Ansys LS-DYNA explicit dynamics element COMBI165 length is affecting the solution - finite-element-analysis

I'm analysing some dynamic models using Ansys LS-DYNA explicit dynamic models.
My model only has beam elements (BEAM161), concentrated masses (MASS166) and springs/dampers (COMBI165).
The problem is that the length of the springs/dampers is affecting the results, which shouldn't happen: according to the manual, you define COMBI165's stiffness or damping coefficient, which is multiplied by the relative displacement/velocity between the nodes to obtain the reaction force.
For my particular problem, the length of the spring/damper is not conditioning the time-step, so that is not the source of the difference.

Related

Minimize a cost function?

I have a cost function and its gradient calculated with finite element discretization (values at integrations points) and I have the data in a text file.
The problem is the cost function and its gradient not mathematically explicit, calculated numerically at some points xi in volume V at each increment of time t using the finite element method. The results for the function and its gradient are stored in a text file.
How to minimize this function? any idea?
Thanks for your help
I don’t think you can do what you’re thinking to do. If your finite element simulations are already done then the only thing you can do is to create a proxy model of your results as a function of your parameters. One possibility is to model your results by interpolating them (using for example SciPy griddata https://docs.scipy.org/doc/scipy/reference/generated/scipy.interpolate.griddata.html) and use that as your proxy model.
Then you select your favorite optimization algorithm, specify your parameters (that have to be part of the griddata interpolant) and you’re ready to go. Depending on how many finite element simulations you have done you can expect very bad/meaningless outcomes (if you have too few) or very good ones (if your finite element simulations cover almost the entire optimization space).

xgboost vs H2o Gradient Boosting

I have a dataset having a large missing values (more than 40% missing). Genrated a model in xgboost and H2o gradient boosting - got a decent model in both cases. However, the xgboost shows this variable as one of the key contributors to the model but as per H2o Gradient Boosting the variable is not important. Does xgboost handle variables with missing values differently. All the configuration to both the models are exactly the same.
Both missing value handling and variable importances are slightly different between the two methods. Both are treating missing values as information (i.e., they learn from them, and don't just impute with a simple constant). The variable importances are computed from the gains of their respective loss functions during tree construction. H2O uses squared error, and XGBoost uses a more complicated one based on gradient and hessian.
One thing you could check is the variance of the variable importances between different runs with different seeds, to see how stable each method is in terms of variable importances.
PS. If you have categoricals, then you're better off leaving the column as a factor for H2O, no need to do your own encoding. This can lead to a different effective count of columns vs XGBoost's dataset, so for column sampling, things will be different.

Implementing a 2D recursive spatial filter using Scipy

Minimally, I would like to know how to achieve what is stated in the title. Specifically, signal.lfilter seems like the only implementation of a difference equation filter in scipy, but it is 1D, as shown in the docs. I would like to know how to implement a 2D version as described by this difference equation. If that's as simple as "bro, use this function," please let me know, pardon my naiveté, and feel free to disregard the rest of the post.
I am new to DSP and acknowledging there might be a different approach to answering my question so I will explain the broader goal and give context for the question in the hopes someone knows how do want I want with Scipy, or perhaps a better way than what I explicitly asked for.
To get straight into it, broadly speaking I am using vectorized computation methods (Numpy/Scipy) to implement a Monte Carlo simulation to improve upon a naive for loop. I have successfully abstracted most of my operations to array computation / linear algebra, but a few specific ones (recursive computations) have eluded my intuition and I continually end up in the digital signal processing world when I go looking for how this type of thing has been done by others (that or machine learning but those "frameworks" are much opinionated). The reason most of my google searches end up on scipy.signal or scipy.ndimage library references is clear to me at this point, and subsequent to accepting the "signal" representation of my data, I have spent a considerable amount of time (about as much as reasonable for a field that is not my own) ramping up the learning curve to try and figure out what I need from these libraries.
My simulation entails updating a vector of data representing the state of a system each period for n periods, and then repeating that whole process a "Monte Carlo" amount of times. The updates in each of n periods are inherently recursive as the next depends on the state of the prior. It can be characterized as a difference equation as linked above. Additionally this vector is theoretically indexed on an grid of points with uneven stepsize. Here is an example vector y and its theoretical grid t:
y = np.r_[0.0024, 0.004, 0.0058, 0.0083, 0.0099, 0.0133, 0.0164]
t = np.r_[0.25, 0.5, 1, 2, 5, 10, 20]
I need to iteratively perform numerous operations to y for each of n "updates." Specifically, I am computing the curvature along the curve y(t) using finite difference approximations and using the result at each point to adjust the corresponding y(t) prior to the next update. In a loop this amounts to inplace variable reassignment with the desired update in each iteration.
y += some_function(y)
Not only does this seem inefficient, but vectorizing things seems intuitive given y is a vector to begin with. Furthermore I am interested in preserving each "updated" y(t) along the n updates, which would require a data structure of dimensions len(y) x n. At this point, why not perform the updates inplace in the array? This is wherein lies the question. Many of the update operations I have succesfully vectorized the "Numpy way" (such as adding random variates to each point), but some appear overly complex in the array world.
Specifically, as mentioned above the one involving computing curvature at each element using its neighbouring two elements, and then imediately using that result to update the next row of the array before performing its own curvature "update." I was able to implement a non-recursive version (each row fails to consider its "updated self" from the prior row) of the curvature operation using ndimage generic_filter. Given the uneven grid, I have unique coefficients (kernel weights) for each triplet in the kernel footprint (instead of always using [1,-2,1] for y'' if I had a uniform grid). This last part has already forced me to use a spatial filter from ndimage rather than a 1d convolution. I'll point out, something conceptually similar was discussed in this math.exchange post, and it seems to me only the third response saliently addressed the difference between mathematical notion of "convolution" which should be associative from general spatial filtering kernels that would require two sequential filtering operations or a cleverly merged kernel.
In any case this does not seem to actually address my concern as it is not about 2D recursion filtering but rather having a backwards looking kernel footprint. Additionally, I think I've concluded it is not applicable in that this only allows for "recursion" (backward looking kernel footprints in the spatial filtering world) in a manner directly proportional to the size of the recursion. Meaning if I wanted to filter each of n rows incorporating calculations on all prior rows, it would require a convolution kernel far too big (for my n anyways). If I'm understanding all this correctly, a recursive linear filter is algorithmically more efficient in that it returns (for use in computation) the result of itself applied over the previous n samples (up to a level where the stability of the algorithm is affected) using another companion vector (z). In my case, I would only need to look back one step at output signal y[n-1] to compute y[n] from curvature at x[n] as the rest works itself out like a cumsum. signal.lfilter works for this, but I can't used that to compute curvature, as that requires a kernel footprint that can "see" at least its left and right neighbors (pixels), which is how I ended up using generic_filter.
It seems to me I should be able to do both simultaneously with one filter namely spatial and recursive filtering; or somehow I've missed the maths of how this could be mathematically simplified/combined (convolution of multiples kernels?).
It seems like this should be a common problem, but perhaps it is rarely relevant to do both at once in signal processing and image filtering. Perhaps this is why you don't use signals libraries solely to implement a fast monte carlo simulation; though it seems less esoteric than using a tensor math library to implement a recursive neural network scan ... which I'm attempting to do right now.
EDIT: For those familiar with the theoretical side of DSP, I know that what I am describing, the process of designing a recursive filters with arbitrary impulse responses, is achieved by employing a mathematical technique called the z-transform which I understand is generally used for two things:
converting between the recursion coefficients and the frequency response
combining cascaded and parallel stages into a single filter
Both are exactly what I am trying to accomplish.
Also, reworded title away from FIR / IIR because those imply specific definitions of "recursion" and may be confusing / misnomer.

Finding Optimal Parameters In A "Black Box" System

I'm developing machine learning algorithms which classify images based on training data.
During the image preprocessing stages, there are several parameters which I can modify that affect the data I feed my algorithms (for example, I can change the Hessian Threshold when extracting SURF features). So the flow thus far looks like:
[param1, param2, param3...] => [black box] => accuracy %
My problem is: with so many parameters at my disposal, how can I systematically pick values which give me optimized results/accuracy? A naive approach is to run i nested for-loops (assuming i parameters) and just iterate through all parameter combinations, but if it takes 5 minute to calculate an accuracy from my "black box" system this would take a long, long time.
This being said, are there any algorithms or techniques which can search for optimal parameters in a black box system? I was thinking of taking a course in Discrete Optimization but I'm not sure if that would be the best use of my time.
Thank you for your time and help!
Edit (to answer comments):
I have 5-8 parameters. Each parameter has its own range. One parameter can be 0-1000 (integer), while another can be 0 to 1 (real number). Nothing is stopping me from multithreading the black box evaluation.
Also, there are some parts of the black box that have some randomness to them. For example, one stage is using k-means clustering. Each black box evaluation, the cluster centers may change. I run k-means several times to (hopefully) avoid local optima. In addition, I evaluate the black box multiple times and find the median accuracy in order to further mitigate randomness and outliers.
As a partial solution, a grid search of moderate resolution and range can be recursively repeated in the areas where the n-parameters result in the optimal values.
Each n-dimensioned result from each step would be used as a starting point for the next iteration.
The key is that for each iteration the resolution in absolute terms is kept constant (i.e. keep the iteration period constant) but the range decreased so as to reduce the pitch/granular step size.
I'd call it a ‘contracting mesh’ :)
Keep in mind that while it avoids full brute-force complexity it only reaches exhaustive resolution in the final iteration (this is what defines the final iteration).
Also that the outlined process is only exhaustive on a subset of the points that may or may not include the global minimum - i.e. it could result in a local minima.
(You can always chase your tail though by offsetting the initial grid by some sub-initial-resolution amount and compare results...)
Have fun!
Here is the solution to your problem.
A method behind it is described in this paper.

Optimizing interpolation in Mathematica

As part of my work, I often have to visualize complex 3 dimensional densities. One program suite that I work with outputs the radial component of the densities as a set of 781 points on a logarithmic grid, ri = (Rmax/Rstep)^((i-1)/(pts-1), times a spherical harmonic. For low symmetry systems, the number of spherical harmonics can be fairly large to ensure accuracy, e.g. one system requires 49 harmonics corresponding to lmax = 6. So, to use this data within Mathematica, I would have a sum of up to 49 interpolated functions with each multiplied by a different spherical harmonic. While using v.6 and constructing the interpolated radial functions using Interpolation and setting r = Sqrt(x^2 + y^2 + z^2), I would stop ContourPlot3D after well over an hour without anything displayed. This included reducing both the InterpolationOrder and MaxRecursion to 1.
Several alternatives presented themselves:
Evaluate the density function on a fixed grid, and use ListContourPlot instead.
Or, linearly spline the radial function and use Piecewise to stitch them together. (This presented itself, as I could use simplify to help reduce the complexity of the resulting function.)
I ended up using both, as InterpolatingFunction gives a noticeable delay in its evaluation, and with up to 49 interpolated functions to evaluate, any delay can become noticeable. Also, ContourPlot3D was faster with the spline, but it didn't give me the speed up I desired.
I'll freely admit that I haven't tried Interpolation on v.7, nor I have tried this on my upgraded hardware (G4 v. Intel Core i5). However, I'm looking for alternatives to my current scheme; preferably, one where I can use ContourPlot3D directly. I could try some other form of spline, such as a B-spline, and possibly combine that with UnitBox instead of using Piecewise.
Edit: Just to clarify, my current implementation involves creating a first order spline for each radial part, multiplying each one by their respective spherical harmonic, summing and Simplifying the equations on each radial interval, and then using Piecewise to bind them into one function. So, my implementation is semi-analytical in that the spherical harmonics are exact, and only the radial part is numerical. This is part of the reason why I would like to be able to use ContourPlot3D, so that I can take advantage of the semi-analytical nature of the data. As a point of note, the radial grid is fine enough that a good representation of the radial part is generated and can be smoothly interpolated. While this gave me a significant speed-up, when I wrote the code, it was still to slow for the hardware I was using at the time.
So, instead of using ContourPlot3D, I would first generate the function, as above, then I would evaluate it on an 803 Cartesian grid. It is the data from this step that I used in ListContourPlot3D. Since this is not an adaptive grid, in some places this was too course, and I was missing features.
If you can do without Mathematica, I would suggest you have a look at Paraview (US government funded FOSS, all platforms) which I have found to be superior to everything when it comes to visualizing massive amounts of data.
The core of the software is the "Visualization Toolkit" VTK, and you can find/write other frontends if need be.
VTK/Paraview can handle almost any data-type: scalar and vector on structured grids or random points, polygons, time-series data, etc. From Mathematica I often just dump grid data into VTK legacy format which in then simplest case looks like this
# vtk DataFile Version 2.0
Generated by mma via vtkGridDump
ASCII
DATASET STRUCTURED_POINTS
DIMENSIONS 49 25 15
SPACING 0.125 0.125 0.0625
ORIGIN 8.5 5. 0.7124999999999999
POINT_DATA 18375
SCALARS RF_pondpot_1V1MHz1amu double 1
LOOKUP_TABLE default
0.04709501616121583
0.04135197485227461
... <18373 more numbers> ...
HTH!
If it really is the interpolation of the radial functions that is slowing you down, you could consider hand-coding that part based on your knowledge of the sample points. As demonstrated below, this gives a significant speedup:
I set things up with your notation. lookuprvals is a list of 100000 r values to look up for timing.
First, look at stock interpolation as a basemark
With[{interp=Interpolation[N#Transpose#{rvals,yvals}]},
Timing[interp[lookuprvals]][[1]]]
Out[259]= 2.28466
Switching to 0th-order interpolation is already an order of magnitude faster (first order is almost same speed):
With[{interp=Interpolation[N#Transpose#{rvals,yvals},InterpolationOrder->0]},
Timing[interp[lookuprvals]][[1]]]
Out[271]= 0.146486
We can get another 1.5 order of magnitude by calculating indices directly:
Module[{avg=MovingAverage[yvals,2],idxfact=N[(pts-1) /Log[Rmax/Rstep]]},
Timing[res=Part[avg,Ceiling[idxfact Log[lookuprvals]]]][[1]]]
Out[272]= 0.006067
As a middle ground, do a log-linear interpolation by hand. This is slower than the above solution but still much faster than stock interpolation:
Module[{diffs=Differences[yvals],
idxfact=N[(pts-1) /Log[Rmax/Rstep]]},
Timing[Block[{idxraw,idxfloor,idxrel},
idxraw=1+idxfact Log[lookuprvals];
idxfloor=Floor[idxraw];
idxrel=idxraw-idxfloor;
res=Part[yvals,idxfloor]+Part[diffs,idxfloor]idxrel
]][[1]]]
Out[276]= 0.026557
If you have the memory for it, I would cache the spherical harmonics and radius (or even radius-index) on the full grid. Then flatten the grid caches so you can do
Sum[ interpolate[yvals[lm],gridrvals] gridylmvals[lm], {lm,lmvals} ]
and recreate your grid as discussed here.