind of problem

Answer 1

You can use grouping and conditional summing. Try this:
SELECT data.Date, data.Income - data.Cost as Profit
FROM (
SELECT Record.Date as Date,
SUM(IIF(Record.Type = 'S', Record.Price * Record.Quantity, 0)) as Income,
SUM(IIF(Record.Type = 'C', Record.Price * Record.Quantity, 0)) as Cost,
FROM Record
GROUP BY Record.Date
) data
In this case you first create a sub-query to get separate fields for Income and Cost, and then your outer query uses subtraction to get actual profit.