get the sorted date in vb - vb.net

i am writing simple program to get the sorted date . But it does not work.
Dim filepath As String = FileStr
Dim directoryPath As String = System.IO.Path.GetDirectoryName(filepath)
for Each file As String In System.IO.Directory.GetFiles(directoryPath)
Dates = {
Date.Parse(System.IO.Path.GetFileNameWithoutExtension(file))
}.ToList
Next
Dates.Sort()
ComboBox1.DataSource = Dates
It only show one date ..where there are more than 10 date. and also the loop is working
I declare the List as global

You're replacing the content of your list in every loop
Dim filepath As String = FileStr
Dim directoryPath As String = System.IO.Path.GetDirectoryName(filepath)
for Each file As String In System.IO.Directory.GetFiles(directoryPath)
Dates.Add(Date.Parse(System.IO.Path.GetFileNameWithoutExtension(file)))
Next
Dates.Sort(AddressOf SortDate)
ComboBox1.DataSource = Dates
UPDATE: Sorting issue
Then as a seperate function add:
Function SortDate(ByVal a As DateTime, ByVal b As DateTime)
Dim result As Integer = a.Year.CompareTo(b.Year)
If result = 0 Then
a.Month.CompareTo(b.Month)
If result = 0 Then
a.Day.CompareTo(b.Day)
End If
End If
Return result
End Function

Your loop replaced the value of Dates each time, so you get only one date.
Change the loop like this:
Dates = System.IO.Directory.GetFiles(directoryPath)
.Select(Function(file) Date.Parse(System.IO.Path.GetFileNameWithoutExtension(file)))
.ToList

Related

Get first and last day from .csv with VB.Net

I have two properties
Property FirstDayOfCsv As String
Property LastDayOfCsv As String
I want that properties obtains min and max values from parsed csv file. Values are days in "dd" format from date column. Now my code looks like this:
Dim csv As String() = IO.File.ReadAllLines("my.csv").Skip(1).ToArray
For Each line In csv
Dim col = line.Split(";"c)
Dim days As Date = col(2)
FirstDayOfCsv = days.ToString("dd").Min
LastDayOfCsv = days.ToString("dd").Max
Next
Unfortunately Min and Max doesn't return values, which I need and I'm stucking here. How to get them?
One option that you have is to add the values to a collection, but converting the String values to Integer values first. Then once you're finished iterating over the lines you would call Min/Max.
Dim csv = IO.File.ReadAllLines("my.csv").Skip(1).ToArray()
Dim everyday = New List(Of Integer)()
For Each line In csv
Dim col = line.Split(";"c)
Dim days = col(2)
Dim daysAsInt As Integer
If (Integer.TryParse(days, daysAsInt)) Then
everyday.Add(daysAsInt)
End If
Next
FirstDayOfCsv = everyday.Min()
LastDayOfCsv = everyday.Max()

How to convert textbox year date value to check if it has only 2 digits?

The problem that I have is related to only being possible to insert 2 digit's on the field year and I was wondering if it was possible to have a string with a value 2017 and only inserting 17 when I press a button.
I have tried to use the CONTAINS property to check if it only has numbers, but now I'm kind of stuck.
You could use regex.
Private Function returnLastTwo(input As Integer) As Integer
Dim matchYearString As String = "(?:(\d\d)(?:(\d\d))?)"
Dim output As Integer
If CStr(input).Length = 4 Then
output = Text.RegularExpressions.Regex.Match(CStr(input), matchYearString).Groups(2).Value
ElseIf CStr(input).Length = 2 Then
output = Text.RegularExpressions.Regex.Match(CStr(input), matchYearString).Groups(1).Value
Else
Throw New Exception("Check input")
End If
Return output
End Function
You can use a string/substring concept;
Module DateSplit
Sub Main()
Dim literal As String = "2017"
Dim substring As String = literal.Substring(2)
Console.WriteLine("Substring: {0}", substring)
End Sub
End Module
I did not test this code but should output 17
Another approach would be casting your date as a string and create a char array, then you can have access to the element and convert them back to numbers if you like
Dim dateToSplit As Integer = 2017
Dim strDate As String = dateToSplit.ToString()
Dim charArr() AS Char = strDate.ToCharArray()
Assuming your user enters a date like this: 01/01/2017, into the textbox:
dim dateFromTextbox = yourTextbox.Text ' ==> 01/01/2017
dim lastTwoDigits = Right(dateFromTextbox, 2) ' ==> 17

For Loop: changing the loop condition while it is looping

What I want to do is replace all 'A' in a string with "Bb". but it will only loop with the original string not on the new string.
for example:
AAA
BbAA
BbBbA
and it stops there because the original string only has a length of 3. it reads only up to the 3rd index and not the rest.
Dim txt As String
txt = output_text.Text
Dim a As String = a_equi.Text
Dim index As Integer = txt.Length - 1
Dim output As String = ""
For i = 0 To index
If (txt(i) = TextBox1.Text) Then
output = txt.Remove(i, 1).Insert(i, a)
txt = output
TextBox2.Text += txt + Environment.NewLine
End If
Next
End Sub
I think this leaves us looking for a String.ReplaceFirst function. Since there isn't one, we can just write that function. Then the code that calls it becomes much more readable because it's quickly apparent what it's doing (from the name of the function.)
Public Function ReplaceFirst(searched As String, target As String, replacement As String) As String
'This input validation is just for completeness.
'It's not strictly necessary.
'If the searched string is "null", throw an exception.
If (searched Is Nothing) Then Throw New ArgumentNullException("searched")
'If the target string is "null", throw an exception.
If (target Is Nothing) Then Throw New ArgumentNullException("target")
'If the searched string doesn't contain the target string at all
'then just return it - were done.
Dim foundIndex As Integer = searched.IndexOf(target)
If (foundIndex = -1) Then Return searched
'Build a new string that replaces the target with the replacement.
Return String.Concat(searched.Substring(0, foundIndex), replacement, _
searched.Substring(foundIndex + target.Length, searched.Length - (foundIndex + target.Length)))
End Function
Notice how when you read the code below, you don't even have to spend a moment trying to figure out what it's doing. It's readable. While the input string contains "A", replace the first "A" with "Bb".
Dim input as string = "AAA"
While input.IndexOf("A") > -1
input = input.ReplaceFirst(input,"A","Bb")
'If you need to capture individual values of "input" as it changes
'add them to a list.
End While
You could optimize or completely replace the function. What matters is that your code is readable, someone can tell what it's doing, and the ReplaceFirst function is testable.
Then, let's say you wanted another function that gave you all of the "versions" of your input string as the target string is replaced:
Public Function GetIterativeReplacements(searched As String, target As String, replacement As String) As List(of string)
Dim output As New List(Of String)
While searched.IndexOf(target) > -1
searched = ReplaceFirst(searched, target, replacement)
output.Add(searched)
End While
Return output
End Function
If you call
dim output as List(of string) = GetIterativeReplacments("AAAA","A","Bb")
It's going to return a list of strings containing
BbAAA, BbBbAA, BbBbBbA, BbBbBbBb
It's almost always good to keep methods short. If they start to get too long, just break them into smaller methods with clear names. That way you're not trying to read and follow and test one big, long function. That's difficult whether or not you're a new programmer. The trick isn't being able to create long, complex functions that we understand because we wrote them - it's creating small, simpler functions that anyone can understand.
Check your comments for a better solution, but for future reference you should use a while loop instead of a for loop if your condition will be changing and you're wanting to take that change into account.
I've made a simple example below to help you understand. If you tried the same with a for loop, you'd only get "one" "two" and "three" printed because the for loop doesn't 'see' that vals was changed
Dim vals As New List(Of String)
vals.Add("one")
vals.Add("two")
vals.Add("three")
Dim i As Integer = 0
While i < vals.Count
Console.WriteLine(vals(i))
If vals(i) = "two" Then
vals.Add("four")
vals.Add("five")
End If
i += 1
End While
If you do want to replace one by one instead of using the Replace function, you could use a while loop to look for the index of your search character/string, and then replace/insert at that index.
Sub Main()
Dim a As String = String.Empty
Dim b As String = String.Empty
Dim c As String = String.Empty
Dim d As Int32 = -1
Console.Write("Whole string: ")
a = Console.ReadLine()
Console.Write("Replace: ")
b = Console.ReadLine()
Console.Write("Replace with: ")
c = Console.ReadLine()
d = a.IndexOf(b)
While d > -1
a = a.Remove(d, b.Length)
a = a.Insert(d, c)
d = a.LastIndexOf(b)
End While
Console.WriteLine("Finished string: " & a)
Console.ReadLine()
End Sub
Output would look like this:
Whole string: This is A string for replAcing chArActers.
Replace: A
Replace with: Bb
Finished string: This is Bb string for replBbcing chBbrBbcters.
I was going to write a while loop to answer your question, but realized (with assistance from others) that you could just .replace(x,y)
Output.Text = Input.Text.Replace("A", "Bb")
'Input = N A T O
'Output = N Bb T O
Edit: There is probably a better alternative, but i quickly jotted this loop down, hope it helps.
You've said your new and don't fully understand while loops. So if you don't understand functions either or how to pass arguments to them, I'd suggest looking that up too.
This is your Event, It can be a Button click or Textbox text change.
'Cut & Paste into an Event (Change textboxes to whatever you have input/output)
Dim Input As String = textbox1.Text
Do While Input.Contains("A")
Input = ChangeString(Input, "A", "Bb")
' Do whatever you like with each return of ChangeString() here
Loop
textbox2.Text = Input
This is your Function, with 3 Arguments and a Return Value that can be called in your code
' Cut & Paste into Code somewhere (not inside another sub/Function)
Private Function ChangeString(Input As String, LookFor As Char, ReplaceWith As String)
Dim Output As String = Nothing
Dim cFlag As Boolean = False
For i As Integer = 0 To Input.Length - 1
Dim c As Char = Input(i)
If (c = LookFor) AndAlso (cFlag = False) Then
Output += ReplaceWith
cFlag = True
Else
Output += c
End If
Next
Console.WriteLine("Output: " & Output)
Return Output
End Function

How can I Parse text document in VB,Net for values?

I'm looking to parse this text file into strings to insert them into a database.
Source Text File gets read as the following string:
Line of unwanted text
Another line of unwanted data
Timestamp: 1/1/10 12:00 PM
ID: 1
Details: All data processed. Length will vary.
I'd like to just read Timestamp, ID and Details and place them into separate strings to insert them into a data table. What is the best method of capturing everything after the : and to the end of the line?
Dim Details as String = TextFile.Substring(Message.IndexOf("Details:"), X)
If you have to use a String as input, you can use String.Split to break it up into lines, and process each line. String.Substring can be used to extract the rest of the line - I've just hardcoded the starting positions below.
Dim timestamp As String = Nothing
Dim id As String = Nothing
Dim details As String = Nothing
For Each line In input.Split({vbCrLf, vbCr, vbLf}, StringSplitOptions.None)
If line.StartsWith("timestamp:", StringComparison.OrdinalIgnoreCase) Then
timestamp = line.Substring(10).Trim()
ElseIf line.StartsWith("id:", StringComparison.OrdinalIgnoreCase) Then
id = line.Substring(3).Trim()
ElseIf line.StartsWith("details:", StringComparison.OrdinalIgnoreCase) Then
details = line.Substring(8).Trim()
End If
Next
If you can change how you read the data, then the loop could just be:
For each line In File.ReadLines("your\file\name.txt")
...
Next
Assuming your files are flawless... One way to do it :
Imports System.IO
Dim AllLines() As String = File.ReadAllLines(FilePath)
Dim DatasIndex As Int32 = -1
For i As Int32 = 0 To AllLines.Length - 1
If AllLines(i).StartsWith("T") OrElse AllLines(i).StartsWith("t") Then
If AllLines(i).ToUpper().StartsWith("TIMESTAMP: ") Then
DatasIndex = i
Exit For
End If
End If
Next
If DatasIndex > -1 Then
' Dim ReadDate As Date = Date.Parse(AllLines(DatasIndex).Substring(11))
' Dim ReadID As Int32 = Integer.Parse(AllLines(DatasIndex + 1).Substring(4))
Dim ReadDate As String = AllLines(DatasIndex).Substring(11)
Dim ReadID As String = AllLines(DatasIndex + 1).Substring(4)
Dim ReadDetails As String = AllLines(DatasIndex + 2).Substring(9)
' send to database
End If
You didn't tell if Timestamp: , ID: and Details: Strings are always in the same order and has a trailing space after each property name.

Run-time error "13": in my VBA excel code

I'm writing a script that will count a numbers of days between few separate dates. I have a data in cell like:
1-In Progress#02-ASSIGNED TO TEAM#22/01/2013 14:54:23,4-On
Hold#02-ASSIGNED TO TEAM#18/01/2013 16:02:03,1-In Progress#02-ASSIGNED
TO TEAM#18/01/2013 16:02:03
That's the info about my transaction status. I want to count the numbers of days that this transaction was in "4-On Hold". So in this example it will be between 18/01/2013 and 22/01/2013.
I wrote something like this(sorry for ma native language words in text)
Sub Aktywnywiersz()
Dim wiersz, i, licz As Integer
Dim tekstwsadowy As String
Dim koniectekstu As String
Dim pozostalytekst As String
Dim dataztekstu As Date
Dim status4jest As Boolean
Dim status4byl As Boolean
Dim datarozpoczecia4 As Date
Dim datazakonczenia4 As Date
Dim dniw4 As Long
wiersz = 2 'I start my scrypt from second row of excel
Do Until IsEmpty(Cells(wiersz, "A")) 'this should work until there is any text in a row
status4jest = False 'is status 4-On Hold is now in a Loop
status4byl = False 'is status 4-On Hold was in las loop
dniw4 = 0 ' numbers od days in 4-On Hold status
tekstwsadowy = Cells(wiersz, "H").Value2 'grabing text
tekstwsadowy = dodanieprzecinka(tekstwsadowy) 'in some examples I had to add a coma at the end of text
For i = 1 To Len(tekstwsadowy)
If Right(Left(tekstwsadowy, i), 1) = "," Then licz = licz + 1 'count the number of comas in text that separates the changes in status
Next
For j = 1 To licz
koniectekstu = funkcjaliczeniadni(tekstwsadowy) 'take last record after coma
Cells(wiersz, "k") = koniectekstu
dataztekstu = funkcjadataztekstu(koniectekstu) 'take the date from this record
Cells(wiersz, "m") = dataztekstu
status4jest = funkcjaokreslenia4(koniectekstu) 'check if there is 4-On Hold in record
Cells(wiersz, "n") = status4jest
If (status4byl = False And staus4jest = True) Then
datarozpoczecia4 = dataztekstu
status4byl = True
ElseIf (status4byl = True And staus4jest = False) Then
datazakonczenia4 = dataztekstu
status4byl = False 'if elseif funkcion to check information about 4-On Hold
dniw4 = funkcjaobliczeniadniw4(dniw4, datazakonczenia4, datarozpoczecia4) 'count days in 4-On Hold
Else
'Else not needed...
End If
tekstwsadowy = resztatekstu(tekstwsadowy, koniectekstu) 'remove last record from main text
Next
Cells(wiersz, "L") = dniw4 ' show number of days in 4-On Hold status
wiersz = wiersz + 1
Loop
End Sub
Function funkcjaliczeniadni(tekstwsadowy As String)
Dim a, dl As Integer
dl = Len(tekstwsadowy)
a = 0
On Error GoTo errhandler:
Do Until a > dl
a = Application.WorksheetFunction.Find(",", tekstwsadowy, a + 1)
Loop
funkcjaliczeniadni = tekstwsadowy
Exit Function
errhandler:
funkcjaliczeniadni = Right(tekstwsadowy, dl - a)
End Function
Function dodanieprzecinka(tekstwsadowy As String)
If Right(tekstwsadowy, 1) = "," Then
dodanieprzecinka = Left(tekstwsadowy, Len(tekstwsadowy) - 1)
Else
dodanieprzecinka = tekstwsadowy
End If
End Function
Function resztatekstu(tekstwsadowy, koniectekstu As String)
resztatekstu = Left(tekstwsadowy, Len(tekstwsadowy) - Len(koniectekstu))
End Function
Function funkcjadataztekstu(koniectekstu As String)
funkcjadataztekstu = Right(koniectekstu, 19)
funkcjadataztekstu = Left(funkcjadataztekstu, 10)
End Function
Function funkcjaobliczeniadniw4(dniw4 As Long, datazakonczenia4 As Date, datarozpoczecia4 As Date)
Dim liczbadni As Integer
liczbadni = DateDiff(d, datarozpoczecia4, datazakonczenia4)
funkcjaobliczaniadniw4 = dniw4 + liczbadni
End Function
Function funkcjaokreslenia4(koniectekstu As String)
Dim pierwszyznak As String
pierwszyznak = "4"
If pierszyznak Like Left(koniectekstu, 1) Then
funkcjaokreslenia4 = True
Else
funkcjaokreslenia4 = False
End If
End Function
And for now I get
Run-time error "13"
in
dataztekstu = funkcjadataztekstu(koniectekstu) 'take the date from this record
I would be very grateful for any help.
You are getting that error because of Type Mismatch. dataztekstu is declared as a date and most probably the expression which is being returned by the function funkcjadataztekstu is not a date. You will have to step through it to find what value you are getting in return.
Here is a simple example to replicate that problem
This will give you that error
Option Explicit
Sub Sample()
Dim dt As String
Dim D As Date
dt = "Blah Blah"
D = getdate(dt)
Debug.Print D
End Sub
Function getdate(dd As String)
getdate = dd
End Function
This won't
Option Explicit
Sub Sample()
Dim dt As String
Dim D As Date
dt = "12/12/2014"
D = getdate(dt)
Debug.Print D
End Sub
Function getdate(dd As String)
getdate = dd
End Function
If you change your function to this
Function funkcjadataztekstu(koniectekstu As String)
Dim temp As String
temp = Right(koniectekstu, 19)
temp = Left(temp, 10)
MsgBox temp '<~~ This will tell you if you are getting a valid date in return
funkcjadataztekstu = temp
End Function
Then you can see what that function is returning.
I tried running your code, but it is a little difficult to understand just what it is that you want to do. Part of it is the code in your language, but the code is also hard to read beacuse of the lack of indentation etc. :)
Also, I do not understand how the data in the worksheet looks. I did get it running by guessing, though, and when I did I got the same error you are describing on the second run of the For loop - that was because the koniectekstu string was empty. Not sure if this is your problem, so my solution is a very general.
In order to solve this type of problem:
Use Option Explicit at the top of your code module. This will make you have to declare all variables used in the module, and you will remove many of the problems you have before you run the code. Eg you are declaring a variable status4jest but using a different variable called staus4jest and Excel will not complain unless you use Option Explicit.
Declare return types for your functions.
Format your code so it will be easier to read. Use space before and after statements. Comment everything! You have done some, but make sure a beginner can understand. I will edit you code as an example of indentation.
Debug! Step through your code using F8 and make sure all variables contain what you think they do. You will most likely solve your problem by debugging the code this way.
Ask for help here on specific problems you run into or how to solve specific problems, do not send all the code and ask why it is not working. If you break down your problems into parts and ask separately, you will learn VBA yourself a lot faster.
A specific tip regarding your code: look up the Split function. It can take a string and make an array based on a delimiter - Example: Split(tekstwsadowy, ",") will give you an array of strings, with the text between the commas.
Did I mention Option Explicit? ;)
Anyway, I hope this helps, even if I did not solve the exact error you are getting.